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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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* * ** * std;

class Adder

{
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{

int x,y;

cin ** ** x * * * **** y;
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sum1 += x; * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * * **** and sum2 are the *** * *** *

else cout *** * *** ** * and sum2 are not the ***** ** *

if (sum1 == sum3)

cout * *** * ** ** and sum3 are the * *** *

else cout ** * * ** * * and sum3 are not the ** * * *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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}
answered by (-367 points)
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* *

{
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answered by (-367 points)
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Hidden content!
* * ** *
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using * * std;



class Adder

{
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};



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{

int x,y;

cin *** * *** x * * * * * y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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cout *** * * * and sum2 are the **** *** *

else cout * ** *** *** and sum2 are not the *** *

if (sum1 == sum3)

cout *** * * ** ** ** and sum3 are the * ** * **

else cout ** * ** ** * * ** and sum3 are not the * * * *******


*** * * *** **** * 0;

}
answered by (-364 points)
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* * * *

{
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*** // *** is * * * * to 0

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}
answered by (-367 points)
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Hidden content!
** ** ***** * *

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * *** * ** x *** **** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout *** * "sum1 is " ** sum1.geta() * ** * * '\n';

cout * *** * * "sum2 is " * ** ** sum2.geta() ** ***** '\n';

cout ** *** "sum3 is " * * * * * sum3.geta() * * *** ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout *** * * ** "sum1 and sum2 are the ***** * *

else cout * ** ** "sum1 and sum2 are not the ** **

if (sum1 == sum3)

cout * *** * "sum1 and sum3 are the * ***** * *

else cout ** * ** * "sum1 and sum3 are not the *** * *

}
answered by (-384 points)
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Hidden content!
* *** * * * ** **

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin ** ** * x * * ** y;

Adder sum1;

Adder sum2(x); // sum2 is * * to x

Adder sum3(y); // sum1 is initialized to y

cout ** * * ***** is " * * * sum1.geta() * *** **** * '\n'; // prints ** * * is 0"

cout *** **** * * ** *** is " * * * ** sum2.geta() * * ** ** '\n'; // prints * **** is x"

cout *** * ** * ** * ***** is " ** ** * sum3.geta() ** **** ** '\n'; // prints * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** **** * and sum2 are the * ** *

else cout ** * * *** ** and sum2 are not the * ** **

if (sum1 == sum3)

cout * * * ** ** * * ** and sum3 are the * **** * *

else cout * ******* **** and sum3 are not the *** *** *

}
answered by (-384 points)
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Hidden content!
** **** ****

using namespace std;

class Adder{
*** *** ** *** * ** *
* *** * * ** * *** * ** * *** * *** * geta();
* * * * * * ** ***** * * * * ** seta(int n1){
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* ** **** ** * ** *** **** *** **** ** ** * * * * * a;

};
* * *
* *** * **** ***** *** **** ** a;

}









int main()

{

int x,y;

cin * **** x ** * ** ** y;

Adder * ** *
** *

*** * // sum2 is ** to x
*** ** // sum1 is ** * * to y

cout * * * ***** ** is " *** * **** *** *** '\n'; // prints * ** * * is *

cout * * * *** * * ** is " **** * *** * * *** ** * '\n'; // prints * * ** is *** **

cout * *** * * *** * * is " * **** *** ** ** * ** ******* '\n'; // prints * ** * is * ***

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * *** *** ** and sum2 are the * * *

else cout * * * ** * *** * * and sum2 are not the ***** **

if (sum1 == sum3)

cout *** **** * * * and sum3 are the * * * ****

else cout * * * * *** ***** * and sum3 are not the ** * ** * *

}
answered by (-384 points)
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