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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

int x,y;

cin * **** x ** * * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * *** and sum2 are the * ***** * *** *

else cout ******** * *** **** * and sum2 are not the *** ***

if (sum1 == sum3)

cout ***** *** * ** ** and sum3 are the * ** *

else cout ** *** ** **** ** *** and sum3 are not the ** *****

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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}
answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
** *

{
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answered by (-367 points)
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* ** **** ***
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class Adder

{
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};



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{

int x,y;

cin * *** * x * * *** y;
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Adder *** // sum1 is * ** to y

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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** ** * ** ** *** * * and sum2 are the *** *** *

else cout * ** * ** **** *** and sum2 are not the *** **

if (sum1 == sum3)

cout ** ** * ** * ** and sum3 are the ** * * * * *

else cout * ** ** *** and sum3 are not the * * **


*** *** * ** * * * * * * 0;

}
answered by (-364 points)
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Hidden content!
*

{
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}
answered by (-367 points)
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Hidden content!
* * ** * *** *

using namespace std;

class Adder{
** ** ** * * * * * * * *
**** *** *** * * * * ** * ** ** ** **
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};

Adder::geta(){
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}

int main()

{

int x,y;

cin *** ** * *** x *** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout **** * "sum1 is " ** ***** sum1.geta() *** * * '\n';

cout ******* "sum2 is " ** * * sum2.geta() ** ***** '\n';

cout ** * ** "sum3 is " * * * sum3.geta() ** *** ***** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout ******** "sum1 and sum2 are the **** ** *

else cout ** ***** "sum1 and sum2 are not the * **

if (sum1 == sum3)

cout ***** * "sum1 and sum3 are the ******* * **

else cout * ** ** "sum1 and sum3 are not the * ***

}
answered by (-384 points)
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Hidden content!
** *** * * *

using namespace std;

class Adder{
** *** * **** * * * ** ***
*** * **** ** * ****** * ** * ** * ***
**** * ** * * * * * * * * * ** * * * *
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*** * ***** * ** ** * ** ** ***** *** ** * c;

};
** * *
* * *** * * *** * ** a;

}









int main()

{

int x,y;

cin * x **** ** y;

Adder sum1;

Adder sum2(x); // sum2 is *** to x

Adder sum3(y); // sum1 is initialized to y

cout * * ** *** **** is " *** *** sum1.geta() * * **** '\n'; // prints * * ** is 0"

cout * ** * ***** * is " * * ** sum2.geta() * * '\n'; // prints * is x"

cout ** * * ** is " ** ** *** * sum3.geta() * ** ** '\n'; // prints * * ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ***** ** ** ** * and sum2 are the ** * ***

else cout *** * * * ** and sum2 are not the * * ***

if (sum1 == sum3)

cout ** * * * * ** and sum3 are the ** * *

else cout * ** ** * * and sum3 are not the * ***

}
answered by (-384 points)
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Hidden content!
******** * **** *

using namespace std;

class Adder{
* * * ***** ** **** * **** *
* ** * ** **** * **** *** **** * ** * * geta();
* * * *** * * ***** ** * **** ** * ** * seta(int n1){
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*** * ** ** * * ** ** ** * **** ** * ** * ** * * * x){
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*** ** **** * *** ** *** * * *
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* **** * ** ** * *** ** *** * *** ** * ** ** ** * ** * *** ***
* * * * ** * **** ** * *** *** ** ** * * * *** ****** * * *** ** * ** * * 1;

******** ***** **** * * **** **** * ** ******** ** ********
** * * ** *** * * * ** * * ** * **** * * * ***** * * * ** * * ** * *** * * ** *** * ** 0;
** * ** * **** *** * * * ***** * *** **** ** ***** * **
**** * ** ** **** * * **
** ** * ** * * * * ***** * ** * * ** ** a;

};
*****
* * * **** * **** * a;

}









int main()

{

int x,y;

cin *** * * * x ** y;

Adder * ***
* * *

* ** // sum2 is ** * * to x
** * // sum1 is ** * to y

cout * * * ** * * is " * ******** ** * * * * ** * '\n'; // prints * * ** is * **

cout * * * ******* is " * ** ** * ** * * * *** '\n'; // prints * * is * ** *

cout * *** * * ** is " * * ** ** **** ** * * * '\n'; // prints * * ** is * ***** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * *** * ******** and sum2 are the * * ***

else cout * * * * **** * and sum2 are not the *** * * *

if (sum1 == sum3)

cout * * * * * * and sum3 are the **** **

else cout *** ***** *** *** and sum3 are not the * * * **** *

}
answered by (-384 points)
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