0 like 0 dislike
5.5k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 5.5k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** * ** * * * ** * * i=0;
**** **** ** ****** ** *
** *** * ** ** * ** * * * ***
* * ** **** **** ** * *** * * * *** ****
* * * * * * ** * * ** ** *** *
* *** * ***** *** * * * * i;

}



int check2(char c)

{
*** **** * ** * * * *** j=0;
** ** *** * *** ***** *** * *
**** ** * ** ** * * ** ** * * **** * *
* ** * ** * **** ** * * * ** *** ** * * ** ** *
** * *** * ** * **** *** **
** * **** * ****** j;

}

int main()

{
******** *** * ** * ** c;
** * *** ** ** * i=0,j=0;
* * ** *** **** ** * * ** **** *

    
* * * * ** ** **** * * * c!='.')
**** * ***** *** ** ***


** * * * ***** ***** **** ** * *** *
* **** ** * * * * * * *** * * * * * **
* * ** * ** ** ** * ** ** * * ** * *** * ** ****** **
* * * * ***** * *
* * * *** * ** *** ** * * * ** ** ******* ** ******* *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* *** * ** * ***
* * * * * *

int main (void)
* *

char c;

int i = 0;

void * * * c)

{
* *** **

i++;
* ** *

i++;
** ** *** * ***
* * * **** * * * * ** ** *** *
****** * * * * * *** 0;

}
* * * ;

}
*** * * * **** * * * * *
** *** * ** ** * ** ** ** **** **
** * *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
*** * *** *** *** ** *** a1=0,a2=0,a3=0,a4=0,in;
* ** ** * * * * **** * * ** && c[in];in++)

    {
* **** ** * *** * *** * * * * * ** * * * (48<=c[in] && c[in]<=57)
** * *** ** * * * * ** *** * * ** ********
****** * * ** ***** * * * ** *** * ** ****** **** ** **** *
******* * ** * ** ** * * **** * * *** * **** * * **
* * * **** * * ***** * **** *** *** *** if(65<=c[in] && c[in]<=90)
* *** ** * * * ** ** * ** * * * * **
** * * * ***** * ** ** ****** * * * *** ** **** **** ** ** *** * ** * * *
********** * * ** ** * * ** ** **** *** * ** * ** * *
* * * * * ** * ****** * * * * * ** ** if (97<=c[in] && c[in]<=122)
* ** * *** *** * * ** * *** **** ** ** * *
* ** ** * * * ** ** * ** ***** * * * * * * ** ***** ** * * *
** ***** * * * * ** * * ****** *** ** ** ** ** *
**** ** * * * *** * * * * *** * *** * if(39<=c[in] && c[in]<=46)
* * ** * ** **** * ** * * * * ***** ** ** * ***
* * ** ***** * * ** ** * * *** * ** *** * *** ** *
** * * ** * ** ****** ** ** ** * **** ***** * * * ** ** **
* ******* * * * ** ***** * * * * * ****** ****
** ********** * * ** * * * * ** ** * **
** ** * * ***** ** * * * * * * ***** * * * * *** * ** * * * * * *** * *
* * ***** **** * ***** * * *** ** * ** ** ***
* ** ***** * * ** * ** * *
** ** ** ** ** ******* *** * ** ** * *** * * **** * *

 }

 

 int main()

{
* *** *** ** * ** *** ** c[100];
** * **** * * * ***** * **
* **** * * ** **** *

    
** ** *** * * ** ** * ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * ** * ** * ** *** i=0;
* * ** *** ** ** ** * ***
* * ** ** ** ** * * * * ** * ** **
* **** ** * * * ****** **** ** * * ** ***** * **
* * *** * *** ** ***** * * * ****** *
** ** * * * * * ** * ** * i;

}



int check2(char c)

{
* * *** * ** * **** j=0;
** *** * * * ** ** * ***
* * * ***** ** ** * ** **** *
*** * * ** * * ********** * ** ** * * **
* * ** * * * * * * ** * * * *** * ****
**** * * **** **** ** ** * * j;

}

int main()

{
** ********* ** ** * ******* c;
* ***** * *** * * * * i=0,j=0;
* * * * ** ** * *** ** * *** * ***

    
** ** * ** ******* * ** c!='.')
***** ** ** * ** *


* ** *** * *** *** * * * * * **** **** *
* ** * * ** * ****** * * * ** * * ** * * *
* * * ***** * ** **** ** ** * * * * * * * ********* ** ** *
** ****** **** ** * * * *
* *** ***** ** ** *** ** ** * * ** ** * * ** * * ** ** * ** ** *** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ** * * * * * * * * i=0;
* * * * ***** * ** * ** * * * * **
* * * * * *** * * ** ** *** **
* *** * ** ***** * * ** ****** ** * *
** * ** ** *** **** * * * **
** *** * * *** * i;

}



int check2(char c)

{
* * ** *** **** * * ** j=0;
*** *** ** * * ** * ** * ****
* * * * *** ** * ** ** * * * *
****** ** *** *** * ******* * ** * *** ** * * **
** ** *** *** *** ********* ** * * ***
***** * ****** * * ** *** ** j;

}

int main()

{
*** * * * * ** ** *** * c;
* ** * ** * ** * i=0,j=0;
* * * *** * * * ** ** ******* * **** ****
** * ****** ** * *** * **** * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* **** * ** *** * * *
* * * * ** * * * *** *** * ** ** **
*** **** ** * ***
* **** **** ***** *** * ** *** c!='.')
* ** * * * * ** ** * **


* * * *** * * *** ** * ** **** *
** * *** *** * * * * *** ** * *** ** *** ** *
* * * ** * *** ** * * * * ** **** ** ** **** ***** * * *
*** * * * * * ** ** ** *
** * ***** * ***** **** * *** * ******** *** * * * ** * * ** ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
***** * ******* *
** * ** * * *

int main *
** * *

char c;

int i = 0;

void ** * * c)

{
* ** * *
* *
**** *** *
**
**** ** * * *
* *** ** ***** * ****** 0;

}
* * ;

}
* * ** *** **** * ******* *
* ****

}
* * ** **** **
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* ** **** * * * * * * * * ** * c;


** **** * *** * ** * i = 0,b = 0;


**** * * * ** *** ***** * *** * * &c);
** *** * ** * **** * * **** c != '.')
** ** * *** ** ** *
** *** * * **** *** ** *** * ** *****






* * * *** * * **** ***** * *** += 1;


** ** *** *** *** ** * ******** * ** *** **** * &c);
** **** ** *** * ** * * * ** ** * ****
** ** * * *** * ** * *** ** ***** * ** *


**** **** **** * * * ** ****** * ** ** i);


***** * * * ** * * ** ** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* ** ** * *
* * * *** * **
main ***
*** **
* c;

int i = 0;
* * *** * ** c)

{
* *** *
***
***** *
*
* * ;

}
** * * * * **** * *** * * * ***
***** *

}








*** * * * ***** * *
** * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * *** *** * * ** * * i=0;
*** * * * ******** ***** *
* * ******* * ***** ** * ** * ** * ** * *
* * ** *** * ** ** ** *** *** * ** * *** *** ***
* **** * ****** * * *** **** * **
* * * ** **** * * ** *** i;

}



int check2(char c)

{
** * ***** *** * ** * * * j=0;
* ** ** ** * *** * ** * ** *
*** * * * * *** * * * * *** * *
* * ** * * * * * * * * * * *** * ***** * ***** ** **
* * * ** ** * * * *** * * * ** * *
* ****** *** * j;

}

int main(void)

{
** * * ** * * ***** ***** * c;
* *** * *** * ** ** i=0,j=0;
** ** * * ** * * * *** **** ** * *** *
* *** ** ** * ***** * c!='.')
* *** *** *


* * ** * * * ** * *** * * * * * * * * *
* *** ** * ** ***** * **** * * **** * *** ** * * *
*** ** * * ***** ** * * * ** * ** * * ** ** ** * * ** **

    }
** * * ** ** * * ** ** * **** * * ** * * ** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * *** **
** * * * ***

int main * *
* **
* c ;

int i = 0;
** ** ************ **
* * **


** *** c)

{
* *****

* *
**
**** ;

}




* * ** ** **
* * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.168
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.8k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.2k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users