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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
**** * * * * ***** **** str[500];
*** ** * *** **** * * * * *** sizeof(str), stdin);
** * * ** * * * i=0;
* ** ** * ***** d=0,a=0,o=0;
* ***** ** ** * ** * ** * * **
* * * * * ** * * * **** * *** * *** * * * *** ** * ** * * * * ** * d++;
* * ** ****** * * ** * * * ****** ** *** **** *** * * * *** * * * * *** * ** * * * * * * ********** * * * a++;
* * * * * ** *** ** **** * * ** * * *** ***** * o++;
* ** **** * *** ** * * *** ** * * * * *** * **
    }

** *** ** * **** * * * *** * * * **** ** *** ** *****

*** **** * ** * **** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** * *** * * ** ** * ** * str[500];
* ** ** ** * ** * ** * * * sizeof(str), stdin);
*** * * ** * ** * *** i=0;
*** ** ** *** * * d=0,a=0,o=0;
* * * ** *** * ** * * ** *
* ***** * ** * ** ** ***** ** **** * **** ***** ** ** ** **** *** * ** * d++;
* **** ** * * * * * ***** * * * * ** ** * * * * ** *** * * * * * * ****** * * * ** ** *** * * * ** * * * ** a++;
**** * * **** * * **** * **** ***** * ** * * o++;
** * * ** * * * * * ** **** ** ** ** * *
    }

* * **** * *** * * ** * ** * * * ** * * ** * * * **** // remove enter count

***** ** **** * ** *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** * ***
#include * * ** * ***

int main()
{
* ** ** ** * ****** A[1000];
** ** * * * * * * * i, digit=0, ** *** other=0;
* ** * **** **** * * ** 1000, stdin);

* ** ** * ** * ** * * **** ** i++)
*** * *** ** ** *
** * ** * * * ** * * * **** *** * * ** * * * >= '0' * ** * * A[i] <= '9')
** * * ** * * ***** * *** ***** ** * * **** ***** ** * ** ** ****** = digit + 1;
* *** ** * ** * * * ** * * * *** if((A[i] >= 65 * *** * * ** A[i] <= 90) || (A[i] >= 97 ** ****** * A[i] <= 122))
** * *** * * ** *** *** ** * *** * * * * *** ** * * * ** = alphabet + 1;
* * * * *** * ** * *** ** ** ***** * ** * if(A[i] > 31)
** * * * * * ****** *** * * * * * * * * **** * ** ******* * = other +1;
* *** * *** * **** *** *

* *** *** * * * **** * ** ** ** * * * * digit);
** * * ********* * * * *** * *** ***** * *** * alphabet);
* * * ** * * * *** * ** * ** ** *** * other);

** * * ***** *** ** ** 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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