11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
3.5k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 3.5k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * * ** ** *   *  * *******   *  *   * %d",&a ,&b );

 **   **  *   **    * ********** * * i=a;i<b;i++){
** *  ***  ****   *      *  * ****  ** *  **  ****  j=2;j<=b;j++){
  **        *   ** * * **       *****   *    * ***   *** *    * * * * *   **** && i%j==0) break;
    *     *** **    * * *  *   ***   **  **  **      ** *  **** ** ** * **   * * if(i==j){
** **** *****      **** *****     ***     *** *    ** *  *** * *    * *    *   ** ** ** *  **     * ***** **   *
** *   ***** **  **** **  ***   ****** *  * * ***  *   ***  * ** * *  **       *** **    ** *  *       **           ***       ***** *** **  **  ** 
   *      * *         *   *  *   * * * ***  ** *   * ****   ***   *** **    ** *  * ***  *  *  * *  *  * *   *   *  *       * * **
    **  ***** *******  *    *** * ** ***  *   ***  **  ***** **  * *     * ***  *   * ** **   ** **  * * *  * 
    ** ****     *   * *********** ***     *** ** ** *  * **** * *****  ** * * ***    ****  **  ***  ***** * ** * printf(" %d",i);
* ** **     **    **  ** *******   * * * *** *     *  * *   *  ******   *  **** *
****    **  *  *       *    * ** * ** *      *   * **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *** *  *       *
* ****    *** *  ***** 
  * *   *  *  **** ** * 

int main()
{
int i,n,m;
       * *****  *   * * *
* ** * *   ***  **   ** *  *
**   **  **      **   *

{



*  * * * ** *******
{
** *  *
 ***  
}
*   ***  ** ** 

     


*  *   *      *    *   * 


}}
      0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *       **** **** *  
 **     ** *   ****  *** 
**  ** *   ***** ** ** *

int main()
{
int i,n,m;
 ** *  ** *    ***** ** *    * *  
*   *    ***  * *    **   **
***  * *    * * 

{



*  **   * **  *  * 
{
  *     
** 
}
*        **** *

    


   ** ** ** ** ** * **


}}
*      0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 * *****     * *  * *   **  **   *   *** *  %d",&a ,&b );

** *** * *  * ***  *   **  **  **   i=a;i<=b;i++){
  *  ** * **  ***  *  ***  * ***  **  * **** * * *** *****  ** *  j=2;j<=b;j++){
*  *** **  ** ** * * **  * *  ** ***** ** **  **  * * *  ** *  * * *   ** **  * *     * && i%j==0) break;
** **    **** *  *** * ** *    **       * * **  **  *   **       *    *****  *     if(i==j){
** ** *  ** **** *  **   *  ** ** * *   * *    *** *   * *  * * * ** * ***** *** **    *  ** **   ***  ****   ** ** **   
 ** * * ****       *** *  **** *  * *  *    * **    *  * * ***  **** *         *  ** **    **** ** ***  ****   ** * ****** ***  *    ** *  ** * ***** * *   
**  ***   * * **      * *********  **  ***** * ** ***  ****  * **   **   * **     * **** ****** ****  ** **** ****  * ** * **  **** * *  *     
  * *     ***  ****  *   ** *   *** * *****  *****  ***** ****  ** * *  **** **      * ****   * ***  *  **** * * *  
    *   *  **  ****   * *   ** *****  ** *   * ***  * * *  *  * *  **** * *      ** **  ***   *     ** ***   ** * printf(" %d",i);
****** ***  ** ** *  **** *  ** *    *   **     **   *** * * **** * * * * ***  *   ** * 
* * **  ** * ***** ** *****  * *** *   ** * **  ***   *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
  ****    * *  ** **   *** a,b;
***  ** *    *  ** **** * **    ** %d",&a ,&b );

 *    *** *** *    * *  *** * i=a;i<=b;i++){
 * ***   **  * *     ****   *   * *  **** ***  *******   * j=2;j<=b;j++){
***** ** * ***  ****  ***    ** * *   * *  *  *    * *  *    ***   ****  * * *****    *   *   && i%j==0) break;
 *   *** *   *  **  ****    **     *  ** * *    ****** *  ***  *  ******* * *** **   **  if(i==j){
*  * *** *     *   *   * *  ** *   * * *** *** **  **** ***    * ** *    * **** ** ***  **** ****  * ** ***  * *  *  * ***   ** ",i);
 **        *******  * * * * *** * *   ** *  *** ** *** **             **  * 
 **  *        *  **  ** *** ** *****   *     *   *

*  ******     **  * **    *** 
  ** *      ** * ******   **** *  *  0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
      ** *   *  * ****  
** ** **    **** 
int main(){
**  * *********    * ** ** * a,b;
*  **  ***    * ** **    *     * * **  **  ****** *     ,&b );

  * * *  **    *   * * **  **  * *** i=a;i<=b;i++){
* *** * **      *  * * ** * * * **  *  *  *      *     j=2;j<=b;j++){
 * *    * **  *  * **   * * **   *  **** **  ****  *    *   ****  ** ***  **  * && i%j==0) break;
  ***** ***** ** **   * * * **  *  *     * *     * *   **** *    * **    * *  ** * if(i==j) printf("%d ",i);
** *    ** *  * ****   ****  ** *** **    * *  *   **
*    * **   ** * **  * * * * **
* * ** ** *   *  **     * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  * *  ** * **   **    * * *** m, n, divider, prime[100], cnt=0, i=0;

  *** *  ***** *      **   **** *  *** %d", &m, &n);

 **  ** ***  *****  *   * *    = m + 1; m < n; m++)
 *** * ***** *  ******  *
** ** * *  * * * *   *** *    * **  *  ***  *** ***  *  **** *** **   = 2; divider < m; divider++)
* ***  * ***  **  *  *     * *     **** ** *****   **   *
 ***  *  *  ** * **** * *** ** *** ***    * *** ** **        ** *  * *   **    % divider == 0)
    * **      * *** *   ** ** *  * ** ** * * * *  ** *   ********  ** *    *  * *****  *   *     * *  ***
 *** *  * * ***  *** * *****  *      ***    *    *  ***
 ** *      *    **   **** * **   *** **  **  ***      *  *     == divider)
*  *   ***    **  *  *** *  ** *       ***  **   *      ** 
* *** *  *     **   * *****  *     ******* *****  *  * * *** * ***   * ** * *  *  *  *  ** *   = m;
 *   * *  ****** *  *****   * ***   **  ***  **   
*  ** * ** ** ** *** * *** **  
*  *  *    * ***  * * **   ****  i<cnt;i++)
* ** *  * ***  *  *  * *  
      **      *     ******  * * *** ** ***  * ***   ***  **   *  * ******  **** prime[i]);
  **     **   ***** *** *  ** * * ** * * **** * **  *   * +1 < cnt)
* ** *****  *** * * *   *       * ***  ***      * * **  * *********  ** *   ******    * * ");
    }

  *  ** ****      * *        **  0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* *   * ***  * * * *   * ****     ****  *   
*** ** *      *** *** *   * **   *  *  ****  * **** * *** * ** *  * * *
* * *** **   **   **  * * ****   *** **  * *  * *** *   * **** *  **  *  *  *  
*   * **  * * *      * ** *  *        *  ** ** *  **** ******** *    *  *  ***** *** **  ** * **   **   
* *       ** ***    *   *   *   **  ** *  * *** *  ** * ****   ***  ***  * **  ** * 
*****   * **   ******  * ********* **   *  **  ** ****  ** * *  *     *** * * ** *****  * *  *  *   *  ** *** *     *   ** ** ** * ",i);
      *   ****   **     * * ***   *     ***    *  *  * **********   * * *      * *  ** * **  ***  *** * **** *
** ** *  ** ***   * ****   *     *** ***   ** **** ** * ****  * ** * **  *** * *  * 
 ***  * ****    ** ***  * *   **  *    *      **    * *  * **   * ** ** * ***   *    ***** if(k==0){
    ***  ********  * *  ****    * * * **** *  * *** ** *  *    * ** *  * ** *   ** * ** ** ** *  *  * *   ** *** ** *
****       *****  *  * **                * *  **  * ***    *** *  *  ** *   ** *  ***  
*****   *   *  *****  **       **  * **   **   *  ** ***
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d  * * *********    ,&b);

for   * * *** *    ** **
{
  ***    * ***** ** *  *** * ***   ** * is testing\n",i);
  ****  **    *    * *     j=0;
* **    * * * * *     * * ** * * = 1;
* * * *    * **** **     *  ** (j=2;j<i;j++)
* * **  ***  * **  *  * * * **
    ** ** * *** ** **** * * ** ** ***  * **  *  * ** * * ** *    **  *   %d is mode\n",j);
  * **** ** *** *** ** ** **    **** * * *   *    ***** reminder=i%j;
 *   * * **  ***   *** ** **    **  *** *        **** *  *  (reminder == 0)
**** ***   *****  **     * **  ***   *  ***   ****** **
  * * *  *     * *  *  ***  ** *    * ******    *   **    *    * *  **    ** ********   *   * **    * ***    * ****   **      
* ** *** ********  ** *   *  ****         **** * **  *** *   ** ***  * *    **    * 
  *  * ** *  * ****   **  **** ***  *  ** ***  ***      **   * *   * **  ********
 ***   ***    *   * * *** ** **  ** *  ** **  * *****    *** **** * *
 ** ****** * *   * * *      *
* **   **  * * *******    *      * (flag==1)
 * ** ****   *   **  * *  **   ***  ***   ** * * **   *  *****   *  ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.8
©2016-2024

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users