0 like 0 dislike
3.4k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 3.4k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
** ** * ******* * ** ** * **** %d",&a ,&b );

** ** ** * ** **** ** * ** i=a;i<b;i++){
** * * * * ***** ** **** * *** * * ** * * **** j=2;j<=b;j++){
* * ****** * ****** *** * **** * * * * * * **** * * * * ** *** && i%j==0) break;
** * *** ********** ****** * * * ** *** ** * ** * ***** ******* *** if(i==j){
***** * * * *** * *** * * * ******* * * * * * * * *** * ** *** * ** ** ***** * *
**** * ****** ** * ** ******* * * * * * * *** ******* * * * * * * * * ** * ***** * * * * ** ***** * * ** ** ** ** * * * *
******* ** * * ** * * *** ** ** ** * ** ******* * * ******** * ** * ** *** * * ** * ** **** ** **
* * * ****** * * * * ** * *** **** * ****** * * * ** * * ***** * *** ** ** ** ** *
** * * **** *** ***** *** * ** ** * * *** ******* ** * ***** *** ** ******* **** ** * *** * * printf(" %d",i);
* * *** * *** * * * ****** * ** * * **** ** * *
** **** **** * * **** *** * *** *** * * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * * **** * * *
* ** * ** *
* ** * * ** *

int main()
{
int i,n,m;
**** * * ** * **
** * * * *
* * * ** * ***

{



********** * *** *
{
** ****
***
}
* * *** ** *

*


* * * * *


}}
** * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ** * * * **** * *
* ** ***** * ** * **
* *** ** * * *

int main()
{
int i,n,m;
** *** * ** * **** **
** ** * **** *** *
** ** ** ** **

{



* * ******
{
**** **
*
}
* **

** *


* *** *** *** *****


}}
** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
****** **** * * * ** *** *** * * %d",&a ,&b );

** * **** *** * ** * i=a;i<=b;i++){
* *** * ** **** ****** ********* * * ** * * j=2;j<=b;j++){
* * *** * * * * ** * * * * ** ** *** *** ** * ** *** * * ** ** *** && i%j==0) break;
***** * * **** ** * * *** * * ** * *** * * * * * * ** * * if(i==j){
*** ******** *** * *** * * * * * *** ** ** * * * **** * *** * ***** ** * * *** * ** ** *** * * *
* * *** ** * * * * * * **** ***** ***** * ** * * ** * * * ** ** ** * * * * ** * **** * ** * ****** ***
** *** * ** ***** * * ** * *** *** * ** **** * * * * * ** ** ******* * * * *** *** * * *** *** * *** ** ****
***** * *** ** *** * ******** ** ** * *** * **** **** * * ** * ** * * * *** ** * ** *** *
** * ** ** ** *** * * ** ** *** * **** * * ** ***** ** * ** * *** * * * ** ** printf(" %d",i);
* * * * * ** * * *** ** * * ** * *** * **** * * *
*** * * * ** * * ** ******** *** ** **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** ** * * ** * * * ** a,b;
* ** ** ** * * *** * ** *** ** %d",&a ,&b );

* ******* * * **** *** * * i=a;i<=b;i++){
* *** *** *** * *** * *** ** * * * * ** * ***** j=2;j<=b;j++){
* ** * ** * ****** * * * * ***** **** * * ** * *** * **** * * ** && i%j==0) break;
** ** * ** * * *** * ** *** * ** * * ** * * * * * * ** * * if(i==j){
*** ** *** * * *** **** * * * * * *** ** * * * **** ******* * ** * ** * * ** ****** * ******* ** ",i);
** ** ** ********* *** **** * * * * *** * * **** ** ** ** ****
* * ** ** ** * * *** ** * * * * **

* * ** * * * **** * ** *
* * * * * * * * * ** *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** * *** **** *
* * ** * * *
int main(){
***** ** * ** a,b;
**** ** ** * * * *** * * * * * * * * ,&b );

* ******* ** * ***** i=a;i<=b;i++){
*** ** **** **** ** *** * * **** * **** * * j=2;j<=b;j++){
** * * * * * * * **** * *** ** *** ** * ** * * * * ** * * *** * *** && i%j==0) break;
* * * ** *** ** * * ***** * * *** * ** ** * * * * ** if(i==j) printf("%d ",i);
** ***** *** * * ** ****** ****** * ** * * *
* * * ** * * ** *
* * *** ***** * * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * ***** ** **** m, n, divider, prime[100], cnt=0, i=0;

* * ** * ** * * ** ** ** * * %d", &m, &n);

* *** ** ** *** * *** = m + 1; m < n; m++)
*** *** * **
** *** *** ** * * **** * ** ** *** ***** *** ** **** = 2; divider < m; divider++)
*** * ** * ** * ** ** * **** * * ** * * * *
** * * *** *** * ** *** *** ** * * * * * *** * ** * ** ****** * * % divider == 0)
* * ** * * * * ***** *** **** * ** ** *** * ******* * * * *** * * *
** * * *** ** * ** ** ** * * ** ** *
* * * * * * * * ** ** **** * ** * * * * == divider)
* ** ***** ****** **** * ** * **** *
* ***** * ** * * * * *** * * * ** ** ** * * **** * ** *** = m;
** *** * * *** ****** * * *** ** * ****** *
** * * ** * *** * ** * * **
* ******* ** ** ** * *** ** i<cnt;i++)
* **** ****** ** * * *** * **
**** *** **** * *** ** *** * ** * * *** ***** * prime[i]);
** ** ***** ** ** ** * * * **** * * ** +1 < cnt)
* * ** * * * * * *** ** ** *** * **** * *** ******** * * * * **** ");
    }

* * *** *** **** *** **** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* * * * ** ** ** * ** * ** **
* * * ****** * ** ** * ****** ****** * ** **** * * *
* * ** *** ** * **** * *** * * * * * * * * ** * * ** ** *
* **** * **** ** *** * ** **** * * ** ** * **** **** * ** *** * **** *
* * ** ** * ** ** ** * * ** ** * *** * *** * *** * ** ** * * *** *
* ** ** * ** * ** * * * ** ****** * *** ** ** * *** * **** **** **** **** * ** ** *** ",i);
* * **** * * ** * *** ** * * *** **** * **** * ****** *** * ** *** **** ** **** *
* ** ** *** **** * *** * *** * * **** *** * ** *** * ** * *
* * ****** * * * * ******* ** * * * ****** * * * * *** * * * * * if(k==0){
* *** ** * * * * ***** ** ** ** ** * * **** ** ** * * ** ** *** * * * ** * * * *
* * * ** * **** ***** ** * * * * ***** ** * * * * *
* *** * * ** *** * ** ** * **
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * ** ** * * *** ,&b);

for ***** * * ***
{
***** *** *** ** * * ** * * is testing\n",i);
* * * *** ********* ** ** ** j=0;
* ** * * ** * *** ** * * = 1;
* * ** ** *** *** ** ** * (j=2;j<i;j++)
** ****** * ** * *** * * *
** *** ** **** * * *** ** * *** * * * * * *   %d is mode\n",j);
** * *** * * ** *** ** * * ** **** *** * reminder=i%j;
* *** ** ** * * * * **** *** * **** * ** * ** (reminder == 0)
*** * * ****** * * *** * ** * * ****
* *** ***** * ******* ***** ** *** * ** * * * * ** * ** * * * * *** ** *** * **** * * *** **** ******** **** * *
*** * **** *** * * * *** ** **** * * *** * * * **** ******* * **** **
******* * ** * * **** * * ** ** * ** *** ** * **** ** *** *** *** **** ** ** ***
** *** **** ** * * * * * * ****** ** * ** ** ** *
* * ***** **** * *
* * * * *** * * **** (flag==1)
** ** **** * * * *** *** ***** * **** ** * * ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.125
©2016-2024

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users