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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 5.3k views

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Hidden content!
#include <stdio.h>

int main(){
* * * ** ** * ** * **** str[500];
** * * * ** * ** sizeof(str), stdin);
**** * * *** ** * * * * * * i=0;
** * ** * * ** *** *** d=0,a=0,o=0;
** * * ** ** * * **
* ** * * *** * *** ** ** ** * * * * * ***** * **** *** **** ** * * ** * d++;
* * ** *** * * * ** *** * * *** ** * ***** * * * ** *** ***** * ** ** *** ** *** ***** ***** * ***** * a++;
** ** ** * * **** ** * * * * * * ** ****** * o++;
* * * * ** ** * * *** **** *** * ****
    }

** ****** ** *** *** * *** ** *** ** **** *** * * * * * *

* * ** * * **** * ** * **** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
*** ** *** **** * * * * str[500];
* ** ** ** * ** ** * * *** sizeof(str), stdin);
* **** ** **** ** * i=0;
* *** *** ** *** * * * ** d=0,a=0,o=0;
* * ** * ***** * ** * * *
* ** * *** * ********** * ** * ** **** * * *** ** * ** * * ******* * **** *** d++;
*** ** * * * ** * * * * * ** ****** * ** ****** ***** ** *** ** * * ** **** * * *** * * * * ** **** * * * a++;
***** * * * ** ** * * * * ** ** * ** **** o++;
******** *** ** **** ** ** * * * * * * *
    }

*** * ** * * * ******* *** ** * ******* ** *** ** * * ** **** * ** // remove enter count

** * * * ** ** * ** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ********** * *
#include ** ***** * *

int main()
{
*** * * * * ** ** * ** A[1000];
*** **** **** * * * * * i, digit=0, *** * other=0;
***** ** ** ****** * * * 1000, stdin);

* ** ** *** ** **** * * * * * *** * i++)
* **** * ****** ** ** **
** ** ********** * * ***** **** ** **** * * **** >= '0' * ** A[i] <= '9')
* * * ** ** * * *** **** * **** * **** ** * *** ** *** ** * * * = digit + 1;
*** ** ** * *** * ** * * *** * * * ** * if((A[i] >= 65 * *** * A[i] <= 90) || (A[i] >= 97 * * **** A[i] <= 122))
* *** **** *** ***** * * *** ** ** ** *** * * ** * * * **** * * * = alphabet + 1;
*** * * ** * *** * ** ** *** * **** ** if(A[i] > 31)
* * * *** * * ****** ** *** * * * * ** * ** **** * ** **** * * ** *** * = other +1;
* * * **** * ****** **

* ** ** *** * * * * *** ** * * ** digit);
** * **** * *** * * *** * *** * * alphabet);
***** * **** * * ** *** ** *** * other);

*** * * * * *** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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