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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{
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{

int x,y;

cin ***** ** x * ** * * y;
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* * * // sum2 is ** * to x
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sum1 += x; * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout **** * * * * *** and sum2 are the * **

else cout * * * * * * and sum2 are not the * * *** *

if (sum1 == sum3)

cout ** ****** * *** and sum3 are the * ** *

else cout ** * ** **** ** ** and sum3 are not the * *** * **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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class Adder

{
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{

int x,y;

cin ** * * x *** * * y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * *** * ** and sum2 are the *** * *

else cout * **** * ** * ** and sum2 are not the * ** ***

if (sum1 == sum3)

cout ** * * ** and sum3 are the * ** * * *** *

else cout * * ** * * *** and sum3 are not the * * *** ****


** * * * * * ** **** * * 0;

}
answered by (-364 points)
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Hidden content!
**

{

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}
answered by (-367 points)
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Hidden content!
* ** *** * ** * **

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin ** * **** x * ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * * * "sum1 is " **** * sum1.geta() *** * * * * '\n';

cout ** **** * "sum2 is " * *** *** sum2.geta() * ** * '\n';

cout * ** * "sum3 is " * ** * * * sum3.geta() ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * * * * "sum1 and sum2 are the **** ** ***

else cout ***** ** *** "sum1 and sum2 are not the * ** * *

if (sum1 == sum3)

cout * ** * "sum1 and sum3 are the ***** *

else cout ** "sum1 and sum3 are not the * *** ***

}
answered by (-384 points)
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Hidden content!
* * * * * *** **

using namespace std;

class Adder{
** ** ***** * ** * * ** *
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};
** *** *
**** *** ** * *** *** * ***** a;

}









int main()

{

int x,y;

cin ** **** x * * y;

Adder sum1;

Adder sum2(x); // sum2 is *** * to x

Adder sum3(y); // sum1 is initialized to y

cout * * ** * * **** *** is " *** * sum1.geta() ** *** ** '\n'; // prints ***** ** * is 0"

cout * ***** * * * ** is " *** ** * * sum2.geta() * ** * * '\n'; // prints * * * is x"

cout *** * * * ******* is " *** ** sum3.geta() * *** ** '\n'; // prints * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * * ** ** and sum2 are the * * **

else cout * * ** ** * * and sum2 are not the *

if (sum1 == sum3)

cout ** * ** * * * ** and sum3 are the **

else cout **** * **** ** * * ** and sum3 are not the * * *

}
answered by (-384 points)
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Hidden content!
* ** *** ** * *****

using namespace std;

class Adder{
** ** * *** * * ***
** **** ** *** ** * * * * ** * * ** **** geta();
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**** ** ***** ** ** * * * ** * ***** *** ** * ***
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* * * * * ** * **** ** *** * **** * **** **** *** * * * * ********
** ** *** * * * * *** *** * * ** ** * ** *** *** * ** * * **** * ** * * ** * ** * 0;
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*** **** * * ****** * * * **
** * * * *** * * * **** * * * *** ** ** * a;

};
***** **
** ** ***** * * * **** * a;

}









int main()

{

int x,y;

cin ** ** * x * ** y;

Adder * * ** **
* *****

** * // sum2 is *** ** to x
******* * // sum1 is ** to y

cout **** * * ** ** is " *** ** * ** **** ** * * '\n'; // prints * * ** is * **

cout * * * ** is " ** *** ** * * * * * * * '\n'; // prints * ** * * * is ***** *

cout * ** ** ** *** * * is " * * ** ** ** * **** * ** '\n'; // prints **** * is * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ******** **** * and sum2 are the *** **

else cout ****** * * and sum2 are not the *** **

if (sum1 == sum3)

cout **** * ** ** ** and sum3 are the ** ****

else cout * ** * *** * and sum3 are not the * **** * **

}
answered by (-384 points)
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