0 like 0 dislike
9.6k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 9.6k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * *** ** * **** ** i=0;
* * * * *** *
* *** ** *** *** * * ** *** * ****** * ****
** ** * * ***** ** *** * **** ** ***** *** * * * **
* ***** * ***** *** *** ** ** ** *** * ** ** **
*** * *** * * **** * * i;

}



int check2(char c)

{
** * * *** * ****** j=0;
* ** ** * ****** ** * **** ** **
* * ** ** * * ** *** ** * ****
* * * ****** * ** ******* ***** ** ** ** * * * * ** *
* *** **** * * * * *** * * ** ** * ***
*** * * *** ***** * * ** j;

}

int main()

{
* ** * * *** **** *** ** c;
*** * * * * * * * i=0,j=0;
** * * *** * *** * * * ** *** ***

    
***** ** ************* c!='.')
* * ** ** * * * **


* ** * **** * ** * * ** * ** * * * **
* * **** ***** * ** * * * * * ** ** * *** *
* * ** ***** * ** ** * **** * * **** *** * ** ** * * ** **** ***
* ******* * ** *** **** * * **
** * * * * ********** ** * **** **** **** **** ** * * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* *** * ** * *
* * * *** * *

int main (void)
** ***

char c;

int i = 0;

void *** c)

{
* *

i++;
* ** **

i++;
*** **** * *
*** ** * * * ** **** * *****
* ** * **** ** * *** * 0;

}
* * ;

}
**** * * **** * *** *
** * *** * * * * * ** **
* * * ***

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
*** ** **** ** ** * * a1=0,a2=0,a3=0,a4=0,in;
* * *** ** * ** * * ** * * * * && c[in];in++)

    {
*** * ** ** * * * * * *** * * * ** * (48<=c[in] && c[in]<=57)
* * * * ** ** ** * *** * ** * ** *** *
* *** ** * * * * * ***** ** ** * * * ** * * ******** ***
* **** * * ***** * ** * ****** * ** ** * **
* * * * * * ****** ** * ** *** ** ** ****** if(65<=c[in] && c[in]<=90)
* *** * * * * ******* * ** * ***** * * **
* ******* **** * *** ******* ***** ** * ** **** * * ** **** * *** * * ***
* * ** ** ** * * * * *** * * ** * ** ** *** **
** * * * * ** *** **** *** * * * * **** ** * **** if (97<=c[in] && c[in]<=122)
* *** * * *** * ** * ** ** ***** ** ** * **
* ****** ****** ** * ****** ** **** ** * *** *** ** ** * *** * *
*** ** ** * *** * ** ** ** ** * * ***
* * * * ******* * * * *** *** ** * if(39<=c[in] && c[in]<=46)
* *** * * *** *** * ** ** *** ** * * * ****
** * * * ***** * ** ** *** *** * ** * * * ******** ** * * * *
* * **** * * ** ** *** * * ** * ** * ** ***** *** *** **
* * * * * *** * * * ** ***** * * * **** * * *
*** * *** ** * *** ** ** * ** ** * * * *
* * ***** * * * * ** ****** ** * * ***** ** *** ** ** **** * * * * * ** *
* *** * ** * **** * *** ** *** * **** *** ** * **** **
**** ***** * * * * *
** * * ** * * *** *** * * *** * * ** *

 }

 

 int main()

{
* * ** ***** * ***** * * c[100];
* ***** *** *** * * ** **
** ** ** * ***** * ***** *

    
* * *** * * * *** ** ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** ** ** * * ** ** i=0;
* *** * **** *** * * ** * *
** **** * *** ** * **** * *** * *** * *
* ** *** * * * * ** * ** ** * ** * **
***** * ** * ** ** * * * *** *** *
* *** ** ** * * **** ** *** i;

}



int check2(char c)

{
* * * **** **** * j=0;
** *** ** * *** ***** * ****
***** ** ** * * *** **** ******* *
**** *** ** ** ** * ** ** **** * *** *** * ** *
* * ** *** ** * * ** * * * * * *** ** *
* ** ** **** *** *** ** j;

}

int main()

{
* * * * ** * * ***** *** c;
* **** * * * ** i=0,j=0;
** ** ****** * * * * *** * * ******* *

    
* * * * **** **** * * ** ** c!='.')
** * ** ** * ***** **


* * * * * *** * * * * * * **
*** * *** * *** * * * * * * * ***** * *
****** *** ** **** * ** *** *** * ** ** ** * **** * * *
* * ** * * ** *****
* * ** * ** * ** **** * *** ***** * * * ** * **** * ** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
****** * ****** * * ***** i=0;
* * ** ** *** ** ** *
******* ** * * ***** * **** *** **** * ** **
* *** *** * * ** ** * *** *** ** * ** ** ***
**** **** ** *** * **** ** ** * ** * * *
* ** *** ** ** * *** * i;

}



int check2(char c)

{
** * * **** ***** * **** j=0;
***** ** * ** ** * *** **** ** **
* *********** * * * * * ****** **
* ** *** *** ** *** * **** * **** *** *** * * **
**** ** **** * ** ** *** ****** *
* * * ***** ** ** *** * * ** j;

}

int main()

{
* ** * ** * * * *** ** ** c;
* * ** * * *** i=0,j=0;
***** ** **** * * * * ******** * ** * * *
* *** ** * *** *** * ** * **** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* * * ***** * ****** ** **
**** **** * * * ** ** *** ** * * **** * ** * ** * *
* **** * * * *** * *** *
*** * * *** **** * * * c!='.')
*** * ** * ** * ** *


**** ** *** * * ** * * ** ** ***
** * * *** * **** * * *** ** * * * ** **
*** * * ** * **** * * * * * ** * * * ** *** * *
** ** ** * ** ****** *
*** ** ** * * ** *** ** ** *** * * ** * * * * * * * ** *** ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
***** **** ** *
***** * ** * * ** *

int main *
* * *

char c;

int i = 0;

void * ******** c)

{
**
*
*** *****

* **** **** * * *
* * ** ** ** * ** * 0;

}
* ;

}
*** ** ** *** * ******
*** ***

}
** ** ** * * * **
* * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* * * ** ** ** ***** * ** * ** ** c;


** * * * * ******* * * i = 0,b = 0;


** * * *** ** * ** ** * * * * * * &c);
** * ** * * * ** * * * ** c != '.')
* *** ** * ** ** * ** *
** *** ** * ** *** * * *** * *** ** * * ** * ***** *** ***






* * * ** * * ****** * * * **** * * * * * * += 1;


** ** * ** * ** * * * *** ** *** ** * ** **** ***** &c);
* * * * * * * ** ***** * ** ** * * * ***
* * ** ** * *** * * ** * ***** * ** **


** * * * * * * * ***** ** * ** ** * i);


**** *** ** * * **** * * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
** *** * ** * *
** * ** * * * * *
main ***
** *****
** c;

int i = 0;
** *** * c)

{
** *** *
* *
* **
* *
* ** ;

}
*** * *** ** ******* * * ****** *
** *

}








** *** * * * *** * **
*** * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * ** * * * * * * i=0;
**** ** * * * * * * *** **
* * * *** * *** * ***** * *
* * *** ** ***** ** ** ** * **** * * * ** ** * * *
*** ** ** ***** *** ** * **** ** * **** **
**** * *** ******** *** i;

}



int check2(char c)

{
* * ***** ** *** j=0;
*** ** * ** ** * * *
* ** * ** * ** ** * * * ****
* *** * * ** * ** ** ** * * * * * ** * *** * ** *** **
* ** *** * ** ** *** * * * ** *** ** * *
* * * * * * ** ** * ********* * j;

}

int main(void)

{
* * * *** *** **** *** *** ** c;
* ** *** ******** ** ** i=0,j=0;
* ** * * * * ****** * **** * * * * * ***
* ********* *** ** **** *** * ** * c!='.')
** * ** * ***** ***** * *


* ** * * ** * * **** **** **** * ** *
* * * * * * ** ** * * * ** ******* * * * *
** * ** ** * * * * ** * * *** * *** ** ** **** ** ** * ** ***

    }
* * ** * ** * * ** * *** * * * ** * * *** **** * **** ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** * * *** * ** *
* *** * * ***** **

int main * **
* * **
*** c ;

int i = 0;
** * **** * ** * **** * *** ***
***


* * ** c)

{
* * **

* *
* *
* * * ;

}




* * * *** *******
* ** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.193
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users