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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 14.4k views

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Hidden content!
#include <stdio.h>

int main(){
* * * ** * ***** **** ** str[500];
* ** * *** * *** sizeof(str), stdin);
** * ** *** ** * * ** i=0;
* ** * * ** ***** * d=0,a=0,o=0;
*** ** * **** *** * * * ** ** * *
* * ** ******* ** * **** * ** * * * * *** * ** * * **** ******** *** d++;
** *** ** * *** * ** ** * * *** * *** *** ** *** * * * *** **** * ** ** *** **** **** * ****** * a++;
*** ***** * ** *** * * ** ** * * * ***** * o++;
* ** ** ** ** * * **** * * *** * ** ***** ** **
    }

* ** ** ** * * *** *** ** ** * * *** * ** ** **** * *

* * * * * ** ******** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** ****** * * ** **** str[500];
*** ** **** * * *** ** ** sizeof(str), stdin);
* ** * * ** *** i=0;
*** * * * * ** * * ***** d=0,a=0,o=0;
** ***** *** * ****** ** * ** *
* * * * * *** * ****** * * ****** ** ** * * * ** * * *** * * *** d++;
** * * * * ****** * * **** * ** * * ** ***** * ** *** * *** ** * *** **** * ******* ** * * ** a++;
* * * ** * ** ** * * * ** **** *** * o++;
* ** * * * * ** * * ** * * * *** *** * * * * * *
    }

** * ** * *** * *** * * ******* * **** ** * * *** * * * ***** // remove enter count

* *** ** * * ****** *** ** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include *** * ******
#include *** ** ** *

int main()
{
* * ** * **** **** * * *** A[1000];
* * * ***** * ** * ** * i, digit=0, **** * other=0;
* * * * * * * **** ** 1000, stdin);

*** * * ***** **** ** ** ** **** i++)
*** **** ***** ** * * * * *
** * ***** ** * ** * * * * *** ** * * ** ** * >= '0' * ** * * A[i] <= '9')
** ** ** * ** * ** ** ** ** * * * ** * * *** * * * **** ** * * *** = digit + 1;
* * * *** ** * *** * ***** * ** *** *** if((A[i] >= 65 ****** ** A[i] <= 90) || (A[i] >= 97 ** *** * A[i] <= 122))
** * * * * **** *** ** *** * ** **** * * **** ** ** *** ** **** * = alphabet + 1;
** ** * * ** ** ** * ****** * * * * * ** * * if(A[i] > 31)
********* *** * * ** * ** * * ** * * * ** * ** ****** ***** * ** ** **** = other +1;
*** ** *** * * *

* ** * **** *** ** **** **** ** * * **** ** digit);
* *** ** ** * ** * * ***** **** ** * alphabet);
* ****** * * ** ** **** * ***** * other);

* ** *** * * ******** * ** ** 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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