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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum3)

cout ** ** * *** * * and sum3 are the * ****

else cout * * * ** *** ** ** ** and sum3 are not the ***** *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
* **

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answered by (-367 points)
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* * ** ***
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{
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{

int x,y;

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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cout * *** * *** *** *** * and sum3 are the * ** * *

else cout * * **** * * ** * and sum3 are not the **** *


** * * * *** * ** ** ** * 0;

}
answered by (-364 points)
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Hidden content!
* *

{
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}
answered by (-367 points)
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Hidden content!
* * *****

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * ** ** * x ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout * * ** * "sum3 is " ****** ** sum3.geta() *** * * * ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

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else cout * * ** "sum1 and sum2 are not the *** * * **

if (sum1 == sum3)

cout *** * ***** "sum1 and sum3 are the ** * ***

else cout *** "sum1 and sum3 are not the * * * *****

}
answered by (-384 points)
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Hidden content!
** **** ***** ***

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin ** ** x *** * *** y;

Adder sum1;

Adder sum2(x); // sum2 is * * to x

Adder sum3(y); // sum1 is initialized to y

cout * * * * is " * * * sum1.geta() ** ** *** '\n'; // prints ** * * is 0"

cout * ** *** ** * * is " * * ** sum2.geta() *** *** ** '\n'; // prints ** ** is x"

cout ** * * ** ** is " *** ** ***** sum3.geta() * ***** '\n'; // prints ** * ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * *** ** ** ** and sum2 are the ***** * **

else cout ** * ** * and sum2 are not the * * **

if (sum1 == sum3)

cout ****** * *** * ***** and sum3 are the * * * *

else cout * * * *** * *** ** and sum3 are not the * *** ** *

}
answered by (-384 points)
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Hidden content!
* * * * * **

using namespace std;

class Adder{
** *** * ** *
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*** * * ** **** * ** ** * * ** ** * ** * seta(int n1){
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* ** * * * **** ** * *** *
* ** ** * ** * **** * * * * ** **** ** * ** a;

};
* * **
**** * *** ** ** * ** a;

}









int main()

{

int x,y;

cin * * * ** * x ** ** ** y;

Adder ***
** * ****

**** * // sum2 is ** * * to x
** ** * * // sum1 is * * * * to y

cout * * **** * ** * is " * ** * ** * * * * '\n'; // prints * **** * is **

cout **** ** * * ** is " * ******* ** ****** * '\n'; // prints * ** is **

cout * *** ** * * * * * ** is " * ** ** * ** * *** '\n'; // prints * **** * is ** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ***** * * * * and sum2 are the ** * *

else cout * *** * * * *** * and sum2 are not the ** * ****

if (sum1 == sum3)

cout * * * ** *** * and sum3 are the * ** * * * *

else cout * * ** * * and sum3 are not the * * ***

}
answered by (-384 points)
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