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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout * * ** **** *** and sum2 are the * * ** *

else cout * **** ** ** ** * ** and sum2 are not the * * * **

if (sum1 == sum3)

cout * * ** * ** and sum3 are the * * **

else cout ** * *** * * * * and sum3 are not the ** ** *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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{

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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * * * and sum2 are the **** * **

else cout *** * * * ** * * and sum2 are not the ***** *

if (sum1 == sum3)

cout *** *** and sum3 are the * *

else cout **** * * and sum3 are not the * *****


**** ** * *** ** 0;

}
answered by (-364 points)
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Hidden content!
* **

{
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}
answered by (-367 points)
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Hidden content!
*** ***** * * ***

using namespace std;

class Adder{
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{

int x,y;

cin * * x * ** * ****** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** * "sum1 is " ***** *** sum1.geta() ** * ** '\n';

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cout *** ** *** "sum3 is " * **** sum3.geta() ** * ** ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * *** "sum1 and sum2 are the * **

else cout * * * * * "sum1 and sum2 are not the * *** ****

if (sum1 == sum3)

cout *** ** "sum1 and sum3 are the ** ** *

else cout **** ** "sum1 and sum3 are not the ***** *

}
answered by (-384 points)
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Hidden content!
**** * ** ** ***

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ** * ** ** x * * * ** y;

Adder sum1;

Adder sum2(x); // sum2 is * *** to x

Adder sum3(y); // sum1 is initialized to y

cout * * * ** *** is " * **** * sum1.geta() * '\n'; // prints ** * **** is 0"

cout * * * * ** is " ** ** *** sum2.geta() * * * * '\n'; // prints * * is x"

cout * ** * * * * is " * * sum3.geta() * ***** '\n'; // prints * * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * *** * * and sum2 are the *** ****

else cout * ** * *** and sum2 are not the * *** * *

if (sum1 == sum3)

cout * ** ****** * and sum3 are the * * ***** *

else cout * ** ***** ** * **** and sum3 are not the ** * * *

}
answered by (-384 points)
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Hidden content!
* ** * * ***** **

using namespace std;

class Adder{
* ** * ** ** * *** * * *
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* * *** ** ** ** ** *** * * ****
** * * * * ** ** ***** * ** ** *** * a;

};
*
* * * ** *** * * * a;

}









int main()

{

int x,y;

cin * * *** * x * ** * * ** y;

Adder * * *** *
* ** ***

* *** // sum2 is * * ** to x
* **** // sum1 is * ** to y

cout * * **** ** * * is " *** *** ** * ** ** '\n'; // prints * * ** ** is *

cout * **** * * ** * *** is " * **** ** * ** ** * * *** '\n'; // prints * ***** * is ** ***

cout ** * * * ** ** is " * *** * * ** ** * * * * '\n'; // prints *** **** is ** * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * **** *** and sum2 are the ** *** *

else cout **** * ** * ** * and sum2 are not the ** * * * *

if (sum1 == sum3)

cout *** * * * ** and sum3 are the ******* **

else cout ** * * and sum3 are not the *** * *

}
answered by (-384 points)
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