11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
24.2k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 24.2k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
  *  **  * ** * * *** *  ** *  *  ******  %d",&a ,&b );

*   ** * **   *   ** *      *    i=a;i<b;i++){
  **** **  *  *   *   * *  **  * *    * ***   * * *   * ** ** j=2;j<=b;j++){
*     ***  ** *  *    * **     *  **     ** *****  * ***** ** * * * ** * *  * ** ******  && i%j==0) break;
*  * * *  *   *** **   ** ** **** **** **** *** **  * *  *  * **  *  * *  *    **  if(i==j){
*        * *  * **** **     ****   * * * *****      *** * * ** *   *   *  **  *** **   ******* ** *  * ***  *       
    *** * ***** *** ** * **  *****   **  *     *  *******  **  *  *** **   *****   *  *   *** ****** ** ***** * *** *   * **  *  *     * *  * * * **  *     
   ** * ***   ** **   ***     *   *   * *     *   ** * *     * *     * ** * ** ***** *  *  ** * * **  *      **** * * **  ***   ****   **  ***** ** 
   *  *  *********  *** * *   ** *  ** * * *** **** *****   *  **   ** ******   **  ** ***** ***    ***  **
*** ****   * * ** *  *    *** *   **   ****   ** **   ***  **** *    ** *** *****   *  **   ** ****    *     **   *  * * * * printf(" %d",i);
** ** *    **    *  *  * * **   ** * * ***** * ****  ** *   ** ** * * ** * **
***  **  *** * **  ***   *** ***  **** ** * * *** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *          ***  *
 **   **  ** **    *
**  *  *** *  **   *

int main()
{
int i,n,m;
** **  ***  *     ***    *
   **   ***   * ** * *  ***  
**  * **  ******

{



  * **   * *** * *  *
{
** *      
 **
}
   * * *  * **  *

** * 


 *   *** *    ** *    


}}
*  * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * *  * * **  * *** **
  * * *          *    *
** * *   *  *** * ** *

int main()
{
int i,n,m;
******   *   ***  *** * *
** *** *   * *   ** *  * 
*   ***  ***    

{



 *** ******* *   *  
{
****  **
* ** 
}
******    * ** * * 

** 


 *     **** ** ***** *   


}}
* * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* **** * *  * ***** ***  ***  *  **   *  * %d",&a ,&b );

**  *  ** *  *   ****    ***    *       i=a;i<=b;i++){
**** ** *   * * * * ****     *  ****  ** *  **   *       ***   j=2;j<=b;j++){
** *  **     *******   * ** ***** ***       **  **    * * **      **    **** **  * && i%j==0) break;
      *  * ****  * ** *  ** **  ****   ***  * *  ****      **  *  ** *   *  *     if(i==j){
** * * *       ***   ******  *  *  **** **     ****   *  * * * *** * ****     *******   *** * ***  *         *  ****  ***
 ***** * * ***  ***** *   *   ***** * * **  ******    *    ** *     * * **** **    *** ***  **** *      ** *** *****     *   * * ****   *        
 ***  * * *  * * ** * ***** ***** **  *******    * ***  *    *   *     * **       * ** *  **    *** * ****  ***    ****  * * ** *     *     *
*  *** *** **** *   ** ** * *  ** *** * **   * ****  ** *** * * ****  *    *** * ****    * * ******  ** *  
**** *** ****    ***  * *** * **  * *  * *  ** *    **     *  * **   ***   *  ******   ***     ** ** * ** printf(" %d",i);
* ** ******    *   *     **    **   ********  **** * **** ***  * ** **   *    *
 **** *  ** *  * *   **  **  * *** *    * *  ***  

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
*****    **    * *  **  *** *  a,b;
 * * *   *   *  ** *** *   ******* *  *** * %d",&a ,&b );

 **** *** ** **  * * ****  * **  * * * i=a;i<=b;i++){
***  ****  *               * *    *    ** * *  ** *     *  j=2;j<=b;j++){
** **   *   **   *****   *** *  * *  *   ** * *** * ** **    *** ***   * *   ** *  *   *    && i%j==0) break;
* ***   * * *     * ******   **        **   ***  ** *  **  *  * ******* * ** * * *   if(i==j){
 *  *    * *   **      ** ***  * **  *  * * * **** * * *** **   *  ** * ** *  ** * ** * * *******  ***       *   * ",i);
** **** **     *  *    **** *   **  ***  **    *  *****    ****    *  ***  **   * * ** 
* *  *   * * *   * *** *  *** **** *    *** * * *   * * **   **  *

  ** ***    * * *   **  *  
* *    *  * * **** *    * *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *   *  *  *   
 *   **** ******  
int main(){
   *    * **     *** * * * a,b;
**** * *  ** * *      * * *** ** *****    *  **  ** *  ,&b );

  * **  *    *  * ****** *  * i=a;i<=b;i++){
** *  ** *****  **  *******  *** ****   * *  * * **  j=2;j<=b;j++){
* **   ******** *  * *  ***  ** * *    **  *****  * *  *  *  ****  * *  ** **  * **   && i%j==0) break;
   *****    **    * * *  *   *** **      *   **** * **  **** ***   **  * *  **    if(i==j) printf("%d ",i);
 *  ****  *****  ** *    ***    ** ***    **     *   *  
* ** **  *** ******* * ***   **
     **  **  *   ** * **  *    ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **  * ** * ** ***  *  *  **   m, n, divider, prime[100], cnt=0, i=0;

         *** **  * *  * **** ** **** ** *  * %d", &m, &n);

 *  * *** *** * *  * ****** *   = m + 1; m < n; m++)
*  *  *   *** ** ** *** **
  *  ** * **  *     *    *** **** * *  ***   * ******* * ***** * *** = 2; divider < m; divider++)
***    ***    ** * ** * * *** * * **  *       *     ***  * * 
* *****    ** *  *   *  ***        ***     * ** ***** *** ***** ** ** *   * **    *   *   % divider == 0)
 * *  *  ** ** * *  *  *  ***  ***   ***** * *  * * **      ***  *  * * * ** * **** ******* *  ** ** *  * 
**    *******  *   *    * *  *      *   * *  *
    * * ** * ***** *  *** ***    **** *   ***    ****   == divider)
 *  ** * *  **   ** * * ** ****     *** ** ** * * ****  *
* ** * * * * **** *  *** ***  *  **   ** *  ** *         * *** **** *     ** ** *   * * = m;
* **  ** *  *** **   *  *  *     * * *  ** **  *
 ** *** **  ****** *   * 
 * *** *  *** * *  * * ** **  i<cnt;i++)
   *  * *   **   * *  **  
*  **   ** *******  * *   ** **      *** **   *** **   *     ***   prime[i]);
* *** * * **  *** *    ***  *   *  ** *  *    * +1 < cnt)
 * * * *    ** *  * *   *  **    * ** *  ** *** ***   * *    *    ***      * ** * ** ***** * * ");
    }

**** **    ** *  ***      *    * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
*    *    * * *** ** *****  ****  * * * * *  
* *  ***   * *    **       **  **   * * *** * ******* *** * * * ***** *    *
    ** *  *    *** ** ** ** ** *  * *  *  ** *     * *    ** **  * ** ** *****  *    *  **
 *    * *     ***  * * * *** * ****    * *     **   ********** ****  *    **** ** *     ** **   *  * * * 
****  ** ** **   *  * *  *   *  **** * * **** *   ****   ** * *** **** *** * * ******** * 
**  *  *  *****  * ***   *  * ***     ** * **** ****  *** * ***     *   *   *  **  *    *         *  **  **  *  *  ",i);
**  * **  *  * **    *  * ******  *  *** * *   ** *** ****   ** *** ****** **  * * ***      *  *  ***   *
*      *     *      ** *   *    ** ** *  *** *  * * *   **    ** * **    *******
 * ** * * * * **** ****** ** * ***** *     *** ** ** **  ** **** ** *     ***  ** ***** * if(k==0){
*   * * * * *   ***  *****  *    * *** **  *** ***  **      **** ** **  *    ** * **** * *** *  ****** ****     ** * 
* * ** **   **   ** **  *** * *** *     * *  *   *  *  ** *    *  *     * * *     *
* *  * ** * * * *  * ** **   ** * *    * *** *    * ** 
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d *   *  * ** *  ,&b);

for  * ** * * **  
{
    **  *** * * ** *******        **  is testing\n",i);
**   * ****** *  *  **  ***  ** * j=0;
 ****  **** ***  *    * * * **  = 1;
  *****    ****  *  *        (j=2;j<i;j++)
 *   *   ***     *  *** ***
* ** **   ***** * * ***    *  ** * **   * **   * *** * * *** ** ** **    %d is mode\n",j);
** *** **   **** ***   *    * **  * *** * ****** *** * * reminder=i%j;
*  *********** * *   **  *  *      * * *   **   *  (reminder == 0)
**  *   **  * *    *   * ****   *  *  *** **    *** **  ***
 **** ****  *       * * **** *  *** * * * *  * ** *** * ***   *    * ** **  * * * ** **  *  *    * *** *  **    * *** **   *  * *
*  *   *   * * ***    * * *** **** * *  **** *  ***   ******   *     * * **    **** * *
*    * * *  * *** ** **** **  *  * *  * **      *******  ******    *     *  * ** *  * 
*  *****     *      ****   ** *    **   *** ****   * *
**     * ***  *   ** ***    
* *   ***   ** * *****  **** ** (flag==1)
*****    *  *** ** **  ******  * ***    *  * * *   * * * ** *** * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.4k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 20.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users