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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ** * * * ** and sum2 are the ** ** *

else cout * ** * ** * * * and sum2 are not the * * * **

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cout **** ** * ** ** ** ** and sum3 are the * * ** *

else cout * ** ** ** ***** and sum3 are not the * **** **

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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using * ** * std;



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cout ** ** * * ** and sum3 are the * * ***

else cout ** * ** ** ** ** * and sum3 are not the * * * *


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}
answered by (-364 points)
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Hidden content!
* * *

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}
answered by (-367 points)
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Hidden content!
** * * *********

using namespace std;

class Adder{
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}

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{

int x,y;

cin * ** * x * ** **** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** ** ***** "sum1 is " * *** ** ** sum1.geta() *** *** '\n';

cout * ** * "sum2 is " * * ** * ** sum2.geta() * * ***** '\n';

cout * *** * "sum3 is " * * * * ** sum3.geta() ***** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

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if (sum1 == sum3)

cout * ** *** * "sum1 and sum3 are the ** ** * *

else cout * ** * ** "sum1 and sum3 are not the ** ** **

}
answered by (-384 points)
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Hidden content!
****** * * * * *

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin * *** * * x *** ** ** ** y;

Adder sum1;

Adder sum2(x); // sum2 is * to x

Adder sum3(y); // sum1 is initialized to y

cout * *** * ** * *** ** is " * **** * sum1.geta() * * '\n'; // prints ** * ** is 0"

cout * * * * ** * is " ** ** * * * sum2.geta() * ** * '\n'; // prints ** ** * is x"

cout ******* * ** * * is " ** * sum3.geta() * * * '\n'; // prints ** * ** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * *** * and sum2 are the ******

else cout * ** *** * *** ** ** and sum2 are not the ** * ** *

if (sum1 == sum3)

cout * * * ** * ** * * and sum3 are the * ** **

else cout * * ****** ** *** and sum3 are not the ** ** ****

}
answered by (-384 points)
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Hidden content!
** ** * *** ****

using namespace std;

class Adder{
******** ** * ** * *
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};
** * *
** * * * *** ** a;

}









int main()

{

int x,y;

cin *** *** x *** * *** y;

Adder * * *
*

* * ** * // sum2 is *** *** * to x
* ** * ** // sum1 is * to y

cout *** ******* ** ** is " * * * * * * ** * '\n'; // prints * ** *** is ***

cout ** * * * ** **** is " ** * * *** ** '\n'; // prints ** ** * is ** **

cout * **** * * *** is " ** * * ** ** ** * * '\n'; // prints *** is ** ****

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * ** and sum2 are the * * * **

else cout ** * * * * *** and sum2 are not the ** ****

if (sum1 == sum3)

cout ***** *** * * ** and sum3 are the *** ** **

else cout **** * * * * and sum3 are not the * **

}
answered by (-384 points)
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