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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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{

int x,y;

cin * * x * * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * ***** and sum2 are the * ** * ****

else cout ** * * * * * * * and sum2 are not the * ** * *

if (sum1 == sum3)

cout * * * **** *** * and sum3 are the ** * *** **

else cout ** *** * *** *** and sum3 are not the ** ** **

}
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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{

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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** * ** *** ** and sum2 are the *** **

else cout ** ** **** * * and sum2 are not the *** ** *

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cout * * * ** **** ** and sum3 are the * *

else cout * * ** * * * ** * and sum3 are not the ** ***** **


* ***** * * * ** * * * * * * 0;

}
answered by (-364 points)
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Hidden content!
**

{
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}
answered by (-367 points)
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Hidden content!
**** ** *********

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin *** * * x ** ***** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout ** * * "sum2 is " * ** * sum2.geta() *** * '\n';

cout *** ****** "sum3 is " * *** ** * sum3.geta() * ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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else cout ** *** * "sum1 and sum2 are not the * ** *

if (sum1 == sum3)

cout ****** *** "sum1 and sum3 are the ** * **

else cout *** ** "sum1 and sum3 are not the ** *** **

}
answered by (-384 points)
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Hidden content!
* ** * * ** * ****

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin ** ***** x * * y;

Adder sum1;

Adder sum2(x); // sum2 is to x

Adder sum3(y); // sum1 is initialized to y

cout * * * *** *** * is " * * sum1.geta() ** '\n'; // prints * * is 0"

cout * ** ** * * * ** is " ** * sum2.geta() *** * *** '\n'; // prints * ***** is x"

cout *** ** * * *** is " * ** * sum3.geta() **** '\n'; // prints ** *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** ** * * * and sum2 are the * * **

else cout * * ** * * **** * and sum2 are not the ** * *

if (sum1 == sum3)

cout * *** * * and sum3 are the ** *** *

else cout ** ** *** *** ** and sum3 are not the * * * **

}
answered by (-384 points)
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Hidden content!
*** ***

using namespace std;

class Adder{
** * **** * * * * * * * *
*** ** **** **** **** * * * * * ******* * * geta();
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**** * ** ******* * * * * * *** ******* ** * ******
**** ***** ** * * * ** * ** * * *** *** * * * *** * * **** * ** * **** **** 0;
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};
* * * *
** * ** ** ****** * **** a;

}









int main()

{

int x,y;

cin **** ** * x **** ** y;

Adder * ** ** ***
* * * ** **

* * * // sum2 is ** * to x
* * // sum1 is ** to y

cout * ** * ** * is " * * ** *** * ** * * ** * '\n'; // prints *** *** is *

cout **** * is " ** ******* **** ** * '\n'; // prints * * ** * is * *

cout * * * ** ** *** is " **** * * * ** ** *** '\n'; // prints * **** * is ** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** *** ** ***** * and sum2 are the *

else cout ** * * ** ** * ** ** *** and sum2 are not the * *****

if (sum1 == sum3)

cout ** * * * and sum3 are the * * * *

else cout * ***** * * * *** ** and sum3 are not the * * ****

}
answered by (-384 points)
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