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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{
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{

int x,y;

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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else cout ***** **** * * and sum2 are not the * ** ***

if (sum1 == sum3)

cout * * * * **** * and sum3 are the *** * * **

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}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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{

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sum1 += x; //adds x to sum1; now sum1 is x

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cout * *** * * ** *** * and sum3 are the ** ***

else cout ***** * * *** * and sum3 are not the ** ** ** * *


** * * ** ****** * *** 0;

}
answered by (-364 points)
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answered by (-367 points)
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* * * * ** **

using namespace std;

class Adder{
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{

int x,y;

cin * **** ** ** x * * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout **** ** ** * "sum1 is " ** * ** ** sum1.geta() * * * '\n';

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout ** * * ** "sum1 and sum3 are the ** ** * * *

else cout * *** * * "sum1 and sum3 are not the * **

}
answered by (-384 points)
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Hidden content!
* * * ** **** *****

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin ** * * x * * y;

Adder sum1;

Adder sum2(x); // sum2 is **** ** to x

Adder sum3(y); // sum1 is initialized to y

cout **** *** * * * is " * * ** * sum1.geta() ** * *** '\n'; // prints ** * is 0"

cout * * * *** * * is " ** ** sum2.geta() *** * * '\n'; // prints * ****** is x"

cout **** * **** * **** is " * ** ** * sum3.geta() * *** '\n'; // prints * ** *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * *** **** * * ** *** and sum2 are the ***** **

else cout * * * *** * * ** and sum2 are not the * ** *

if (sum1 == sum3)

cout * * * ** * * and sum3 are the ** * ** *

else cout * ** * ** and sum3 are not the * ***

}
answered by (-384 points)
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Hidden content!
******** ***

using namespace std;

class Adder{
** *** * ** ** **** *
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};
* * **
*** * ** * * ******* a;

}









int main()

{

int x,y;

cin * * * ** x * ***** * y;

Adder ****
* * * *

* ** * // sum2 is * * to x
*** *** // sum1 is * ****** to y

cout * * * is " * * * * * * *** ** ** ** '\n'; // prints **** *** ** is * **** **

cout * * ** ** ** ** is " ** *** * ** ** * '\n'; // prints **** * * is **** *

cout * ** ** is " * * *** * ****** * '\n'; // prints * ** is ** **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** *** * * * * and sum2 are the * * * * * **

else cout * *** **** * * * and sum2 are not the ***** *

if (sum1 == sum3)

cout ** * ** * and sum3 are the * * ****

else cout * * * * * ** *** and sum3 are not the * ** ****

}
answered by (-384 points)
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