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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

int x,y;

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum2)

cout * * * **** * * and sum2 are the ** *** **

else cout ** * *** ***** ** and sum2 are not the ** ** * **

if (sum1 == sum3)

cout * * ** **** and sum3 are the *** ****

else cout * *** * * ** and sum3 are not the *** * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

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else cout ** * ***** ** * and sum2 are not the * * * * * *

if (sum1 == sum3)

cout * *** * * * * *** * and sum3 are the * **

else cout * * * * * * * ** and sum3 are not the * ** ***


***** **** ** ** * 0;

}
answered by (-364 points)
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Hidden content!
* *

{

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}
answered by (-367 points)
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Hidden content!
* * ** * *** * ****

using namespace std;

class Adder{
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{

int x,y;

cin * **** ***** x ** * * * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout ** * *** "sum2 is " * **** * sum2.geta() * * * '\n';

cout * * ** "sum3 is " * ** * * sum3.geta() ** * ** '\n';

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout **** * ** "sum1 and sum3 are the * ** *

else cout ** * * ** "sum1 and sum3 are not the * * ** * *

}
answered by (-384 points)
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Hidden content!
* * * *** * *

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin ** **** x * * * *** y;

Adder sum1;

Adder sum2(x); // sum2 is ** to x

Adder sum3(y); // sum1 is initialized to y

cout *** ***** * *** is " * ** sum1.geta() * ** *** * '\n'; // prints * * ***** * is 0"

cout ** ******** * ***** is " * * * ** sum2.geta() * * * * '\n'; // prints * * * is x"

cout *********** ** * * is " * * ** sum3.geta() **** ** '\n'; // prints *** *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * *** ** ** * *** and sum2 are the **** ******

else cout **** * *** and sum2 are not the ** * *** **

if (sum1 == sum3)

cout * * ** ** * and sum3 are the **** * * *

else cout ***** ** ** * * * * * and sum3 are not the * ** * * ***

}
answered by (-384 points)
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Hidden content!
* * * * * * ** *

using namespace std;

class Adder{
** ** ** * * ***
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* * ***** * * * * ***** * * *** ** * *** *** a;

};
* *** * **
* ** ** * * * *** * * *** a;

}









int main()

{

int x,y;

cin **** ** ** * x * * *** y;

Adder ***** * *
*** * *

** * ** // sum2 is ** * to x
****** * // sum1 is *** ** * to y

cout * * ** * *** is " * ** * * *** * * ** *** '\n'; // prints ** ** is * ** **

cout * * **** ** ** is " * * *** * ** * *** * '\n'; // prints * **** * is ***

cout ** * * ** * * * is " *** * * * * **** ** **** ** '\n'; // prints ** ** * is * * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ****** ** ** * * and sum2 are the * * * * *

else cout ** * ** ** ** ** and sum2 are not the * ** *

if (sum1 == sum3)

cout ** * * ** * and sum3 are the * *** * ** *

else cout * **** **** ***** and sum3 are not the * * * ***

}
answered by (-384 points)
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