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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
*** * * * ** ** **** str[500];
* **** ***** * * * sizeof(str), stdin);
** * ******* ** ***** i=0;
******* * ** * *** ** d=0,a=0,o=0;
*** *** *** * * * ** * *
* * *** ** * * ****** * * **** ** * ** * * ** ** * ***** * * ***** * *** ***** d++;
**** ** * **** *** *** * **** ** ** * * *** * * *** * * * ** ** * ****** **** *** ** **** * * * ** **** *** a++;
* ** * ** * ** * * ** * * *** * * * ** * * * ** o++;
**** ** *** * ** ** * * ******** **** *
    }

*** ** *** * * * * * * * ** * * *** ** *** *** ** *

**** **** ** ** * ** ** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** * * * ** ******* * * * str[500];
**** * * * * * ** **** sizeof(str), stdin);
* *** ** ** * * *** *** i=0;
* ***** *** ** * * d=0,a=0,o=0;
***** * * ** *** **** * * ***
*** * ***** * * * *** * **** ** ** *** *** ** * ** * *** ***** ******** d++;
** * * * * ** * ** * ****** ***** ** * ***** * * ** *** ***** * ** * * ** * ** *** ***** *** * *** ****** a++;
* ** **** ** * ** *** * **** ******** ****** ** o++;
* * * * * * * ** * ** **** * * * **** ***
    }

* ** * * * *** *** ***** *** * * * * * ** ********* * * // remove enter count

****** ** * **** * * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** ** **** * * *
#include * ** *** * *

int main()
{
******* ****** ** * *** A[1000];
* ** ** **** *** ** *** i, digit=0, **** other=0;
** ** ** * *** * ******** * * 1000, stdin);

****** **** * **** * * * * *** ** i++)
* *** * ** ** * ** *****
**** * *** *********** * * *** * * ** * * >= '0' * * ****** A[i] <= '9')
* ** * * ** ** ******** **** ** ******* * * *** * * ** * * * * * **** *** *** = digit + 1;
*** * *** * ** ******* ** * ** * ** * **** ** * if((A[i] >= 65 ***** * * A[i] <= 90) || (A[i] >= 97 * * ** * A[i] <= 122))
*** * ** * ***** * * * * * ** ****** ** ** * ** ** * **** * * * = alphabet + 1;
** ******* * * ** ** * ** *** * * ** ** ** if(A[i] > 31)
***** ** ** ** ** ** ** * * * **** * * * * *** ** * * * = other +1;
* ** ** ** **** ****

* * * ** * ***** *** ** *** * * ** * * * ** * *** * digit);
* * **** ** ** ***** * ** * * *** * * *** alphabet);
* ** * ** * **** ** *** other);

* *** **** **** ** ***** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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