11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
13.8k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 13.8k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* **   ***** * *  ***     ** * *** * * ** %d",&a ,&b );

 *    *     * **  *   *   *  * * * i=a;i<b;i++){
* *   * *  * *  ** * *** * * ** * ** **    **       j=2;j<=b;j++){
* * ** * **  ** ***** *** * ****     *** *     *** ** **** ** ** * *  ** ** ** * *    ****  && i%j==0) break;
   * * *  **  **** *  ***** ** ** * *       * ** * *   *** *** *     *   **  ***  * if(i==j){
* *    * **     *  ***  *     ** ** * ***   ****** ******** ** * * ** **    * *   * * * ***  **  * * * ***    * *  
 *  ** *    * **** *  ** **** * * ** * * ***   *      *  *** **   **  * *   **       * *  ** ***  *** *   *    ***   ***  ** *  *** ****  ** **  **  
*   *  ***** * *  * ** * * **    ***    * **  *** **    *    *   *   *   * *    * *  * * ** ** ***   *    **  *   *  **   *   * * *  
  ** * * ** * *  * * *  * **  * * ****** *** ** * *      **** * *     **    * * * *  *** * * *   **  * ** ** *   
  ** **** ** *    *   *  ****  * **     ** ** *  *****  **   ** * * ** *** *  * * *   *   * **  **** ******** *** *****  ** printf(" %d",i);
 *   * ** * * ** ** *  *  **    * *    *  ****   ***  ***     * **    ** *****  *   ** *
 ** ** ********     * ** **  **  * ****  * *   ** *** * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ****  *** * *    * *
**   *  **   *** **  ****
***     * *  **** * ****

int main()
{
int i,n,m;
  ** *** *  **  ** *** **   ** **  
    ***  ** ***** *  *********
* ** *  *  *   *  *  *

{



** ** *  ** ** * *****
{
*  ** 
 * ***
}
    **  ********

***


 ****** * *  ***  *    **


}}
       0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *****  *** *      
  ***    ***** **   ** 
 **  *   ** * **    *

int main()
{
int i,n,m;
*  * *  *** *****      **   
*** *    **    *   **    *
*** *   * *****  

{



  **  **** *  * *** 
{
***   
    
}
** *** *** 

 * *  


* * *  * ***   ***   **  *


}}
** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* ** ** * * *   **** *** ** * * ***** * %d",&a ,&b );

  ** * * ** ** ** **  *     *  i=a;i<=b;i++){
 ****    **   * *** **** ****  **     *  *     *    * **   **    j=2;j<=b;j++){
  * *** ***  *     ** *  * ***  ** *     ***  ***** ****   *** *  *  *    * **** * && i%j==0) break;
***     *** * * *  * * * * ** * **  * * * **  *   * ****  **   ** *  * *  ** *  if(i==j){
  *   *  *** **** *   *       ***** **    **  * *   ** * **  *  *     * ** ****  * *   * *    *   **    * 
*  *  * *      *  * * *    **  **  *  * * **        **     * *****  * ** *  ** **** **** * ** *  * * ***    * **  *   ** * *   ***   **   * **  *   *** **
 **  * * * **   *** *  *  *  * *****   **  *******   * **   * *****  ***        * *** ** **    *  * * *  *   ****  * *  ***   ***** **
 *      *** * *   **   * * *   * *    ***  * ** *    **   *   * *  * **  **** ** **  ** *  ****   * *   
 *  ****     **  * *  ** ***** *    *  *  **  *   *     ****  *   *  * *     * **   *  * ** *  *  * * ** **  *** * ** **  printf(" %d",i);
* *  *      *  *** *  *** * * *  *   *   *    *  * *  *     ***  *      * 
 *   *  * *   ** ** * * * **** ** * ****** *** * * *  *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
**** * **  * ** **** ***** **  **   a,b;
**  **** ***  *****  * * *   ***    *  * %d",&a ,&b );

**** ** * **  **  ***  *  ** * i=a;i<=b;i++){
 ** *** * * ** ** **    **  *****     ** ***** *  *     *     * j=2;j<=b;j++){
** * ***   ****   * ** ***  ** *       ** *    * **** * * *    **     *      ***    * ** && i%j==0) break;
    **     * **** * **  ** * **   *  *    **  * ***    *** ***    ** **   ******  **     * * if(i==j){
 *   * **** ** ** ***   *    ****     ***    *  *** * ** ** * *   * *    * * ***** *    * ******   **    ***  *  ****  ** ",i);
** **  *  ** ** *     ** ****  ** ** * *   *** **    ** **** *    * *    *
    **  ** **   * **       ****   * ****** *** * ***   *  *    

*    **  ** **     *  *** ****  
 **  *   ** ***    *** *  * * *  * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ****  ***  * **** * * ***
*   **  *  * * * *** 
int main(){
 *   *  * ***     * ** **  * **  * a,b;
*** *  *     * * *     * **   ** *   * *****   * **  ,&b );

********** *** * **** * *** i=a;i<=b;i++){
* *** ** *** * *    ***   ***  ** *  * *  * * ****   * ** * j=2;j<=b;j++){
*   **       * *** * * *   *  ***** * *** *  * * * **** *      ** * ** **      && i%j==0) break;
**    *     *** *** *    **   ** * ***** *   *  * * **  * ** * **  * * * **   ******   if(i==j) printf("%d ",i);
 *    *      * *  ** **        *  * *       ***  ** 
     ***** *   ** * ***       **
  ** * ***  * *  *    *     *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *  ***     * * **  **  *** m, n, divider, prime[100], cnt=0, i=0;

  *  ** *    ***** *    *   ** *  %d", &m, &n);

* ***  **    ***    ** * = m + 1; m < n; m++)
      * * * ** **      *** 
* *  *** ** * *   **  ***  ***  *  *** * ***       * *    = 2; divider < m; divider++)
*  ***       * *   * *    *  *  * * ** ** **  * **  **  *   * 
***    ** *****  ** **  *  **** **  *  * ** *  **  *  *******    * ****     **  % divider == 0)
****   *   ***  *** * *    * *  **  *   * ***  *  * ***  *     *     * * *   * *    * * * **  *** *****
 *   *  * **      ** *   *** ***  *  *  *    ** ***   **
  *   ** * * ****      ***  *   * *  *    * * *   * *   ** == divider)
**  ***   **  * * *   * ** * *** ** ** ******** **
 ** * *  *   *  *** *** ** * *** **** ****     * * **       *******  * ** ***** **** * **  = m;
*   *****    ** *   * ** *** *   ** *  **** *  
*  *  *  *  * *    ***  *
 * *  *  * *  *    ** * **  *  *  *  *  i<cnt;i++)
*  * * * * ***** ** ** ***  * 
** ** *   * * *    *******  *****  **     * *  * ****  **   * *****   prime[i]);
* *  * *   *  *** **** ** *** ****   *  * ****  * *   +1 < cnt)
  *  * * * * * * *** *  * ** * *  *  *  **   *  *     * * * *  * ***   * * ***  * * * **    * * ");
    }

      * ** *** * **  * **** *  * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* ***  **** * ****     ** ** * **  ** * *  *** * *
  * **  **  *  *  * * **   ****       * * ****** **** *  *** ** ***       * 
* *   *****       **  * *  *  * **  * ** * **  *** **  ***  **** ** ** **  * * * ***** **** 
** ** *  *  **    **** * *** *   *    * ** ** *  ******   *  *****  **** *     *    *   * * * *   *** * * ** 
 ******** ***        **            *  *   ***  * *   *** **   ****** *  * ******* ** **** 
*  ** **      **  *     * *  * **  * ** *   **** **  **** *    *   * * * *    **  *         **** * *  *    **** ****  ",i);
**      * ** ***      * **   ***   *   *     * ***  **  * ** *  **    *  ********** *    ****  *   *   * 
*         *  ** *     *** ******* *    ** *    *****  **   * *      *  ****    ** 
**   **** *    **    **   * *  * *  *   * *     *   ***  ************** **  * ***    * ** * if(k==0){
   *     *  * * ** * **   *** * ***  *     ***  **  *   ** *   ***  ***  ****  **   ** ****   *  ** * * * **
   *** *   *  *   **  ****  ***     ******* *  **      * ** *  *  **  * *     *    *   *
**  **** * *  *** * ****   *** **             *   *  * 
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d     *   * *** * ,&b);

for   **     *  **
{
 *    *** * *   *  ****** * * ***     * * **   is testing\n",i);
 **  *   *****   **** ** ****   j=0;
**  *   *    *  **   *  ** **  * * = 1;
 ** *** ** **  * * *****  (j=2;j<i;j++)
***** ***** *   *      ***** 
  * * *****  * * * *** **** *  ** *  *  * * ******** *    **** * *** **  *   %d is mode\n",j);
 **** * * **   *  *      **  *      *  ****   * * * **   reminder=i%j;
 * * ** ***   ****  *  *  *  ***    *       *      (reminder == 0)
* *    **** ** **  ****    ***     *  * **    * *** ** 
 * **  ** *  ***     * * ** * **** * ** **   ** *    **   **  * * * **    ***** *  **  *  **   * * *   ***  *  **  ** ** *  *  *  * 
 * * ***    **    ** * ****  *****  *         *      *  ***     *  * *  *  * * * ** * * * ** *
 ** ****** ** *** *  ** **  *    *  * *****  **  ***** * ***   *****  *** ***  
    * *** ****  ** ***  **  ** * ** *  * *  ***  *** *
****** *      ** * * **    
* *   ****     * ** ***  *  (flag==1)
 ** *    * ****  *     *  ********** **  *    **  *   *   *   * * *   *  ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.142
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.5k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users