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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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}



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{

int x,y;

cin **** ** x * ** * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; **** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ******* *** * and sum2 are the * ** *

else cout * * ** * * and sum2 are not the * ** *

if (sum1 == sum3)

cout * * * *** **** * and sum3 are the * * *

else cout *** * * * *** ** * and sum3 are not the *** *** * **

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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* **

{
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answered by (-367 points)
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*** * * ** ** **
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using ** std;



class Adder

{
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};



int main()

{

int x,y;

cin ** ** * x * * * * ** y;
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Adder ** ** // sum2 is * ** to x

Adder * ** // sum1 is to y

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cout * ** *** * ** * ** is *** * * * * * ** ***** ** '\n'; // * * ** is ** *

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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * * ** ***** and sum2 are the *** * *

else cout * ** *** * * and sum2 are not the ***** * *

if (sum1 == sum3)

cout ** * *** ** * * * and sum3 are the * * **

else cout **** ** * * **** and sum3 are not the * * ** **


***** * *** ** * * * ** *** * 0;

}
answered by (-364 points)
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Hidden content!
** ****

{

* * ******* x * ****** * y;
* *** * // * is ** * * to 0

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** * ***
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*** * ** * * ** * * * ** ****

}
answered by (-367 points)
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Hidden content!
* * * ** * *

using namespace std;

class Adder{
** * ** *** * * ****** ** * **
**** * * * * **** ** *** ****** *** **
*** * * ** * ** *** **** * * ** *** * * **
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};

Adder::geta(){
* * ** * * * **** * a;

}

int main()

{

int x,y;

cin * ** *** x * * **** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout **** **** * "sum1 is " *** * **** sum1.geta() * * '\n';

cout ** **** "sum2 is " *** * **** sum2.geta() *** ** * '\n';

cout ** * * "sum3 is " ** * ** sum3.geta() ** * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * "sum1 and sum2 are the **** * *** *

else cout *** * * "sum1 and sum2 are not the *** **** *

if (sum1 == sum3)

cout * * *** * "sum1 and sum3 are the **** *** *

else cout * * ** "sum1 and sum3 are not the * *** * *

}
answered by (-384 points)
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Hidden content!
** * * *

using namespace std;

class Adder{
** *** **** ** * * *
** **** * * ** ********* *** * * * *** **
**** * * ** *** ** *** * * * ****** * ** **
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* ** ** *** *** * ** **** * **** ******** * * * * * ** *** ** * * *** * ***** ** ** * *** 0;
* *** * **** * ** ** *** * * * ******* *
* *** ***** ** ** ******
* *** ** ***** *** * * * * * ** **** ** a;
* * * **** **** ** * *** * *** ***** * * * ** c;

};
** ** **
* *** * * ** * ** a;

}









int main()

{

int x,y;

cin * ***** * x * ** * y;

Adder sum1;

Adder sum2(x); // sum2 is * * to x

Adder sum3(y); // sum1 is initialized to y

cout ** **** * is " * *** * sum1.geta() ** * '\n'; // prints * ***** * is 0"

cout **** * ***** is " **** * sum2.geta() * ** '\n'; // prints ****** * is x"

cout **** * * *** * *** is " * * ** *** * sum3.geta() * * * * '\n'; // prints * ** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ******* * *** * * and sum2 are the *** * *

else cout ** ** ** *** ** and sum2 are not the *** ** ***

if (sum1 == sum3)

cout * ** *** and sum3 are the * *** **

else cout ** * * * * *** * and sum3 are not the ** * ** **

}
answered by (-384 points)
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Hidden content!
** ** **** *** * * *

using namespace std;

class Adder{
* * * * * * * ** ****** * *
* ** ** * * ** ** ** * * **** * * *** * geta();
*** **** * ** ***** * * ** * * *** * seta(int n1){
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******* * * * ** * * *** ** ** ** * **** ***
* * ** *** ** * * * *** * * * * * * *** * *** ** ** **** x){
* * *** ** ****** *** ** ****** * * * ** * c;
* * * * ** ** * ** *** * *** *** ** * **** **** * **** * *
* * * ***** * ** * * ** * *** ** ** **** * **** * * c;
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* *** * ** *** *** *** * * * * * * * ** ** ** ** * ** b){
*** * *** ***** **** ** * ** * * **** **** * ** * ********* ** * c;
******* **** **** ** ** * * * * ********* ** ** ** ** * * * * ** * **
*** * ** ** *** *** * * * * **** * * * *** ** * ** ** * ** * * **** ** * *** * * ** 1;

** ** * * ** * ** ** * ** ** * ** ** ** ** ** * ********* **** *
* * **** *** * ***** * ** **** * * ** ** **** * * * **** ***** ** *** * * * * ** * * 0;
**** * * *** ** **** * * ** * * ** **
* *** ** * ** ** ** ** ** ** **
* * * *** * **** * * ** *** *** * * ********* a;

};
* *** **
*** *** * * *** * *** * * a;

}









int main()

{

int x,y;

cin * ** x ** * * y;

Adder *****
*******

****** **** // sum2 is ****** to x
** * // sum1 is ***** * to y

cout * ** * ***** *** ** is " * *** *** * ** '\n'; // prints *** * * * is * *

cout * * *** * * * is " * * * *** ***** ** *** '\n'; // prints * * ** ** is * **

cout * * * ** * ** is " ** * ***** ***** *** ** ** '\n'; // prints **** ** ** is ** * * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * * * * and sum2 are the * *

else cout * ** *** * ** *** and sum2 are not the ** ** * ***

if (sum1 == sum3)

cout ***** *** * * and sum3 are the * ** * *

else cout *** * * * * ** * * and sum3 are not the ** **** *

}
answered by (-384 points)
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