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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 18.6k views

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Hidden content!
#include <stdio.h>

int main(){
* * * *** * ** ** **** *** str[500];
** * * * * * * * * **** *** sizeof(str), stdin);
* ** * * * * ** * i=0;
* * * * *** ** * ***** d=0,a=0,o=0;
*** ** ** *** ** * * * ****
* * * * **** * * * * ** * **** ***** * **** * ** * * * ** * *** * * d++;
* * * **** * ** ** * * * ** * * ** ** ** * ** * ** * * **** ** *** ** * * ** **** ** ** * ** ** ** * a++;
** ** ** * ** ** * ** * * * * * * o++;
* ** *** ** ** ** * * *** * *** ** ** ** *** *
    }

* ** ****** ** * * * * *** *** * * * *** * *** *

** *** **** * * * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
*** ****** * ** ** *** *** str[500];
*** * * **** * * sizeof(str), stdin);
* * * * *** *** ** * * i=0;
** * **** * * ** d=0,a=0,o=0;
* ** * * * * * ** *** * ** ** ** ***
** * * ** ** ** * * * ** * ** *** ** * ** * * **** * ** * d++;
* * * * * * ** * * * **** * * *** * * ** ** ***** * ***** * ** ***** *** * ** ** ** ***** * * * **** * **** * ** ** * a++;
* * ** **** * ** * ** ** ** ** * * * * * ** ** * o++;
** * ** * *** ** ** ** *** * * * **** ** *** ***
    }

* * * *** * * * * *** ** ** ** * * // remove enter count

*** * * * ** * * * * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include *** * * ***
#include **** ** * *

int main()
{
** **** * * ** * * ** A[1000];
* **** * * *** * * * * * i, digit=0, * ** ** other=0;
* **** **** ** * * * ** ** 1000, stdin);

** ******* * * * ** **** ** ** * * *** i++)
* **** * **
* * ** * * * * ** *** * * * ** *** * * >= '0' **** ** * * A[i] <= '9')
** *** ** ** ** * * * * ***** * * * **** ** * * ** **** = digit + 1;
* * * * * ** *** * **** **** ** ** if((A[i] >= 65 * * * * * * A[i] <= 90) || (A[i] >= 97 * * * A[i] <= 122))
* ** **** * * ** ** *** ** * ** * * * *** *** ** **** * *** * *** * * = alphabet + 1;
* *** * * * ** * ** *** **** *** ** * ** * * if(A[i] > 31)
* * * ** ** ** *** *** * * ** * * ** ** ** *** * * ** ** *** * = other +1;
***** * *** * * ***

********* * * *** ** ** * ** * * *** * * * digit);
** * * ** ** * ** ******** ** ** ****** * alphabet);
* *** *** * * ** **** * * * * *** * other);

**** *** * ** **** ** * * * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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