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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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cout **** * * * *** and sum3 are the * ** **

else cout ** ** * * * * and sum3 are not the * * **


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}
answered by (-364 points)
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** *

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answered by (-367 points)
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Hidden content!
* * * * * *** ** *

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class Adder{
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Adder sum2(x);

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if (sum1 == sum3)

cout ** ******* "sum1 and sum3 are the * * *** **

else cout * * ** "sum1 and sum3 are not the ***** *

}
answered by (-384 points)
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Hidden content!
** ** ** ** **

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class Adder{
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}









int main()

{

int x,y;

cin * * **** x ** ** y;

Adder sum1;

Adder sum2(x); // sum2 is * ** ** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** * * *** is " * * * ** sum1.geta() ** * '\n'; // prints *** * * * * is 0"

cout * * *** ** is " ** * * ** sum2.geta() ** ** '\n'; // prints * **** is x"

cout ** * *** * **** * is " *********** sum3.geta() ******* **** '\n'; // prints ******* is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** *** * * ***** and sum2 are the * * **

else cout * *** * ** * * * ** * and sum2 are not the *** ****

if (sum1 == sum3)

cout ** ** ** * ** **** and sum3 are the ** *** *

else cout *** * * * * * * and sum3 are not the * **

}
answered by (-384 points)
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Hidden content!
** ** **** * ****

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin * * ** x *** * y;

Adder *** *
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* * * // sum2 is * ** * * to x
** *** // sum1 is ******** to y

cout *** * * ** ** is " * * ** * **** ** * **** '\n'; // prints ** * ** is * ***

cout ***** ** * *** * * is " *** ** *** * *** *** * ** * '\n'; // prints ** ** ** * is **** *

cout * ** *** * ***** is " * * **** * * ** '\n'; // prints *** * * is * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * *** ****** and sum2 are the ***** *

else cout ** * ** * * * and sum2 are not the * **** *

if (sum1 == sum3)

cout ***** ** * **** * ** and sum3 are the * ***

else cout * * ** * * * * and sum3 are not the ** *** *

}
answered by (-384 points)
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