11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
24.2k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 24.2k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 *  ***   *   ***      *** **    *** %d",&a ,&b );

    ***    *     ***  * * * *   i=a;i<b;i++){
* *** ***      * *  *    ******** * * *     ** **   * j=2;j<=b;j++){
** **   *  *   ***   *****    * ** ** ** *    *  * *** ** **  ***  * * * *  *** ****   *   * && i%j==0) break;
*   *      *  *    **       *        *   ** * ** **** **  *  * *  *****     **  ****  if(i==j){
*  *** ** ***   ****  * *  *****     ********    ***** **  *    * **  *         **  ** * **  **  * *** 
* *  * ** ********  **  ** *  **   **   ** ****      ****        *  *  ***   *   * ** * ***** *    * **        *** * *    * * **  * * *    *** * ***   *  **
 ****   *****  *    *    * *  **  ** ** *    * ** *  * *  *  ** *  * *   **  ** * *  ***  ** * **   *  ** *  * **  ** **  **  *** *   
*    ***  ****    **  * ** * ***   ** *** *****  **** * *  ***  *   * *  * * * **      *  * *** * * 
 **  ** ***** ** ***  ** * * *  *         ***  * ** * *****     ** * * ** *****   *   *** * **  *  ** *   *   printf(" %d",i);
*  **  *  *** ***  *   *** ***  ** **    *       ***  * * ***   *  * ***  ** * 
*   * ***** ****   *   ** *** *   ** **  *     *** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** **   *   **  *  
 ****   *  ****** **  **
**   *     *   * ** **

int main()
{
int i,n,m;
  ****  **  *      ** * *  ***
    * **** *  *  ***      
*** *** ***  *  *

{



*** *  ** *   * **   
{
** ***  
  *
}
** * ** ***   **

   


 **  ***  *  *** * *  


}}
*  *  0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*    *      *  *   *   
   * *  *    *    * 
* **    *  **** * *

int main()
{
int i,n,m;
**** *  ******    ***  ** *  *
**  *** *  *  ****  * * * * 
 *     *  *    *  

{



** * ** * * *   *
{
** *  
  *  
}
***  ****** 

 ** *


 *  * *    ***  *    


}}
 **  0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 * * *   **  *  *   *   * ***      *     %d",&a ,&b );

**  ****    *  ** ***  *  ***  ***  i=a;i<=b;i++){
  * *** ** *** ** **** **** * **** **** ***   ***  ****  j=2;j<=b;j++){
 ** ** * ******** * * * * ***  * *  **  **         ***   ***** *    *  *** * * ** *  *   *  && i%j==0) break;
***   ** ** *   * ** **  *    **  * * ***    ***   *    *   ****     ** * * ** ** *     * if(i==j){
* * ** ** *  * *   *** *  ****   *****   * ****    ** *  ***   *  **   **     * * *  *  * * *  ** ** * 
   *****  * *   * *  *  ** *** * **    * ***    **  ****** * **  *   *     *       * * ***  **  * * ** ***** *  *   *  **      **   * * *   ** * *** * *   * *  * 
  * * **  *     * * **    * **    ** * **** *  * * ** ** **         * * *      *****  *    ** * * * *   *  **  *   *  ****  *** *  **   *
* *    ** * ** *****  ** * *  **** *** * *   **    **  ***    *** * ** ****  ***** * * *** * * **** *** **   
 *   * ** * *** *  **         ** * * *     **  *   *  **** * **  ** ***** *  **     **** ** *  ** *  *   * ******  printf(" %d",i);
  ** *  * * ** *****  *      **  * ****** **   **   **   *** *****    ***** *     ** **** 
 **  **   **** *  * *** **  *********  *** *  * ** **   ***  *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
 **** *  * * ****  **** * *   a,b;
*    * * **** ***   * * ** ****  ****  %d",&a ,&b );

 ** *      **   ** * *   *  **** *    i=a;i<=b;i++){
 * *  *****   *** *** ******* * * *** *  ** *      **  *  j=2;j<=b;j++){
* ** * ** * *     ** ** ******  ** * *  ***  * * ***   **     **  ** **  ***  *  * * && i%j==0) break;
 *** *    * * ** ** *   *  **    * ** *    * **  ** * * *  **  *  *** *   **   **    if(i==j){
****    *** * *  ***  **  * *  ****  * ** *  *** *   * * * *  * ** ** * *     ** **  ***   *   **** *****  **   *   ***  *  ",i);
 *      *  * ****** ** **     *****   *  ***  * ****     *** *     ** ** * **     ***
 ****** ***    * ****   * **     * **  ** * ****       ** * 

*** *  **** **   *******
** *  *** * *  *  * *      ** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
       **  ** ***   ** 
  *  ******* *      
int main(){
    * *  ** *    ****** ** ***   a,b;
 *** * * ** *  * *  **   *   ****   *   ** * *   *****  ,&b );

 * *  * *** **  **  *  *** i=a;i<=b;i++){
     *    *    * **  ******* * * ** *    **        ** *   j=2;j<=b;j++){
 * * ** *    **     *    **  *   *******       * * *** *** *  **  ***** * * ***  **    **  ** * && i%j==0) break;
  ** *  ** * * ** ***  ***  *     * *  *******   **** *** *   **  ***  **     *  ** if(i==j) printf("%d ",i);
 ****    ** **     *  ***  ***       * ** *******       * * *
*  *   ****   * **  *  * *  *
   *  * ***  **    **  * ***  * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *  * *   **  *     ** * **   m, n, divider, prime[100], cnt=0, i=0;

 ** *  * *****  **** *  * * * ** %d", &m, &n);

* * * *  *   * *  * * * **  = m + 1; m < n; m++)
*     *  ******* * ***** * **
* * *****   *   *  ** ** ** *****  *   * * ****      ***  = 2; divider < m; divider++)
 **     * *   ***  *   ***** * * ****    * * *  *  ** *
 *   *  * **   *** *    ****** **  ** ****    **    * **    ** * **      *   *   ***  % divider == 0)
* *   *   *  *          *     **  * **   **** **    **    **    * *   ***  * **  *******   *** **  *  ***      *  
     * *  **  ** ** *  * * * ***   **** *  ** *** **  
 * *** ***  *** * *  * ****  *** * *** ** ****    * *  ** == divider)
* *  **    ****  * *       **   **   **  *  *  * ** *    ******* 
******* *** *   *  *     *  *  *  **  *  **   *      *     ***   *   *  **   **  ***    ** = m;
 *** * *   *     * * ** ***** *** *** *    ****  
 * ****  *  *  **   *  * *
**  ****  ** ***  *  *    ** ** *** i<cnt;i++)
***   ** ** * *  * ** ***  * **   
*  *        *          ** *  *  ******  * **  * **         ** **   ** *  ***   prime[i]);
* ** * * **  *** *** * ***  ** ** **  *   ** ** * *  *** * +1 < cnt)
 *     ****** * * *  *    **  *** ****   **       *   *  ***   *  * ***   ****** * * *  ** * ");
    }

   * ** **** *       ** * *   *   0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
  ***     ** * **  **  *  * *  * *  ***** 
 ****  * * * *     *** ** ************  *  * **** *  * ***  **     *
*     *  *   ** *    *   ***  **    *   * *   * **  *  *  *  * *  *** ***** **
*** ** ***      ** * ****    ***** ** *   *  *  *** *  * ** ** * * ****  * **  * *** *    *   * *****   *     *  **
   * **** *  *  *  **   **     **   * **  *  *  * * **      ***   *** *******  * *   
*   *   * **   * **  **  * *   ** * **  ** * **** *****  ****** **    * * ***   ******** * **   *    **  ***     **  **** **  ",i);
       *** *  ****** ** **  *  *   ***     *  * ***  *   * **     *  ***  ***   **  * *   ***  * **  * ****   *
* * * ** ***  **   **   *        *   **  **  ****     * ** *    *   *  ****    ** 
 **  ***   * ***** ***** *   **   ** **    * * * * * * ** *   * **  ** * * *** * if(k==0){
*     ** * *  * * ****  * ** ***  **  * * **        * **   ** *  *** **   *** *** ***  **  * **** **** *    * 
*   *  ** *****      *******      *      *  *   * *  *    *****    *  *** *** ** *  *     
 *  * **      *  ** *     *    ** ****** *  * ***  *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d  **** *  *    *     ,&b);

for   * **  *  ***
{
    ** * *** **   * ** *   ****  * * ****   *  is testing\n",i);
*  * **  *  *  *  **    j=0;
***   *   * **  **  ****** *   = 1;
*   * * * ***   ** ** ***    **  (j=2;j<i;j++)
* *  ** **  ** ****     *****
  *  ** * * * ** ****     * **    * ****** *  ** *** * **  ** * *** *   %d is mode\n",j);
  ******   *****    *  ***   **  *  * *  **   ** * *  reminder=i%j;
 **  *  *  ***** *   * *  *    *** * **    ****  *** (reminder == 0)
* *   **  *  **  * *** * *  *  ****  **** **  *  *    * *
* ****** **** ***  ***  *    * **      **     * ****     **   *    ******** * **  **** *      **    **   *  ** ** ***   * **
    **     * *  * *** *** * ** *       **   *******   * ** ****** *   *  **  *   * *  * 
*   * * * **   *       ***  * * *****  *   ***   ****** * *    * *  *    ***   *  *  
*  **   * ** * *** * *  **** *  *  *  *   ** **  *  **** 
 ***  **  *** ** **  *    * *
** * * * * * * *  * * **   (flag==1)
 *  *****     * ***   ***   ** *   *   *  ******   * *****  *    * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.4k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 20.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users