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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* * * * * * ** * str[500];
** * * * ** ********* **** * * sizeof(str), stdin);
*** * *** * * *** * * **** i=0;
*** * * ** * * ** ** * ** d=0,a=0,o=0;
* *** * **** * * ** **** * *** * ** *
* ** * ** * **** *** ** ** * ** **** **** ** * ** ** * * * *** ** * d++;
* ** * * * *** *** * * ****** ** *** * *** ******** *** * ** * ** ** ** * ** * * **** * * ** *** a++;
*** * ******* ** * * ** *** * * * * o++;
*** * ** * **** * *** ** *** * ** * * * * *
    }

** ** * *** *** *** **** * ** ** * * ** * * * * ** * ***

*** ** ** ** ** * ****** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * **** ****** ** * * * str[500];
** * * * * * ** **** sizeof(str), stdin);
**** * * *** ** * * i=0;
* ***** *** * **** *** d=0,a=0,o=0;
** * ** **** *** ** * ** ******
* * ** * * * * * * * *** * * ** * *** * *** ***** ** ** ** ****** * *** * * * d++;
* * ** * * ** *** ** * ********* * ** * ***** ***** * ** ** * * ** **** * **** * * ** *** *** * * * a++;
* *** ***** * ****** ****** * ** * * *** * ** * * o++;
* * * ***** ** ** ** * *** * * *** * *** * **
    }

** * * ** * *** *** * * *** * ** * * ***** ** * ** * * * * // remove enter count

** ** * * * * **** ** **** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** ** ** ** *
#include ***** * * *

int main()
{
* * *** **** * ** ** A[1000];
* * * ** ** * **** i, digit=0, * * other=0;
* **** * ** * * * * * * 1000, stdin);

* *** * * *** * ** * * ** * ****** i++)
* ** ** ** * * ***
** * * * *** **** ** *** ** * ************ * * >= '0' * *** **** A[i] <= '9')
* * * * * ** ** ** **** ** ********* ** * **** * ** = digit + 1;
*** ** ******** *** ** * ** * * if((A[i] >= 65 ** * *** A[i] <= 90) || (A[i] >= 97 ** * * * * ** A[i] <= 122))
*** ** ** * * * **** * ** **** * ******* * ** ****** ******** * = alphabet + 1;
** * * ***** * ** **** * * *** * * * ** if(A[i] > 31)
*** * * * ** ** ** ** * **** * * * **** ** ** ** * * * ** = other +1;
** * *** ** ** ** * **

**** ** **** * ** *** ** * * ** ** ** ***** ** * digit);
**** **** ** * **** *** * *** **** * alphabet);
* * * * * ***** **** * * * **** * * **** * * * other);

* * * * * * *** ** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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