0 like 0 dislike
7k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 7k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** *** **** * *** **** ** * i=0;
* *** * ** * * ** * **** ***
* *** *** * * *** ** ** * ** **
** * ******** * ** * * ****** * ***** *** *** *
* * * ** ** ** ** ** * ** * *** ** * * ****
** **** ** * ***** * ** ** *** i;

}



int check2(char c)

{
* * ** ** * ** *** * * j=0;
****** * ** * ** ******* *** * ***** *
* ***** ** * * * ** * ** * ** **
* **** * * * *** ** ***** ***** * **** * * *** * *
** * **** **** ******** * * * *** ** *
* * * * ** * * * * j;

}

int main()

{
* * * * ** ** ** * * ** c;
*** * *** **** * ** * * i=0,j=0;
** * ***** ******* * * *** *** * * * *

    
* ** * * * * * ** ***** ** c!='.')
** * * * * * ** * *** *


** * ** * * *** ** ** * *
** * ** *** ** ** **** ****** ***** * * *
* * *** **** ** *** ** * ** * ** ** * *** * ***** ** * * **
******** **** * *** * * ***
*** * ****** ** * ** * ** ***** *** ** * * * **** * *** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* **** * * * **
* * *** ** *** * *

int main (void)
** *

char c;

int i = 0;

void * * ** c)

{
** *

i++;
*** ** *

i++;
* * ** * * *** ***
* * ***** * * * * * ****** * * * * * * *
** *** ** ** ***** * *** 0;

}
*** ;

}
*** ** ** * ** * ** ** *
* * ** * * * * ******* ** ****
*** ***

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * * * * ** ***** *** a1=0,a2=0,a3=0,a4=0,in;
* ***** * *** * * **** && c[in];in++)

    {
* * ** * ** *** * * * * * **** * ** ***** * *** **** (48<=c[in] && c[in]<=57)
** ** * ** * * * ***** * *** ** *** ** * *
* * * ** * **** ** *** *** *** ** * ***** * * ** * * * * ***
* * ** * ***** * * *** *** ***** ******* *
***** ** * ** * ** *** ******* *** * * ****** * **** *** if(65<=c[in] && c[in]<=90)
* * ** * ** * ** * ** * ** ** ** **** **
** * * * ***** * * ** * ** ** *** * ** *** * ** * * **** ** ***
* ** *** *** **** * **** * * * ** *** ** *** ***
* ****** * * *** *** ** *** * * ** ** ** if (97<=c[in] && c[in]<=122)
* * *** * **** * * ** **** ***
*** ** * * * **** * ** * * ************ * **** *** * * ** * **
* * * ** * * *** *** * * * ** *****
* **** * * * * ** ** ** ** * * * * * ** * if(39<=c[in] && c[in]<=46)
** **** *** * *** **** * * * * ** ***
** * ** *** ** * * ** * **** ****** ** **** *** * * *
* * * *** ** * ** ** *** **** * * * * * **
* *** * ** ** ** * *** **** ** ***
* ** * *** ******** * * ** ** * * * *** ** * ****
** **** * *** *** * * * * * * ** * * ** * *** ** *** * * **** * **
* * * **** * ** **** ** * ** * *** ** *** *
* * * * * ** ***** *
* * * ** *** *********** * ** * * *** *** ***

 }

 

 int main()

{
* * * * ********* ** c[100];
*** * * **** * ** **** ** *
* * * * * * *** * *** *

    
* * ** * ******* * * *** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** *** * *** ** i=0;
** * * ***** * * ** * * ****
** * * * * **** ***** * * *** ** * ***
****** * ** * * * ** ** * ** * * * * *** * * ****
* *** ** ****** * *** ** ** * ** ***
* * ** **** * * * * ** i;

}



int check2(char c)

{
* ** * * * * ** *** **** j=0;
**** ** * * *** *** ** *** ** *
* * *** **** * * * * * * * * *****
* * ** *** ** * * ** **** * *** *** *** * ** * **** ***
** ** * * ***** *** ** ** *****
** ******* ** ** ******** j;

}

int main()

{
** * * * * ** ** * c;
* * * * ** * ** * * i=0,j=0;
* * *** * ** * * * *********** * * ** ** *

    
* *** * * * * ** *** ** * c!='.')
** ** * * *** * * **


*** ****** *** * ** *** * * * * * ***** * ******
* *** ** ********* ** ** *** * * **
* * ** ** *** *** * * * * ******** * * ** * ** * * * ** *
* * *** * * * ** * **
*** * *** *** ***** *** ** * ******* * * ** ** *****



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
************ * ** i=0;
** * ***** * * * * **** * * * **
** ***** * * * * * * * *** * ** **
* * ** * * * ** *** * * ** * *** * * * *
* * *** ** ** * * **** *
* * ****** ** * * * i;

}



int check2(char c)

{
*** * *** * * * * j=0;
* ** * * * ** ** * * *
* ** * ** ** * ******* * *** *** *
** * * * * * ***** * * * ***** ** ***** *
* ** * *** * * * ** ** ** * **** * *
** *** **** ** * *** ** * j;

}

int main()

{
** ** **** *** c;
* *** * * **** *** i=0,j=0;
******** ** * **** * * *** ** * ****** **
**** **** * ** *** *** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* ** ** **** * ***
* * ** ** * **** ** * ** ** * *** *** * *** * ** *
** ** ** * ****
**** ** * * * ******* ** c!='.')
**** ** * * *


********** * **** * * * * * *** *** *
** * ** * ***** * *** * * ***** * * * **
***** **** ** *** * ***** * * * **** * ** *** ****** * * *
*** **** * * * ***** ** *
* ** * * * ** * ** * **** * * ** * ** *** *** *** *** ******** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** ** * *****
* * * ** *** ***

int main *** *
* **

char c;

int i = 0;

void ** * * c)

{
* **** ***
* *
* ** ***
* **
*** * **** * ****
* ** *** * * ** ** * 0;

}
**** ;

}
*** ** ** * *** * * ** *
********

}
* *** ** * *
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
** **** ** * ** * *** ** * * c;


* ** * ** * ** * ***** i = 0,b = 0;


* * * ** * ** ******** ** * * ** * ** *** &c);
*** ** ** * * * * c != '.')
* * * *** * * * * ***** *
** * ** * ** ** * * * * * * *** * * * *** * * ** *






** * *** * * ***** *** * * ** * * * * **** * += 1;


* ** * *** * * ** *** *** * * ** ** * * ** * * **** &c);
* * ** ** * * * * *** * ** * * * * * **
* * ** *** * ** ** *** ** * * *** *


** ** * ** ** ***** ** * * ** ** * ** * * i);


* ** ********** ** * * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
** *** * **** *
** ** **** *** * ****
* * main ***
*****
* c;

int i = 0;
** *** c)

{
**
*
* *** *
*****
* ;

}
* * **** **** * ** * ** * *
* * * *

}








** *** ** * * *
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** * ** ***** * ** **** i=0;
** ** * * * ** * * *** ***
* *** ** **** * ** * ** ** ** *** *
** * ****** * * ** ** *** * * *** ***** *** ** * ** * **
*** * * * *** * *** ****** * * * * *
* * * ** *** *** * * ***** i;

}



int check2(char c)

{
* ** *** * *** ** * * j=0;
*** * ** * ***** **** **** *
*** * ** *** ** * ** ** * * *** * ****
*** * ** **** * ** * ** * *** ** **** ** *
** * ** ***** * * ** *** * ** *
** ** * * * ** ****** * j;

}

int main(void)

{
* * * * * * ** ** *** * c;
******* * * *** * ******* i=0,j=0;
***** **** * *** * *** * * * *** *** **** * ** *
* * *** *** ** * ** * * c!='.')
* * ** * *** * ***


** * **** * ****** * * ** ** * ** * * ** * *
* ** ** ** ** * ** *** * *** ***** ** *
*** * * * **** * ** * ** ** ***** * * * ** **** * ****** ** *

    }
* **** **** ** ** ***** ** ******** *** ** *** * * * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** * * ***** * *
* **** * **** * *** **

int main *
* ** ***
** * c ;

int i = 0;
* * ** * ** ** * *** **** *
*** * *


* ** * c)

{
* ** **
*
* * * *
*
* * ;

}




* * * * *** * *
*** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.106
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 4.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users