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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* * *** ** ** * * ** * str[500];
** ** ** * * * ** ** * * * sizeof(str), stdin);
**** ****** ** * ***** * * * i=0;
* * * * ** * ***** * * * d=0,a=0,o=0;
* ** * * * * * * * ** ***
* * * **** **** ** * * ***** **** * * * *** ** ** ** *** * ** ** **** d++;
* ***** * * ** ****** ** ***** ** * * * * * * * * ** ***** * ** * * * *** ****** *** ** * * **** *** * * a++;
* ** * ** * ** * *** * * *** ** * *** ** o++;
* *** ****** ** * * * * ** ** * ** * ** ** ** *
    }

** * * * * * ** * *** * * *** **** * ***** ******* * **

** **** *** ** ** * * *** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
****** * * * * * * str[500];
** **** ** * * * *** ** sizeof(str), stdin);
* ****** ** **** **** i=0;
* *** ** **** * * * d=0,a=0,o=0;
** ** * ** ** ** ** * ** ***** *
* **** * * * * * * *** * * **** **** * * *** * * ** * * **** * **** d++;
* * ** * * * * * **** * * * ** *** * * *** * * *** *** * * **** * * * * ** ***** * ****** * * ** a++;
* *** * *** * **** * * * ** ** ***** * o++;
** *** * ** * **** ** * * * * * * * * * ** * * **
    }

* * * * * * * * ** ***** * * * * ** * **** **** * * // remove enter count

** *** ** * * ** **** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include *** * * *
#include **** * * *

int main()
{
* ** ** ** * ***** * * ** A[1000];
** * * ** ** *** ****** * i, digit=0, * * ** other=0;
* *** * * ***** 1000, stdin);

** * * ** ** * ** **** ** *** i++)
**** **** * *** ** ****
* **** * * * ** *** * * * * * * * ** *** ** ****** * >= '0' ** ** * * A[i] <= '9')
* * ** * ** **** * * ** *** *** *** * * * ** ** ***** * * = digit + 1;
** ** * ** * * * * * *** * * **** * ** * if((A[i] >= 65 ** ** * A[i] <= 90) || (A[i] >= 97 **** ** A[i] <= 122))
** * ** * * * ** **** *** * ** ** *** *** * **** **** ** = alphabet + 1;
* **** *** * * *** * ** * ** * * * if(A[i] > 31)
** ** * ****** **** *** * ** * ** ** * * ******** * * *** ****** = other +1;
* * * * * *** *** * *

*** *** ****** * * *** ** ***** ** *** ** digit);
** * ******* ** * * ** * ****** * ** * * * ** * alphabet);
*** **** * ** ****** * ** * * * *** * * other);

**** ** ** * * *** ** * ** *** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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