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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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}



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{

int x,y;

cin *** * * x ** * *** y;
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sum1 += x; * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** *** **** and sum2 are the ** ***

else cout ** *** * ** ** * ** and sum2 are not the * ** **

if (sum1 == sum3)

cout * **** ** * * * * * and sum3 are the *** * ** **

else cout * * * *** *** * and sum3 are not the * **

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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{
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout ***** * * *** ** and sum3 are the ** * * *

else cout ** * ** * * *** * *** and sum3 are not the * * *


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}
answered by (-364 points)
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}
answered by (-367 points)
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* ** ** * *** ******

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class Adder{
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{

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cin ******** * x ** ** ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * ***** "sum1 is " * ** * sum1.geta() * '\n';

cout * *** * "sum2 is " ** ** * sum2.geta() * ** * * '\n';

cout ** * * * "sum3 is " *** * * * sum3.geta() *** * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout ** *** * * "sum1 and sum3 are the ** ** **

else cout ***** * *** "sum1 and sum3 are not the * *

}
answered by (-384 points)
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Hidden content!
** * ** * ******* ** *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * *** x * * * y;

Adder sum1;

Adder sum2(x); // sum2 is * * * to x

Adder sum3(y); // sum1 is initialized to y

cout * * ** * * is " * *** * * * sum1.geta() * *** ** '\n'; // prints * * ** is 0"

cout ** * * ** ** ******* is " * * * ***** sum2.geta() * * * * * '\n'; // prints * *** is x"

cout ** **** is " * * ** sum3.geta() * * *** '\n'; // prints * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** *** * ******** and sum2 are the * ***** *

else cout ** * * * * ** and sum2 are not the *** * * *

if (sum1 == sum3)

cout *** * * * * ** *** and sum3 are the * * * *

else cout ***** ** *** *** and sum3 are not the * ** *

}
answered by (-384 points)
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Hidden content!
* * **** ** * ** *

using namespace std;

class Adder{
* * **** *** ** * *
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};
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** ** * * ** *** *** * * a;

}









int main()

{

int x,y;

cin * *** * x * ** y;

Adder * *****
* ** **

* // sum2 is ** * ** to x
** ** // sum1 is ** ** to y

cout * * *** * is " ** *** * ** * * * '\n'; // prints **** ** *** is *** **

cout * * * ** **** is " *** * * **** ** ***** '\n'; // prints *** * is ** * **

cout ** ** ** * is " ** * ** * * ***** '\n'; // prints * * * *** is * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout **** * * ** * * * and sum2 are the * * ** * *

else cout * * * * * and sum2 are not the ** * * *

if (sum1 == sum3)

cout ** ** * * * *** * and sum3 are the ** * * * **

else cout * * ** * ** and sum3 are not the * ** * *

}
answered by (-384 points)
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