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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

int x,y;

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; *** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ****** *** * and sum2 are the *** **

else cout * ** ** **** * * ***** and sum2 are not the ** **

if (sum1 == sum3)

cout * * * * ** * ** and sum3 are the **

else cout * *** ** * * *** and sum3 are not the * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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cout * ***** ** * ** **** * and sum3 are the * ** * **

else cout *** * * * and sum3 are not the * ******


* * **** ****** * ** ** 0;

}
answered by (-364 points)
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****

{
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}
answered by (-367 points)
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Hidden content!
* * ** ** * **

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * **** x * * ** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * * * * * "sum1 is " **** ** sum1.geta() * '\n';

cout * ** * "sum2 is " * * *** sum2.geta() ****** * '\n';

cout ** * * "sum3 is " ***** * sum3.geta() * **** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * ** * * "sum1 and sum2 are the * * * * **

else cout ** * * "sum1 and sum2 are not the * *** *

if (sum1 == sum3)

cout * **** * * "sum1 and sum3 are the * * *** *

else cout * *** * "sum1 and sum3 are not the * ****** ** **

}
answered by (-384 points)
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Hidden content!
* ** ** ** *** **

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ** ** ***** x **** * ** y;

Adder sum1;

Adder sum2(x); // sum2 is *** * to x

Adder sum3(y); // sum1 is initialized to y

cout * ****** *** is " * * *** sum1.geta() *** ** * * '\n'; // prints **** ** * is 0"

cout * *** ** *** ** is " *** * sum2.geta() ** **** *** * '\n'; // prints * * * is x"

cout ** * ** * **** * is " * **** sum3.geta() * ** '\n'; // prints ** ** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** * ** * * and sum2 are the * ** *

else cout * * * ****** and sum2 are not the * **

if (sum1 == sum3)

cout **** ** * * and sum3 are the *** ** *

else cout *** * * ** ** and sum3 are not the * * ** **

}
answered by (-384 points)
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Hidden content!
** * ********** *

using namespace std;

class Adder{
**** ** * * **
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};
* *** *
** * *** *** * ** * * a;

}









int main()

{

int x,y;

cin * ** ** ** x * * ** y;

Adder ** **
* **** *

*** // sum2 is to x
* *** // sum1 is * *** to y

cout * * * *** *** * * is " * * ** * * ** ** ** ** * '\n'; // prints * * *** is * * *

cout ** * ******** is " *** * *** * *** ** ***** '\n'; // prints * * ** is **

cout * **** * *** * * * ** is " * * * * * * *** *** '\n'; // prints ** * ** is ** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** *** * * ** *** and sum2 are the * *** *

else cout * *** ** ** * * and sum2 are not the * * **

if (sum1 == sum3)

cout * ** ** ** * and sum3 are the * * ** *

else cout ** * * ***** and sum3 are not the * * **

}
answered by (-384 points)
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