0 like 0 dislike
10.7k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 10.7k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ** ** * * * * * * i=0;
** ** * * * * ** * *
* * * *** * * * * * * ** * ** ** *** **
** ****** ** ** * * ** * * ***** * * * * **** * ** *** *
* * * ****** * **** **** * ** ** *
* * * *** *** *** * * *** i;

}



int check2(char c)

{
* ** * * *** * * * * ** j=0;
* * * **** * * ** * * * **
* * **** * * * * **** * * * * **
* *** ** *** **** * ** ** *** ** * ** ** * * * **
*** * * * * ** * * * * * ** * * *
* * ** ** ** ***** * *** j;

}

int main()

{
*** ** * * **** ** * ** ** c;
* ** ** * ** * * * i=0,j=0;
** *** * * * ** ** * ** * ***** **

    
*** ** * ****** * ** ****** c!='.')
* *** ** * * ** * *


*** **** * * **** * ** * ** * * * ** *
*** *** * ** * ** ** ** * ** * * **** ** *
* * * ** ****** * ** ** * * **** *** ** * * *** * * * ***** * ** * *
* * * *** ** * * * * **
* * ** * * ***** ** ** ** *** ** ** **** ** ** *** ****



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * ******
*** *** ** * *** *

int main (void)
***** **

char c;

int i = 0;

void * ** c)

{
* *

i++;
* ** *

i++;
* ** ** *
** ***** * ** * *** *** * *** * **
* * * ** *** * * * ** 0;

}
* * ;

}
*** * *** ** *
* ** *** * ***** ** ** * *
** ***

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * ** ** ** * * * a1=0,a2=0,a3=0,a4=0,in;
* * ** * ** ** ***** *** * **** * && c[in];in++)

    {
*** **** * ** ******** ** ** ****** ** **** * (48<=c[in] && c[in]<=57)
*** * * * ** *********** **** * ** *** * *** *
***** *** * ** **** ** * * * * *** ** ** ** * * * **** **
** * * * * **** * ** *** * ** * * ** ******
*** * ** *** * * * ** *** * * * * * * if(65<=c[in] && c[in]<=90)
** ****** * **** * * * * * * * * *** * * *
* * * * **** * * ** *** ** ** * * ** *** * *** * * *****
* * ** ** * ***** ** *** *** ** ** *** ***** ***
* *** ** * * * * * *** *** ** ** ** * **** if (97<=c[in] && c[in]<=122)
*** ** * *** ** ** * * **** * * * * *
* *** * * *** * ***** * * * * * ***** ** *** * * ***** * **
* * ** * ** ** * * * *** *** * *** * *
*** * ** ******** ** ** * * * * * * if(39<=c[in] && c[in]<=46)
* * ** * * *** ** * ***** ***** * * *
* ** ** * *** * ** ** * ** ** * ** ****** ** ***** * * * * **
*** *** *** ** **** ** * *** *** * * ** ***
** * * ** **** * ** * * *** *** * * ** * ** * * *****
* ** * * ***** * *** ** * * * * * * * *** **
* *** * *** * ** * * * * ********* ** ** * * * * *** ** ** * * * ** * **
** * * *** * ***** ******* * * * * ** *** * *****
* * *** ** * * ***
** **** * ****** ** ** ** * * * * * * * ** * ** *** * *

 }

 

 int main()

{
**** *** * ****** *** * * * c[100];
*** ** * ** ** * ****** *** *
** **** ** ** * *

    
* * ** *** * ** ** * * * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ******* ** * * * i=0;
* * * ** **** **** *** * * *
*** * * * ** **** * ***** *
*** * ** ** * ** ****** * *** * * * * * * ** * **
* * * ** ** * *** ** ***** ***** * **** * *
**** ** * *** * * ** ** i;

}



int check2(char c)

{
* ** ** * ** * * ** j=0;
* * ** * *** * * * * * *
* * ** * * *** *** * *** * **** * ****
* * * ** * ** * *** ** ** *** * **** * *** ** * * **
*** ** ******* * * ** **** *** * ** ***
* ***** * *** * ** * j;

}

int main()

{
* *** **** ** * * ** * * c;
** * *** ** * ** i=0,j=0;
* * * * * * ** * ** * ** * * *** * *** ** * *

    
* * * * * * * ** *** c!='.')
* * ****** ***** ** *


* ****** **** * * *** ** * ** * ****
** *** ** * * * *** **** ** ***** **
*** * * ** ** * * * *** * * ** * ** * * * ** * *** ** * * *
* * ** * ** * * ** * **
*** *** * *** ** ** * * * * ** * * ** ***** ** ** ** ** **** ** *** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** * * * i=0;
** * ** ** * * ** * ** *****
* * *** ** *** *** * * * ** ** * **
* * ****** ** * * *** * * *** ** ****
* * * ** ** ** * *** * ** * *** * **
** * *** * ** * * *** i;

}



int check2(char c)

{
* * * * * *** * *** * *** j=0;
* ** * ** * *** *** * **
**** * ** *** * ** * ** *** *** * **
**** ** *** *** * * * * * * * *** *** * *
* *** * * * ** ** * * ** * * * * ** * * *
** ******* * * *** * j;

}

int main()

{
* ** * * *** * **** * c;
**** ** **** * **** i=0,j=0;
* * ** ***** * ** *** ***** ****** * **** *
*** *** * * ** ** *** * ** * * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
*** ** *** ** * * ** **
* * * ** * * * * ** * * * ***** * * * ***** * *** * *
* * *** * * ** *** ***
* ** ** ** * **** c!='.')
*** * * ** * **** **


** ***** * *** * ***** *** * ** * **
* * * *** ** * * ** * **** *** ** *
* ** * ****** ******* *** * * * * ** * *** *** **** * ****
** * ** **** * ** **
**** *** **** **** *** * * * * *** *** * ** *** * * * * * ** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** * * ** * * * **** **
** ***** * * * ** **

int main *
*** *

char c;

int i = 0;

void * ** ** c)

{
**** * * **
**
* * *
*
*** *** *
* * * * ** * * ** 0;

}
* ** * ;

}
* * * **** * * * * ****** ***
* *

}
******* *** ** *
* ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
** **** **** * * * * * c;


* * **** * ** * ** * ** ** i = 0,b = 0;


* ** * *** ****** *** **** ** * ** &c);
** * * * * ** * ***** ** c != '.')
**** ** ******* * **** * *****
** **** * ** * ** * * *** * ***** ** * * *






* ** *** **** * ** *** * ** *** ****** += 1;


** * * * *** ** * ** ** * ** * * ** *** ** * *** ** ** * ** &c);
** * * * * * * * * ** * * * * * **** *** * **
*** * * ** ** ** ** * * *** * * ***** ** ** **


* ** * * * ** ** *** *** * * i);


** * * **** * ******* * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
*** *** * * *
* * ***** *** * ***
main *
* *** **
* * c;

int i = 0;
* ** * * c)

{
* *****
*
** ** **
**
*** ;

}
* *** ** *** ** * * **** * * ** *
*****

}








* ** * ** ****
* ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** * * * ** **** *** i=0;
***** * * ** ** * ** * ** *
* * ** * ** ***** * * * **
** **** * * ** ** **** ** * * ** * ** ******** * * **** ***
* * **** * *** * *** ** * ** ** ***** *
****** ** * * ******* ** i;

}



int check2(char c)

{
* * ** ** ***** *** j=0;
**** *** * * ******* ** * *
* * *** ** * *** * *** **** * * * *
* * *** *** ** * *** * ****** *** * * ** * *
* * * ******* ** *** * **** * * ******
**** * * * ****** ** j;

}

int main(void)

{
* * * * ****** ****** * * c;
** *** **** * * ** ** * i=0,j=0;
** ** * ******* ********* **** ** * ** **
*** *** * ** * *** * c!='.')
* * ** * * ** *


***** * * *** *** ** * ** *** * ** ** ** * **
*** * * ** ** * ** * * * * ** ** ** ** * * *
* * * **** * * * * * ****** ** ** ***** ** **** ** * ***

    }
** * **** * * ***** *** * ** *** **** * ** ***** * * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * ** * *
* ** * ** * ****

int main ***
* * **
* c ;

int i = 0;
* ** * * ***** * * ** *** **
*


* ** c)

{
* *****

* ***
***
*** ;

}




***** * *** * ** *
* 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.50
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.7k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users