0 like 0 dislike
6.7k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 6.7k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * *** ** * * * i=0;
* ** *** **** ** *** * *
**** ** * * ** ** ** * * * * *****
* * * **** ******* ***** * ** ** * * ****
****** * *** ***** **** ** *** **
* * ******* ** ***** * i;

}



int check2(char c)

{
** *** * * * * * * j=0;
*** * * * * * ** ** ****
** * *** * * * * * * ** **** ** **
*** * * ** * ****** * * **** * **** * * **** * *
**** * * * *** * * ** ** *** ** ** *
* * ** * * j;

}

int main()

{
**** **** * * * ** * * c;
** ******* ** * ** * i=0,j=0;
* ***** * ** * ** * * * ** * ** ** * *

    
* * ******* ** * c!='.')
** ** * * * ** **** * *


** * * ** * * ** ** * * * * * * **** * * * **
* * * * * * ** * * * **** ** * * ** * *
* ** * *** *** * * * ** ** *** * * ****** *** * * * *** *
** ** **** *** **
*** * **** **** * ** ** * * * * * * * * * ** * * *** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * *** * ** * *
* *** * *

int main (void)
*

char c;

int i = 0;

void * *** c)

{
* * ***

i++;
* ** ***

i++;
* * * * *** * **
** ** **** * * **** * *** ** **** * * * ** * *
** **** * *** ** * * * 0;

}
* * ;

}
* * * **** ** * **
**** * * ** *** ** * ** * *
* *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
** *** ** * *** **** a1=0,a2=0,a3=0,a4=0,in;
* ** * * *** * ** * * *** *** && c[in];in++)

    {
**** * ** * ***** * ** * *** * * * ** * (48<=c[in] && c[in]<=57)
* ** * * * * * ** **** * ** * *** *
** *** * * ** * ***** * ***** * * ** **** * * * * * * *
* * ** * ** ** *** ** ** ** * ** **** * **** ** ***
* * * * ** * ** ** * **** ** ** ****** * if(65<=c[in] && c[in]<=90)
* ** * * * ** * * * *** ** ** ** * ** ** ** **
****** * ** ****** * ** *** * ** *** * * ***** * ***** * *** * * * **
* * * * * ** ****** * **** ** ** * ******
** * ** * *** ****** * **** * * * *** * * ** * if (97<=c[in] && c[in]<=122)
** ** ** * * *** * * ** ** ** * **** * * ** ********
** ** * ** ** ** * * *** * *** * * * * * *** ** ***** * ** * **** * **
* * * * * * * * * * * * * * **** ** ****
* * * * * *** * * ** ** * * *** * ** if(39<=c[in] && c[in]<=46)
*** * * ** * * * * * * ** ** *** ** * *
** * ** *** *** * ** * * ** ** ** ** * * ******* * * *** * * * * ** ***
* * *** ** * ** ** * ** ** * * *** *** * *
**** ** ** * **** * * *** * ******* * ** * * *
* ***** * ** * ***** * ** * * * **** *
** * ** ** * ** * **** * * * ** * ** * * ***** * * ** *** *
* **** ** * *** ***** * ** **** ** * *
** * ** * *** ** ** *****
* ** * ** ** ** *** *** **** ** ***** * * * **

 }

 

 int main()

{
* ** ** **** **** * ** * * c[100];
** * * ** ** ** * ***
** ** * ** * **** *** ** *

    
*** ******* * * ** ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
*** * ** ** * ****** * i=0;
* * ** *** ** * * * * * * *
* ** * * **** * * * **** *** **** * **
* * ** * ** **** * * ***** ** ****** ** * ** ***
***** * *** ** ** *** ** * * *** *
** * **** ** *** * * * * * i;

}



int check2(char c)

{
* **** * * * * * * **** * j=0;
* * ** *** *** * **** ** * *** * ***
* ** * * ** ** * * * **** * * ** *** *
* * * * * ** ***** * **** **** *** ****** ** * ** * *
** * ** ** * ** * * * ** ** * * ** **
* ** * *********** ***** ** * * * j;

}

int main()

{
* * ** * * * * *** *** c;
* * * * ** ** *** **** ** i=0,j=0;
* * * ** *** *** * ** * ** * *

    
* *** ** * * *** ** ** * c!='.')
** * * ** ** * ** ** **


* * * * *** * * * ** * ** ** * * * *** **
** ***** *** *** * ** ** * *** * ** ** * *
** * * * ** * * ** *** ** * ** *
**** *** * * ***** * **
* * * ** *** ** * * *** ** **** ****** * * ** ** ** * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ***** * ** * * i=0;
* ** ** **** * ****** * ** **
* **** * ** ** * ****** * * **** ******
**** ** * * * * *** * ** *** * ** * ** ** * ** *** **
******* * ** **** ** * ****** *** ** *
*** **** * *** * * *** *** i;

}



int check2(char c)

{
************* ** * j=0;
*** ****** * * ** ****
* * ***** * * *** * ***** ** **** **
* *** * ** **** ** *** ** * * ** * ** * ** * * ** *
** ** * ** ****** ** * ** ** * *
* ****** ** ** * * ** * ** ** j;

}

int main()

{
* ***** ** * *** * * c;
** * * * * ** ** i=0,j=0;
** ** * * * **** ********** * *** ***** *
**** * *** *** * * * * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
** ** ***** * ** * ** *
* **** ** ** * * *** ** **** * * * *** * *** **
***** * *** * * ******
**** * **** * ** * * * c!='.')
*** * * * * * * * **


* * ** * ** ** *** * * ** * * * * * **
*** * * ** * ** ** ** * ** **** * * * * * *
* ** ** ** ** **** *** ** ** ** *** ** * * * * * * ***
* ***** * * * * ***
* *** ** ** *** **** * ******** * * * * * * * * * **** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * ** ** ***
** * * ****** * *

int main *
* *

char c;

int i = 0;

void ** c)

{
* ****
* *
*** *
*
* * ***
**** * **** ***** * * * * 0;

}
* ;

}
* * * * ** *** * * *
* *

}
* * ** * * *
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
*** ** **** ** ****** *** c;


** * * * * * ****** i = 0,b = 0;


* ** * * ****** * * * * **** **** * &c);
* *** *** * * * * ** * * c != '.')
** * ** **** ** * * **
* ******* * ** * **** * * * ** ** * **** ****** ***** *






*** *** *** **** * * ** **** ** * **** += 1;


** ** ***** ** * **** ** * *** ** *** * **** &c);
* * * *** *** * ** * * **** *** *** **** * * *
* * * * **** ** *** ** **** **** ** **


* *** * * *** * *** **** * ** ** *** i);


* *********** *** *** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
******** ** ** *
** ** ** * * * *
* * main ** *
**
c;

int i = 0;
* * *** c)

{
*** *
**
***** *
***
* ** ;

}
** ** ** *** *** ** *
******

}








*** * ***** * * **
* ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** ** *** * *** *** i=0;
** * *** ** * ** * * ** ******
** * * ** * ** **** * * * * *** ****
* ** * ** ** * ** ** * ** * *** * ****** * ** *** * ** **
* **** * * * * * ** **** *** * * * * *
* **** * * * *** i;

}



int check2(char c)

{
* ***** * **** ** ***** j=0;
* ****** * ** ** * * * * *
*** ** * ********* * * ** **** * ** ***
* * * **** *** * * ** * * * **** ** *** *** ** ***
** ** * * * * * ** ***** * ** **
** * ** ** * * ** * j;

}

int main(void)

{
** ** * * ** ** * c;
* * *** * * * ** i=0,j=0;
*** ******* **** ***** * ** * *** * ** * * *** * **
* * ** * *** * **** * c!='.')
** * * *** * * **** ** **


* *** * ** ** ****** *** *** ** * *
* * * ** * * * * * ** * ******* * * * *
* **** * * ** ** * * ** ******* * *** ** * *** **** * * * * * *

    }
** *** ** ** ** * *** ******** * ** * **** *** ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * * * ***
** * * *** ** **

int main *
** * **
c ;

int i = 0;
** * ****** ***** * *** *** *
** **


* * c)

{
* * **
*
** * ****
*
* ;

}




* * * ******* *
* * * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.138
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users