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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout ** ** ** ** ** ** and sum2 are the ** *** *

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if (sum1 == sum3)

cout * ** ** * *** * and sum3 are the ** *** **

else cout * ** **** *** and sum3 are not the * *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum3)

cout * * *** * * and sum3 are the * * * **

else cout ** * * ******** and sum3 are not the * * **


******** * *** *** * * 0;

}
answered by (-364 points)
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Hidden content!
** * *

{
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}
answered by (-367 points)
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Hidden content!
* ** * *

using namespace std;

class Adder{
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}

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{

int x,y;

cin * ***** x ** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * * *** "sum1 is " ****** *** * sum1.geta() * * * ** '\n';

cout * * **** "sum2 is " * * * sum2.geta() *** ** '\n';

cout **** * ** "sum3 is " * sum3.geta() ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout *** * "sum1 and sum3 are the * * *

else cout * * ** "sum1 and sum3 are not the *** * * * *

}
answered by (-384 points)
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Hidden content!
* ***** ** *

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin * *** x * * * * y;

Adder sum1;

Adder sum2(x); // sum2 is * * * to x

Adder sum3(y); // sum1 is initialized to y

cout ** * **** * * is " ***** sum1.geta() ** ** * '\n'; // prints * * is 0"

cout * ***** ** **** * is " * * **** * sum2.geta() ** * **** * '\n'; // prints *** **** is x"

cout * ** * * * is " *** * * * sum3.geta() * * '\n'; // prints * ** ***** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * ** **** * and sum2 are the * ******* *

else cout * **** ** ** and sum2 are not the * ****

if (sum1 == sum3)

cout * * ** *** * * ** * and sum3 are the * * *** **

else cout *** * ** *** * ***** and sum3 are not the * * * * **

}
answered by (-384 points)
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Hidden content!
** * **** ***

using namespace std;

class Adder{
* *** ** *** * ** *
* * **** * * * * ****** * * * *** * ** * geta();
** ** * ** ** ** ** * ** * *** * ** seta(int n1){
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* * *** ** *** * * * *
******* ** ** **** * *** * * ** ** * *** *** ** ***** a;

};
*** * * * *
* * ***** ** *** * a;

}









int main()

{

int x,y;

cin ** * **** * x **** **** * y;

Adder *** ****
* * *

* *** // sum2 is * to x
* ****** // sum1 is **** ** to y

cout * ****** ** ** * **** is " ** * ** * **** * ** * * * '\n'; // prints * * is ** **

cout ** * * * * ** is " ** * * *** ** ** * *** '\n'; // prints * * *** is * *

cout **** *** * * is " ** * * * **** ** ** *** '\n'; // prints ** ** *** is *** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** *** * * and sum2 are the * ** * *

else cout ***** ** * and sum2 are not the *

if (sum1 == sum3)

cout * * * ** * *** * and sum3 are the * * ***

else cout ** * * ** *** and sum3 are not the * ** *

}
answered by (-384 points)
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