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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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else cout * * * * * and sum2 are not the ** * * *

if (sum1 == sum3)

cout ** * ** * * * * and sum3 are the * ** *** **

else cout ***** ** ** ** *** and sum3 are not the *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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*** * * * ** **
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};



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{

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cin * ** ** * x *** * * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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else cout *** ** *** ** * and sum2 are not the *** *

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cout ** ** *** * * and sum3 are the ***** ****

else cout * ** ** * * * ** and sum3 are not the * *** ** ** *


* * ** ** * * **** ***** * * 0;

}
answered by (-364 points)
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* *****

{
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}
answered by (-367 points)
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* * ** ***** ** **

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * ** x * * *** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** *** * ** "sum1 is " ** ** * sum1.geta() *** **** * * '\n';

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cout ****** * * * "sum3 is " * * ** sum3.geta() *** * * ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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else cout ** ** ** "sum1 and sum2 are not the ** *** ***

if (sum1 == sum3)

cout * * * ** "sum1 and sum3 are the * *

else cout * ** "sum1 and sum3 are not the ** *** ** *

}
answered by (-384 points)
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Hidden content!
*** * **** ** *

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin * *** * x ** *** y;

Adder sum1;

Adder sum2(x); // sum2 is ** * to x

Adder sum3(y); // sum1 is initialized to y

cout **** * * * is " ** * * ** sum1.geta() ** * '\n'; // prints * * ** is 0"

cout ** * ** ***** *** is " ***** * * * sum2.geta() * * ** * '\n'; // prints *** * ** is x"

cout * *** ** * *** * * *** is " ** ** ** * sum3.geta() * ** '\n'; // prints * **** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** ** * and sum2 are the * ** **

else cout **** ** * * * **** and sum2 are not the ** **

if (sum1 == sum3)

cout * *** * * *** * * and sum3 are the * **** ***

else cout * ***** * * ** * and sum3 are not the * ** **

}
answered by (-384 points)
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Hidden content!
*** *** * * *****

using namespace std;

class Adder{
***** ** **** * ** * * ** * *
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* ** * * ** * ** * * * *** * ** * ** *** ****** * ***** *** * * **
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* ** ** * * * * ** * *
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};
*** *** ***
**** ** **** ** * ***** * a;

}









int main()

{

int x,y;

cin * *** ** * x ** ***** y;

Adder * ** * *
** ***

** * // sum2 is * to x
* ******* * // sum1 is ** *** to y

cout *** * ** * * * is " * * * * * '\n'; // prints *** is * **

cout * ** ** * ** is " **** * * * *** * ** '\n'; // prints * ***** is ** * *

cout * **** is " * **** **** ** ** * * '\n'; // prints *** is ****

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * *** ** **** * and sum2 are the * * ***

else cout ***** ** * * and sum2 are not the * * ****

if (sum1 == sum3)

cout ** * *** *** and sum3 are the * *

else cout * * ** * ** and sum3 are not the * *** *

}
answered by (-384 points)
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