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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 9.5k views

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Hidden content!
#include <stdio.h>

int main(){
** ** * * * *** * *** ** str[500];
* **** * * **** * * * * sizeof(str), stdin);
* * * ** ** * ** ** ******* i=0;
** * * ******* ** **** d=0,a=0,o=0;
** ** *** * **** * * * * ** * * *
* *** * ** ** *** * * ** ** **** ** * ** * *** * *** * **** *** * ** d++;
*** **** * ** **** **** * * * * *** * * * * *** ** ** **** ** ** * ** * *** * * * ** * *** *** * * a++;
* * ** ****** ** * * ** * * * **** o++;
** ****** * * ** ****** * * ***** ** ******
    }

*** *** * * * *** ** **** * ** * * * **** ***** *********

* * ***** *** * *** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** ** * ** * *** ** str[500];
** * * ** * * ***** * sizeof(str), stdin);
* ** * *** * * * *** ** ** i=0;
** * ** * ***** d=0,a=0,o=0;
* * ** * * * *** *** * * *****
** * * * * ** * ** * ** **** ****** *** *** * * ** * ***** ** * * *** d++;
**** **** ** **** ** * * ** * *** * * * ** * ** ****** *** *** *** **** ** * * * * *** ** ** **** * * * a++;
** * ** * * * ** * ** * * * * ** ** * * o++;
** ** * * *** *** * * * ** * * ** * * * *
    }

** **** ****** **** * ** * * ** * * * * ** * * * * ** // remove enter count

** *** * ** ** ** *** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * * * * *
#include * * ** *** * *

int main()
{
** * ** * ** * ** * A[1000];
* *** * * **** * * * * i, digit=0, ** other=0;
** ** * ** ********* ** **** ** 1000, stdin);

** * * **** ** ***** * * * * * * i++)
** * **** ******** * * *
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** ** * ** * * * * *** * ** * * ** * * *** * * * * * * ** * * *** * = digit + 1;
* ** ** ****** * * ** * ***** * if((A[i] >= 65 ***** *** * A[i] <= 90) || (A[i] >= 97 * *** * *** A[i] <= 122))
* ** * * ** * * **** ** * * ** * * * *** **** ***** * * * *** ***** = alphabet + 1;
** * * * * * *** ***** * *** **** * if(A[i] > 31)
* * **** *** * ** * *** * * * *** * * * ** * * **** ** ** * = other +1;
** * ** * * **** * * *

* * * ** * * *** * * ** ** * *** **** * * *** digit);
** ** ** ** *** * *** **** ** *** * * * * ** * * alphabet);
***** * * * ** * *** **** ** * * * ** * * other);

** * * * * *** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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