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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum3)

cout **** *** * and sum3 are the * * * **

else cout ** ** * ** * * * * and sum3 are not the * ** *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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}
answered by (-364 points)
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* **

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answered by (-367 points)
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Hidden content!
*** * * * * * * *

using namespace std;

class Adder{
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{

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cin *** * * x *** * y;

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if (sum1 == sum3)

cout ** ** "sum1 and sum3 are the ** * * **

else cout * ** ** * "sum1 and sum3 are not the *** * *

}
answered by (-384 points)
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Hidden content!
* **** * * ** *

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class Adder{
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int main()

{

int x,y;

cin * * ** x * ** * y;

Adder sum1;

Adder sum2(x); // sum2 is ** to x

Adder sum3(y); // sum1 is initialized to y

cout ** * * *** * *** is " ***** sum1.geta() * ** ** '\n'; // prints * * * * is 0"

cout * ** * * ** ***** is " * * ** sum2.geta() * * * '\n'; // prints *** * * is x"

cout * * ** * * is " *** * * * sum3.geta() * ** * * '\n'; // prints ** ** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** * ** ** * * and sum2 are the * * *

else cout *** * ** *** *** and sum2 are not the *

if (sum1 == sum3)

cout ***** ***** ** * ** and sum3 are the * ** * * *

else cout * * ** * *** and sum3 are not the ** ** * * **

}
answered by (-384 points)
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Hidden content!
* * *** ** ** * *** **

using namespace std;

class Adder{
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};
* * ** **
*** ** ** ** ** * a;

}









int main()

{

int x,y;

cin ** ** * x * ** * y;

Adder * *
* * * *

* **** // sum2 is *** to x
** * // sum1 is ** *** to y

cout ******* ** is " **** *** ***** * ** * * '\n'; // prints * * is *** *

cout ** * *** ** ** is " * * * ** * ******* ** '\n'; // prints ** * ***** is * *****

cout * ** ** * **** ** ** is " *** * * *** * '\n'; // prints *** ** * is * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * *** * and sum2 are the ** *

else cout * * * * *** and sum2 are not the * * * *

if (sum1 == sum3)

cout * * * ** * and sum3 are the *** *

else cout * * ***** * * and sum3 are not the ** *** *

}
answered by (-384 points)
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