0 like 0 dislike
8.9k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 8.9k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** * ** * ** * * **** i=0;
** * *** ** * ** * * ** **
* * ** * *** * ** * ** ** * * *****
* * * * * ** * * * * * *** * ** * *
*** * * * ** * * * ** * * *** *
* ***** ** **** * ** * * i;

}



int check2(char c)

{
* ** *** *** ** ** j=0;
* * * *** * * * ** *** * **
** *** * * * ** * * ***** * *
** * * * ** ****** * **** * * *** *** **
* ** * *** * ** * ** * * **** * *
*** ** ** ***** ***** ** ** j;

}

int main()

{
* * *** * * *** ** c;
* ** * ** * ** * i=0,j=0;
*** * * * ** ** *** * *** * * ** * ** ** *

    
* **** ** ** ** * ** * c!='.')
** * * *** * * **** * ***


* *** ** * * * ** ** **** ** * **** ** *** *
** * **** * ** *** *** **** * * ** ** *** ***** * *
* * **** **** * * ** * ***** ** * *** * ** * * * *
* ** *** ** **
* * ** ** * * * **** * * *** * * * * **** *** * *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** ** * ** **
*** * * ** * * *

int main (void)
* * *

char c;

int i = 0;

void ** c)

{
** * ** *

i++;
* * *** *

i++;
** * * ** ** ** *
** * * **** *** *** * * ** **** ***
** * ** ***** * * * ***** 0;

}
** ** ;

}
** * * *** ** *** ****
* ** * * ** **** ** * * ** *
** * **

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
** * ** * ** ***** a1=0,a2=0,a3=0,a4=0,in;
* **** *** * ***** ** ** * * * && c[in];in++)

    {
* **** **** * ** * * ** * *** * * * (48<=c[in] && c[in]<=57)
* * ** * * *** ** ** ** * ** * **
* *** ** * * * ** * * * *** ** ** * *** **
**** * * ** ** *** * * * * ** * * ****** **** *
** ** **** * ** * ** ** * * ** * * ** * if(65<=c[in] && c[in]<=90)
*** *** ***** * * * * *** **** * * * ***** ***
* * * ** * * ***** **** * *** * **** * * * * * * *** * ** * ** *
* ** * * * ** *** * *** ** *** * * ****** * ** * *
* ** ***** * * ** ** **** * * *** ** if (97<=c[in] && c[in]<=122)
* *** *** ** * ***** ** * * ** * *
*** * * * ** * * * *** * *** * *** * * ** * * * * * *** * ** ** *
*** * ** *** ** **** * * *** * * *** **** **
*** * * * * *** * * ** * ** **** * ** if(39<=c[in] && c[in]<=46)
* * *** ***** ** *** * * ** **** * * * *
* *** *** ** * * ** *** * **** * ****** * **** *** * **
** ** ********* ** * **** ** ** * * *
*** * * * **** *** **** ** * **** * **** * *
* ***** *** * * * ** * *** * ** *** * **
** * * ** **** * *** ** * ** * **** * * * * * * ***** ** **
* *** * * * * * ** **** * ** * ** ** ** * **** * *
** * * **** * * * *******
* ** * ** ** * *** **** *** * ** * ** **** * ** *

 }

 

 int main()

{
** * * ***** * * * c[100];
********* * * ** * * *
** ******** * ** * * *

    
* * ** * ***** ** * ** * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** ** ** *** ** ******** * i=0;
* *** * *** ***** * * *** * *
* **** ** * **** ***** * ** ******* *
*** *** * * *** ** ** * **** * ** * * ****** * **
* **** * *** * *** * * ****** *
* ** * * * * *** * ** ***** i;

}



int check2(char c)

{
* *** ** * * * ** * j=0;
** * *** * * * * ** ** ** *
* * ** *** * ****** *** * ** * *** **
* * * * ** *** * ** *** * ** *** ** * *** **** *****
** *** * * ** * **** ** * ** *** **** ** *
** * * * * ** * *** * j;

}

int main()

{
* * * * * * ** * * c;
**** ** *** * * i=0,j=0;
* * * **** ***** * ** * * ** **** *** * * *** *

    
* *** ****** *** * * * c!='.')
* ** * * * ** ***** **** *


** **** ** ** * *** * ** * * **
** * * ** ** * ** *** * * **** * * ** * * **
* **** **** * * ** * ** ** ***** *** ** *** ***** * * * * *** * *
**** * ***** *** *****
* ***** *** ** ** * *** ** ** ** * * **** ****** * *** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** *** * * ****** i=0;
** ** * * ** * **** * *
* * ** **** * * ** ** * * **** * ** * *
**** ** * ** * * *** * * * * * ***** ** ** ***** *
** ** *** ******* * ** ** ** * *** **
*** * *** * ** i;

}



int check2(char c)

{
*** * * * * * * ** **** j=0;
** *** *** * * * ** ** *** *
* ** *** ** ** * ** * * * * ****** ** * ***
** ** * **** * ** *** *** *** **** * * *
** * * * * * ** ** *** * **** ** *
****** *** ** ** * * * j;

}

int main()

{
*** ** * *** * * * c;
* * *** * * * * * i=0,j=0;
**** ** **** *** *** * ** *** **** **** **
*** * * * **** ** ***** * ** * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* *** *** ** ** * ** * **
********** ** ** *** ** * ** ** * * ** * ** ** *
* * ** ** *** * ***
* * * ** ** * * ** *** ** c!='.')
* *** *** ** * * **


*** ** **** ** * **** * ** * **
* ** *** *** * **** * *** * *** * ** * **** **
* ***** **** ** * ** ** ** * ** * ** ** * *** ** * * ******* * ** **
* * *****
* ***** * *** *** * * ** ** * ** * *** * ** ** * * * ** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* **** **** ** **
** ***** ** *

int main * **
* * ****

char c;

int i = 0;

void * * c)

{
* * * * *

* * *
*
* ** ** *
* *** ** ***** ** ** * 0;

}
* * * ;

}
* ** * * * * * * *** * * *
* *

}
** ** **
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* * ** * *** * * * ** **** c;


** **** * ****** **** * i = 0,b = 0;


* ** * * * * * *** * ** ** * &c);
* * * * ** ** ** * * c != '.')
* * * * * * * ***
*** * ** * * * ** ** *** * * ****** * * * * **** *






**** *** * *** ***** * * ** * * *** * += 1;


* * ** ** * * ***** * ** ** ** ******* *** * ** * *** * *** &c);
* * * ** **** * * **** *** **** **** * ** **
** * ** *** * * *** **** * ** * ** ****


** * ** * * ** *** * **** * ** ** * * * * * i);


** * * * * * *** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
** * * ** ***
* * * * *
** main * **
* * *
* * c;

int i = 0;
* ** ** * c)

{
*
**
* **
*
* ** ;

}
*** **** ** *** * *********
** * *

}








*** * *** *** **
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * * * * ** *** i=0;
* ********* *** ** * ****** * *
** *** ** ** **** * * * ** ***** * * *
** ** ** * **** * ** * * *** * * * ** * * * * * **
* ** * *** ***** ** *** ** *****
* * * * ** * * *** * * ** i;

}



int check2(char c)

{
** *** * ** * ** * * j=0;
*** ** * *** ** *** ** * ** ** *
*** * * * * ***** * ** ** ** * ***
** * **** **** * * * **** ** **** ** * * ** *
* * ******* ** ** * ** * **
*** *** * * * ** * j;

}

int main(void)

{
*** * * ** ***** * * * * c;
* *** ** * ** * * *** * * * i=0,j=0;
* ** * ** * ** **** ********** * * * * * ***
**** ***** ** ** * * c!='.')
* * * **** ** ** ** *


* * ***** ** *** * * ** **** * * * *** ** **
**** **** ***** ****** ** **** ** *** ** ** *** * *
*** * * * *** * ** * * * * * ** ** *** * **** *** * * **

    }
** *** * * * * ** ** * ** * *** ** * * * ** ****** **** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** ** * ***
*** * * ** *

int main ****
* **
** * c ;

int i = 0;
* * * ** * * * * ******
* *


*** ** * * c)

{
*** *****

*** ** * **
*
** ** ;

}




* ** ** *** ** * ** **
*** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.172
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users