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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum2)

cout *** ** * * ** * * and sum2 are the ** **

else cout **** * * * and sum2 are not the ** *

if (sum1 == sum3)

cout * **** * and sum3 are the * * * * *

else cout ** * ** ** and sum3 are not the * * * * *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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class Adder

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout ** ** *** * ****** and sum3 are the ****** * * **

else cout ******* *** ** and sum3 are not the * * * **


* * ** * * * * * ** * * 0;

}
answered by (-364 points)
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Hidden content!
****

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}
answered by (-367 points)
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Hidden content!
** ***** * * *****

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class Adder{
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{

int x,y;

cin ****** ** * x * ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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sum2 += -3;

sum3 += 2;

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else cout *** "sum1 and sum2 are not the **** ****

if (sum1 == sum3)

cout * ** *** "sum1 and sum3 are the * * **

else cout * * ** ** "sum1 and sum3 are not the * * *

}
answered by (-384 points)
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Hidden content!
* ** **** * * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * * x * **** * y;

Adder sum1;

Adder sum2(x); // sum2 is ** ***** to x

Adder sum3(y); // sum1 is initialized to y

cout * *** * ** * *** is " * * ** * sum1.geta() ** * *** '\n'; // prints * *** is 0"

cout * ** * **** * *** is " ** *** sum2.geta() ** * ** ** '\n'; // prints * * is x"

cout * * *** is " ***** * * sum3.geta() * * * '\n'; // prints * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** and sum2 are the * ** * **

else cout * ** ** ***** ** and sum2 are not the *** * **

if (sum1 == sum3)

cout * * ** * ** * *** and sum3 are the * *** ***

else cout **** *** * * and sum3 are not the ** ** * **

}
answered by (-384 points)
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Hidden content!
** *** ******* **

using namespace std;

class Adder{
** * *** * * * ** * *
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** * * * * *** ** * * * ** * *** * * seta(int n1){
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};
* * ***
** ****** * * **** * ** ***** a;

}









int main()

{

int x,y;

cin * **** ** x * ** *** y;

Adder * *** * *
** ** *

* * ** // sum2 is *** to x
* ** *** // sum1 is ****** to y

cout * * * * ** is " ** *** * * *** * * **** '\n'; // prints * *** * is * **** **

cout ** * * ** * is " *** ** * ** * * ** '\n'; // prints * ** * is *** *

cout *** **** *** is " ** * ** * ** * ** ** '\n'; // prints *** is * * * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ** *** and sum2 are the *** *

else cout * ** * * * * * and sum2 are not the ***** *

if (sum1 == sum3)

cout *** **** * * * * * and sum3 are the * ** * **

else cout ** * * *** * ** * and sum3 are not the * **** **

}
answered by (-384 points)
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