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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum2)

cout * * * * ** * *** ** ** and sum2 are the **** ******

else cout *** * *** **** and sum2 are not the ** * **

if (sum1 == sum3)

cout *** *** * * * *** and sum3 are the **** *

else cout **** *** ***** and sum3 are not the * *****

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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using * * std;



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{

int x,y;

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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else cout **** ** * ** ********* and sum3 are not the * * * **


** * *** *** * * * * ** ** * 0;

}
answered by (-364 points)
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Hidden content!
* *

{
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}
answered by (-367 points)
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Hidden content!
* *** * * ** * *

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * * x * ** ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ***** "sum1 is " * * * sum1.geta() ****** '\n';

cout *** *** "sum2 is " ** ** ** * sum2.geta() *** '\n';

cout * ***** ** "sum3 is " * * ** * * sum3.geta() *** *** * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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else cout * "sum1 and sum2 are not the ** * * **

if (sum1 == sum3)

cout *** * * * "sum1 and sum3 are the * * * ** *

else cout ** * **** "sum1 and sum3 are not the * * * ***

}
answered by (-384 points)
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Hidden content!
** *** *** * ** *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ** * ** x ** **** * y;

Adder sum1;

Adder sum2(x); // sum2 is * ** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** ** *** * is " *** * ** sum1.geta() * * * * * '\n'; // prints is 0"

cout * ** * **** * is " ** ** * sum2.geta() * *** '\n'; // prints * ** is x"

cout * * * * *** is " *** ** * sum3.geta() *** * * * '\n'; // prints * ** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * * * * * and sum2 are the * ** ****

else cout ** * ** ** **** and sum2 are not the * ** *

if (sum1 == sum3)

cout **** *** ** ** * and sum3 are the **

else cout * *** * * * * and sum3 are not the *** ****

}
answered by (-384 points)
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Hidden content!
****** * *** * ****

using namespace std;

class Adder{
* * ** ** * * ** **
*** * * * * * * * ** ** * * * *** ** ** ** geta();
** * * **** * ** ** ** * *** **** * * * * * ** seta(int n1){
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***** ** *** * * *** * * * * *** ** **** *** *** ** * * ***** **
* * * * ***** ** * * ** * ** **** * **** * ** * *** ** ******* ** ** *** * * ** *** * *** * 0;
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* ***** ** * *****
* * * * ** ** * * **** ** ** **** * a;

};
** * * **
* ******* * * * ** ** a;

}









int main()

{

int x,y;

cin *** * * x ****** ** y;

Adder * *
* *

* * * // sum2 is ** * ** to x
*** * ** // sum1 is to y

cout * ** * * * is " * * * ** * * ** *** '\n'; // prints ** * * is * **

cout * * * ** ** is " ** *** ** * ***** * * '\n'; // prints ** * is ***

cout *** * ** ** * **** *** is " ******* * *** * ** *** ** * '\n'; // prints ** ** ** is

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * *** * ** and sum2 are the ***** *

else cout ** * ** ** * ** * and sum2 are not the * **

if (sum1 == sum3)

cout * *** * * * * *** and sum3 are the * * * **

else cout * ** * *** *** and sum3 are not the ***

}
answered by (-384 points)
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