0 like 0 dislike
3.4k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.4k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* *** ** * ** *** * i=0;
* ** *** ** * * * *
* ** * ***** *** ****** **** * * **
** *** * * ** **** ** * ***** * * ***** ****
* * * ** * * * ** * * * ***
**** ** * ** ** * * * * * i;

}



int check2(char c)

{
** * ** * *** * *** j=0;
** *** **** * **** ***** *** * * *
* * * **** **** ** * ** * * * *
***** ** ** ** * ** **** * * * *** ** * **** **
* *** ** *** *** ** * ** * * * ** * * **
*** ** ****** *** **** *** ** j;

}

int main()

{
** ** * **** * * ** * * c;
* ** * * ******* *** ** i=0,j=0;
* * *** *** * * * * ** ***** * *** *

    
* ** * * * * *** ****** * c!='.')
* ** * * ****** ***


* * ** *** ** * ****** *** * * * ** * * *
*** * ** * ** * ** * * * ****** ** *
** * *** ** * * * ** * *** ** * * *** *** **** * ** **** *
** * * ** ** ***
*** *** *** * *** *** ** * ****** ** * * * * *** ** *** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * *****
* * * ** * ****

int main (void)
** *

char c;

int i = 0;

void ***** c)

{
**

i++;
*****

i++;
* * * **** ** * ***
* * ** * ** * * *** * ** ** *** *** *
***** *** * * * * * * **** 0;

}
* ;

}
* * * * ** *
** ** ***** * * ***** ** * *** * ** **
*

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
*** * * * *** ** * ** ** a1=0,a2=0,a3=0,a4=0,in;
*** * * ** * * ** * ****** * * * * && c[in];in++)

    {
** * ** ** ** *** * * * * ** ** * ** ** * (48<=c[in] && c[in]<=57)
**** * * * * ** * * *** * * * *** * * *
** *** *** * ** ***** * ** ** * * *** ** * * * * * *
* ** **** * ** ****** * ******* * ** ** * ****
** * * * * * * * * ** * * * **** * * * * * *** * ** if(65<=c[in] && c[in]<=90)
* **** * ** ** * **** * * * * ** * *
** ** * * ***** ** ** ** * ** * ** **** * *** *** ** * * ** * *
** **** ** ** * * * * * * * **** * * * *
*** ****** ** * * *** * * * * * *** * ** **** ***** if (97<=c[in] && c[in]<=122)
* * *** ** **** ** ** ** * * * * *** ***
* **** **** * * * * * * * * *** * ***** ***** ** * * *
* * * *** ** * * ** * * * ** * * ** * *
****** * ** * ** * *** ** * * *** * * **** ******* * if(39<=c[in] && c[in]<=46)
* * * * * * * ****** ** * ** ** * * *** * ***
* * * * ** * * * ** * ** * **** * **** * ** ** ********
* * ** * ** ** ** **** ** * * * *
** ** * * **** *** ** *** * ** * ***** ** *
**** ****** * ** * * ** * * * ** * **** * *** * * *
* * * ** * ** *** *** * * *** ** *** **** * * * ** * * *** * ** * **********
*** *** *** * **** * * *** ** **** * * ** * **** * *
**** ** ** * *** *** ** * ***** ** **
** * * * ******* ** ** ***** * * * ** ** * ***

 }

 

 int main()

{
* ** ** * * * * c[100];
* * ** * * ** * * ***
** * *** * ** * * ***** **

    
** * * *** * * * * * * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * * ** *** * * * * i=0;
** *** * * * ** * ** ** *
* *** * *** * ** * * ** * ** ** *
******** ** ** * * ** * ******* * *** * * * *** * * **
* *** ***** ** ***** ** *** * * *** **** *
** * **** * **** * ** i;

}



int check2(char c)

{
* ** ** * **** **** *** * ** j=0;
*** * ** *** * * * ** * * *****
** * * * * ***** * * * * ** * * * *
* * * * * * * * * ***** * * ******* ** * * *
* ** ** * * ** ** * * ** * ** * *** *
* * * * ** * ** **** * * j;

}

int main()

{
* * ****** * c;
** * * ** **** * i=0,j=0;
** *** ** * * * * *** * ******* * * ****

    
* * * ** ** * ******* c!='.')
******* * * *** * ** *


* * ******** * ** * ** *** ** ** *** * **
*** * * * *** ** * * ** ***** *** **
* * * * * * ** ** ** **** *** * * * ** *** ** * * * * * * *
* ** * * *** ** *
* *** ** * * ** *** * * * ***** * *** ** *** * ************ ***** * **** ** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* *** ** ********* ** i=0;
***** * * * ************ *
**** ****** *** **** * * * ** * * *
* * *** ** * *** * ** **** * ** * * * * **
*** * ** *** * ** * * *** * *** * ***
*** * ** * * ** * * ** * i;

}



int check2(char c)

{
*** *** *** ** ** ** j=0;
*** *** * **** * ** * *** *
*** * * ** **** * * ** ***** ** * *
**** ** **** *** ** * * ** * ** * ** * * *** **
*** * * ** ** ** * * ** *** * * * *
* * * * ** * * ** ** * j;

}

int main()

{
*** ** * ** * * ** c;
* * * ** ***** *** i=0,j=0;
*** **** ** *** ****** ** * *** ** *******
* ** **** ***** * ** ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
** * **** *** ** * *
* *** ** *** *** ***** *** * ** ** * * * ***** * **
* ** **** * *
* * *** ***** ** * *** * *** ** c!='.')
*** *** *** * * * *


** * ** * * * ***** * * * *** * ****
* ** *** **** * * * * ** *** * ** ** ***** *
******* * * * * * * **** * ***** * *** * * * *** ** * ******* * *** *
** ** * * * *** *****
** * * * * * * ****** * * ** ******* ** * ** **** ** *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** ** * ** ****
*** ** * * ******

int main *
**

char c;

int i = 0;

void *** * c)

{
**** * **

* * * * **
**
* ** * * ** *
** *** ** ** ** ***** * * *** 0;

}
** * ;

}
*** * * ** * * ** * *** *
* * **

}
* * ** *** * * * * *
*** * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
** * * ** ****** **** * c;


* * * * ***** **** * **** i = 0,b = 0;


* * * * * ** ** ** *** * ** ** * &c);
** **** ** ** * * *** * ** c != '.')
***** ** * * **
* * * * * * * * * ** * * ** ** * *** ** ** * ** *






* * *** *** ** * *** *** * ** * += 1;


* * * * * * ** * * * ** * *** ** *** * * **** **** * * * &c);
** ****** * ***** * * ** ** **** ***
* ***** * ** * ** * * * ***** ** **** * **** * *


* * ** *** ** ** * * * ***** * ** * i);


****** * * ***** * ** * ** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* * *** *******
*** * ** ** ** ****** *
main ** **
* **
** c;

int i = 0;
* * * ** c)

{
* * *
*
*** ***
* *
;

}
** *** **** * ***** * **** ****


}








* *** ** *
* ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** ** * ** * **** i=0;
** ** *** ** * * * *
** * ***** * * ** ****** * **** ** *
******** ***** ** * * * ** * * * * ***** ****
*** ** ***** ***** ***** **** * * *
* ** * * ** ** ** *** ** * i;

}



int check2(char c)

{
* * * * ** * * * * ** j=0;
* ** ** * * ** ** * *** **
**** ** * ** * * * *** * *** ** ** *
*** ** * * * * * ** * * *** ** ** * * * * * **
** * ** ** * **** * *** ** *** ** *
** ***** ** * * ** * ** * j;

}

int main(void)

{
*** ** ***** ** *** ** ** c;
* * ****** *** * * i=0,j=0;
*** ** ** * * * * ****** * * * * ** * * ** *
* * * ***** *** * * ** ** c!='.')
* ** ** * **** * * * ***


**** * *** * *** * * **** * * ** * *** *
* *** ****** * ** * * ** * **** ****
* **** * * ** * ** * ******** * ******* * * * *** * * * *** ****

    }
** * * ** * ******** * * * *** * ** * *********** ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** ** * *
* ***** * * ***

int main **
* * **
c ;

int i = 0;
** ** * **** * * **** * ** * ** **
**


* *** * c)

{
* * *
***
**** *
*
* *** ;

}




** * ** ** * *
* 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.50
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 958 views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users