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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* *** ******* * * * str[500];
* * * ** * *** **** sizeof(str), stdin);
** *** **** *** * *** * * * i=0;
***** *** ** ** * * * * * d=0,a=0,o=0;
** *** ** *** ******* * * *** *
* ** * ** * * ** * * ** ***** * * * * ** * **** * ** ** * ** * * ******* * * * d++;
* * ***** * * ***** * * **** **** ** * ** * * * * * ** *** * **** * * * ****** *** ** * ** * **** a++;
* * * ** **** ** * * ** * * * * ** o++;
** * *** ** ****** * * ** * ** ** *** ** ** **** *
    }

* **** * * ** * * * * * ** * ** * * * *****

* ** *** * ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
*** ** ** * ** * ** * * ** str[500];
* * * * ** *** * ****** sizeof(str), stdin);
** * ** ** ** ***** * ** i=0;
** * * *** ** * * ** * d=0,a=0,o=0;
**** * * **** ****** * ** ** ** * *
*** * *** * * * * ******* ** ** ** **** *** ** ** ** * ***** * * d++;
* ** ** ** * ** * *** * ** ******* *** ** * * * * * * ** ** * ********* ***** ** *** *** * ** ***** * a++;
*** * * ** *** * * *** ** ** ****** * * * o++;
* *** ** ** ** ****** **** * **** ***
    }

* **** * * * ** **** *** * * * * **** *** * ** * // remove enter count

**** * * * * *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include *** * * * **
#include * ** ***** ***

int main()
{
** * **** * ** *** * ** A[1000];
* * ** *** *** *** * * i, digit=0, * *** other=0;
* **** * ****** *** ** 1000, stdin);

* * ** ** * * * * * * *** * * * i++)
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*** * * * * * * * ** ** * * ** * *** ** **** * * * * ** * ***** ** = digit + 1;
* ** * * *** * ** * * * *** ** * * * ****** if((A[i] >= 65 * ** * A[i] <= 90) || (A[i] >= 97 *** * * A[i] <= 122))
*** ***** * *** *** * * **** * ** *** ** *** * **** = alphabet + 1;
* * * *** ******* ** *** ** ** * *** ** * * **** if(A[i] > 31)
** * * * **** **** *** **** * * * * * ** *** ** * ** * * * * * * * = other +1;
** ** ** *** **

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* ** ** ** ** * * * *** * * ** * ** * * * alphabet);
* ** ** * * ***** ******* *** *** *** other);

** * **** ** * ** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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