0 like 0 dislike
1.6k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 1.6k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
**** **** ** * ** ** * * i=0;
**** * * * * *** * **** **
* * * *** ** * * ** ** ** ** * ***
* * * * * * ** * ** ** * ** *** * * *** **
** *** ** ** **** * * * * ** * *** *
* ** ** *** * * **** *** ** ** i;

}



int check2(char c)

{
* * * *** ** * * j=0;
* *** * * * ***** * * * *
* ** * ** * *** * * * * * * ** * *****
**** *** *** * ** ** * * **** * ** * * * ******
* **** ** *** ***** ******* * *** * *
** ** *** * *** * * ** * *** j;

}

int main()

{
* ** ** * **** ***** * * c;
* *** * *** ** * ** * ** i=0,j=0;
***** * ** * * ** ** ** * * *** **

    
*** * **** * * * ** * **** c!='.')
* ** * * * * * ** *


** ***** * * * * * ****** ** * * * * * *
** * * ** * * * * ** * * * * * * * ** * * *
**** ** ** *** *** ** * * ** *** * ***** * **** * * * * *** * *
***** * * *** * *
** *** ** ******* * ******* *** *** * * * * * ** * * ** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * * ** *
* * * * * **

int main (void)
** ** **

char c;

int i = 0;

void ****** c)

{
* * * *

i++;
*

i++;
**** ** * * * * ****
*** **** * *** ** **** ** * ***
* ** * * ** * *** * ** 0;

}
* ;

}
****** * * ** * ** *** *
**** * ** *** ** ******* ** * *
* ***

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
**** * *** ** ** ** a1=0,a2=0,a3=0,a4=0,in;
* ** ** * * * ** * * ** **** * * **** && c[in];in++)

    {
* ** ********* * * *** * **** * ** * *** * (48<=c[in] && c[in]<=57)
* * * *** * * ** * ***** * * ** * * ** * * ** *
***** * * * *** * ****** **** * * ***** * ** ** * ** * ***
*** **** ** ** ***** * ***** * *** * ** * ** **** **
* * * ** ** * *** *** **** ** * * *** if(65<=c[in] && c[in]<=90)
* ** * * * * * *** *** * *** ***** *
** * ** ** * * * * ** ** * * * ***** * ** ** * ***** ** *
* * ** * * *** **** ** * * *** ** * * * ** **
** * * * * * ** ** * **** * * ** **** ** *** * if (97<=c[in] && c[in]<=122)
* ** * ** * * * * * * **** * **** ****
*** * *** * * **** ** * * * ** ** * ****** **** * * * * * ** * *
* * ** *** * *** ** ****** * * **
** * *** **** **** ** ** * *** * * ** * ** if(39<=c[in] && c[in]<=46)
* * *** * * * ** * * * * * ** *** * * *
* *** *** ***** * ** * *** * * ** * * *** * * *
***** * ** * **** ** *** * * * ** * * * ***
* * *** **** ****** * * * *** ********* * * ** * ** **** *
* ** * ** * * **** * * * **** **** * *** **
**** * ** * * * *** *** ** ** * * * * * *** ** *** ** * * * *** **
*** * * * ** * * * * *** *** ** ***** ***
* ****** * ** * * *** ** **
**** * * * *** * * ***** ** *** **** ** **** ** * *

 }

 

 int main()

{
* * * * ** * * * * ****** c[100];
** * ** *** *** ** ** ********
* * ** ** * *** **** * * * **

    
**** *** ***** ** * *** * ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * *** * * * * ** i=0;
* * * * * ** * ** * * ** *
*** ** * * * * ****** *** * **** **
* * ** *** ** * * * * ** * ********* ***
*** ** *** ** ** * * * * *** ** *
* * *** *********** ** * * i;

}



int check2(char c)

{
* * * * ******** j=0;
** *** ** * ** *** ***** **
* ** ** ** **** ** *** ** * ** * *
*** ** * ** ** *** * * *** ** * ** * ** ***
* ** *** ** *** * * * * * ** *
* *** ** ** ** * * * * * j;

}

int main()

{
**** ** * * ** * * c;
* * * * * * *** * i=0,j=0;
*** * * * * ** **** ** ** ** * * * ** * *

    
**** *** ** * * ****** * * c!='.')
* *** * *** * ** **


* *** ***** * * * ** ******* ** * *** * ** ** *
* ** ** * * * * * *** ** * * * *
*** * ** ***** * * ** ** * * * * * * * * * ***** ****
**** ** ** * *** **
* * ** ** * *** * ** ** * ** * ** ** ** * * * ** * * *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * * * * * ** i=0;
* * * * * * ** * * * *
* ** ** * *** ** * * * * * * **
* ** * ** ** * * * ****** * * ** * * * ** **
* * * * ** * **** ***** * *** * ****
* ** * ** * *** ** *** * * i;

}



int check2(char c)

{
* ****** * * *** ** * j=0;
** ** *** * * * *** * ** * * * ** *
* ** ** * * ** *** *** ***** * *** * *
******** * * * ** * * ** * * * ** ** * ** *
*** *** ** * ***** * **** * ** *** * *** *
* * *** * ******* ** * j;

}

int main()

{
*** ***** * * * ** * ** c;
* ******* ** * i=0,j=0;
** ******** ** * * * *** * *** *** *** ** * ***
*** ****** * *** * *** ****** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
** * * * * * *
***** * ** * **** * **** ** * * * * * ** * * ** ** * * * ****
**** * ** **** * *****
* *** ***** * *** * * c!='.')
* * *** * ** *** ****


* * ** **** * *** * ** **** * * **** * ** * ********
* * ******* ** * ** ** **** *** *** * * **
*** ***** * ** *** *** * * ** ***** * ** * * * * *** * ** * * **** *
* * * ***** * * * **
** ** * * * * ** * * * *** * ** ** ** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ** ** **** * *
* * *** * * *

int main ***
** * *

char c;

int i = 0;

void ***** c)

{
* ** *** *
*
** ** ** *
*
*** * ***** * *
** ** * ** * * ** **** ** 0;

}
** ;

}
* ** * ** ***** *** *** ** *
* * *

}
*** ** * ** * * *
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* * * * * *** * ** ***** * * c;


* * ** * ***** * * * * i = 0,b = 0;


* * ** **** * * ***** * ** * **** * &c);
* * * * * *** ** **** * * c != '.')
* ****** * * * **
**** ** * ***** * * **** * *** **** **** * *






* ** *** * ** * * * ********* * * * ***** += 1;


** ** *** ** * *** ** ***** * **** * ** ** ** ***** ** &c);
** *** ** ** **** ** *** * ** ** ****
** * * * * ** ***** *** * ** * *


* * ** * * * *** * *** ** *** * i);


**** ** * *** ** ** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* ** ** ** ** * *
** ***** *
main * * *
* ***
c;

int i = 0;
* *** c)

{
**** * **
* *
** **** * *
***
* ;

}
******** * * * * * * ** * ** * *
** *

}








* ** ** * *
* ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
***** ** ** * *** ** i=0;
** * * ** * *** *
*** * * * ** ** * *** *** * ** * ** ****
* *** ** ** **** * * * *** * ** * ** **
* * * ** ***** * *** * ** * * ** ******
* *** * **** * * * * i;

}



int check2(char c)

{
* * ** * * * ** * j=0;
* * * * * ** ** ** ****
*** ** *** * * * * ** * * * * ** *
***** *** * ** ** ***** ** ** *** *** ** * ******** *
* *** **** * *** * ** ******* ** *** ** *
* *** * * *** ***** *** j;

}

int main(void)

{
* * * * ** * ** * c;
* * * *** *** ** * * ** * i=0,j=0;
* ****** ** * * **** * ** * * * * ** **
* * ** * * * *** * **** *** c!='.')
* * * * * *** * *


* ******** * * * * * * * * ** *** * **
* *********** **** * ** * * *** * ** ** ***
* * * ** * * ** ** * **** * *** * * ** *** * * * *** * * * ***

    }
*** * * ** **** *** * ** * * * ** * * ** **** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ** ***
** * ** **********

int main ***
*
** c ;

int i = 0;
** **** * ** ** * ** ****
*


** * * c)

{
* *** *
*
* ** ** **
*
** * ;

}




*** * **** *
* * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.132
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 481 views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 950 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 501 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users