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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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cout * ** ** ******** and sum3 are the * **** * *

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}
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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}
answered by (-364 points)
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***

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answered by (-367 points)
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******** * ** **

using namespace std;

class Adder{
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{

int x,y;

cin * * * *** * x * * * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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sum3 += 2;

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if (sum1 == sum3)

cout * ** * * "sum1 and sum3 are the * * *

else cout * ** *** "sum1 and sum3 are not the *** * **

}
answered by (-384 points)
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Hidden content!
***** ** *** *** ****

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ****** * * x ** *** y;

Adder sum1;

Adder sum2(x); // sum2 is ** to x

Adder sum3(y); // sum1 is initialized to y

cout * *** * * **** * * is " * * * *** sum1.geta() ** ** ** '\n'; // prints * ** is 0"

cout ** *** * ** is " **** * * sum2.geta() ** * * * * '\n'; // prints ** * is x"

cout ** *** ** *** * is " * * * sum3.geta() * **** * *** '\n'; // prints *** ** ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * **** * ** * and sum2 are the * * * *

else cout * ** * * *** * and sum2 are not the ***** *** ***

if (sum1 == sum3)

cout * * * * * * ** ** and sum3 are the * *** ***

else cout *** * * ******** and sum3 are not the ** * **

}
answered by (-384 points)
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Hidden content!
**** ** ** ***

using namespace std;

class Adder{
** ** ** **** **** *** * * * **
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};
* * **
** *** *** *** ** * * *** ** a;

}









int main()

{

int x,y;

cin * ** * x * *** * y;

Adder ***** * ***
**

* **** // sum2 is * * * to x
* *** **** // sum1 is * to y

cout ** **** ** ****** is " * ** * * * ** ** * * ** '\n'; // prints ** ** * is * *

cout *** *** * is " ** * ** *** * ** * ** '\n'; // prints ***** * is ******

cout * * * * is " * * ****** * * *** * * ** '\n'; // prints **** is * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * *** * * * * and sum2 are the * * * *

else cout *** ****** ***** * and sum2 are not the * *** ****

if (sum1 == sum3)

cout * * ***** * * *** * and sum3 are the *** * * * *

else cout ******* *** *** ** and sum3 are not the ***

}
answered by (-384 points)
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