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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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else cout * ** *** * *** * ** * and sum2 are not the ** ** *

if (sum1 == sum3)

cout *** * * * * *** *** and sum3 are the ** * **

else cout *** ** * ****** * and sum3 are not the ** * * ** *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum3)

cout *** **** *** * and sum3 are the ** ** * *

else cout *** ** *** * * * ** and sum3 are not the ****** *


**** *** * ** ** 0;

}
answered by (-364 points)
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*** ** *

{
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answered by (-367 points)
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** * ** * ** ** **

using namespace std;

class Adder{
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{

int x,y;

cin * * ** * x *** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout * *** "sum1 and sum3 are the * *

else cout * * "sum1 and sum3 are not the * * ** * *

}
answered by (-384 points)
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Hidden content!
** ** ** *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ***** ** * * x **** **** y;

Adder sum1;

Adder sum2(x); // sum2 is * to x

Adder sum3(y); // sum1 is initialized to y

cout * **** * * * * is " ** * sum1.geta() * * ** * '\n'; // prints *** * is 0"

cout ***** ** **** * is " *** **** sum2.geta() ** **** * * '\n'; // prints ***** ** is x"

cout * * ***** * * ** * is " * ** ** sum3.geta() * * * *** * '\n'; // prints *** * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * * * **** and sum2 are the * **

else cout ** ***** * * * * * and sum2 are not the * ** * **

if (sum1 == sum3)

cout ** * ** ** ** ** and sum3 are the * * * *

else cout * ** *** and sum3 are not the * ** * *

}
answered by (-384 points)
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Hidden content!
* ** * **

using namespace std;

class Adder{
* ***** *** ***
*** * * * *** * ** ** * **** *** * * * * * geta();
**** ** * ***** ******* * *** * *** ** * seta(int n1){
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*** * * ** * *** * ** *** * ** ** * ** * ** ** ** * * * *** * * * * *** ** ** *** 0;
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** ** * * * ** *****
*** ******** * * ** ** * * * ** * a;

};
** * ****
* * * * * ** * ****** ** * a;

}









int main()

{

int x,y;

cin *** **** ** x ** * * y;

Adder * *** *
* ** **

**** ** * // sum2 is *** ** to x
* * * ** * // sum1 is ** ** * * to y

cout ** * * * * * ** ** is " *** * *** * * * * * * * '\n'; // prints ** * ** is ****** **

cout * * *** * ** * ** is " *** ** ** ** ** ** * '\n'; // prints * ** is ** **

cout * * **** * ****** is " * * * ** * ** ** **** ** * '\n'; // prints * * * *** is ** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ****** * **** and sum2 are the ***** **

else cout * * ** * * * and sum2 are not the * ***** ** *

if (sum1 == sum3)

cout **** ** * *** and sum3 are the *** **

else cout * ** * ** *** and sum3 are not the ** * * ** *

}
answered by (-384 points)
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