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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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}
answered by (-364 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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}
answered by (-384 points)
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Hidden content!
** ***** * *

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class Adder{
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int main()

{

int x,y;

cin ** * ** * x ** * * y;

Adder sum1;

Adder sum2(x); // sum2 is * * to x

Adder sum3(y); // sum1 is initialized to y

cout ** * ** is " * ***** * sum1.geta() * ** * '\n'; // prints * * * is 0"

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cout * ** *** * is " **** *** * sum3.geta() ** * * '\n'; // prints * ** **** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * **** *** *** and sum2 are the *** ** * ***

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if (sum1 == sum3)

cout ** *** **** * ** ** and sum3 are the ** * ** *

else cout * * * *** * * * and sum3 are not the ***** * *

}
answered by (-384 points)
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Hidden content!
* * **** *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ** * **** x * * **** * y;

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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** ** * **** * * and sum2 are the * * ** *** *

else cout * * *** ** * * ** and sum2 are not the * * **

if (sum1 == sum3)

cout ** * * * ** and sum3 are the ** * ***

else cout * **** * ** ** *** and sum3 are not the ****** *

}
answered by (-384 points)
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