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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* ** ** * * * *** str[500];
** ** ** ** ** * * * ** * * * sizeof(str), stdin);
*** * * ** * * * i=0;
* **** * ** ***** ** * * d=0,a=0,o=0;
* * ** * * * * ** ***** ** *
* *** * * *** * ** * * ********* ** ** * * ** ** * ** * * * **** ** * * * d++;
** ** **** *** * ** ** ** *** ***** * ** *** ** * * *** **** *** * * * ** * * * * * ** ** * *** ** *** a++;
**** * ** *** *** * ** **** * * *** * * * o++;
***** * ****** * *** * ** ** * ** * * * * * * *
    }

* ** * * ** ** *** **** **** ** * * ** * * ** ** ** ** *

** * * * *** **** ** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * * * ** ** *** *** ** str[500];
* ***** * * * **** ** ** sizeof(str), stdin);
* * ** ** * ** i=0;
* ** * * ** * * * d=0,a=0,o=0;
*** ** * * * ** ******* *** * ** **
* * ** ***** ** ***** ** * * **** ** * * *** * ** *** **** *** ** * * d++;
*** * * ** * * * * *** ****** * ** * ** * * * * * * * ** ** ** ** * * *** ** * *** ** ** * **** ** ** ** a++;
** * ** ***** * ** * * * ***** ** *** ***** o++;
*** **** * * * ** * ** *** ** * * * ******* *
    }

* * ** ** * ** ** ** ** *** ** **** * * * * * ******* // remove enter count

** ****** ** * * ** 0;
}
answered by (-116 points)
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Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** ** ** * *
#include * * * * * **** *

int main()
{
* ** **** ** * * ***** A[1000];
*** *** ** * * * ** * i, digit=0, ** * other=0;
*** ** ** * ** * * ***** * 1000, stdin);

* * *** * ** * ** ** *** ** **** * i++)
* * * **** ** ** ***
*** * ****** * *** * ** *** ** * * *** * ** * * * ** * >= '0' * * **** A[i] <= '9')
* * * * **** ** ** **** * *** ** * * * * ****** ** * ** ** = digit + 1;
* * * ** * ** ** *** ** *** ** ** * ** * if((A[i] >= 65 ** ** ** A[i] <= 90) || (A[i] >= 97 ** ** *** A[i] <= 122))
* ** ** * ** * **** * ** *** ** * *** ** *** * ** * ***** * = alphabet + 1;
******* * * *** * * * * ****** *** * * * * * *** if(A[i] > 31)
*** ** * * * * ** *** * ** * * ** **** *** * * ** * = other +1;
* * * * ** *

* ***** * ** * * *** * *** * ** * digit);
**** * **** *** * * * * * * * * * * **** alphabet);
****** ***** ** *** * ***** * * * ** * ** ** ** other);

* * ** ** ** * * * ** 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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