11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
22k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 22k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
*********  **           *** **   * ** *  %d",&a ,&b );

 *  ** * ** ** * * *** * **** i=a;i<b;i++){
  * **  ****  * *** ** *  ** **** **** ***  **  **   ** j=2;j<=b;j++){
  ** *** * ** *** ****  *  ** *  *   *      *  ** *  ** ***  * **  *** **** * * **   *    && i%j==0) break;
*** ** * * *   ***     * ****   * * ******** ** ** *  **   *  ****  *** *  *** *  *** * if(i==j){
*   * *** ** * ****   ***  *    **  *****   ******* *      *    *   *  * **  *******  *** *   *** *  *   ** 
** **        *   * *     **  * **** ** ****    ***   *  *    ** * * ** ***   * ****   *** ***   * *  ** **  *    *** ***      *   * **    ** ****
  * ** ** *  **** ***  **   *    ****     *  *      **         *  *** * *   *** **   **    ******    *  *  *    **  ********  *** *  ******** **
 ** **  ** ** ** ** ***  ** *   **   *    **  * * *** * * *** ** * *********** *  * ** *    ******     ***  *  *  **
* * * *  * ***  *  ** * **** ** **    *********  * * ** ** ** ***  ***  *    *   * *  **         * **   *  *    * printf(" %d",i);
* * *       * **  ** *  *   ** *  * *    **   * * *   ** **      *  *****   * ** *
*   * ** *    * ***** *  ***** ****  ****   *    *   * ** *** *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ** *  ***  ****  *
* **   **   *    ****  
 *   **      * *  * * 

int main()
{
int i,n,m;
   * * *         *   ** ** 
 *  **  * *  ****   * ** *
    *** *** ** ****   *

{



***** ***  *  *** *   
{
***  *  
**   
}
* *      ** *  

  **


***  **   **  *  ** * ** 


}}
*** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *       ***** * *** 
*  **** *** * *   **
         **  * **  * * 

int main()
{
int i,n,m;
* *    ****   ** *** *  * **
****** * ** ** **  *
 *    * * ** * *  

{



  *****   *  *****
{
**    
*   
}
* *  * *** ******  

**  * 


 ** **   ****** *   ***  * 


}}
* ** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* **********  ****  * *  **    * *  %d",&a ,&b );

**** *** *    * *  **   *  * *  * i=a;i<=b;i++){
  **    ** ***** ** **  ****   *    *   *     ** *    *  j=2;j<=b;j++){
 * *  * * **  *   * ** **   * * * *  ***  * *    * ** *       *  *   * * * *   * **** && i%j==0) break;
*    ******   * ** *   * *  ***      * * *******  * *  * * *** ** * * ***** *  ** * * if(i==j){
*   **  *  **** *   ** * ***  *   ***** **  **    *    * ** ** *  **    ****   *   *** ****  **  * *    * 
 ** * * *   ***   * * *  ***  *****  ***   **  ****      **** *  *  *  * *  * **    ***   ** ****  ****  * * ****  * ****  *  *     **  *** * **  *  * * *   **  
* * **** * *  *** *  *  *   *    * ***  *   * *  ** ** *   * * *   **    ***  *  **  *  ** *     *** *  **  ** ** ***  **  **** * ***  ****
 *   * *** *   * *   * *     *  * ** **  **** * **  *  ****    **** **    ****** ** *  ******* *
 *** * ** ** *   ****  **  **   * **  *  *   *            ******  ***   *** *    **** *   *   * *** **** *    ***  printf(" %d",i);
 ***  ***** * *    **   ****  ** ** *** ***** *  ****   **  * * *   *   * ** * *    *
*  * * ** * * ** ** **  * ** *  *******   *  **   * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
   **  * *       * * * **    * a,b;
    * * *** ****** ** ***** *  ** *    %d",&a ,&b );

*****   ** *  **  * *   *  **   i=a;i<=b;i++){
* * **** *   * * * *   **  **  **** **** ** ** * * * *  j=2;j<=b;j++){
 *  * * *     *   **  **  **  * ** *  *  **   ***** * **  **  ******** **   *  **  *   && i%j==0) break;
    **   **** **** *  *** *  **   **  *  **** ** *** ***  * * * **** **  ** ** if(i==j){
 **   ***** *** ** * ***   **    *  ****   *  *****  **   *    ** **  ** ****  *  * ** ******  *** **   **  **    * *   **  ",i);
***    *    * *  * **      ***         *** *** *    * *    * *** *  ** *  ***  * *
  * ****    **  ****  * ***   *****   *****    ****    ** *

 *   **  ********* **   **** 
**    *      *** *  * *  *** *   0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * *  *  ***   *   
** ******    *     
int main(){
* *** *** * ***  **  ******  *  a,b;
  * ***     ***  *** * *    *  ** ** * * * * ***  * ******* ,&b );

** *** ** ****     * * ****   **** * i=a;i<=b;i++){
 **    **** **  *   *      * * * * * ****  **  **  **   ***   j=2;j<=b;j++){
  ***   ***  *    ** * *  ****   ** * *   * ***** *    **  *    ** *** ***    ****   && i%j==0) break;
*  *** *    ** *   *** *   *  * * ** ***  ***  *********  * ** *    * ***** * * ****    *    if(i==j) printf("%d ",i);
****   ** * * * **    **  *  * *   **    * *     *** *
* *   ****  ***  *** ****** * 
 **   ** *  **    ***  * ** ***** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 ***  * * ** * *  *  *    ***   m, n, divider, prime[100], cnt=0, i=0;

   * **** *   ** * **  * ** * **    *   %d", &m, &n);

 *** ***    * * * * **** *  * **  = m + 1; m < n; m++)
       *  *   ***   **    
*  ****** * *    * *** * ***    **    *     ** * ***    ****   = 2; divider < m; divider++)
***** ***   *** * **     ****  ***   ** ****  *** **  *
** **** ***  *   *   *** * * ***** * * * **   **  * ** * * * *** * ***   *     % divider == 0)
* *** ****  **   * ***** *  **  *** ** **      ***** *** ** *** * *   **  ***  *  *           * * **  *  *  **      * ** **
**** **** * *** * **** *    *   *****    **     **  *
    * *** *   **  *** ** *    ******    * * *   ***  *  * *    == divider)
*  *    *** *** * *** ** ******   **** ** **    ** *  ****
** **   ****** *   *  * * * *** *    *   ***  **  ***     **      * ****** *  * *******  = m;
* **  *  **** **   ** *    *   ** ***  * **  * * *
 *** *     *  ******   **
* **   *    *  ** **  **  * * * * i<cnt;i++)
* *      **  *  * *** * ** * *
 * ***    ****   ** ***** ** * * * ***** * **** **  * * * *  ** * * *  prime[i]);
*  ** **    *  ** ** **  *     * **    * **** * * ** * +1 < cnt)
** * ** **   **   ** **  **   ******* ** ** *     ** * ** **   **** ***  * *  **** ** ******** ***  *  ");
    }

 ********** **** *  **  ***  **   ** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
*******  *   *    *   * *****  ******    
* **** * ***** * ****  *   ** *  **** * *  ** ** *    * *   ***  ***
 *  * * * *  * **   * ****  **       ******* *  ** *     **** **   * * ** **  **** *   
****   *        * ** *    **** ****  *  **  **  **     ****  ****** ******* * *   * * * *   ***** ***  ** * *   *
  ** ** * *    ***  **   **       * **  *    * **      * ***  ***** **   *   **   
*   ** * **   ***** ***  ****  **   *  ** ***  *    **** *    **  **** **** * *  ****   **      * * ** **  *    * * ",i);
* *** *    *** ****    *   * * **** * ** * *  **  ***  **  ** ***  *  *** * * **     *  * ***** *** **   *
 *** * *   *   **** *     ** *     **   *  ******** ** ** * ***  **  *   **   *
*     ***    ** ** *    ****  **  *   *** * *  * **  **** *****  *    **  * ***  **  ** if(k==0){
** **** *      ***  * **   **  ** **    *  **   *  * *   * * * *     ** ***   * ** ***     *  *  **** ** *** 
  ** **  ***  ***  **   **** * **   **** ***  **** *****  **  *    * * *** **    ***
 ****    * * *  ** **  * * *      * **  ** *  *** *   
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d     ** *   ,&b);

for  * *** *    * *  *
{
 *   ** *  ** ** * ****  ** **  * ****  **  is testing\n",i);
 * **  * * ** **  * ** * ** * ** * j=0;
 * * **** *****    **  ***  * = 1;
*     * *    * *   **  * *** (j=2;j<i;j++)
 *  * ***  **  ** *  ***
 **  *    *     **    ******** * *  **** ** ** *** * **   *     * *  **   *     %d is mode\n",j);
  ** *** * ***   * ** ** **   * *    *** **** *   ** *  * * ** reminder=i%j;
**  * * ******* **  ** ** *  **   * ** * ** **   (reminder == 0)
** * *   ****** ** *    **  *  ** **    **         ** ** 
* * * ******  * * * *  * ** *    * * *  *** *   ** ****  * * * ** ****     **  ** * ***   **      *   ********   ****** * **   *
*** ** **  *  *** *  ** **       ****  *** * **   *      *  *    ** ***  ** ***  * 
****  **** *  * ****   **   ***********  *    *  ** * **  *******         ** * *  ***
   ****** ** **  * * ** ***  *  ** *    *** **   **  * **
* **  *       **    * **  
  ***** ** **   ***** ** *     * (flag==1)
**   ** *      *******  ** *  *    ** *    * ****  **   * *   **   **    *   ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.16
©2016-2026

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 15.2k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 18.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users