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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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*** * * std;

class Adder

{
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};



int ** * * ***

{
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}



int main()

{

int x,y;

cin * ** ** x * ****** y;
*** sum1; // sum1 is * * to 0
** * *** * // sum2 is * * to x
*** * // sum1 is * * to y

cout *** * * ** * * is *** * *** ** * ***** * *** '\n'; // * ** *** ** is * **

cout * * * * * *** * is ** * * **** * * **** * '\n'; // ** * * * * is * *** **

cout * ** *** *** ** * is * * * *** ****** * * * '\n'; // *** ** * *** is ** *

sum1 += x; x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; ** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * * ** and sum2 are the *** * ****

else cout * * * * * * ** * * and sum2 are not the * **

if (sum1 == sum3)

cout * ** * * * * and sum3 are the * * *****

else cout * ** * ** * * ** and sum3 are not the ** * **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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}
answered by (-367 points)
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Hidden content!
** *

{
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* ** *** * * x ** * ** y;
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}
answered by (-367 points)
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Hidden content!
** * * * *
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using *** **** std;



class Adder

{
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};



int main()

{

int x,y;

cin * ** x **** * y;
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Adder ** * * // sum2 is * ** ** to x

Adder ** * // sum1 is * * * to y

cout * *** *** ** * * is **** * ** **** * * * ** * * * '\n'; // prints * * * * ** is ********

cout ** * ** * * * * * ** is * * * * * *** ** * * * * * * '\n'; // * * *** is **

cout *** **** ** * * is * * **** **** * * * ** '\n'; // prints * * * ** is ** * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** ** * ** and sum2 are the *******

else cout **** *** * **** ** ** and sum2 are not the ** * *****

if (sum1 == sum3)

cout * * *** * ** and sum3 are the * ** * * **

else cout ***** **** * * * ** and sum3 are not the * **


** *** *** ** ** * * * ** 0;

}
answered by (-364 points)
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*

{
*** *
*** ** * x ** * ** * y;
** * ** * // * * is to 0

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}
answered by (-367 points)
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Hidden content!
** ** *

using namespace std;

class Adder{
** *** * *** *** * * * * * * **
** * * ******* ******** ** ** ***
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};

Adder::geta(){
* *** **** * * * * *** a;

}

int main()

{

int x,y;

cin * *** x ** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** **** * "sum1 is " * ** ** ** sum1.geta() ** '\n';

cout ***** ** "sum2 is " * ** sum2.geta() *** * * '\n';

cout * **** "sum3 is " * *** * sum3.geta() * * ** ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * * * "sum1 and sum2 are the *** * *

else cout * * * * "sum1 and sum2 are not the ** **

if (sum1 == sum3)

cout ** * ** "sum1 and sum3 are the **** * *

else cout *** "sum1 and sum3 are not the *** * * * *

}
answered by (-384 points)
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Hidden content!
* * ***

using namespace std;

class Adder{
* ** ** ** **** * * **
*** * *** *** * *** ***** *** * * * * *** * ** *
*** * * * * **** ** * ** * * * **
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** *** ***** * * *** ** *** *** * * * ** ***** ** * * *** ** ** * * * **** * 0;
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* * ****** ** * *** *** ** *** *** ** **** * a;
** *** ** * **** * *** ***** ** ** *** * c;

};
* ** **
* * ** * * * * * a;

}









int main()

{

int x,y;

cin ** ** * x * * *** y;

Adder sum1;

Adder sum2(x); // sum2 is ** * ** to x

Adder sum3(y); // sum1 is initialized to y

cout ** ** * ** * * * is " * * * sum1.geta() * * '\n'; // prints *** is 0"

cout * * **** * is " * sum2.geta() * '\n'; // prints ** * is x"

cout *** ** * ***** is " *** ** * sum3.geta() * * * '\n'; // prints ** ****** ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** ** * * * * * and sum2 are the * * **** **

else cout * * ** ** *** * *** and sum2 are not the ** * * ***

if (sum1 == sum3)

cout * * ** ** * * * and sum3 are the **** *

else cout ** * ** * * * ** * and sum3 are not the * ***

}
answered by (-384 points)
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Hidden content!
** ** ** * * * *

using namespace std;

class Adder{
* ***** * * *** * ****
* * ** ** * * ** * ** *** * * ** * *** geta();
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* * ** * ** ***** ****** * **** *** ** * ** ** * * **** * * ** * c;
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* * * ** *** * * * * * * * * *** * ** ***** ***** **** * ****
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* * ** * * **** ****
** ** * *** ** * * * * ** *** * ** *** ** a;

};
** **** *
** * ** *** ** * ** * ** a;

}









int main()

{

int x,y;

cin ****** * * x * * * * * y;

Adder ********
* * **

** * ** * // sum2 is * * *** to x
* *** // sum1 is * ** ** to y

cout **** ** * * ** is " ** ** * * *** *** * * '\n'; // prints * * *** is * *

cout **** *** ** * *** *** is " *** ** * *** '\n'; // prints * ** ** ** is * ***

cout ** ** * * * is " ** * *** *** * * * ** * '\n'; // prints ** ** * is ** **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * ** * ** * *** and sum2 are the * *** *

else cout ** * *** * ** * * and sum2 are not the * * * ***

if (sum1 == sum3)

cout ** *** * * ***** and sum3 are the ** *** * **

else cout ** * ***** * and sum3 are not the ** * *

}
answered by (-384 points)
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