0 like 0 dislike
3.5k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.5k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ***** ***** ** * *** i=0;
** ** *** ** * *** * **
* * ** ** ****** ***** * * * ** *
****** *** * * * ** * ********* * ** * *** ***
* * * ** ** * ** ** ** *** *
***** ** * * ** * * ** i;

}



int check2(char c)

{
* * ** * **** *** * ** j=0;
***** * * ** ** ** * ****
** *** *** * ** * **** * *** **** * * ** *
** **** *** ** ** * *** *** * * ** *** * * ** * *
** * * * * ** * * * * * *
** * ** * * *** ** * j;

}

int main()

{
* ***** * * * * c;
*** ***** **** ** * ** * i=0,j=0;
** ***** ** * * * * ** *** *** * ** * *

    
** ** * * *** ** **** * c!='.')
* **** **** * *


***** * ** * * * * ** * *** ** ** * * *
* * * *** ** * * * ***** *** ** * *
* * ** * *** * ****** * ** * * ** ** * * * * * * **** *** ** ** **
* * * ***** ** *
* **** * **** *** ** ** ***** ** ** * ** *** **** * * **** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * *** ** ***** **
* **** *** * **

int main (void)
** *

char c;

int i = 0;

void ** *** c)

{
** *

i++;
** ** * *

i++;
****** **** **
** * * *** ** * *** * ** ** ** *
* ** *** ** ** * * * * 0;

}
* * ;

}
*** * *** * * ** **
* ******* *** ** ** ** * *
* ***

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
** *** * * * * *** * a1=0,a2=0,a3=0,a4=0,in;
*** ***** * ** ** * && c[in];in++)

    {
* * *** * * ***** * **** ** *** ******* * (48<=c[in] && c[in]<=57)
* *** * * ** * ** ** * * *** * *** ***
** * ** ******** * *** ** * **** ****** * * * * * *** ****** ** * *
******** *** * ** * *** * **** *** *** **
* * * * * * * * ** *** * * ** * * * *** * if(65<=c[in] && c[in]<=90)
* * * *** * * *** * * ** * **** ** *
** * * * * ** * * * ** *** * *** ** * * * * * * * *
* *** **** **** ***** * *** * * * * * **
* ** * * * *** * ** * * * * ***** if (97<=c[in] && c[in]<=122)
* * ****** ****** ** *** ** **** ** *** * * ***
* * ** * * ** ** ** ** * * ** **** ****** * * ** ** * ** ****** * * *
***** * * ** * * * ** *** **** * ** ** * * * *
**** * ******** ** * * * **** ** * * if(39<=c[in] && c[in]<=46)
* * ******* * *** * ** **** **** **** ***
** ** ** * ** ** ******** * * * ***** * * * * ***** * * * ** ***** * * * * **
**** *** * * ****** * ** * * * *** * ** ** *
** **** * * ** ***** ** * *** *** ** ** * *
* *** **** * * ** * ****** * * ** * * * *
*** **** * ** * * *** * ** ** ** * * ** *** * * ** *** * ** * ** * ** * ****
*** ** * * * ** ** * ** *** * *** ** ***
* * * * **** * ** * ** *
* * * * ** ** * * ** * * * ******* * ** ** * ** * ******

 }

 

 int main()

{
** ** ** *** *** c[100];
* * *** * ** ** * **
*** * ** **** **** *********

    
* * * * *** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * *** * ** ** * * * ** i=0;
* * * *** ** ** **** * * * ** *
** * * *** *** * * ** * * ** *
***** ** ** ** * * * **** *** * ** ****** ******
**** * *** * * ** * ** *** *** * ** * * ***
** * * ** *** * * ** i;

}



int check2(char c)

{
* ** * * * * * ** j=0;
* *** * * ** * * ** ***
* ** ** * * ************ * * **
* * * * * *** ** * ****** * * *** *** *** **
****** ** ** * **** * ***** *
** * ******** * * * * **** * j;

}

int main()

{
*** * *** ***** *** ** * c;
** *** * *** **** i=0,j=0;
* * ****** *** * * * * ** * ** ** **** * * *

    
** * *** * * * ** **** ** c!='.')
********** * **** *** **


* ** ** * * *** *** **** * ** * ** * * **
** * * * *** * * * *** ** ** *** *** * * ***
* *** * * * * *** ****** *** **** * * * * **** * ****** * **
* * * * ** * * ** ** ***
* * ** * ** * * ** **** * ***** * * *** *** ** * **** *** ** * * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * ** *** * * *** i=0;
** * * * **** *** *** * *
* * * * **** *** ** * * ** ****** ** *
*** *** * ** **** * *** *** * * * * ** *** *
******* *** ** * * ** * * * * *******
** * **** ** ** *** i;

}



int check2(char c)

{
* * **** ****** ** j=0;
*** * **** ** ** *** * * ** **
* * * ** ** ****** * * *** ** * ***
* * * *** * * * * * ** * ** * **** * * *
* ** * * * * ****** * * * ** * *** **
* *** ** * ** *** *** j;

}

int main()

{
** * ** * * * *** ** * *** c;
*** **** * * ** * * i=0,j=0;
** ****** ***** * * * * * ** * * * * * * * *
* ** * * * ** * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
*** * ** ***** ** ***
** * * ** **** * ** * * ** * * * *** * *** * **** **
* ** ***** * *** *** * *
* ****** ** * ** *** c!='.')
*** * ** * * *** *


* ** * * ***** ** ** * ** * * * *
** *** * ** * * ** * ** ***
* *** ** * ****** **** * * ** ** * * * ** * ** * * ** *** * *
* * * ** * * * *
* ** * * ** *** * * *** ****** ** * * ** **** *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** *** * *** * *
* ** ***** * ** **

int main * *
* * *

char c;

int i = 0;

void ** * c)

{
**** **
*
* **
**
**** * *** *
**** *** * **** * * ** * 0;

}
***** ;

}
** **** * ** ****** * ** * *****
** *

}
* * ** * **
0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
*** * **** * * * * * **** ** c;


* * * * * * * ** * i = 0,b = 0;


* ** * ** *** *** * *** * ****** &c);
* * * *** ** * * **** c != '.')
** * * *** ***** **** * *
*** * * *** ** ** * * ** *** ** * ******* **






** *** ** * * * * ** ***** * ** **** * += 1;


* * * * * ** *** ** * ***** * * ** * * * ** * *** ** * * * &c);
* * * ** *** * * *** ********* *** *
* ***** * ** * * ** * * **** * **** *****


* * *** * * * * **** * * * * i);


** ** * * ** * ** * * ** * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* * *** ***** ** * *
* **** ** **
**** main **
*** **
*** c;

int i = 0;
* * c)

{
*** *
****
** *** **
**
** ;

}
* ** ** ** * * *** ** * **
* ***

}








* * *** ** * * ****
** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * * *** * ** * ****** i=0;
*** *** * ** **** * **** *****
*** ** * * * * * ****** *** * **
* * **** **** **** * * ** *** * ** *** * * * * ** **
* ** * * * ****** * ** * ** * * * * *
*** ** **** * * * * * * * i;

}



int check2(char c)

{
*** ***** * * ** ** * j=0;
* * * ** * * * **** **** ** ** ***
* *** ** **** ** * ** * **** ***** * *
* *** ** *** * * ** **** *
* ** *** * ** * * * ****** ** * * ** ** ***
** *** ** * ****** ** *** ****** j;

}

int main(void)

{
** **** ** ** ** ** c;
*** *** ** * *** * ** i=0,j=0;
* * **** * * * ** **** **** ** *** * * * *
** * * *** * *** * *** ** * c!='.')
* * * * **** * *** * * ***


*** ** * **** * * * ** * * * ** ** **
* ** ** ** * ** * *** * *** ***** * *** ** *** * *
* * * * *** *** ** * * ** *** * * * * * * *

    }
** * * * * * *** ** **** * ** ** *** * * * ** * * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * **** *
** *** * *** ** ** *

int main ** *
** *
* c ;

int i = 0;
** *** * ** * * *** ** * * **
*** * ***


** * ** * * c)

{
** **

* *** ****
*
* ** ;

}




* * * * ** * *
* 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.193
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 959 views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users