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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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}



int main()

{

int x,y;

cin * **** * * x * ** * * y;
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*** * * // sum2 is * *** to x
**** * **** // sum1 is *** to y

cout * * *** * * is * * **** *** * * ** ** * '\n'; // ** * * * * is ****

cout * * ** * ** ** is ** * * * * **** * * * **** '\n'; // * * ** * * * is * *

cout * * is * ** *** * * * ** * '\n'; // * *** ** * ** * is *** *

sum1 += x; *** x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** ** * * and sum2 are the * * **

else cout ** ** ** * * and sum2 are not the **** ****

if (sum1 == sum3)

cout * ** * **** and sum3 are the * ** ** * *

else cout * * ***** ** * * ** and sum3 are not the * ** *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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}
answered by (-134 points)
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answered by (-367 points)
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** *

{
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* // * is * * * * to 0

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}
answered by (-367 points)
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Hidden content!
** * * ** ** ***
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using * *** std;



class Adder

{
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};



int main()

{

int x,y;

cin * ** ** x * y;
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Adder *** // sum1 is ** * * to y

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cout * **** * * * * is * ** ** ** * * ** *** '\n'; // * * *** * * is *** *

cout ***** * *** **** is ** * ** * * ***** ** * '\n'; // prints * * is * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ***** * ** * * * * and sum2 are the ** * *****

else cout **** **** * ** ** and sum2 are not the * *** * *

if (sum1 == sum3)

cout *** * * * ** ** and sum3 are the * ****

else cout ** ** * ** * and sum3 are not the * * ***


* * * * *** ** 0;

}
answered by (-364 points)
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* ** ***

{
*
* *** ** * x * * ***** y;
*** // ** is ** * * to 0

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}
answered by (-367 points)
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Hidden content!
* * ******* * *****

using namespace std;

class Adder{
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};

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}

int main()

{

int x,y;

cin * ** *** x ** ** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** **** * "sum1 is " ** * sum1.geta() * *** *** '\n';

cout *** * * "sum2 is " * ******** sum2.geta() * * ** '\n';

cout * * ** * "sum3 is " **** sum3.geta() * * *** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout ** * * ** "sum1 and sum2 are the *** * ***

else cout **** *** "sum1 and sum2 are not the * * *** * *

if (sum1 == sum3)

cout **** * * * "sum1 and sum3 are the ** ** *

else cout ****** "sum1 and sum3 are not the * ****

}
answered by (-384 points)
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Hidden content!
* * * * * ***

using namespace std;

class Adder{
* * **** * * * ***
** * *** * * *** ** * * ** ** * *** **
* * ** * * ****** *** *** *** * * * *** * ***
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** * * ** ** *** **** * * * *** ** * * c;

};
* * *
* * * * * * a;

}









int main()

{

int x,y;

cin * ** x * * **** y;

Adder sum1;

Adder sum2(x); // sum2 is ***** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** * * * is " ** * ** * sum1.geta() * * * * '\n'; // prints * ** ** * is 0"

cout * *** **** *** ** is " **** * sum2.geta() *** '\n'; // prints * ** is x"

cout * ** ** * *** is " * * ***** sum3.geta() * **** ** '\n'; // prints ***** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** ** * * * and sum2 are the ***

else cout * * *** ** and sum2 are not the ** ** *

if (sum1 == sum3)

cout ** * ** * *** and sum3 are the **** * * **

else cout ** * * * * ** * and sum3 are not the * * *

}
answered by (-384 points)
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Hidden content!
** ** ** * **** * *

using namespace std;

class Adder{
*** * *** * * ** ** *
** * * * * * * ** * *** ** **** *** *** * geta();
* **** ***** * *** * * **** * * * *** * * * * seta(int n1){
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* * ** *** ** * ** ** ** *** * ** **** * **
** * ** * *** * * ****** * ** ** *** * ** * * * ** * * x){
**** * *** * **** * ** ** * ** ** **** * ** * * c;
* *** ** * * ** * * * ** * ***** * * ** * ** ** **
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* ** *** * *** * * *** * *** * ****
* * **** * * * * ** * ********* * * * * * ******** * * b){
* *** ** * **** * **** ** ** ** ******** *** ** ** ** ** *** * * * c;
* * * * * * ** ** * ** * * * * ** *** * **** * * * ******* * *** ** **
* * * * ** **** * * ******* * **** * ***** * * * * * * *** * * ******** *** *** ** ***** 1;

** ** * ** **** *** * * * * * * * * ** *** ** ******* * * * * * ***
* * *** * * * * * * ** * * * * * *** * * * * * ** * *** * * * * ** * * * 0;
* ** * ** ** * *** * *** ** ****
*** *** ** *** *** * ** *
*** *** ** * * * * * *** * * ** * * a;

};

** * * ******** * * * *** a;

}









int main()

{

int x,y;

cin ** **** * x *** y;

Adder *** *
**

** ** // sum2 is ** ** * to x
** ** ** // sum1 is * * ** to y

cout **** *** * * * ** is " * * * *** ** * * * '\n'; // prints ***** * is * *

cout * * * * * * ** * *** is " *** ** * * ****** **** * *** '\n'; // prints * * * is ** *

cout * *** * * ** * * * * is " ***** *** * ** ** ** * ** '\n'; // prints ** ** **** is *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** *** ** * and sum2 are the **** **

else cout * * ** * *** and sum2 are not the ** ** **

if (sum1 == sum3)

cout **** * ** * *** * and sum3 are the ** ** *

else cout ***** ** ** *** ** and sum3 are not the * **

}
answered by (-384 points)
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