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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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}



int main()

{

int x,y;

cin * ** ** x ** * y;
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cout *** **** * ** is *** ***** * ** ***** * * *** * '\n'; // * * * ***** is *** * **

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cout ** ** * * * ******* * is ** ** * *** ****** * * * ** * '\n'; // * ** * ** is * * **

sum1 += x; * * ** x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; ** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * * * and sum2 are the *** ** *

else cout * * *** *** ** and sum2 are not the * *

if (sum1 == sum3)

cout * * * * *** * and sum3 are the ** ** *

else cout * * ** * * * ** and sum3 are not the **** * *** ***

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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using * ** * std;



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{
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{

int x,y;

cin * *** *** x ** **** * y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

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else cout ** *** ** **** ** *** and sum2 are not the * ***** * *

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cout **** ** * * * and sum3 are the * * * *

else cout ** * * **** * and sum3 are not the *** * * *


*** *** * * ** *** ** **** * 0;

}
answered by (-364 points)
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Hidden content!
* * *

{
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** * **** * x * * y;
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}
answered by (-367 points)
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Hidden content!
* **** * * * * *

using namespace std;

class Adder{
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}

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{

int x,y;

cin * **** ** * x ** ** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * ** * "sum1 is " * * ** ** sum1.geta() *** * '\n';

cout * * "sum2 is " * * *** sum2.geta() * ** ** '\n';

cout **** ***** "sum3 is " ** *** *** sum3.geta() * * **** * '\n';

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sum2 += -3;

sum3 += 2;

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else cout *** * * "sum1 and sum2 are not the *

if (sum1 == sum3)

cout * * "sum1 and sum3 are the ** * * *

else cout * ** * "sum1 and sum3 are not the * **** **

}
answered by (-384 points)
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Hidden content!
* * * ** * ** * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * *** x * ** ** * y;

Adder sum1;

Adder sum2(x); // sum2 is * to x

Adder sum3(y); // sum1 is initialized to y

cout ** ** * * *** is " ** * * ** sum1.geta() * * '\n'; // prints ** * *** is 0"

cout *** * * * ** *** *** is " * * *** * sum2.geta() **** *** '\n'; // prints * ** **** is x"

cout * * * ** * ** is " * ** sum3.geta() * ** '\n'; // prints **** * ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** * ** ** **** and sum2 are the ** * *****

else cout ** ** *** *** * * and sum2 are not the *** ** *

if (sum1 == sum3)

cout ** ** * * * ** ** and sum3 are the *

else cout ** * ** ** ** *** and sum3 are not the * ****

}
answered by (-384 points)
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Hidden content!
* ** * ** *

using namespace std;

class Adder{
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};
*** * **
* *** ****** * ***** ** a;

}









int main()

{

int x,y;

cin * * ** x ** *** y;

Adder * ** *
** *

* * * // sum2 is * ***** to x
* **** // sum1 is * ** to y

cout ** **** *** ** ** is " * ** * ** * ** ****** * '\n'; // prints ** * * is * * *

cout ** ** *** ** is " * * * * *** * * *** '\n'; // prints * * * * ** is * *

cout * ** * * * ** * * is " **** * *** *** ** * * * * '\n'; // prints ** * * * is *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * * and sum2 are the * *** ** ** **

else cout ** * * * *** * * and sum2 are not the ***********

if (sum1 == sum3)

cout *** ** *** * and sum3 are the * **** **

else cout ** ***** *** ** and sum3 are not the * ** *

}
answered by (-384 points)
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