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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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int main()

{

int x,y;

cin *** * * x ** ** y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * **** *** and sum2 are the * * ***

else cout ** ****** ** * * * * and sum2 are not the ** * *

if (sum1 == sum3)

cout * * **** ** * * ** and sum3 are the * ** * *

else cout * * * ** and sum3 are not the ** * *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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{

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else cout * ** *** ** ** and sum2 are not the ** * *

if (sum1 == sum3)

cout * ** ** * ******* and sum3 are the * * **

else cout * * * ** * and sum3 are not the **** **


** ** **** *** * **** 0;

}
answered by (-364 points)
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Hidden content!
* *

{
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}
answered by (-367 points)
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Hidden content!
* * *** ** * * * * *

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * * * * x ** * ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** * * "sum1 is " * ** * sum1.geta() * * '\n';

cout **** "sum2 is " * * * sum2.geta() * *** ** ** * '\n';

cout * * *** * "sum3 is " * sum3.geta() ** **** * '\n';

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sum2 += -3;

sum3 += 2;

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else cout *** * ** "sum1 and sum2 are not the *** * * *

if (sum1 == sum3)

cout ** ** *** * "sum1 and sum3 are the * ****

else cout ** * *** "sum1 and sum3 are not the **** **

}
answered by (-384 points)
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Hidden content!
* * ** ** ** * ** *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * *** x * * y;

Adder sum1;

Adder sum2(x); // sum2 is * ** * to x

Adder sum3(y); // sum1 is initialized to y

cout * ** ***** * * ** is " ***** *** * sum1.geta() ** * '\n'; // prints ** * ** is 0"

cout ***** * * *** * * is " * * * sum2.geta() * * ** * '\n'; // prints *** ** * * is x"

cout * ** * * * ** *** ** is " * * * sum3.geta() ** ** '\n'; // prints * ** *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ***** ** * *** * and sum2 are the * * ***

else cout * * ** * * * and sum2 are not the ** * *****

if (sum1 == sum3)

cout **** *** * **** * and sum3 are the *** * *

else cout ** * * * * ** ** and sum3 are not the ** ** *

}
answered by (-384 points)
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Hidden content!
* * ** * *

using namespace std;

class Adder{
* ** ** * * ***** *
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};
* * *
* * * * ** * ** * ** * * a;

}









int main()

{

int x,y;

cin * * * * x *** * * y;

Adder ** * * *
* *

* * // sum2 is *** * to x
** *** // sum1 is * ** ** to y

cout * * * * * * * is " ** ** *** *** * * ** '\n'; // prints * **** is * ** *

cout * * * * * * * *** is " * * * ** *** * * * ** * '\n'; // prints ** *** is *** **

cout ** * ** * ** is " * ** ** * * ****** '\n'; // prints ** *** is * ** **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** *** * * and sum2 are the * * ** **

else cout * * * * *** * and sum2 are not the ** * ** **

if (sum1 == sum3)

cout ** **** ** * *** * and sum3 are the ** *** **

else cout ** * * * and sum3 are not the **** * *** *

}
answered by (-384 points)
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