0 like 0 dislike
3.5k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 3.5k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * * * *** ** * ** *** * %d",&a ,&b );

* * **** *** ** ** ** * * * * i=a;i<b;i++){
** *** * * *** ** * ****** * * ** *** * **** * j=2;j<=b;j++){
* * * * * * * *** * ** ** * * * ** * ** * * **** ******* * * * && i%j==0) break;
* **** *** * ** ** * * ** ** * * * *** *** *** ** if(i==j){
****** ** * * ** ***** ** * * * ** * * **** * * *** ** *** * ** ** ** * ** ** ** ** * * ** ** ****
** ****** *** ** ****** ** *** **** **** **** * * ** * ** * * ** *** * ** * * ** * *** * * * * ** *
* * ** * * * *** * * ** * ** * * * * * ***** * * * * * * ** ****** *** ****** * ** * * ** ** ***** ** * * *** * ** * *
**** * ** * *** * * ** ** ** *** *** ** * ** * ** * ** * *** * * **** * **** * ** ** *
* * ** *** * * * * *** * ** * * ** ** **** ** * *** * * * **** **** *** * * printf(" %d",i);
** *** *** *** * ****** ***** * * *** * ** ***** * * * ** * * *
* * ** ** * ** * ** ** ** * * * ***

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ** *
* * * * * ***
** * ** *** ******

int main()
{
int i,n,m;
** * ***** ** **** ** **** *
* *** * * * ** ****
********* **

{



* * * *** * ****
{
* *
** *
}
* * * ** *




*** * ** ** *


}}
**** * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ****
*** **** * * ***
*** * *** *

int main()
{
int i,n,m;
** *** ** * *
** ** * *** *** * ** *
* * ** * **

{



*** *** ** *** *
{
*** **
*
}
** * ****

**


* ** ***** * ****** *


}}
* * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* ***** *** * **** *** * %d",&a ,&b );

* * *** ** *** * ** * * i=a;i<=b;i++){
* * *** * * * * **** *** **** ** * * * * j=2;j<=b;j++){
* * * ****** * * ** * ** * *** ** ** *** * * * ***** ** * ** **** && i%j==0) break;
* *** * ***** *** * * ** * * ** * * * **** * ** * * * * if(i==j){
* * *** ** * ** * *** * ** **** ** * * ***** ***** * *** * **** * ** * *** ** ** * * ** ** **
** ** * * *** * * ** * * ****** *** * ***** * ***** *** ** * ** * *** ** * * ** ** *** * * * *** * * * * * ** * ** * * * * **
** *** * * * *** * ** * * * **** * * * * * ****** * ** ** ** * * * * * **** *** * ** *
* * * *** ** * ** ** ** * * * ** ****** * *** * * ** *** ** * * ** * * ** ******** * *
* *** ** * *** ****** * **** *** *** ** * ****** ** *** *** * ** ** * * * * printf(" %d",i);
** * * ** ** ** *** ** *********** * ** ** ** **** * * ***
** * *** ** *** * *** *** * * ****** **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** * * **** * * * *** ** a,b;
* * ***** * * * **** * ** *** %d",&a ,&b );

** *** ** * * *** * ** **** i=a;i<=b;i++){
* ** * ** * * ** * ** ** **** * * * *** *** j=2;j<=b;j++){
** ** *** * * * ****** * * ** ** * **** ** ** * * ** * && i%j==0) break;
* ***** ** ** ** ** **** * * ** ** * *** * * * * * * *** * **** if(i==j){
* ** * ** * * * ***** ** ** **** ** **** ** ** ** * *** ** * *** * * * * ** ** *** ** ** ",i);
** ** ** * * ******* * * ***** * * ** * ** ** * * *** ** ** * ** * *
* * ******* **** ** ** * ** ** ******* * * * *

** ** * * **** * * **
** * ** ** * ** ** ** ** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** **** * **
* ** *** * * **** ***
int main(){
** ** * *** * * * * a,b;
* ** *** ** * ************ * *** *** * ** ,&b );

* * ***** *** ** ** * i=a;i<=b;i++){
* * * * * * * * * ** ** **** * *** ***** * * j=2;j<=b;j++){
* * * ********** **** * ** * * * *** * * ** *** ** * **** * ** * * * ** && i%j==0) break;
** ***** * * * * ** * ** *** * * * *** **** * ** *** ****** * ** * * * if(i==j) printf("%d ",i);
* * * * ** ** * **** * * * * * ** ***
* * ** * *** * **
* *** * * ** * * * ***** **** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ***** * **** * * * * m, n, divider, prime[100], cnt=0, i=0;

* * ** ** *** ** * * ** **** * * %d", &m, &n);

* *** ** * * **** = m + 1; m < n; m++)
********** * * *** ** **
** **** * * * ** *********** * * ** * * = 2; divider < m; divider++)
** **** * * ******* ** ** ** * *** * ******
* ** ******* * ** ** * * *** ***** * * ** ** ****** *** ** % divider == 0)
* * ***** ** ** * ** * * * ** ** **** ******** ** * *** ** **** * ****** ** * * * * *** * ** *
* ***** *** * ** **** ***** * * ** *
********* * * ** * * ** * * * * ** ** * ** * == divider)
** *** **** * * * * ***** **** *** * ** *
*** * * *** ** ** *** * **** * *** * * * *** * ** ** * *** ** *** * **** = m;
* * ** * ***** * *** * *****
** * *** * * ** *
* * * * * * ** * *** i<cnt;i++)
** * **** *** ** ***** *
* * ** ** ** *** ** * * ** ** ** ** ******* prime[i]);
* * * * **** ** * * **** * ** *** *** * * *** +1 < cnt)
* * **** * **** *** ** *** *** * * *** *** * * *** ** * ** ** ****** * ");
    }

*** ******* * ** ** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
** **** **** ** **** ** **** ** ***
** * ** ******* * * * ** * ** ** ** ** * *** * ** **
** ** ** **** ** * *** ** * * * ** * ******** ** * * * ****
** *** ** * * ***** ****** ** * * * ** *** * * * *** * * ** * * ** *** **
**** * ** ** * * ** * * * * * ** * * * ** * **** * ** * * * **
** * * *** * ** ** * * * * *** * ** * * *********** * * ** ** * ** ** * ************* *** * ",i);
* * * * ** * ** *** *** * * ******** * * ***** * * * ******** * ** ***** ** *** * ** ** ** **
**** ** **** ** * * * * * **** * * *** * ** * * * ** * * * *
* * ** * * *** * * * ** ** * * *** ** ** * * ** * * if(k==0){
* * ** ** **** * * *** * * * * * ***** *** *** *** * *** * * * * *** ** *** ** * ** **** * *
***** ******** * ****** * *** *** * * * **** *** ***** *** * *** ** * *
* * ***** * * * * *** * * *** * *** * ** ***
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d ** ** * * * ** ,&b);

for * ** ** **
{
**** * * **** * *** * *** * * * is testing\n",i);
*** *** ** * * * ** j=0;
** ******* ** ** *** **** = 1;
** *** *** ** (j=2;j<i;j++)
* *** **** * **** * **** ***
* * ** * * * * * * *** *** *** ** * * **** *   %d is mode\n",j);
*** ***** *** * ** **** ****** * *** reminder=i%j;
* *** ** ** * * **** * **** * * * *** * ** (reminder == 0)
* ** ** * * ** ** * * *** ** ** * ** **
***** * * ** * * * ***** * ** * ** * * * ** * * *** * * * * *** ***** * *
* * ** ******* ******* * * ** ** * * * * ** **** * *** ** *** * *** *
* *** ** * *** **** * * **** ** ****** **** * ** ****** ** ** *
*** * **** ** ** ** * * * * * **** *
* * ** * * ** * *
* ** ***** * ** ** ** * (flag==1)
**** ** * * *** ** * * ***** ** *** ****** * **** ** * ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.165
©2016-2024

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users