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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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cout * **** * * * and sum3 are the ** * ****

else cout **** ** ***** and sum3 are not the * ***


** * * ** *** * * * * 0;

}
answered by (-364 points)
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answered by (-367 points)
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Hidden content!
* ** * * * ** ** *

using namespace std;

class Adder{
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{

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Adder sum2(x);

Adder sum3(y);

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if (sum1 == sum3)

cout * * ** "sum1 and sum3 are the **** *

else cout * * * * "sum1 and sum3 are not the *** * *

}
answered by (-384 points)
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Hidden content!
* ** * ** * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin *** ** * * x * *** y;

Adder sum1;

Adder sum2(x); // sum2 is ** * to x

Adder sum3(y); // sum1 is initialized to y

cout * * *** ****** * is " **** ** sum1.geta() * * ** '\n'; // prints ** *** * is 0"

cout ** * ** * ** * is " * * **** ** sum2.geta() ***** ** '\n'; // prints * * * is x"

cout ** * * * *** is " * **** sum3.geta() *** ** '\n'; // prints * * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * **** * * * * **** and sum2 are the * **** *

else cout * * * * * ** and sum2 are not the ** ** *** *

if (sum1 == sum3)

cout *** and sum3 are the * *** ** *

else cout ** * * **** and sum3 are not the *** *

}
answered by (-384 points)
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Hidden content!
***** ***** * * **

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin ** * * x * * ** ** y;

Adder * *** *
* * *

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*** ** // sum1 is * * * to y

cout ***** ** ** * is " * * ** * * * *** * *** * '\n'; // prints **** * is ** * **

cout * * ** * **** is " *** * * * **** * ** '\n'; // prints ** is * * ***

cout ** * ** * * is " ** * *** * * * *** *** ** '\n'; // prints ****** * is ***

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * **** * * * and sum2 are the ** ***** *

else cout ** * ** ** * * ** * and sum2 are not the * * * **

if (sum1 == sum3)

cout * * * * *** * and sum3 are the * * * ** **

else cout * *** * * ** **** and sum3 are not the ** * **

}
answered by (-384 points)
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