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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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else cout * * * *** ** *** **** * and sum2 are not the *** * * * **

if (sum1 == sum3)

cout *** *** * *** * *** and sum3 are the **** **

else cout ** * * ** and sum3 are not the ** * * * **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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using * std;



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{

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cout **** * * * ** and sum3 are the * * ** *****

else cout * ** * * * ** and sum3 are not the * * *** *


*** * * **** * ** * ** 0;

}
answered by (-364 points)
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Hidden content!
* ***

{
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}
answered by (-367 points)
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Hidden content!
********** *

using namespace std;

class Adder{
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}

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{

int x,y;

cin ** * * x ***** *** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout *** ** * * "sum1 is " * *** sum1.geta() * ** * '\n';

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cout * *** *** "sum3 is " **** ** * sum3.geta() ** * * * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout *** ** *** "sum1 and sum3 are the ***** *

else cout * ** *** "sum1 and sum3 are not the * * ** * ** *

}
answered by (-384 points)
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Hidden content!
** ** *** * * * **

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin *** **** ** x *** * ** y;

Adder sum1;

Adder sum2(x); // sum2 is * * ** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** * *** * is " ** ** * * sum1.geta() ** * * * * '\n'; // prints *** * * is 0"

cout ****** * * * * * * is " * * *** sum2.geta() **** **** '\n'; // prints ** is x"

cout * *** * ** * * * * is " * * * * sum3.geta() *** * *** '\n'; // prints * * * **** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ** * **** and sum2 are the **** * **

else cout * * * ** ***** **** * and sum2 are not the ********

if (sum1 == sum3)

cout **** ***** ** and sum3 are the * *

else cout * * *** *** * and sum3 are not the * ** ** *

}
answered by (-384 points)
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Hidden content!
* * * * * * **

using namespace std;

class Adder{
** * * ** * ** * *******
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* ** **** ** * ** ****** * *** **** ***** a;

};
**** * *
** * **** *** ** ** * ** a;

}









int main()

{

int x,y;

cin * * * x * *** y;

Adder * ** * ****
* *

**** ** // sum2 is ** to x
* *** ** *** // sum1 is ** * to y

cout * **** ** * * ** is " ** * * ** *** * * ** * * * '\n'; // prints ** * * is ** ** * *

cout * * **** * **** * is " **** * * ** * * * * * '\n'; // prints * ***** is ** *

cout ** * * * ** * *** is " * * * * * **** *** * * * '\n'; // prints ** * * * is **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** ***** * and sum2 are the * *** * *

else cout *** **** * ** and sum2 are not the * *

if (sum1 == sum3)

cout * ** * *** ** and sum3 are the * * * * *

else cout * *** *** * ** and sum3 are not the *** **

}
answered by (-384 points)
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