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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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{

int x,y;

cin ** * x * ** ** y;
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* * * // sum2 is ** * to x
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ***** *** * ** and sum2 are the * **

else cout ***** * * * ** and sum2 are not the ** * *** *

if (sum1 == sum3)

cout ** * ** * ** and sum3 are the * ** * *

else cout * ** *** * and sum3 are not the ** **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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using std;



class Adder

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{

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cin * * ** * x **** * y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * **** * ** ** and sum2 are the * ** ***

else cout * *** * * * * ** * and sum2 are not the * ** ***

if (sum1 == sum3)

cout * * * ** ** * * and sum3 are the * * * *

else cout ********** ******* and sum3 are not the * ** **


* ** **** ***** * * 0;

}
answered by (-364 points)
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Hidden content!
* **

{
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}
answered by (-367 points)
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Hidden content!
* *** ** **

using namespace std;

class Adder{
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}

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{

int x,y;

cin *** **** x * * * ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout ******* "sum2 is " ** *** * sum2.geta() ** * * * '\n';

cout ****** "sum3 is " ** * ****** * sum3.geta() * * '\n';

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout * ** *** "sum1 and sum3 are the * * ****

else cout * * ** "sum1 and sum3 are not the **

}
answered by (-384 points)
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Hidden content!
* * * ** * * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin *** ****** * x ** y;

Adder sum1;

Adder sum2(x); // sum2 is *** to x

Adder sum3(y); // sum1 is initialized to y

cout ** ** * ** ** is " * * ***** * sum1.geta() ****** ** * '\n'; // prints ** * is 0"

cout * ** * *** ** is " *** * * sum2.geta() ** ** '\n'; // prints * ** is x"

cout ** * ** * * *** ** * * is " *** ***** * sum3.geta() * *** * '\n'; // prints * * *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ****** * ** * * and sum2 are the * *** ***

else cout * * * * * * and sum2 are not the *** * **

if (sum1 == sum3)

cout * ******* * * *** and sum3 are the **** **

else cout * * * ** *** ** and sum3 are not the * ** *

}
answered by (-384 points)
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Hidden content!
* * ** * **** ***

using namespace std;

class Adder{
** * **** ** ** * * *
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};
* *
* *** ******** *** * ** a;

}









int main()

{

int x,y;

cin * x * ** * *** y;

Adder ****** **
* ** * *

** * ** * // sum2 is **** * to x
* ** // sum1 is *** * to y

cout * ** **** * * * is " *** * * * ** * *** * '\n'; // prints ******* is * * * *

cout * ** * *** ***** is " ***** ** * * ** ** '\n'; // prints * * * * is ******

cout * **** **** ***** is " *** * ***** * * * **** '\n'; // prints **** **** is ** **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** * * ** ** and sum2 are the ** ** * * *

else cout * * * * ** *** and sum2 are not the * * * *

if (sum1 == sum3)

cout ** * * ** ** and sum3 are the ** ** *

else cout * * * * ** *** ** ** and sum3 are not the * ** * *

}
answered by (-384 points)
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