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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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}



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{

int x,y;

cin * * ** *** x ** ** * * y;
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sum1 += x; ** x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; ** * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ***** * ** **** ** ** and sum2 are the * * * ** *

else cout ******* ***** *** * and sum2 are not the *** * * *

if (sum1 == sum3)

cout * * * * ** * and sum3 are the *** * * **

else cout *** * *** * *** ** and sum3 are not the ** *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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** * *

{
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answered by (-367 points)
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Hidden content!
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{

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cin *** * x ** * * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ***** * **** * and sum2 are the * * * * *

else cout * **** ** * * * and sum2 are not the * * *

if (sum1 == sum3)

cout ** *** *** ** * ** **** * and sum3 are the * *** *

else cout * * *** * ** and sum3 are not the * **** *


** * ** ** ** * ****** * 0;

}
answered by (-364 points)
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* *

{
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}
answered by (-367 points)
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** ** * * ** **

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * * * x *** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout **** "sum1 is " * * **** * sum1.geta() ** ***** '\n';

cout ** ** * * "sum2 is " ** * * ** sum2.geta() ** * * * '\n';

cout * **** "sum3 is " ***** * *** sum3.geta() * * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * ** *** "sum1 and sum2 are the * * *** *

else cout * ** * "sum1 and sum2 are not the ** ******

if (sum1 == sum3)

cout **** ** ** * "sum1 and sum3 are the * * * *

else cout **** * "sum1 and sum3 are not the * * * *

}
answered by (-384 points)
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Hidden content!
** * * ** **

using namespace std;

class Adder{
** * *** ** * * * * * **
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*** * ** **** * *** ** * * **** *** *
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};
* * * **
* * * ** * ** * ** a;

}









int main()

{

int x,y;

cin * ** x *** * ** * y;

Adder sum1;

Adder sum2(x); // sum2 is **** * to x

Adder sum3(y); // sum1 is initialized to y

cout * ** * ** * ** is " **** * sum1.geta() *** * ** ** '\n'; // prints ***** ** is 0"

cout * ***** * *** * * * is " * * * sum2.geta() ** * '\n'; // prints *** is x"

cout * * * * **** ** is " **** * ** sum3.geta() * * * '\n'; // prints * * * ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ****** **** * ** ** * and sum2 are the * * * ***

else cout **** * *** and sum2 are not the ** *** *

if (sum1 == sum3)

cout *** ** * * *** ** and sum3 are the * * ** **

else cout * ** ** * * and sum3 are not the * ** *

}
answered by (-384 points)
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Hidden content!
* ** * ** * **** *

using namespace std;

class Adder{
** ** ** ** * ** * * ***
***** *** * ********** * * ** ** **** * geta();
** ** * * * **** * * * ** * *** ****** ** ** seta(int n1){
** * ** ***** ** ** * * ** * ** ** * *** ** * * * * ******* ** ** *
* * * **** * ** * * * ** * *************
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* * * * * ** * * * * ** **** * *** * ** c;
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** ** ** *** ******** * **** * ** * ** *** ** * ** *** *** *** c;
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**** * *** * * * * * * ** * * ** * ***** * ** * * ** * * ** * *** *** * *** * 1;

** *** ** ** *** * * ** * ** * * * ** **** * *** *** *** ** **
* * * * *** * * * **** * ** * * ***** *** ** * * ** ** * ** *** ** **** ** * **** 0;
* * * * * * ***** ****** * * ** **
** ***** * ***
** **** ** ** ** * * * * ** *** * * * ** * a;

};
* * *****
* * *** *** ** ******** * a;

}









int main()

{

int x,y;

cin **** * *** x * * * y;

Adder * ***
* *** ***

* **** ** // sum2 is ** *** to x
*** * // sum1 is * * * to y

cout * * * ** * is " ****** ** * * * * '\n'; // prints * * ** * is * * *

cout ** ** * * is " * ** * * * * * * * **** '\n'; // prints * * ** is ***** *

cout * *** * *** is " ** * *** * * * **** * ** * '\n'; // prints *** is *******

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ****** * ** *** and sum2 are the * ** **

else cout *** * *** * * * * and sum2 are not the ** * *

if (sum1 == sum3)

cout ** **** * * *** * and sum3 are the * ** * ** **

else cout * **** ** ** ****** and sum3 are not the *** *** **

}
answered by (-384 points)
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