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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 16.3k views

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Hidden content!
#include <stdio.h>

int main(){
** * * **** * ** ** * * ** ** str[500];
* * **** * * * * * sizeof(str), stdin);
*** ***** ** **** ** * i=0;
** ** ** ** * *** * d=0,a=0,o=0;
* ** ** **** *** * * *
** ***** **** ** * * * * * ** **** * ** ** * ** ** * ** * d++;
* * * **** * * * * * * * ** * *** * ** ***** * ** *** * **** ******* * ** *** * ** ** * * ** ** *** *** * * a++;
* ***** ** * ***** *** * * * *** * ** ** o++;
** *** * ** * ** * *** *** * ******* ** *****
    }

* * * * * *** **** * * ** ** **** * *** * ** * **

* * **** ** * *** *** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* **** * * ** ** *** *** *** str[500];
** *** * * * *** *** sizeof(str), stdin);
* * * *** *** ** *** * *** i=0;
* * *** * * * * d=0,a=0,o=0;
**** * * ** *** * **** * *** **
** * * **** ****** * ***** * ** * ***** * ** ***** * * * *** * * *** * * * d++;
* * * * ***** * ** ** ** * * * * ** * ** ** * *** ** * * * **** * * * * ** * * * *** * * *** *** a++;
* ** * * ** * ** * *** * ** * ****** * ** o++;
** *** *** * * * *** * * * * * * ** *** **
    }

* ******** **** ***** **** * * ** * ********* * ** *** * * // remove enter count

** *** ** * *** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ***** ** *****
#include *** * * *

int main()
{
* * ** * * * * * * A[1000];
****** * * * * **** * * * * i, digit=0, * **** other=0;
* ** **** * ** * * ** * 1000, stdin);

* * ** * ** * ** * * * ** i++)
** * **** * *****
*********** * ***** ****** ** * ** * * ** * * * >= '0' * * * A[i] <= '9')
** ** ** ** ***** * ** *** * *** * * * **** * * * **** *** = digit + 1;
** ** *** * *** * * * ** * **** *** * *** *** * * if((A[i] >= 65 ** ** A[i] <= 90) || (A[i] >= 97 ** **** * A[i] <= 122))
* * * * * * *** *** ** * * **** ** * * * ** * * * * ** * **** ** * * * ** = alphabet + 1;
** * ** ***** ** * ** **** * * * ***** * if(A[i] > 31)
* * * *** * * * * * * ** * *** * ** * * * *** ** * *** * ** = other +1;
** * * ***** * *

* * * *** *** *** * ** * ** * * digit);
**** * ** *** * * ****** *** ** *** * ** ** * alphabet);
* **** ** **** *** * ** * * * *** other);

* * **** *** * ** * **** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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