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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* ***** *** * * **** * str[500];
* * *** * * **** * * ** sizeof(str), stdin);
* *** * *** * * i=0;
* * ***** ** * d=0,a=0,o=0;
** **** ** * * ** *** * *
* * * ** * **** ** ** * * * ** *** * * ** ** **** * ** * *** ** **** d++;
**** * *** * ***** ** * *** * * *** *** *** ******** * * * * * * * * * * * ** ***** *** * * ** ** *** * * * * **** * ** * a++;
* * * ** * * ** * ** *** * * ** * *** * o++;
** * * * *** * ***** * * *** ** * **** * *** * ***
    }

* * * *** * ** * * * * **** ** *** ** * **

* ** ***** * * ** * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * * * ** **** ** str[500];
* * * **** ** *** ** **** sizeof(str), stdin);
** ** ******* ** *** i=0;
**** ** ** ** ** *** d=0,a=0,o=0;
* * * *** * *** *** ** ** **
* * *** * ***** * * * **** ** * * ** * ******* ***** * * ** ** * * *** * * d++;
****** * ** * * *** ** * * * * **** * ** ** *** * * * * *** ** * ** * * * *** * **** ** ** * ** ** *** * * a++;
* **** ** * * **** ** ***** * ******* * o++;
** * *** * * *** **** ** ** * * *
    }

**** **** * *** * * * * * * **** * ** ** * *** // remove enter count

* * * *** * ** * ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * ** ***
#include ** ** * * **** *

int main()
{
*** * **** ****** *** ** *** A[1000];
* * * * *** ** * ** *** * * i, digit=0, ** other=0;
* * *** * ** * ** 1000, stdin);

** * ** * ** * ** * ***** * * *** ** * i++)
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* * ** **** *** * * * * * * * * * ** **** * * * * * * * * *** * * = digit + 1;
*** * * *** ** ** * * ** * ** *** * if((A[i] >= 65 * ** *** * A[i] <= 90) || (A[i] >= 97 * * ** A[i] <= 122))
* ** ** * * * * ** **** * * ** * * ** * ** * ** *** ** * ** * ** * * = alphabet + 1;
* * *** *** *** * **** * * **** *** * *** * ** * if(A[i] > 31)
**** *** * ** ** ** * * **** ** **** ** * * * * * **** = other +1;
** * **** * * ****

* *** ******* ** * ** *** ** ** * * ** * ** digit);
** **** ***** * * ** ** * **** ***** * * * alphabet);
** *** ** ** **** * * * * **** * * * **** other);

****** ** **** ** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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