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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** *** and sum2 are the ** * ***

else cout *** ** * ** * * ** and sum2 are not the * **** * ***

if (sum1 == sum3)

cout *** ** * * ** and sum3 are the * ***

else cout **** ** *** *** and sum3 are not the ** *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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cout ******* ** *** and sum2 are the *** **

else cout ** ** *** ** and sum2 are not the * * **

if (sum1 == sum3)

cout * **** **** ** * and sum3 are the * ** * *

else cout * ** * * ** *** * and sum3 are not the * ** *


*** * * * * **** ** ** * * 0;

}
answered by (-364 points)
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Hidden content!
**

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}
answered by (-367 points)
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Hidden content!
*** ** * ** **

using namespace std;

class Adder{
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{

int x,y;

cin ** * x * * * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout ** * ***** "sum1 and sum3 are the ******* ***

else cout *** ** "sum1 and sum3 are not the *** ** *

}
answered by (-384 points)
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Hidden content!
* * * * *** * * * **

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin *** *** ** x * y;

Adder sum1;

Adder sum2(x); // sum2 is ** ** to x

Adder sum3(y); // sum1 is initialized to y

cout * *** * *** * **** * * is " * ** * * * sum1.geta() * ****** * '\n'; // prints * *** ** is 0"

cout ** ** * * ** ** * is " * * **** sum2.geta() **** * * * * '\n'; // prints * is x"

cout * *** ** * ** * is " ** * * * sum3.geta() * * * '\n'; // prints * **** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** ** ** ** and sum2 are the *** * **

else cout ** * * * * ** *** and sum2 are not the * *** * **

if (sum1 == sum3)

cout * * * * ********* and sum3 are the *** ** * *

else cout ** * ** * ** * ** and sum3 are not the ** ** *

}
answered by (-384 points)
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Hidden content!
* * ** *** ** ***

using namespace std;

class Adder{
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};
* * *
*** ** ** * * *** *** *** a;

}









int main()

{

int x,y;

cin * ** x * ** * ** y;

Adder * * ***
** ***

**** ** *** // sum2 is **** to x
** ** // sum1 is *** * to y

cout * ** * * * * * is " ** * ** * ****** '\n'; // prints ** ** * is ** ***

cout ** * *** * * * is " *** * * * *** * * * '\n'; // prints ***** ** is *** * *

cout * ** *** * ** *** is " * * ** ***** * ** * '\n'; // prints ** *** is * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** ** ******** * and sum2 are the * * ****

else cout * * **** *** and sum2 are not the **** * *

if (sum1 == sum3)

cout *** * * ***** and sum3 are the * ***** * *

else cout *** *** * ** ** and sum3 are not the **** **

}
answered by (-384 points)
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