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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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*** * * * std;

class Adder

{
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int main()

{

int x,y;

cin * * * * x ** **** * y;
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sum1 += x; * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ** * * * ** and sum2 are the * ** *

else cout *** *** * ** * **** and sum2 are not the * ** * **

if (sum1 == sum3)

cout *** * * * and sum3 are the ***** * ***

else cout * * * * * * * and sum3 are not the *** * * * * **

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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{
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answered by (-367 points)
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Hidden content!
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using * std;



class Adder

{
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{

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cin * **** x ***** ** * y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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cout ** * * * * and sum3 are the * * **

else cout *** * ** * and sum3 are not the ***** * *


* * *** * * * * *** * * * 0;

}
answered by (-364 points)
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Hidden content!
* *

{
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}
answered by (-367 points)
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Hidden content!
* * *

using namespace std;

class Adder{
*** ***** * ** * ** * *
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}

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{

int x,y;

cin * **** x *** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout * * ** * "sum3 is " ** ** ** sum3.geta() * *** * * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout * ** *** "sum1 and sum3 are the * * **

else cout **** * "sum1 and sum3 are not the ** *** ***

}
answered by (-384 points)
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Hidden content!
****** * * *

using namespace std;

class Adder{
* * * * * ** * * *
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**** *** * *** ** ** * * * ** **** * *
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};
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}









int main()

{

int x,y;

cin * ** * ** x * **** **** y;

Adder sum1;

Adder sum2(x); // sum2 is * * * * to x

Adder sum3(y); // sum1 is initialized to y

cout *** * ** * * * is " **** * * * sum1.geta() * * '\n'; // prints * **** * is 0"

cout *** * ** ****** is " *** sum2.geta() * * ***** '\n'; // prints * ** * ***** is x"

cout * *** **** * * ** * ** is " * * * * sum3.geta() * ***** '\n'; // prints ** *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * ** and sum2 are the ***** * *

else cout **** ***** **** ** and sum2 are not the ** * *

if (sum1 == sum3)

cout **** * * * ** * * * and sum3 are the ** * * * *

else cout * ** * ** * * and sum3 are not the *** ** *

}
answered by (-384 points)
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Hidden content!
** * * * ** ** *

using namespace std;

class Adder{
*** ***** ** ** * ** *
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* ***** * * **** * * * ** * *** * ***** * a;

};
* ****
****** * * ** *** * * a;

}









int main()

{

int x,y;

cin ** * * *** x ****** y;

Adder * *** *
* * *

* * // sum2 is * *** to x
** * // sum1 is ** to y

cout **** * **** **** * is " * * *** * * ** * * * ** ** * '\n'; // prints *** ** is ******

cout * * ** * * * is " * * * * ** ** **** * * '\n'; // prints ** ** ** ** is * ** *

cout ** *** * * * ***** * is " * **** ** * * * * * '\n'; // prints * *** is

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * * * and sum2 are the * * *

else cout ** * ** ** ** ** and sum2 are not the * * ** *

if (sum1 == sum3)

cout * * * *** ** and sum3 are the ** * * * **

else cout * ** ** ** ** * ** and sum3 are not the * * * ** *

}
answered by (-384 points)
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