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Suppose we have the following two points in a 3D space:

The distance between point1 and point2 is:

Please create ThreeD class inherited from Point class which is used in previous exercise and then use ThreeD class to calculate the distance between two 3D points.

Hint:

  • Add two more public functions to Point class to get the value of X and Y
  • ThreeD initialize: 
  • class ThreeD:public Point
  • The following constructor of ThreeD class reuses the constructor of the Point class and the only way values can be passed to the Point constructor is via the use of a member initialization list.
  • ThreeD(double i, double j, double k):Point(i,j){z = k;}

     

Example input:

1 1 1
2 3 4

Example output:

Distance is: 3.74166
[Exercise] Coding (C) - asked in C++
ID: 24589 - Available when: Unlimited - Due to: Unlimited

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#include <iostream>

#include<math.h>

using namespace std;



class ThreeD
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{
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double ThreeD::getx()

{
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double ThreeD::gety()

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double ThreeD::getz()

{
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void ThreeD::dist(ThreeD other)

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int main()

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** * * * * * * ** * 0;

}
answered by (0 points)
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** * *** * * **
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using *** ** std;



class Point{
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};


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{
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}


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{
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***** *** ** * ***** = ypos;
** * * * ** * = zpos;

}


* * *****

{
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}


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{
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}


** * ** ** **

{
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}



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{
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}


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}



int main()

{
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** *** ** ****** ** * 0;

}
answered by (5.2k points)
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This is not correct answer. We require ThreeD class is inherited from Point class which is used in previous exercise
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Hidden content!
class Point

{
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** * **** *** * ** x, y; // x and y ** *** * ** * *
* * *** ** ** * ** *** *

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* * ** ***** * *** * * *
* ***** * ** * * ** inline *** * of member *
* **** ** *** * *** ** * * * * * * = NewX;}
* * * **** ** ** *** ** * = NewY;}
* *** *** *** *** getX() const *** x;}
**** * * **** * ** ***** getY() const ** y;}

};



class * ** Point

{
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* *** * ** *** * ** *** * * **** **** * * z;
* **** * * * *

** * ****** ***** * ** * ** *** ** ** **** * Inline * of **
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* *** ** * ***** The * * * * * of ThreeD class reuses the

** * *** * * * *** ** * of the Point class and the only way ****
**** **** * ** ** *** ** ** can be ** to the Point * * is via the use
** ** ** ** *** of a * * *** * list.
** ** *** *** * * * * i, double j, **** ** * = k;}


** * * * *** **** * ** ** * * = * *
** * ** **** *** * * * * * z;}

};





int main()

{
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** * *** ****** * ***** ** ** **** * * * *** * * *** * ***** * * ** * *** * ** * * *** * ** ** *** ** * * * * endl;
* ** * *** * * ** ** 0;

}
answered by (12.1k points)
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