0 like 0 dislike
10.7k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 10.7k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ***** ** * ** * * i=0;
** ** * ***** ** * * * * ***** * *
* * * * * ** **** * *** * * ** *
*** ** ** *** * * * ** * * ***** ** * * * * *
** **** ** ** * *** ** *** **
* *** * * ** ** ** ** * *** i;

}



int check2(char c)

{
** * ** * *** ** * ***** j=0;
* *** *** * ** * * * **
* **** ** * *** * * ** * ***** *** **
* * ** * * * *** * *** *** ** * * * * * ****
* * * * * * * ** * ******* * ** * ***** * **
**** * * ** ******* ** j;

}

int main()

{
* * *** * * ** * ** * c;
** ** ** ** *** ** *** i=0,j=0;
** * * **** * * * **** * * ***** ***

    
* * *** * ** ** * ** *** c!='.')
** * * ** * * ** * ** * *


** *** ** ** * * * * ** * **** * ***** * ** *
** * * ***** ***** * * *** ** ** ** ***
* * ** * * ** ******* * ** ** * ** **** ***** * *** * * *
*** *** * * * **
* * **** * * * ** ** ** *** *** ** * * * * * * *** ****** * * * ** *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** ** ** **
** ** ** * ** * **

int main (void)
* * * *

char c;

int i = 0;

void * c)

{
*

i++;
* *

i++;
** ***** * *** *
* ** * * ** *** * * * ****** * * ****
* ** *** * * ***** * * * 0;

}
** ;

}
* ** **** * *** *
* *** * * * ****** **** * ** ***
* * *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* ***** ** *** * * * ** a1=0,a2=0,a3=0,a4=0,in;
** * * * *** ** ** ** * * * * * * *** && c[in];in++)

    {
* * *** **** * * ** ***** * ** ** * **** *** (48<=c[in] && c[in]<=57)
** ***** **** *** ** * * * * ** ** * * * *** *
* ** ****** * *** *** *** ** * * ***** ****** * ***** * * * * *** **
* ** * * *** * *** ** ** * ** ** * * ** * * *
* ** ** * ** *** *** * ** *** * ***** *** ** * * if(65<=c[in] && c[in]<=90)
* ** *** ** ** * * *** **** **** *** *** *
** * ** * *** ** * *** ** **** *** *** * ** * * ** *** * * * * * *
* * * ** * *** * * ** * * ** * * * ** ** *** * ***
* * ** ** ********* * *** * * * ** **** if (97<=c[in] && c[in]<=122)
** *** ** ** ** ** * ********** * * * ** **
* * ** ** *** ** * * ** * * *** *** * * ** ****** * * * ****
*** ** * **** * *** * * * * ** *** * ** * * ** *
* * **** * * ** * ** * ***** ** * if(39<=c[in] && c[in]<=46)
* * * ** * ** * * * * * ** ** *** ***
** ** * *** **** * * * ** ** **** * ** ** * * * * ** ** ***
**** **** * * ** * * * *** ** ** ** * * ***
* * * * * ** * * ** * * * * * *** * * ** **** *****
* * * ** *** ** ** * * ** * ***** *** * * * *** **
*** * ********* ** * ** * * * ** ******* * * * * * * * * * **** ** ****
*** * * * * **** ** ** * *** * *** * **** * ***
**** * * *** ***** *
* ** * ** *** * ** ** * * ** * * ** * * ** * * ** * **

 }

 

 int main()

{
** * * * ** **** *** * c[100];
* * * ** * * ** * ***
** ** ** ** * * ** * * **

    
* ** * * * *** * *** * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** * * **** * * *** * i=0;
* ** * ***** * * *** * * **
* ** * * *** ** * * * *** * ***
** * * ** * * * ** * ** * **** * * ** * * * * **
** ** ******* * ********** * * *** * ****
*** *** *** **** * ** i;

}



int check2(char c)

{
** * * ****** ** * ** j=0;
*** **** ***** ** * * *
** **** **** **** ** **** **** ** *
*** *** ** ** ***** **** * *** ** **** ******* **
* * * ** ** *** ** ******* *** *
**** **** * * *** * * j;

}

int main()

{
*** * * *** * * * * ** *** c;
***** *** * ** **** ***** ** i=0,j=0;
* * ** * *** **** * ** * ******* *

    
* ** ** * ** * c!='.')
** * ** ** * ** * *


* * * * * * * * * * ** * * ** ** * ** * ** *
* * ***** ** * ** * ** * ** ***** * ***
*** ** * ** ** ** ** *** ** ** * * *** * * * * * * ** **** * * * **
** **** ****** * ** ** ***
**** ** * ** * ******* **** * ** *** ** * * * ** * * ** **** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* **** ** * * * ***** *** i=0;
* **** * * * ***** ** **** **
*** * **** * * * ** ** ***
** * ***** * **** *** ***** ** * * ****** *** ***
* * * * * * * * ***** * * * * **
** * ** * * ** ** * i;

}



int check2(char c)

{
* ** **** ** ** * ** j=0;
** ** * ** ** **** ** * * ***
* * * * *** * *** *** *** *** ** ** **
*** * * * * * * * * **** ** ** * ** *******
* **** * *** ***** * * * * * * ****
* **** *** * * * * * **** j;

}

int main()

{
** ** * * * **** ****** c;
** ** * * * * * ** i=0,j=0;
* * *** **** * * * * * * *** **
* *** ** *** ** ****** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* * *** ** * * ** *****
** * **** ** * * * * ** *** ** ** ** * ** * * * *
**** *** *** * * ***
* * ** ** * ** **** * c!='.')
** * * ** * * *** *** * * *


** ** * * * **** * ** * ****** ***** * * **
* ** * ** * ** ***** * ** ** ***
** ** * * *** * *** * **** *** *** ** ** * ** *** **** *
*** ***** *** * *** * ***
** * * * * *** *** *** *** ***** * * ** * ** * *** * ** ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * **** ** **
* * ** * ** **

int main ***
** * *

char c;

int i = 0;

void **** c)

{
* * ***

** ****

* * * * *** *
* * *** * * *** * * ****** 0;

}
* * ;

}
* ** ** ** * *** **** *** * *
* * *

}
* **** * ** ** * *
* **** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* * ** ** * *** * ** ** * * ** c;


****** ** * * ****** * i = 0,b = 0;


** * * * **** ** * * * **** ** * ** * &c);
** ** * * ******* *** ** ** c != '.')
************ *** * ***
* * ** ** ** ** * ***** * ***** * * * * * ** ** * *






** * * *** ** * * *** * ***** * * * *** += 1;


**** ** * * ****** * ******* * * **** ** *** * **** * ** &c);
* ** * *** * ** * * *** *** * * **** *
* * ****** * * **** * ** * * ** * * ** * * *


*** * * * **** ** * * *** * *** * * ** * ** ** i);


* * *** ** *** * ***** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
** *** ***** * ***
*** * * ** *
** main * **
** *****
** c;

int i = 0;
* * * * c)

{
* **
**
** **

**** ;

}
** * * ** ********* * **
*** ** *

}








**** *** ** ***
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** ********* ****** * i=0;
* * ** ** * ****** ** ** *** *
* **** * * * **** **** * ** * * ** *
*** * * ** * * ***** **** ** * *** * ****** ** * *
* ** * ** ** ** ** * ******* *** ** **
*** *** ** * ** ****** * * * * i;

}



int check2(char c)

{
* ** ** ** ** *** *** * j=0;
* *** * ** * * **** **** *
** ***** * * *** * ***** * * ***** ** * *
* *** * *** *** *** ** * * * * * ** * * * * *** * * **
* * *** ** * * ******** ****** *** * * ** ** **
** ** ** ** * * ** j;

}

int main(void)

{
*** ** ** ** ****** * ** ** c;
*** * * **** * * ** i=0,j=0;
* ** * * ** ** * ** ** * * ** * * * * **
** ***** ** ******* * *** ** c!='.')
* * ** * * * **


* * ****** ***** **** ** * * * * *** *** *** *
***** * ** * * ** ** ** **** * **** * * * *** ** **
* ** * * *** * *** * * ** *** * * ***** * * * *** * ** * * * **** * *

    }
* ***** *** * * * * ** * * * * ** ** ** * ** * * * *** ** ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** * ** * ** ** *
** * ** *** * **

int main ***
**** ***
* c ;

int i = 0;
* **** * * *** * *** ** **** ** *
* * *


* * c)

{
** *
***
** ***
*
* ;

}




* *** * * ** ** **
** * ** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.92
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.7k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users