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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

edited by | 11.8k views

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Hidden content!
#include <stdio.h>

int main(){
**** ** * * ******** * str[500];
* * ** * * *** * ** * *** ** * sizeof(str), stdin);
** *** ** * ******** i=0;
*** **** ****** * * d=0,a=0,o=0;
* ** ** ** * *** ** * ***
** * **** * ** ** * ** * **** ** ***** ** * * *** *** * * * d++;
* * * ** * * * ** **** * ** *** ** ** ** * * ** * * * ** * ** * * * **** * ** * * * * *** * * *** ** a++;
** ***** ** * * ***** ** * ** ** ** ***** o++;
* *** *** * * * * * * * * * * ** ** * * * * * *
    }

* * * *** ** **** ** ** **** **** * * * *** * * * *** * * ***

* * * * ** **** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
** ***** * * *** ** * * str[500];
** ****** * * *** *** * sizeof(str), stdin);
* ** * **** ** * * i=0;
** ** * **** ***** d=0,a=0,o=0;
** * * ** ***** ** * ** ** *** **
** * *** * ***** ** * ** * * ** * * *** * ** * ****** ***** ** ** * d++;
* * * ***** ** **** ** ** * ** * * * * ** * ** **** * * **** * ** *** * ** * ** * ***** * *** * *** ** a++;
* ** ** ** *** * **** * * ** * * * * * o++;
* * * * * * * * ** ****** * *** **** ** * ***** * * *
    }

* * ** ** **** ** * *** ** * **** * ** * * ** **** * // remove enter count

* * * * ** ***** ** ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * *** * * *
#include * *** ** * *

int main()
{
* * * * ***** ** *** A[1000];
* ** ** ** * ** * * *** i, digit=0, * **** other=0;
*** ** * * *** ** *** * * 1000, stdin);

* ** ** * ***** * ** * * ** ***** * * i++)
* *** *** * *
* ** * * * * * ** **** ***** * ** ** * ****** * * * >= '0' ** * *** * A[i] <= '9')
* * ** * ** ** * ** ** ** * ** ***** * *** *** * ** * ***** * = digit + 1;
* *** ** ** * **** **** * * **** * ** **** if((A[i] >= 65 ** **** A[i] <= 90) || (A[i] >= 97 ** * ** * A[i] <= 122))
* * ** ** * * * ** * ** * * *** ** ** * * ** * * ** * * = alphabet + 1;
* *** ***** * * *** ** * * * *** ** * *** if(A[i] > 31)
* * *** *** ** * ** ** *** * ** ** ** ** *** *** * * * ** *** * = other +1;
*** * * * * ***** *

* **** *** ** ** ** * ** ** * ** ******** digit);
**** * * ** ***** ** ** ** * ** * * ***** alphabet);
* ****** *** * *** * ** * * ** **** * ** *** other);

** ***** * *** ** ***** * 0;
}
answered by (5.2k points)
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prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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