0 like 0 dislike
14.2k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 14.2k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * ** ** * ** i=0;
*** * * *** * * ** * **** * ******
* **** * **** ** ** *** ******* * * * **
* ***** * ** * * ***** * ***** *** * ** * ***
* * * * *** * * * * * ** **** * **
** * * * * ** * ** * **** i;

}



int check2(char c)

{
* ***** ** * ** * * * ** j=0;
* **** * * * ** * * * **** ***
* ** ** **** * * * * ** * * ** * * * ***
* **** *** ** * * * **** ****** *** * * *** ** * * * **
* **** ** * ***** * * * *** ***
**** *** ** * ** *** *** j;

}

int main()

{
* * ** ** ** ** **** c;
* * **** * * ** i=0,j=0;
* * *** ** * * * * * ***** * ** * **** ** ** *** **

    
* * ** ** * * **** **** c!='.')
* ** ** **** *** ** ** *


* ** ** ** ***** ** ***** **** * *
**** ** * ** * * *** *** *** ** **** * *
** * * **** *** ** * ** * * * * **** ** * * * * *
* ** ** ** *** ** * **
* * ** * * ** * * * * * * **** * * * * ** * *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** * ** **
***** *** * ** **

int main (void)
* * ***

char c;

int i = 0;

void ** * ** c)

{
** ****

i++;
* ** ** *

i++;
* ***** * ** *
** * * * ** ***** ** ** * * **** * * **
*** *** **** ** * ** * 0;

}
* * ;

}
** ** * * * * *** ** *
* *** ******* * ** ** ***
*

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* *** ** ** ** * **** ** **** * a1=0,a2=0,a3=0,a4=0,in;
*** * ** ****** *** ** *** ** * && c[in];in++)

    {
* ** * * * * * ** *** ** ** * ** ** (48<=c[in] && c[in]<=57)
*** * ** ** * **** *** * * **** * * * **
* * **** * **** *** * * * *** * ** * ** * * ** ** *
* * * * * * * * * ** * * * ** * ** * *** * ** * *
* * * ** * ** * **** ** ** * **** *** *** ****** if(65<=c[in] && c[in]<=90)
******** * * *** * *** ** ** * * ** *
* ** ******* * ******** * * *** ** *** ** ** ** **** **** ** *
* * * * * * * * * * ****** * * *** *
* * ** *** *** * *** ** * ** ** *** * if (97<=c[in] && c[in]<=122)
** ** * ** ** ** ****** *** * ** * * * **
* * ** * *** * * ** * ** **** * * * *** * ** * * *** * * ** ** *
** ** * ** * ** ** ** * ** ** * *
* * * * * * **** * ** ** * * ** * ***** if(39<=c[in] && c[in]<=46)
* * * ** **** *** * * **** * * * *** **
** * * * * ** ***** * * * * * *** * ** * ** * **** *** ** *
** ** ** * * ******* *** * * * * ** *** * * *
* *** * ** ** * ** * * * * * * * * *******
* ***** ** * * * * **** ***** **** * **** *
** * * * * * * ** ** **** * * ** * * * *** ** ** * ** * ** ** ** ***
* * ** * * ** ** ** ***** * ** * ** * ** * ** * **
** ** ** * * ** * ** ** ** * **
*** ** * * * *** **** ** * * * **** ** * * ***

 }

 

 int main()

{
*** ** * *** * **** ** ** * c[100];
* * ** * **** * ** ** * *** **
* ** *** ** * ****** *** *

    
* ** * * *** * * ** * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
**** * * * ** ** * * ** i=0;
** * * **** *** *** * * * **
******* ***** ** **** ** ** ** * *
* * * * * *** * * * * ** * ** *
*** ** *** * * ****** ** *****
* ****** **** * * i;

}



int check2(char c)

{
* ** ** ** ** * j=0;
* ** **** * * * *** **** * ***
* ** * **** ** * ** ***** *** * * * **
** * * *** * * * ** * ** ********* * * ** ** ** ** ***
* ** * * * **************** ** ******
****** *** * * * ** j;

}

int main()

{
* * * ****** * ** ** * * c;
** * * * ****** ** ** * *** i=0,j=0;
** * * * ** ** ** *** * * ***** ** ** *

    
* * * ** * ****** * ** c!='.')
* *** ****** * * * * *


* ***** *** * *** ** ** ** *** **** ** *** **** ***** ** *
* ** * * ** * ** * ** ** ******* * *
** *** ** ** * ** * ** * ** * ** ** * * * * * * * * * ****
**** * ** * *** **
* ** ***** ** ***** * * **** * **** *** **** * *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** *** ** * **** ** i=0;
* **** * * * **** * **** ** *
**** * ****** * ** ** * * * ** ***
***** * * * * ** ** *** ** *** * ** ***** **
* ** * * ** * * ** *** ** **
* ** * * * *** * ** ** * i;

}



int check2(char c)

{
* *** * ** ** **** **** j=0;
* ** * * ** *** * * * * ** *
* **** ** * *** *** ** * *
* ** * * ** * ** ** * * ** * * * * * * * *
* * ** ** * * **** ** ** * ** * * * **
* ** ** * *** * ** ** * j;

}

int main()

{
* *** *** * * ** ** *** c;
* * * * ****** * ** * i=0,j=0;
*** * * **** * * * **** * * * ** * * ***** ** **
***** ***** ** *** * * * * ** ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* * *** * * ** *** * *
** ** * ** * * ** * ** * *** * * **** * * ** * ** *
* * * ** * * **** **
****** * ** * *** c!='.')
** * *** **** **** ** **


* *** * ** * **** * ****** * * * * *
* * * *** * *** * ** * * * ** * * **
* **** ******* ** * *** * ** ** * **** * ****** * ** **** * ** **
*** * * ***** *** * ** *
********* * **** ** * ** * * * * * ** * *** ** *** * * * * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ***** **** *
* **** * ** * ** ** **

int main * **
* **

char c;

int i = 0;

void **** c)

{
** * * ****

* ** *
**
* * ** * *
* ** * * * *** **** * * 0;

}
* * * ;

}
* **** ** * * *****
**

}
* ******* *** ****** ** *
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* ** ** * * ***** ** ** ** c;


* * ** **** *** * * * i = 0,b = 0;


**** * ** * * * * * * * &c);
** * * ** ** ** * * c != '.')
* * * * ***** **** **
* ***** *** * ** * * * * *** * ** ** ** * *** * *






** * * * ** ****** *** * * * ** ******* ** *** += 1;


* * * ***** * * **** **** ** * * * * * ** *** *** ********* ** ** &c);
** * ** ******** *** ** * * ** ** *** **
** ****** * *** ***** * * * * * **** * ***** *


** ** * * * **** * ***** *** * * * * ** i);


*** * * * ** ** * * ** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* * ** * ** * *
*** ** * *** ***
main * *
** **
c;

int i = 0;
* * *** c)

{
**
**
***** *
** *
* ;

}
**** * * * * *** * **** * * * ****
* *****

}








** *** * ** ** * * *
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * * ***** i=0;
*** *** * *** * ***** ***** ****
*** *** * ** * ***** ** *** * * **
* *** * **** * * * * ** * *** *** ** ****** * * *
* ** ** ** **** *** *** *** * * * *
*** ** * * ** * * ** * * i;

}



int check2(char c)

{
**** *** * * * **** *** * j=0;
* * ** * **** * * ** * ***
* * * * ** **** **** *** * ***** * *
* *** * ** * * * **** ** * * * ** * * * ***** *** *** ** *** **
* * * ** * ** ** * * * **
* * * ** * ** *** * j;

}

int main(void)

{
* *** * ** ** * * ***** c;
** * *** * **** * **** i=0,j=0;
* * ** ***** * **** ** ** * * * * *
*** * ** ***** * **** * * ** c!='.')
* ** * ** * ** *


*** * ***** * ** * ** ** ** * * ** ****
** * * ***** ** * *** ** ** ****** *** * ** ** ***
*** * ** * *** * **** ******* ** * ** ** ** ********* * ** * *

    }
** * ** * ** *** ***** * * *** * ** ** ****** * *** * ** *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * * ***
* * ** *

int main *
** *
**** c ;

int i = 0;
** ** ** * **** *** * ***
** *


** ** * * c)

{
* * ***
*
** * *
**
* * * * ;

}




* ** * **** * * * *
** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 8.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.9k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users