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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* ** * * * * **** str[500];
*** **** ***** *** * * * * * sizeof(str), stdin);
** ******** ** *** * i=0;
* ** * * **** d=0,a=0,o=0;
* **** * ** ** * **** **
** **** *** ** * * **** * *** * * * * * ** *** ********* *** ** ** ** ** * * d++;
** ** ** **** ** *** * ** * * * * * * ** * * * * ** *** * * ** *** * ** ** ** ***** ** ** *** *** * ** ** a++;
* *** ** * * * * * *** * * **** *** o++;
* *** * ******** **** * * * * ** ***
    }

* * **** * * ***** ****** **** ** *** * * * * *** * **

* ** * * * * ** *** * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** * * ** ** **** ** **** str[500];
** * ** * ** ******** * sizeof(str), stdin);
* * ***** * ** * i=0;
** ** **** * ** d=0,a=0,o=0;
* * ** *** * * ** * ******* ****
* ** ** ***** *** * ***** ** **** * **** *** * * ** * * *** **** * ** ****** * d++;
*** * **** * * * * *** ** *** ** * **** * * ***** * * *** **** * ** * * * *** * ** * * *** * * ****** *** a++;
*** * *** ** ** * ** * ** **** **** * * * *** *** o++;
**** ** * * ** ******* *** ***** * ** * *****
    }

* ** *** * * ** * ** * * ** *** * **** * ** * * * // remove enter count

** **** * * ** **** ***** ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ********* ** **
#include *** * ** **

int main()
{
** * *** *** ***** * ** A[1000];
** * *** * **** *** i, digit=0, ** * other=0;
** * * * * ** * * * 1000, stdin);

**** ** * ** *** ** * * ** ** i++)
*** * ** ***** **
***** * * ** ** *** ** ***** ** ******** ** * * >= '0' * *** **** ** A[i] <= '9')
* ****** * ** ** ** * * ** * **** ***** * **** ***** *** * ** ** ** = digit + 1;
** **** ** ***** * * * **** ** ***** *** * * if((A[i] >= 65 *** A[i] <= 90) || (A[i] >= 97 * ******* A[i] <= 122))
** * ** *** * * * ** ** *** * * *** ** ***** ** * ** * * * ** ** * ** = alphabet + 1;
* * * * *** *** * *** ****** *** ** * if(A[i] > 31)
* ** ** ** ** ***** * *** * * ***** * * *** * ***** **** * = other +1;
* **** * *** * * * *

* * ** * * * * * ** ******* * * * *** digit);
** **** ** * ** ** **** * * *** * ***** ** alphabet);
* * *** * **** * ** ** * ** * ** * * other);

*** *** *** * * ** * * * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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