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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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cout * *** * *** and sum3 are the ** *

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** * * ** *** ** *** 0;

}
answered by (-364 points)
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answered by (-367 points)
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Hidden content!
** ** ** ***

using namespace std;

class Adder{
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{

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cin * * *** x ** ** ** y;

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Adder sum2(x);

Adder sum3(y);

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sum3 += 2;

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if (sum1 == sum3)

cout * * *** * "sum1 and sum3 are the * * * ***

else cout * * ** "sum1 and sum3 are not the ** ***

}
answered by (-384 points)
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Hidden content!
**** * *** *** *** *

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class Adder{
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}









int main()

{

int x,y;

cin ** * ** x **** ** * y;

Adder sum1;

Adder sum2(x); // sum2 is ** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** * *** ** * ** is " ** * sum1.geta() * * * '\n'; // prints *** * is 0"

cout *** ** ** * is " * ** * sum2.geta() *** ** '\n'; // prints ******** is x"

cout * * * * ** * ** is " * ******* sum3.geta() * ** * '\n'; // prints * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

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else cout ****** * **** and sum2 are not the **

if (sum1 == sum3)

cout * ******* ** * * * and sum3 are the * **** * ***

else cout * ** and sum3 are not the **** *

}
answered by (-384 points)
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Hidden content!
** * ******* ******

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin * *** * x * ** * y;

Adder *** ***
* * * **

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* * * // sum1 is *** ** to y

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cout ** ** * * ** **** is " * **** * **** ** * ** * '\n'; // prints * is * **

cout * * ** *** is " *** ** * ******* * * * '\n'; // prints ** * * is * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** * ** ** * and sum2 are the * * *

else cout ** ***** * and sum2 are not the ** ****

if (sum1 == sum3)

cout *** ** *** * ** ** and sum3 are the * *

else cout ** * *** ** * and sum3 are not the ** **

}
answered by (-384 points)
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