0 like 0 dislike
8.4k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 8.4k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * ******* * ** i=0;
*** ** * * * * * * ***** ****
* * * * * * * ** ** * ** *
* * ** ** ***** * * * * *** * *** *** * ** * * *
* ** ** * ** ** * **** * * * *** * **
*** * * * * ** *** i;

}



int check2(char c)

{
** ** ** * ****** * * j=0;
** * **** * * ** * ** ** * ** * * ***
* ** * ** **** ** ** * ** **** *
** ***** ** * ******** * ** **** *** * ** * *** ** *
** * * *** *** * * * ***** *** ** *
* * ****** * ** * ***** * j;

}

int main()

{
*** ***** ** *** ** c;
* ** ** * ***** ***** i=0,j=0;
***** ***** * * ****** * ** *** * *** ** *

    
* ** * * * *** ** c!='.')
*** ** * * * * *** * **


*** * * * ** ** ** ** * ** * ** * * * * * ****
** * * ** * * * ** * *** * * * ** * * * *
** ** ******* * *** ** * ****** ***** * * * * * * * * * *****
*** ** ** ***** ** * * **
* **** * * * * ** **** ** ** * ** ** * *** ** * ** **** *** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** *** *
*** * * * *** * ***

int main (void)
** * **

char c;

int i = 0;

void ** c)

{
***** *

i++;
* ****

i++;
****** * * *
** ***** * *** ** ** * ** * *** * ** ** *
* ***** ** * *** * * * 0;

}
* ;

}
* ****** *** * *
** * * * * **** **** * **
* *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
*** * ** * *** * ** a1=0,a2=0,a3=0,a4=0,in;
*** * * *** * * ** * * ** * * * && c[in];in++)

    {
* ***** * * * * *** **** *** ** *** * * (48<=c[in] && c[in]<=57)
* * ** * * * **** ** * *** ** ***** * *
**** * * ** *** * **** ***** ******* * * * ** * * *** **
* ** * ** * * ** ***** * *** * ** * ** * *** ****
* * **** *** ** ** ********* **** ** * *** * * * ** if(65<=c[in] && c[in]<=90)
* * * * * * * ** * ** * ** ***** *
** ** *** * ******* *** * * * * * * ** * ** * * **** * *
** * * * * * *** *** ** ** * ****** *** *** **** * *
* ** * * * ** ** ** ** * ** * ** ***** * * * * if (97<=c[in] && c[in]<=122)
** * * * ** ** ******** * * ** * * * *
**** * * * * ******* * * ** * ****** * * * *** **** ** ****** ****
*** * * * * * * ** * * * * * * ** ** * **
* *** * * ** * * * * ** *** ****** * ** if(39<=c[in] && c[in]<=46)
**** * *** * ** ** ** * * ** * ***
** * * **** * * ******* *** * * * *** ** * * * * ** * ** **** * *
** * ** * **** ** ** ** **** * *** ** *** * * * * * **
** ** * * ** * * * **** *** * ** ** *** * *
** * *** ** * * * * * *** * * ** *** * *
* *** *** ****** ** * * *** *** * * *** * *** * ** *** * *** **** **** *
* *** * ****** *** ** ** * ** * *** ** ** * **
* ** ** * * ** ** **** ***
** *** ** * * * * ** * ***** ********* * ** **

 }

 

 int main()

{
* * *** * ** * * c[100];
** *** * * * ********
* ** ** * *** * *

    
* ** * * ** *** *********** * ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * ***** * ** *** * i=0;
* ** * * * ***** * * *** * ** *
*** * * ** **** * ** * * **** * * *
* **** ** ** * * ** * * * ***** * * ** ***** * ** **
**** *** **** ** **** *** * *
***** * * * *** ** * * ** i;

}



int check2(char c)

{
*** * ** ** * ** * * j=0;
** * *** ** ** **** *****
*** * ***** * ****** *** * *** *** * ***
**** * ** *** * * *** ** ***** ***** * * * ******** *
* * * * ** * *** ** * * * ** ****
** *** ***** * ** *** *** * j;

}

int main()

{
* ***** * * ** * c;
* * ** ****** * *** * *** i=0,j=0;
**** * ** **** * ** * ** * **** ***** *

    
* ** * ************* c!='.')
* * * *** * **** * **


****** **** ***** * * * * * * * * **** ** *
*** * * * ** * * * * * *** ** * * ****** * ***
** **** * *** * *** ** ** ** * * * ** *** ** * * **** ** ** ** **
*** * * * ** *****
*** ** ** * ** * * ** * *** * * * ******* * *** **** **** ** * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* *** **** * * * * i=0;
*** *** * * * * * ***
* * * * ** * *** * * ** * ** *
** * * ** **** * ** * *** * ** **** * *********** * * ***
* * * *** ******* ** * **** * * *** **** * * *
**** ************ **** * **** * * i;

}



int check2(char c)

{
*** * **** * ** ** * *** ** j=0;
* ** ** * *** * * ****** **** ***
* * * * ** * * * * * **** ** ** ***
* * *** * * ***** ** * **** ***** * * * * *** * * ** **
* * ** * * *** * *** * ***
* ** * *** * ***** *** j;

}

int main()

{
** * * * **** ***** * c;
** ******* * ** * * * i=0,j=0;
** **** ** *** * * ******* ** * * ** **** * **
* ** **** *** ** *** ******* to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
*** * ** ** ** ***
* * * * *** *** * ****** * **** ** * * * * ** ** ** ** * *
* ** *** ******** * * *
** ** * *** * * * ** c!='.')
* * ** ** * **** * ***


* ** * *** * * ************ * **** * **** *** * * *
* ** * *** ** ** * **** **** *** ** * **** *
* * ***** *** *** * *** * ** ** * * * * *** * * * * * * ***
* ** ** **
* ***** ***** * * ** * * *** * ** * * * ** * **** * *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** *** **
** *** ***** * ***

int main **
****

char c;

int i = 0;

void * *** c)

{
**** * *
*
** * **
**
* ** ** * ** *
** * **** * * ** * 0;

}
*** ;

}
* * * ***** **** * * * *** ** **
**

}
* ** *** * * **** * ***
* * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* *** ** ** * ** * ***** * * * ** c;


* * ** * ** * * i = 0,b = 0;


* * * * * **** * * * * * * *** &c);
** * * ******* ****** ** ** * c != '.')
***** ** * ** * * *
*** * **** ** ** ***** * **** *** * * ** * * *






* * * * *** * *** *** **** *** * * ** * += 1;


* * * ** * **** *** * * **** **** ** **** *** *** **** * * &c);
* * * * **** * * * * * * * * ** * * * *
* ****** * *** **** **** ** *** * * * * * * * * *


* * * **** **** * * * * * * ** * **** i);


* ** ** * * ** **** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* ** * * **
* * *** * *** *
main *
*******
* c;

int i = 0;
* *** * * * * c)

{
* * * * * *
***
*********
**
* ;

}
* ** * * * * **** ***** ** ** ***
* * **

}








** * * * *
* 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* **** * ** * * * i=0;
* ** *** * * * * *** * * * * * *
* * ****** ** * * * *** * ***** * * * * *
* * *** * * * * ** ** * ** ** * * * * *** *
* ** ** *** ** * * ** ** * *** * * ** *
** ** *** * **** ** ** *** ** i;

}



int check2(char c)

{
*** ***** ** * * j=0;
******** * *** * **** ***
* * ** * ** *** ** **** * * * *
*** * * * * ** * *** *** * **** * *** **** * ** *
** * * * *** *** * ** **** ** **** *
** * ****** * * * ** j;

}

int main(void)

{
*** *** * * * ** ** * c;
** ** * ** * ***** * * i=0,j=0;
** ** ** * ** * *** * * * * **** ** **
* * * ******** ***** *** ** c!='.')
* *** ** * *


* * ***** *** ***** *** ****** *** *** * *** *
** * * ** ** * * ** * *** ** ** **** * ** ***
* ** * ****** **** * *** ** ** ** * * * ** *** * * * * *

    }
* * *** ** ** * ** ** * *** **** ** ** ** * *** * * ****



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** ** * *****
* ** *** * **

int main *
*
* c ;

int i = 0;
* * * *** * * ***** **** *
* **


* ** ** * c)

{
* **** *
*
* * ** *
*
*** ;

}




** * * * * ****** ***
** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.80
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.6k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 4.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users