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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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int main()

{

int x,y;

cin * * ** x * ** y;
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sum1 += x; ** x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** * ** and sum2 are the *** ***

else cout * *** * * ****** ** and sum2 are not the ** * * * *

if (sum1 == sum3)

cout * ** * * * * * * * * and sum3 are the * * ** *

else cout * * * and sum3 are not the ** * * * ***

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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** * * *

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answered by (-367 points)
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Hidden content!
* *

{
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*** * ** x * * * y;
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answered by (-367 points)
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Hidden content!
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};



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{

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cin * ** ** x ** ** y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * * * * and sum2 are the ** **

else cout * * * ** ** and sum2 are not the ** * *

if (sum1 == sum3)

cout * * * * **** *** and sum3 are the * **** **

else cout **** * * * * ** * and sum3 are not the ** * *


* * ** ******** * ******** 0;

}
answered by (-364 points)
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**

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}
answered by (-367 points)
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Hidden content!
* * * * * ****

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * ** * * ** x ** *** ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout *** * ***** "sum1 is " **** ** * sum1.geta() * * '\n';

cout ** "sum2 is " *** * ** * sum2.geta() ** * **** * '\n';

cout *** * "sum3 is " *** * * sum3.geta() *** * * ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * * *** "sum1 and sum2 are the * ** *** *

else cout ** **** "sum1 and sum2 are not the ** *** *****

if (sum1 == sum3)

cout **** "sum1 and sum3 are the *** **

else cout **** *** "sum1 and sum3 are not the * * * **

}
answered by (-384 points)
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Hidden content!
** *** *** **** *

using namespace std;

class Adder{
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};
** **
****** * *** *** * * **** *** a;

}









int main()

{

int x,y;

cin *** **** x *** *** **** y;

Adder sum1;

Adder sum2(x); // sum2 is * ** to x

Adder sum3(y); // sum1 is initialized to y

cout *** ** ** ** **** * is " * * * sum1.geta() *** * ** '\n'; // prints * * * * is 0"

cout * ** * * is " ** ** * * *** sum2.geta() * * * *** '\n'; // prints **** ** is x"

cout * *** * * is " *** * ** * sum3.geta() ** * * ** '\n'; // prints ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** *** ** * and sum2 are the ** **

else cout * * * *** * and sum2 are not the * * * * *

if (sum1 == sum3)

cout ** * ** * ** * and sum3 are the * ** * * * *

else cout * ** ** * * * and sum3 are not the * ***

}
answered by (-384 points)
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Hidden content!
* * * ** *** **

using namespace std;

class Adder{
* * * ** ** *** **** ***
* ** ** ** **** ***** *** ** ************ * geta();
* ** ** ** ** **** ** **** ** ** * * * * * seta(int n1){
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* * * * * *** * * ***** *** ** *** ** * * * * *** *** * **** ** * **
** * ** * * *** * ** *** * *** * * ****** **** ** **** * *** * ** * * * * 0;
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*** ** * * * * ** * ** * ***
* * ** ** * * ** * **** * *** ** *** ****** a;

};
** **
**** *** * ** *** ** * a;

}









int main()

{

int x,y;

cin ** * ** x * * *** y;

Adder **
***** *

**** // sum2 is *** * to x
* * * // sum1 is * to y

cout *** * * * * * ** *** * is " ** * ***** * ** * ** '\n'; // prints * ** *** is *** *

cout ***** * * *** **** is " *** *** * * * * **** '\n'; // prints *** * *** is ** *

cout * ***** * **** * * is " ** ** ** ** *** * **** '\n'; // prints is ** ***

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * * ** * * * and sum2 are the

else cout * * **** * * ** * ** and sum2 are not the * * * *

if (sum1 == sum3)

cout ** * *** **** * * and sum3 are the * **** ****

else cout **** ** * * * and sum3 are not the *** ** * *

}
answered by (-384 points)
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