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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串,計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited

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Hidden content!
#include <stdio.h>

int main(){
* * * * * * * * * ** **** str[500];
* ** *** * ** ** *** * sizeof(str), stdin);
** ** * * ****** **** i=0;
* * * **** * * * *** d=0,a=0,o=0;
** *** * **** * ****** ** *** * ****
* ** * * **** **** * * ***** * * *** * ** * ** ** ** ** *** *** ** *** d++;
*** ** * **** ****** ** * *** * * ***** *** *** * ** ** **** * * * ** *** * *** *** ** * ***** * * * ** * * ** ** * a++;
* *** * ****** * * * ** * ** * ** **** * o++;
******** * ** *** * **** ** * * * *** ** * ** *** *
    }

* ***** ** * * **** **** * * * *** ** * *

* *** ***** *** **** * **** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>

int main(){
* ** *** *** * ** str[500];
** **** ** ** * * * ** sizeof(str), stdin);
** ** ***** ****** * * i=0;
* ** * **** ** **** * ** * * d=0,a=0,o=0;
** **** * * ** **** **
* ** **** **** ** *** ** ** * ** *** * * ** ** * * * * ** ** * d++;
**** * *** ** * * * * **** * * ** ** **** * ** * ** ** * * ** ** * * * **** * ** * * *** * * ** *** * * a++;
* ****** ** * ** *** **** *** ** ** * ** * * o++;
*** * * * * ** * * **** ** * * ***** *
    }

* ** ***** ** * * * ***** * * * * ** ****** ** * *** ** * // remove enter count

** ** **** ** * * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * * *** *
#include * ** ****

int main()
{
**** * * * * * * *** * A[1000];
*** ** * *** **** **** i, digit=0, * *** other=0;
* * * * **** * ** ** 1000, stdin);

* * * ** ** * ** *** * ** *** ** *** ** i++)
* * * * * *
** * **** * * * **** * * *** * * * * *** >= '0' ** * A[i] <= '9')
*** * * * * *** *** * *** * ** * * ** * * * ** ******* * * ** * = digit + 1;
* * * *** ** * * * * * ** *** * if((A[i] >= 65 ** ** ** ** A[i] <= 90) || (A[i] >= 97 * * *** **** A[i] <= 122))
*** * ** **** * ** * * * * * * * * ** * ** * * *** * ** **** = alphabet + 1;
* * * *** * **** * ** * * * * * * ** * * * if(A[i] > 31)
* *** *** **** *** ** ****** * *** *** ** **** **** ** * * *** **** ** = other +1;
* * ** ***

** *** * ** *** * ************ *** * * *** digit);
** ** *** * *** * * * *** ** * * * * * *** alphabet);
** **** *** **** * * ****** * * other);

* * * * * **** ******** ** 0;
}
answered by (5.2k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(A);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccSj5aoA.o: In function `main':
prog.c:(.text+0x44): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:8:7: error: assignment to expression with array type
     A = getchar();
       ^
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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