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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 14.4k views

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Hidden content!
#include <stdio.h>

int main(){
* * ** * ** * ** str[500];
****** ** ** * *** **** * * ** sizeof(str), stdin);
* ** *** *** ** * ** *** * i=0;
** *** ** **** * * **** * * d=0,a=0,o=0;
* ** **** * ***** * *** * **** *** ** *
** *** * * ** * * * * *** * * * * * ** * ** ** ** ** *** * * * *** * * d++;
* ** * * ** ** ** ** ** * ** ** ** *** * * ** ** ** * ** * *** * *** * ** * *** * *** *** a++;
* *** ***** ** *** * * * **** **** ** * o++;
* * * * * *** ** ** ** *** * ** * ****** *
    }

* ** * * *** ** * *** **** * * **** **** ** *** * ** ** ** * *

** * * ** *** * ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* * ** *** ** ** * * str[500];
** *** * * *** ** * * * sizeof(str), stdin);
*** *** * * *** * * ** i=0;
** * ***** * * * d=0,a=0,o=0;
* ** ** * *** * * * ** * * **
** * ** **** * ** ** * * * **** ** *** * * * * * * ** * ** * * * d++;
*** * ** ** * ** * ****** **** ***** ** * ** * * * * ** ** * *** * * ***** * * ** **** * * * ** *** **** * a++;
** ** *** * ** * * * * ** * ** * * ** * * * * o++;
***** *** ****** ** * ** ** * ** * * *****
    }

**** * ******* * ** * **** * * * ** * *** *** * * ** ** *** // remove enter count

** * ** * * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * ***
#include ** *****

int main()
{
*** * ***** ** ** ** A[1000];
* ** * ***** * * * i, digit=0, ** * other=0;
** * *** *** * * ** * ****** 1000, stdin);

* * *** ** * * *** ** **** * *** i++)
*** *** *** *** * *
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* * **** ** * * * * * * ***** ** * * * *** * **** ** = digit + 1;
* * **** * * * *** *** * * * ** * ** **** *** if((A[i] >= 65 * * * A[i] <= 90) || (A[i] >= 97 * * * ***** A[i] <= 122))
*** * **** **** * * ***** *** **** ** * ** * ** * * * * ** * ** * = alphabet + 1;
* *** * * * * ****** ** * * ** ***** * * if(A[i] > 31)
* *** * * * * ** * *** ** * * ** * * * **** ** * *** *** *** * * **** = other +1;
* * * ** * * * ** **

* *** ** **** ** **** ** * * **** * * ** ** ***** ** digit);
**** ** *** * * *** *** * * ****** alphabet);
* * **** * *** ** * *** * ******* ****** * other);

* ** * ** * * * ** * 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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