0 like 0 dislike
8.9k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 8.9k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * *** ** ***** *** * i=0;
* ** **** * * ** **
* ***** * ** * ** ******** ** *** * **** *
* ** ***** **** * **** * ** * * ***** ** ***** **
** * **** ***** ** ***** * *** ** *** * *
* * * * *** *** * **** ** * i;

}



int check2(char c)

{
*** * ******* * ****** j=0;
** * ** ** ** * * **** * *** *
* ******** * * **** *** **** * * **** * *
* ** * ** * *** * ** * ** * * **** * *** ** **
* **** *** * *** *** * **** ** **
** * * ** ** * ***** j;

}

int main()

{
* * ** * *** ******* c;
**** * * * * * * * ** i=0,j=0;
* ** ** *** *** *** * ** * * * *** ** **

    
* * ** ** * * *** c!='.')
* ** *** * * **** ***


* *** * ** * ** *** **** ** **** * *
* * * * * *** *** * * ** *** * ** ** *
** *** * *** *** * *** * ** * ** ** ** * * * *** * * ** ** * ** * **
* * ** * * *** *
** * * ** ** * * * ** * *** * * *** * * ** * ** * **** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** * ** * ***
** * * ** * **

int main (void)
*** **

char c;

int i = 0;

void *** * c)

{
**** * *

i++;
* **

i++;
* ****** * **
** * * * *** * ** * * ***** **** *
* * * **** *** * * *** ** 0;

}
* * ;

}
* ** *** * * ** * *
** * * * ** *** ****** *
***

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * ** ** * * **** ** a1=0,a2=0,a3=0,a4=0,in;
** * ** * * * ** ** ** ** * ** && c[in];in++)

    {
* **** * **** ** *** * *** * ** * *** * (48<=c[in] && c[in]<=57)
** * ** *** ** ***** ** ***** ** *** * ** *** **
*** ** * ****** *** **** ** * * * ******* ** * * *
* **** ****** * * * * * * * ** *** **
* * *** *** ** * * ** ***** * * ** ** if(65<=c[in] && c[in]<=90)
* *** ** * * * * ** *** * ****
** ** ***** ****** * **** ***** * ** ** * ******** * * ** * *** ** *
** *** ** ** ** **** * * *** ***** * **** *** *
** ** ** *** ** *** * * * **** ******** **** if (97<=c[in] && c[in]<=122)
** ** ** ****** * * ** ** ** * **** * **
* * ** ** * * * ******* **** * * * * * ** ***** ** ** * *
** **** ** ** *** **** ** * * * *** **** *
** * * ** *** **** ** *** * * ** ** * ** ** if(39<=c[in] && c[in]<=46)
* **** **** ** * * * * ** * * ** * *
* ** * * ** ** **** *** * ************ * * * ** ** * * * *** ***
****** * * * ** * ** * **** * * * *** * * ** *
* ** *** ** * * * *** ** *** * ***** * * * * **
* ** ** * * ** ** * * *** ***** * * ****
** *** ** *** * ** **** * * *** ** * * * **** * ** * * ** * ** ** * * ** *
* * * * * *** ** * *** * **** ** **** *** * ** ***
**** * **** ** **** * **
*** * * ***** * * * * * *** **** ** *** *****

 }

 

 int main()

{
***** ** *** * * * * *** c[100];
* * **** * * *** ***
** * * * ** * * * * * * **

    
* * * *** * * * ** * **** * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * ******** * * ****** i=0;
*** ** * * * **** * *** * *
* *** * *** * * * * ** **
***** * * ** *** ** * *** * * **** *** ** *
** *** * * * ***** * **** * ** * ** *
** *** * ***** **** * **** i;

}



int check2(char c)

{
* * * ** *** * ** ** * j=0;
** * ** * * *** * * ** ** *
** ** *** * * ** * *** * ** *
*** ** * ** ** *** *** ***** * ****** ** ** *
* ** * ** * **** * ** ** * ********
* * * * ** ** ** *** j;

}

int main()

{
* ****** * ** * c;
* * **** * * *** **** * *** i=0,j=0;
* ** *** *** ** ** * * * ** ** *** * * * ***

    
* *** * * *** * * ** c!='.')
***** *** ********* * *** *


** * * ** ** * * * * ** ** ** ** ***
** * * ** * * ** *** * * ** ** ** * ** **** **
* **** *** ** * ** * *** **** * **** * * * *** *** ***** * **** **
* ** * ** ** * ******
* ** * * * * * ** * ** * * ** * * * * * * ** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
**** **** * * ** ** ** i=0;
* * *** * ** *** * * * * **
* * * ** *** * * *** **** ** **
* * * ******* * ** * * * **** * ***** *** * * *
* * * * * * * ** * ** *** * *
* * ** * * * ** *** i;

}



int check2(char c)

{
* **** ** * * * * *** j=0;
* * * **** * ** * * **** * *****
* **** * * * * ** * * ** * *** *
* ***** * ** ** * * **** * * * * ** ** * * * **
* ** ** ** * * **** * ** * *** **
* * ** * * * * j;

}

int main()

{
* *** * * * * ** **** ** c;
**** *** * ** * * i=0,j=0;
* * * * *** ** ** * * ** * * * * *
** ** ** **** *** ****** ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* ** ** * * ** ** * *
** **** ********** **** **** * * ** * * * *** *
* ** * *** * * ** ****
* ** * ****** ** ** * c!='.')
* * ***** ***** ***


** * * * ** * ** * * *** ** ******* *
*** * ** ** * ** * * * * * *** ** * *** *
* * **** ****** ** *** * ** * * * *** * * * * ** ** **
* * ** ** * ***** **
* ** ** ****** ** ** **** * * * * ** * * * *** * *** **** ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
**** * **
** * ** *****

int main * * *
**** *

char c;

int i = 0;

void * c)

{
* *** ****
* **
* ** *
****
* * ***** * *
*** ** ** *** * **** ******* * 0;

}
* ** ;

}
**** *** * ******* ****** * ****
** *

}
* * ** ** * ** * *
* * * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* ** ** * * ** * ** ******* c;


** * * * ** ** * * * * * i = 0,b = 0;


** ** * ********* ** ** * * * * &c);
** * **** * **** ** * * c != '.')
** * * * * ** * * *
* * ** *** ** * ********* ** *** **** ** *** **** *






* *** * * * * * * ** ** += 1;


** ** ******* ** * * * ******** * * * * ** * *** *** * ** &c);
**** ** * * ** * * * ***** ** *** * *
* **** * ** * * * ** * * **** * ** * * * ***


* * * * * **** * * * ** * * * *** i);


*** *** ***** *** * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
**** *** * **** *
* * ** ** **
** main
*
* * c;

int i = 0;
* * **** c)

{
*** * *
**
* * *
*
** ;

}
*** * *** * **** ** * * *
* *

}








* ** * * * ** * *
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** * * *** ** ** i=0;
* * * * ***** ** * * ** * ****
* ** * * ** **** ** ** **** *** **
** * * * * ** ** * * *** *** ** **** ** ** ** * **
* * * ** * ** * *** ** ** ** ** * ****
** ** * * * *** ** * i;

}



int check2(char c)

{
** * * *** * * * ******* * j=0;
** * ** * * ** * *** *
* * ** * * * **** * ** *** * ** *
* * ** * *** * ** * * * ** * * * *** *** *
** ** * *** * *** ** * ****** * ** * ** ** *
* **** * *** **** ** ** * *** j;

}

int main(void)

{
* * ****** * * * c;
*** *** *** * * * * * i=0,j=0;
* * * ** * *** *** ** * *** *** * ** *** *
* *** * *** * * ** ** * c!='.')
** ******* * ** ** * ***


****** * ** ** *** * * * **** * **
* **** * * ** ***** **** ** * ** *****
* * * ** * *** *** *** ** ** * ****** * * **** * * * *** *

    }
* ***** * ** * ** * * ** *** ** ** * *** * * * * * * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * * * *
* * * * **** *** *****

int main * *
***
* * c ;

int i = 0;
* *** * ***** ** * * ** * **
* * *


*** * ** c)

{
*** ****
**
* * *
**
* ** ;

}




* ** * * **
** ** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.129
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users