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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* ***** * * *** ** ** * str[500];
* ** * ** ***** * * ** ** sizeof(str), stdin);
* ** ** **** **** * ** i=0;
* *** * ** * ** *** d=0,a=0,o=0;
* * * * ** * *** * ** ** * *****
** * *** ** ** * * * * * * ** *** ** * *** * ** * * ****** ** ** **** * * * ** ** * d++;
* * *** ** **** ** ** * ** *** **** * *** * ******* **** * ** ** ******* ** * * ** * * ** * * a++;
*** * * ** * * * * ** * **** * ** * * **** **** o++;
*** ** ** * ***** * **** * * * * **** * **** *
    }

* * * ** * ** * ** **** *** * * **** * **** * *

**** * *** ** *** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
*** ** * * *** * ** * str[500];
* ** ** * * ******** * ** sizeof(str), stdin);
** ** * * * *** * ** * * * i=0;
* ** ** ** * *** * d=0,a=0,o=0;
* ***** * ** * * * ** * * *
*** * ** * ** * ****** *** * * ** * * * *** * * * *** * ***** *** ** * d++;
** * * ***** *** ** ** * *** **** * * *** * * ** * ** ** * * ** ****** *** * ** * *** * *** ****** * * a++;
* ** * * **** *** * * *** * * * ** * * ** o++;
** * ** * *** * * ***** * ***** ** * * * *** *
    }

****** *** * * * * * * * * ****** **** * *** * ** ***** * // remove enter count

* * ** * ***** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * *
#include * ** * * ** *

int main()
{
******** * **** * A[1000];
* * *** * *** * * * ** i, digit=0, ** ** *** other=0;
* ** ** ** * *** * ** 1000, stdin);

* * ** ** ** * * ****** * * **** i++)
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* * * * ******* ** ***** ***** * ** ** *** ****** ** >= '0' * * A[i] <= '9')
* * ** **** * * * ***** * * **** * ** * * *** ** ** ** ** * * = digit + 1;
** * * ** *** *** *** ** ** *** ***** ****** if((A[i] >= 65 * * ** ** A[i] <= 90) || (A[i] >= 97 * **** A[i] <= 122))
* ** * ** * ** * * ** ** ** *** ** ** * *** * * * * * * ** * ** ** = alphabet + 1;
** * *** * * ****** **** * * *** **** * * * * if(A[i] > 31)
*** ** *** * ** ** *** * ** ***** * *** *** * * * **** * * * ** = other +1;
* ** * * * ** *

* * * ** * * ** * *** * ** *** ** * digit);
* ** ** ** * * *** **** * ** ** * * ***** alphabet);
** ***** **** * ** ** * * * * ** * ** other);

*** * ** * *** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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