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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 12.2k views

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Hidden content!
#include <stdio.h>

int main(){
** ** ** **** * * **** str[500];
* ** ** ** *** ** * * sizeof(str), stdin);
* * * * ** * ***** * ** i=0;
*** * ** * * * * * d=0,a=0,o=0;
* * ** * ** ** * ** ** * *
**** **** * * * ** * * ** **** * ** ***** ** ** * ***** ** * * ** d++;
*** **** ** * * ** ****** * *** ** ** * **** **** * * **** ***** * * **** **** * **** * * * ** * ** *** a++;
* ** * ** * * * * * ** * * *** ** o++;
* * ** * * * * * ****** ***** *** * * * ***
    }

* * * * *** ** ** * *** *** * * ** **** * *** *

* * * * * ** **** * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** *** * * ** ** ** * * str[500];
*** * * *** ** ** *** sizeof(str), stdin);
** ** ** * ** ** * **** * i=0;
* ***** * * *** d=0,a=0,o=0;
* * * ** ****** ** * ** * * *
* * * *** **** * * ** * ** * * ** * * * ** * * ** * **** ** * ** d++;
** **** ****** ** ** ** * * * **** * *** *** * *** * * ** **** * ** * * *** * **** * * * **** * ***** * a++;
**** * * **** * ***** * ** *** * *** * o++;
* * * ** ** * ** * * * * *** *
    }

* * * * * * *** * **** * ** * ** ** ** * *** * * ** * **** * * // remove enter count

* * ** ** * ** ***** * *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include **** * ** **
#include * ** * **** *

int main()
{
* * * * ** * * * * * ** ** * A[1000];
** * ** ** ** ** i, digit=0, ** ** *** other=0;
******** **** * * * * * * * ** * 1000, stdin);

* ** *** * * ** * ******** ** * * i++)
*** * ** ****** ** ***** *
****** * * *** * * *** * * ***** ** **** * * ** >= '0' ** * ** A[i] <= '9')
*** * ******* * * ** * * **** * ** ***** * * **** ** ** ***** * * = digit + 1;
** * **** ** *** * * * **** * * ** ** if((A[i] >= 65 ** * * *** A[i] <= 90) || (A[i] >= 97 **** * ** A[i] <= 122))
* ** ******** * * * * * ** ** *** ** ** * * * * ** * *** *** *** * * = alphabet + 1;
**** ** * ** * *** *** ** * * * * * * * if(A[i] > 31)
* ** *** * * * ** *** * * ** ** ** * * ** ** * ** * * * * * ***** = other +1;
** ****** * * **

* **** *** * * **** ** ** ** * * * *** digit);
* *** * * ** ***** * ** *** * ** * * ** **** alphabet);
** * * ** * * ** * **** ** *** ** other);

* ** * * * *** ** * ** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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