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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* ** ** ** *** * * str[500];
****** ***** * * *** ** * ** * sizeof(str), stdin);
** * * * * * ** * ** ** i=0;
* * *** * *** ** ** * * d=0,a=0,o=0;
** ** ** ** * * ** * * * * *
* ** ** ** * * * *** * * *** * ***** * * * * * * ** * **** ** * *** d++;
* **** ** * * * * ** * * * * * * ** * * *** **** *** *** **** ** ********* * *** * * * * ** * a++;
*** **** ** * * ** * *** ** **** ** * *** o++;
** ** ** ** * ** ** *** *** * * *** * * **** * *
    }

** ** * ** ***** * ** ** * ** * * ** ***** * * ****** * *** * * ** **

* *** * ** ** * *** ** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
****** *** ** * * ** ** *** str[500];
* * * * * * *** * * * * ** sizeof(str), stdin);
**** * ** ** * ** i=0;
** * ** *** * **** *** d=0,a=0,o=0;
* *** ** * * * *** * * *
* * **** * ** * ***** * *** * * *** ****** * *** * * *** * ** **** * * * ** * * * ** * * d++;
** * *** * *** ** * * * * *** ** * ** * * * ** ** * ** ** *** *** *** ** ** ** * ********** *** * * * **** * * a++;
***** **** * ** * * ***** *** * * * ** *** o++;
** * *** *** * ** ***** * **** * **
    }

* ** * ** * **** ****** **** **** ** ******* * * ** * * * ** // remove enter count

* ****** *** * *** *** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** * * ** *
#include * ***** *

int main()
{
* * * * *** ***** **** A[1000];
* ***** ** * *** * i, digit=0, *** other=0;
** * ** * * ** *** * ** 1000, stdin);

***** * ** * **** ** *** * ** i++)
* *** * ****** * * ***
* * ** * ** ** *** ** * ****** * >= '0' * * * * * A[i] <= '9')
*** ** * ** ******* **** ** * * ***** * *** * ********** * ** * **** ** = digit + 1;
* *** * * * ** * * * ** * *** ** if((A[i] >= 65 * * * * A[i] <= 90) || (A[i] >= 97 *** *** ** A[i] <= 122))
*** * * *** ** *** * ** * ** ****** ** ** * ****** * * * * * ** ******* = alphabet + 1;
* * * * *** **** *** * ****** **** * * if(A[i] > 31)
** * * * * * * ** *** * ** * * * **** * * * * ** *** ** * = other +1;
* **** ** * ** *** ***

* ** * *** ** * * ** * ** * ***** **** * digit);
**** ****** * * **** * ** ** ** * ** alphabet);
* * ** * * *** * *** * * *** * *** * * other);

** * * ** *** ** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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