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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* * *** ** ** * * * str[500];
** * **** ** * ** * ** * * sizeof(str), stdin);
* * *** ** ** * **** * i=0;
** **** * **** * ** *** d=0,a=0,o=0;
* * * * * * * ** *** **** * ***
*** * ** * * ** * * * * ** ****** **** * * * ***** ** * * * ** * d++;
* ** ** * *** ** ** * ** ******** * * * ** **** *** ** * * ** * ** *** * *** * ** * * * ** **** a++;
** * **** ** * ** ** ** *** ***** o++;
* ** **** * ** ***** * * * **** * * ** * *
    }

** ** * *** * * * ** * ** ** ***** * * *** ** * * ** * ** *

*** * ***** *** **** *** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** *** *** * **** str[500];
** *** * * * * ** ** ** * sizeof(str), stdin);
** *** *** * * * ** * i=0;
* * ** *** * * * d=0,a=0,o=0;
** *** ** ** ******* * ** ** *** * **
**** * ** *** * * * * ** * * * * * * * ** ** * * **** * *** * *** **** d++;
** ** * ** **** ** * * * ** *** ** **** * *** *** *** *** * * ** ** * ** ** * * * * *** * ** ** a++;
***** ** ****** ******* ** * ** * ** ** ** * * ** o++;
* * * * * ** * * ** *** *** * * * ***
    }

* * *** * * ** ** ** ** *** *** ******* * * * ** **** * * *** // remove enter count

** * *** ****** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** * * ** * *
#include * ** ** * * ** *

int main()
{
*** *** * **** *** ** * A[1000];
* ** * ** * *** * ** * * i, digit=0, * * other=0;
* ** *** ** * 1000, stdin);

** * * * * * *** ** * ****** ** * i++)
*** *** ****** *** *
* *** * * * * ** * **** * * * ** * * *** * ** >= '0' * ** ** A[i] <= '9')
* * *** ** * * ** ** * * ** ******** * * * *** **** = digit + 1;
* * * * ***** * * ** *** *** * ****** * if((A[i] >= 65 * * *** ** A[i] <= 90) || (A[i] >= 97 * * * * A[i] <= 122))
**** * ***** * * ** * * *** ***** * *** * **** *** *** * * ** = alphabet + 1;
* * * ** * ** * ** * * *** * * ** *** if(A[i] > 31)
**** ** ** * * * * * * ****** * * *** ** ** ** * ** ***** * * * * ** * * ** * = other +1;
*** ** * ** ******

* * * *** * * * ** ***** *** ** * digit);
*** * ** * * * *** * ** ** * **** * * ** ** alphabet);
* ** * * ** *** * * **** * * * *** ** other);

* * *** *** * ***** * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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