0 like 0 dislike
13.9k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 13.9k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* **** * ** ** *** i=0;
* ***** * ** * * * * ** **
* * ** ** ** * ****** * **** *** * *
** * ** *** * ** ***** * * * * ** * **** * *** **
* **** * * ***** *** *** * **** ** **
****** * **** ** * * **** * ** i;

}



int check2(char c)

{
* ****** * ** *** ** * j=0;
*** * ** * *** * * ** ***** **** ***** *
* ** * ** * *** ** ** * * *
***** ** * * * ** **** * *** ******* * *
* ** * * ** *** * * * ** * ** * * **
** ** ** **** * * j;

}

int main()

{
** ** * *** * * ** ** c;
*** * *** * * * ***** * *** i=0,j=0;
*** * **** * **** * ** * * * * * **

    
** * *** * **** * * * ** c!='.')
* * *** * ***** *** * *


* ** * * * * * * ** * * ** * * * * * * **
* * * **** **** ** * * ** * * ** * *** * *** * * *
****** * *** ** ** * * ** * * **** ** *** * *** ** ****
** * ***** * * *
* ** ** * **** *** * ** ** ***** ** * * * ** **** *** *** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** *** ** *
* * *** * ***

int main (void)
* *

char c;

int i = 0;

void ** c)

{
*** ***

i++;
* *

i++;
** ** **
**** ** * * * **** ******* ** * * *
* *** ******** * * ** * 0;

}
* ** ;

}
* * * * ** ** * *
* * ** * ****** * ** * * *
* ***

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
** * * * ** ** * * a1=0,a2=0,a3=0,a4=0,in;
* ** * *** * **** * ********* * *** && c[in];in++)

    {
* ** * *** * * ** * * * ** *** * * (48<=c[in] && c[in]<=57)
* ** ** *** ** * * * ** * *** ** ** *** *****
****** *** *** **** ** * * ****** * * ******* * ** ** **** *** * ***
** * **** * ** * ** *** * ** ** * * ***
*** ****** * ** * * **** ** ** * * * * * if(65<=c[in] && c[in]<=90)
** **** ** *** * * ** * * *** * * * * *** * **** **
** * ***** ** * * * * * * *** * * * ** *** ******** ** ** ****
* * * * * * * ********* * * ** ** * * * * *
* ** ******* ***** * ** ** * * * *** * if (97<=c[in] && c[in]<=122)
* * * ** * **** **** *** ** * * **
*** * **** * ** ** ** ***** * * ********* * * **** *** * **** ** ** *** * *
* * * ***** ** ** * * * ** * * *** ** ** *
**** * * * * ** ** * ***** *** ** ** ** * * if(39<=c[in] && c[in]<=46)
** *** *** *** * ** ** ** * **** *
** * ** ***** * **** * * * * * * **** * ** ** * *** * **** * * * *
* ** **** * *** * * ** ** ** *** ** * ** *
*** *** * * ** * * ** * * * * * ** ** * *
** * ** ****** ** * * *** * * ** ** * * * ****
** ** * * * ** * *** ** ** ** * * * * ** * * * * * *** ***** * ** ***
* * ** * ******* * *** * * * * *** *** ** ** ** *
* * * * **** * * * * **
* * ** * **** *** * * * *** * *** ** * * ***

 }

 

 int main()

{
******** * * * *** ** c[100];
*** * * * ** * *
* * * *** * * * ** *** * **

    
***** * **** ********** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * * * * ** * **** i=0;
** * * * * ****** * * *****
** * * * ***** *** * ** *** * * * *
* * *** * * * * ** * ** * ***** ** * * **
** * * *** * *** * ** *** * ** *** ** ** *
* * **** ** * * * i;

}



int check2(char c)

{
*** ** * ** ** ** ** **** **** j=0;
* ** * * * * ** ***** ******* * **
* ** ** * * * * ** ***** ** *** *
** ** ***** * **** * * ** ** * * ** ** ** *** * * *
** ** * * *** **** * * *** ** *** **
* * * * * * * ***** * ***** j;

}

int main()

{
* ** **** **** **** *** c;
** * * ** **** ** i=0,j=0;
**** *** ** * * * * * ***** ** * * * * *

    
** * *** ** * * ** **** c!='.')
* * **** * **** *


** ** *** ** * ** ** * * * *** * * * ***** *
* **** * ** * **** * ** *** *** *** ** **
* ** ** * * ** * **** * **** ** ** * ** ******** * *** * *
* *** *** * * ** * * *
* * * * * * * ** ** ** * * * * * ** ** *** ****** * * * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ****** * *** * * ** i=0;
* * * ** * * * ** *** * *
* *** * * ***** * *** * **
** * ** ** ******* * * * * *** * * * *** ** * * * ** * *
** ***** * ***** * *** ** *** * * *
***** ** * ** * *** i;

}



int check2(char c)

{
**** *** ** ** *** * ** j=0;
* *** * **** ** ******** ** ** ** *****
* * *** **** * ** ** *** ** * ***
*** * **** * *** ** * ** * * **** * * *
* * * ***** ** *** ** * **** * *
* * ** **** **** * *** * j;

}

int main()

{
******** * ** ** *** c;
**** * ** ** *** * * i=0,j=0;
*** * *** ** ** *** * * * ** ****** ** **
* ****** * ***** ** * ****** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
** ** ** * ** ** ****
*** ** ****** **** *** **** * * * ** ** ** **** *** **** *** **
* ** ** * * ******
* * * ** ** ** *** c!='.')
* ** ** * ** *** *


* * * * * *** ** ** ** * * ** *** ** * ** **
* **** ** **** * *** ** * * * ** **** * *
*** * * ** * ** * *** **** ** ** * **** ** * ** **** * ****** * **** *
* * * ** ** ***** ** * *
** * ** ** *** ** ** * * * * * ** * * * * * * * ** ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** *** * * * *
** * * * ****** * ** *

int main ****
*

char c;

int i = 0;

void * c)

{
* ** *

**

**** ** ** * * **
*** ** * * * * ** * * *** 0;

}
** * ;

}
* *** *** * * * ** *** *******
*

}
** ** ** ** **** * *
* * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* ** * * * * ****** * ***** * c;


** ** ** * * ***** **** i = 0,b = 0;


* **** *** ** *** * ** * * * ** ** &c);
** * ***** ** ****** * c != '.')
* ** * * * * *** * * ** ***
* * * *** ***** * ** * ***** ** *** ** ** ** *






* ** ** * * **** *** ** ** * ** ** * * *** ** ** += 1;


*** *** * ** ***** ** * * ** * * * * **** ****** * **** &c);
* *** * * ** * ** ** *** **** * ***** ***
* ** * *** * * * ** ** ***** * ** ** ** ***


* * * * * *** ** ** * ** ** * * * * i);


* ** * ** * ** *** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
** ** ** * * * * ** **
*** * * * * *
main ***
****
c;

int i = 0;
* ***** c)

{
* * **
*
* * *
*** *
*** ;

}
* *** **** ** ** ** ** ** *****
**

}








* *** * ** * *
0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** * **** * *** ** i=0;
** * ** **** **** **** * ******
* ** * *** **** * * ** ** *** ** ***
* * * *** **** ** * * * ** * * ** *** * * * ** *
**** * * ** * * * * * * *** *
**** * *** * ** **** ** * i;

}



int check2(char c)

{
* * * * ** ******** j=0;
**** * ** ** ** ** *
* * **** *** ** * * * **** ** ** * *** *
***** ** * ******* ** * ****** * * * * * * * * ** * *
** ******* * * **** *** ** ** * *
* * * * * ** *** * ** ** j;

}

int main(void)

{
** *** * * **** * c;
* * * ** * * * i=0,j=0;
*** ** ** ** *** * *** ** * ** *** ** * ****
*** * **** * *** * c!='.')
** ** ***** ** * * *****


* ** * ***** * ** ** * **** * * ** ***** ** * **
** * ** * * ** *** ** ** * * ***** *
* * ** **** * * ** *** * * * ***** * ** ** * ** * * ** *

    }
***** * **** * ** **** *** ***** *** ** * ****** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ** * * ** ***
* ****** * * * **

int main
* ** ***
* * c ;

int i = 0;
*** *** * * * * * * **** ** * **
**** *


*** * *** c)

{
* ** *
* *
* *********
*
* ;

}




** *** ** ** * ** * *
* * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 7.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users