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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 14k views

53 Answers

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Hidden content!
#include <stdio.h>

int main(){
*** * *** * ** ***** * * str[500];
* ** * * * *** ** * *** *** sizeof(str), stdin);
* * *** ** * * **** ** i=0;
* * ** **** **** ** *** d=0,a=0,o=0;
* * ** * **** * ***** ** *** **
*** *** * *** * * ***** * *** * * * ** *** ** **** * * * ****** * * **** d++;
****** ** * * * * ** * * *** * * ** ** * *** ** * * ** ***** * *** * * * * **** ***** ***** ** *** *** * ***** a++;
* ** * * * ***** * * ** ** * * * **** ***** **** o++;
* * * * ***** **** * * * * *** * * ** ***
    }

* * *** ** ** ** *** ** *** * * * * ** **** * ***

* * *** **** ** ** * ***** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** * * ** * *** * str[500];
* ** ** ** ******** * * * sizeof(str), stdin);
* * *** * * ** ** i=0;
* **** * * * * *** *** * ** d=0,a=0,o=0;
* ** * ** * *** ** *
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** *** *** * * * * * **** ** o++;
* * ** * * * ***** * *** *** ** *** **
    }

* * ** ** * ** * *** **** ** * * * * * * **** // remove enter count

*** **** * ** ** * ***** *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ***** * **** ***
#include * * * * *

int main()
{
* **** * * * * * * ** **** A[1000];
** * * * *** i, digit=0, ** other=0;
**** * * * **** * 1000, stdin);

* * * * * * *** **** **** i++)
* * * *** * * ****
* * ******* **** * ** **** * * **** ** * >= '0' * * * *** **** A[i] <= '9')
* ** ** * ** **** *** * * **** * ******** * *** * * * ** ** **** ** = digit + 1;
** ** * ******* * * * * * ** **** *** *** **** **** if((A[i] >= 65 * ** * A[i] <= 90) || (A[i] >= 97 * * ** A[i] <= 122))
*** * * ** * * * * ** * * * *** *** * ** * * ** * * * * *** * * ***** * ** = alphabet + 1;
* **** * * * * * * * ** ** * ** ** * * * *** * if(A[i] > 31)
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*** ** ** * ** * ** *

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** * *** ** * ** **** * * * * ******* ** ** * alphabet);
** * ******* ** *** **** * * ** * ** ** other);

** * * * * ** * * * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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