0 like 0 dislike
10k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 10k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
****** *** * * * ** *** ** * %d",&a ,&b );

** *** * * * * *** * i=a;i<b;i++){
* ** ** * ** * ** * * **** * * *** ** j=2;j<=b;j++){
** * **** *** * * * * * *** * * ** **** ** * * ** * ** * ** ** * **** ** && i%j==0) break;
* ****** ** * ** ** ** * *** **** *** ** * ** ** ** * **** * * ** if(i==j){
* *** * ** * * * *** * * * ***** ***** * **** * *** * * * **** * * * ** * ** ***
* * * * *** ** ** ** ** * *** * * *** *** ***** * * * * ***** *** * ***** * ** ** * * ** * * *** * * * *
* * * * * * ** ** ** ** **** * ** * ** * * ** **** * *** **** * * ** * * * * * * * * * ** * * *
* ** * * **** **** *** ** * **** ****** * *** * * *** *** ** ** ** * * * ** *
* ** * **** * * * *** * ** **** * ******* * ** ** * **** * * ** ** * * * printf(" %d",i);
** ** * * * * ** ** * *** ******* **** * * * *** * * *** * *** *
* * * * * ****** * * * ** **** * * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * **** * *
** * ** ** *** *****
*** * **** * ** * *

int main()
{
int i,n,m;
** * * *** * * * ** * *
** * * ** ** * * ** * **
* ** ** *** *****

{



**** * * ** * ****
{
***
* ***
}
* * * * * *

* *


* * ** ** *** ** ***


}}
** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * **** * *
** * * *** * *
***** * ** ** * * * * *

int main()
{
int i,n,m;
*** * *** * *** *
** * * * ** * **
** * ** *

{



* **** ** * ** *
{
*** *
**
}
* * * * *** *

* * *


* * * * *****


}}
0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
** ** ** * ** * * * * * *** *** %d",&a ,&b );

* ** ** ** * ******* * * ** i=a;i<=b;i++){
* * ******* * ** * * * *** *** ** ** * * j=2;j<=b;j++){
* * ** * * ** * ** * *** **** * * **** * **** * * * **** * * *** && i%j==0) break;
* *** ****** * ** **** * * * * **** * ** * ** **** **** ***** * ****** *** if(i==j){
* ** ** * ****** * ** * *** * * ** *** ** *** ** * * *** ** * ** ** ** ** * **
* ** *** *** ** *** ***** * * * * **** *** * * * * * * ** *** * *** *** * * * * ** ** *** ** *** ** ** **** * * * * * *** *** *** * ****
** ** ****** ** * ** *** * ** **** ** ** * * * ** *** ******** * * ** * * * * ** *** * * *** *** * * **
* ** ***** * ** * *** ** ** * *** ** * * *** ** * * ** ** ** ** * * **** ***
* * ** * *** ** * * * * * ******** * *** **** ***** *** *** ** * * * ***** * **** ** ** ** printf(" %d",i);
* ** ****** * * * ** * *** * * * * *** ** *** ** *** * *** ***** * *
**** ** ** *** * *** * *** ** * ** * * * * * **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* ** ** ** * * * ** * * a,b;
* * ** *** * *** * ***** * * %d",&a ,&b );

* * ** * * * *** * * * * * i=a;i<=b;i++){
* ** *** * * * ** * * ** ***** * * * ** * ** ** j=2;j<=b;j++){
*** **** * * * ** * ** *** ***** *** * ***** * * * ** * *** * && i%j==0) break;
** ** **** ** *** * ****** *** * * * * *** * * * * * * ** **** ** if(i==j){
*** ** * * ** * * * * ** * *** * * ** * ** * * * * ** * *** * * ** * * * * ** ",i);
**** * ***** * * * * ** * ** **** * * ** **** * * *** * ** * **
** ** * * * *** ** * ** * * **

* ***** * ** *** ******* *
******** * ** *** ** * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** * ** ** ***
** * * ** * ***
int main(){
* ** * * * ** * a,b;
* ** ** ** * * * * * ******* *** * **** *** ,&b );

***** * * * *** * * * ***** i=a;i<=b;i++){
* **** ** * * *** ***** **** * * * ** * * j=2;j<=b;j++){
** * * * ** * ** * *** * * * * * * * * * ** * ** *** ********* * && i%j==0) break;
* ** * **** * *** ** ** * * * * ** * * ***** * * ** **** * *** if(i==j) printf("%d ",i);
** ** *** * ** *** *** ** * *** * ** *****
** ****** * *** *** ** **
** * *** ** * **** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *** ** * ** **** * * m, n, divider, prime[100], cnt=0, i=0;

* **** * * ** *** *** * * ** %d", &m, &n);

* ** * *** ** * * ** * * = m + 1; m < n; m++)
** * * * ** * * * * * **
** * * * * * *** * * * * *** * * * * = 2; divider < m; divider++)
* *** **** * ** ** ** * *** ****** * ** * ** ***
* * * * *** *** * * ** * * * ******** * ** * *** * *** *** *** % divider == 0)
***** * * **** * * ** *** ** * * * * *** * * * * ** * * *** ******* * * **** * * *
**** ** ****** ** * * * *** ** **** * * * **
* * * ** **** ** * ** * ***** ** ** * *** **** **** == divider)
* * **** *** ** * * *** * *** * * * *
* * *** **** ** ** ***** *** ** * ****** * ** ****** **** ** = m;
** *** * ** * * ** * * * * * * *** * ** * *
* *** *** * ** ****** * *
*** * ** *** ** * * * ** i<cnt;i++)
***** * * * *** * ****
* ***** * * ** *** **** * * * * ** * * ** ** * ** prime[i]);
*** * * ******* ** *** * *** *** * * ** +1 < cnt)
* * *** * * ****** ** **** * * * ** * ** ** ** * * ** * * * ");
    }

** ****** ** * * * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* ** * * * * ** * * **** * * **
**** ** ** * * *** ** ** ********* * * * * * * * ** ** *
** * ** **** ** * * ** * ** * ****** * * **** ** *** * ** * *
* ** * * ** * *** * ** ** * * ***** * * * * * *** ** ** * * ******** ** **** * * *
* ** ** * * *** *** * * * * ****** **** * ** ** ****** ** ** ** ** *
***** * * *** * * ** * * * * *** *** * ** ** ** * * * ***** ** ** ** * * ** *** ** * ",i);
****** * * ****** ** ** ***** ***** * ***** * * ******* * *** * * ** * * ** * *****
* ** * * * ***** * * *** * * **** * ** * ** * * * ********* * ****
*** ****** * ** ***** * * * **** * * * ** * ** ****** * ** **** if(k==0){
* * ** *** ** * **** * * **** **** ** ****** * * ** * *** ** * * * * * * * **
* * ** * * * ** * * *** * **** *** * *** ** * ** * * * * *** * ** **
* **** * ** * * ** ** * *** *** * * * *** *****
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * * *** * * *** ,&b);

for ** ** *
{
*** ** * ** ** ** *** * * * is testing\n",i);
* ** **** * **** **** * ***** j=0;
***** ** * * * * * ** * = 1;
* * * **** * *** * *** (j=2;j<i;j++)
** * *** * *** ** **
*** * ** * ** ***** **** * *** * *** * *** * **** ****   %d is mode\n",j);
* ***** * ** * ** * **** * *** ***** reminder=i%j;
**** **** ** *** *** * **** *** ** ****** (reminder == 0)
*** ** * * *** ** ** ** ** *** *** ** ** * *
* * * ** ** * * *** * *** ** ** ** ** * * ***** *** *** **** * * ****** ** * ** *** * ** * **
******** ***** * *** **** * *** * *** * * * * * ** * ****** *
*** ***** ** **** *** * ** * *** * * * ** * * *** *** *
* * ****** * * ** ** *** ** ** * **
* * *** * * *
** * ** *** * *** *** *** * (flag==1)
* ** ** ** **** * ** * *** * *** *** * * ** * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.191
©2016-2025

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 6.7k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 8k views
12,783 questions
183,443 answers
172,219 comments
4,824 users