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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 5.3k views

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Hidden content!
#include <stdio.h>

int main(){
* *** * ** * *** *** **** str[500];
**** *** ** * * * * * sizeof(str), stdin);
* ** * * *** * *** i=0;
** ** * * * d=0,a=0,o=0;
* ** * * **** * ** * *** * *
* * * * * ** * * * * ** ** *** * * * ** ****** ** * ** *** ** * ***** * d++;
* ** * * * ** * * **** * * *** ** * * **** * *** * ** ** ** * * * * *** * * ****** * * ** ** * ** ** ** * a++;
* ** *** ** * * * ** * * * ** * * ***** *** o++;
* * * * * **** ** * ** **** * ******* * * * **
    }

* *** ** * * **** **** * * * * * * ** * * ***** *** ** * ** ***

** ** *** ** * * * * ** * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * ****** *** ** ** str[500];
* * ***** * * * ****** * sizeof(str), stdin);
** * *** * * **** ** i=0;
* ******* ******* d=0,a=0,o=0;
* ** * * * * * ****** ** * ** **** * *
* ** **** * * *** ** * * * ********* ** ** ** ***** ***** * ** ** ** d++;
** *** ** ** * * ** * ** * * * * *** * * ** * * *** * * ** * * * * ***** * **** ***** *** ** ** * * ** * a++;
*** * * * * * ****** ** **** *** * ** * * o++;
**** ***** **** * ** ** **** * ** ***** **
    }

* *** * * * ** * * **** * *** *** * * * * **** * // remove enter count

****** ** ** * 0;
}
answered by (-116 points)
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Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** *
#include * * ** *

int main()
{
* **** ** * * A[1000];
* * ** *** * *** * *** * * i, digit=0, **** other=0;
**** * * * ** * ** * * 1000, stdin);

* ** * * ** * * * * ***** * * ** ** i++)
****** **** ****** ** * **
* * * ** ** * ** ***** * * * **** ** ** *** ** ** * >= '0' *** * A[i] <= '9')
**** *********** * ** ** *** ** ** *** *** * ** ******** *** * = digit + 1;
* * *** * ** **** ** * *** * ***** ***** * * if((A[i] >= 65 ****** * A[i] <= 90) || (A[i] >= 97 *** ** *** A[i] <= 122))
*** ** * * ***** ******* ** *** * ** ** * * *** ** * ***** * ** * *** * * = alphabet + 1;
** ** * * **** * *** * ****** * * * * if(A[i] > 31)
* * ** **** ** * * * ** * * * **** ** ** * * ** ** * * *** * * ** * * = other +1;
** * * * * ** * ** * *

* * *** ** *** ** *** ****** ** ** * * * *** digit);
* * * * **** ** *** ** * * *** **** *** * * alphabet);
**** * ** ** * *** * * * * * ******* * other);

* ** * **** * *** * * * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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