Final Exam 2 (20%)

1 like 0 dislike
2.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.2k views

37 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
* *   *  **      ***   *  ** i,flag=1;
**** * *  * *    * *   *  * *       *** **  ** *** * ** * 
** *     ** ** **   ****   ** * *  *** *    ** * * *    *** *  ***** *  
*    *** ***********  

*      ** *   * **        *  * flag;
}


char prefix[100],txt[100],i;

int main(){
 * ***** ** * ** ***** *    * ***** * **
   *  * *      ****    *   *    ** *****  ** *

* **  * **  *  *** **** *    ***** * **
*** *    *   * * **** *  **   * * *    **  *** ** * ****  * * * ** *     * * ** **   *  * **  **   *
  * *  **** ** * ** *  *  *** ** *** * * ** * ***********  * ***  is a prefix of ",prefix, txt);
   *  ***  * * *** *  **  ** ****   **   *  *    *****  ** **  *****   ************  ****   *  
**     ***   *****  * *  *  *
**    *     *** ** *    ***   {
   * *   *****  ** *      *  *    ** ****  *** *   ** *    * *  *** *** * ** *** **** ****   ** * **  *  *   **
 ** **  * ***  **  **     ** * ***** ** ** *   * ******* is not a prefix of ",prefix, txt);
*  **    *** ******  *   * ** ** **  *** *   *******   * *** ***    ** **   *  *  **  ***  ** **  * **    
********    * *   *  ***   **
* * *  * *     *  ***   * **  ** 0;
}
answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*    * ***  **  ****
 ****  * ** ****   ** 
char prefix(char string1[],char string2[] )
{
*  **     *  ****   *  *  i,a;
 **** * ***   *   *    **   ***   
*   * **  * *   * *  **  * *  *  ** *
   * ** ** * 

** ** ** *  * *** *       ** * * **    **  * 
  {
**  *** * ** * * **  *  * *********** ****  * * *  ***  ** **
 ***  **   * *  *** *  * * *  *   ** **** * ** *  
*   * * ** *  
** **** *  * *  * ***    **  **  
   * *  *  ** * ***  **   * * * is a prefix of %s", string1,string2);}
* **   *  *** *** ***** * *   *** *   * * is not a prefix of %s", string1,string2);}
  **   **   **  **
 *   ***  * ** 
*    *  * * *
*  *   *  * *    * * ***  ***   *  * *** ***** *  *  *   * *****  *   ** * * *
* ** *  **  **
  * *  *  *   **  * * * * * ** *** **   *  *** *    *
**  * *  ****  * *     *   * * *  ******
* * *   **        * ***** **  * * **** **   *** * * **  * *   ** *    ** *  
 * *  *  ******** * *  ****     * * *  * * *
  ** *    * 
 *     * ** ** ** *** * *** ******
*  *** *  *   *     **      * * *  is a prefix of %s", string2,string1);}
***  ** *  **   *  *   * *** *   * ***  is not a prefix of %s", string2,string1);}
** ** *   ****  

}
int main(void)
{
* ****  *** *   *  chaine1[1001], chaine2[1001];
* ***  ** **  *  * * *    *  *   * *  ** * *
 * * * **   *   * ******  ***  * ****   ****
******  **  * * *  **  *     **  
**   ** ***  ** *  0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
**   ** ****  *  *** * *
   * **** *  ***    
int main(void)
{
 * *****     ** ** *** ** str1[100],str2[100],i;
 * * * *****  **** ****   * *** * *   *** * ****** ***  ****
   *** *  **  ** *   * *  **  ** *  ** * ****  *   
***  ***  **   ** ****  *** 
*   * * * * *******  **  ***   *  *     *   * *  ******* *  ** ****  **
*   *  *     ** **  *  ***  * ** ** **    ** *  *****  ********    *   *******  *  ** *** * *   is not a prefix of %s",str1,str2);
   *    *    **  ** *   *****  * * ***** * ** ** *** **  * ***    **     ** **  ** 0;
*  * * *   **   ****  ** ***  ** *** *  * * * ***** *      * * *****  * * ***  * *
****    ** * *     * ***** 

 printf("%s is a prefix of %s",str1,str2);
*  *     * *  ****   *  ** ** ***   0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
**  *    *  ****   * ** *********  str1[100],str2[100];
* *  *  *******  ***   * * * ** * i,c=0;
   **  *   ******** *** **     ** *     **** ** *
* * **  *   **  * ******* ** **   * **** *   *** *** * ***
* * **  ***     **   *      ** *** 
**** ***  *  *      *    *
*    * *** * ** * *   *  **       ** *     *  **** * ******* *
***    *** ***    *  * ***   * *  **   ** ** ** ****   * 
 *   **  *  ** ***  ** * * *  * *    * ***    *     * *  *  **** * * * ** * ** *  * * * 
*** ** **  *    ****    *** ***   *   * **   * *   **   
    }
**    *******    * * *  * * *
   **    * ***  *         **  
** ** *** * *** **  * * ***     **** **     **   *** ** **  ** *  is a prefix of %s",str1,str2);
  *  **     ***  *  * ** **
 **** **   ** **  ** * ** * ****
   **      * ****   *   ****
* ** **    ***  * *** *    * **   *  ** * * *   **  * * * *  ** *  **** is not a prefix of %s",str1,str2);
   * * **  * ***   ***** **  ** *
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
* * **   *  *   * ***** *  * ***** pre[100],str[100];
*  ** ***** *   *    ** *    *  ** * * i;
 ** ** ***   *  ****  *****  ******   ***  **   * * *****    *
*       **     ******    **   *** *   **** *****  *    * **
** *   * * *** ******   **       *  *** **    **   ***
    {
  *    ***    * *   *****     ***  * *** ***   *  *****  *** *    * **  *   *    
   *  *   ***  *  *    **  *** ** ** ** *   *    *** ** *    *   *** **  *****   *  ***       *
 *  *** * **    * **   ***  * *      ** *  ***      ****** *   **  * *** *   ***  *        * ****    **  ****  **    *  *   *** is a prefix of %s",pre,str);
* *** ** *****   *** ** *   **  *    *  *     ** *** **  *   ***  * *     *** **** *** * ** * * *   **    ** ** 
 *   * *  * * *  *****              *** *   ** *  ** **  * *** **      ***  ** * 
   *** **** * ***     ** ***   *  ********* ** ** *** **     

  ** ** *     *** ** *  ** ****** **  ** **** *      * *  * *** *  ***
*    ** *   ***  *****   ** * ***    *   **  **    * ** **     * **** *    * **  ***     **   ** ***  * **  ** is not a prefix of %s",pre,str);
    * *  * **  *  **   *  *  * *   *   * ***      **   *   *   *** ************  ** ** ***  ***  ***   * 
***   * * * **       * *  *   * * *  * *  * ** *            * * * * * ***  
    }
    return 0;
 }
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
* * **** **  ** * * ** *        str1[100],str2[100];
** ******** * **  *  *** * *** *** i,c=0;
* *  ** ** ** * **     ** ***  *** * * *  ****** * * * * 
***  *   * * *  ****** *** *  ** *** **  * 
* ** *** * ***  ** *   * * * **     **  ****  *
* *  * * * **   ** *  ** * **  * 
* * **  *  ***  **  *    ** * * *** *  *   *     ****  * **       *   * *
***  *     * ***  *****  * ***  * ** *  *    ** ** * *  * *
** * ** *****  *   * ** *** *** **  ****    *  **     *** **    *    ** *  ** **** *   
 ***** *     ****** **  * ***     * **   *** ****
    }
*  *  * ****  ***    *     **   * *
  * *  ***   ** *      *  ***
 * *  *** ** * * * *    *   *  * *     *  * *  *     * *****   is a prefix of %s",str1,str2);
* * ** *  **   **  * ** ***
*    * ** *   * *      * **  
   * **** *** *** *** * ***  ** ** 
** *   ** *** *    * ** **  * **   *** **** * **    *  **   ***   ***  *  is not a prefix of %s",str1,str2);
* **  ** * ** ****  *** * 
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ******   *    
#include *****  *** * ** **
#include ***** *    ****   

int main()
{
**  ***** **   * *   * **   *  prefix[100];
*     * *  * *  * **     ** word[100];
*      * * * * ***   ****   ** *****    %s", prefix, word);
***  * *   *  * *   *** *  *   i;
** * *  * ****   **** ** ** *  = 0; i< strlen(prefix); ++i)
*  *  *    ***    **   *
 **  *** *    * *  **  **   *   ** * *  * * **    ***    * ***   
**  *   ***     *  *   **   *    * **  *** ****  
** * ** *   **   ** ***    ****   **    *** *    *     * ****  *  ***  *    * ** *     is not a prefix of %s", prefix, word);
 * **   ** *  * ****  *  *     * **********   *     * *     *   **       *     *   * *    0;
  ***** *  *   *** **      **  * ** ** *** ** **** * ****   ***
 ******        *    **   *    
**  ******  * ***    * ** **  ** **  *   is a prefix of %s", prefix, word);
 ****  * *** ** *  *    **    0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  ******   **  *******  ** * * n,count;
**      *  ***   ****  **  * a[100],b[100]={0},c[100]={0};
** *    **    *  * *    *****  *****  **  ***   %s",a,b);
*  ** *** **** * * ** * **  * * *   *
** * *    *****   **  ****** *  * ***      *   * ** 
 ** * *    * *****       ** *   **  * *    * * ** **
 **    **     * ***** ***    *
*   * ** **  * **** ***** * ** ***   ** * *** * ** * * **  * *****   *
    * ** ****   *   **   *** ** 
  ***  *  *  *** * **   *  **** *  * *   *   *     * ** ***
      *   * ** **** *  *  (strcmp(a,c)==0)
    * *   ** *   *     *     
 * ** * *   ** ** *  *** *  *       **** **  ** **     ** *  *      *    is a prefix of %s",a,b);
  * * *       *   *   *    
      ** *   ** *   * * **
 *** *** ** *       *   *  *  *
 * *  **  *   ** * * *****  * ** *  * * ****      ***  ** * * ****   is not a prefix of %s",a,b);
*****  * *** *  * * ** * *  *  * 
   * ****  * **   *  * * * **** ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
   *** * ** ****** ***  *  *    String[50],string[50];
** *  * *   *    *    *   **  a,b=0;
 *        * * *   * * * * **   *  ** * *  * ** * *  
  ** **** *    ***   ** *  *    *********   * ****

*  * * ** **  * *     * **  *   ****   * ** * **
**  **  * ** *  *** *  **** 
 *  ***    *  * **   *** *** *  ***    *        * ** * *** ** * *
    * * *  *     *  ****  * * * *** * **  * **   
** ***** *  **    * ** **  ** ****   **   ****  *** ** *   *  ** ***** * *  *
  ** **     ****       **    ****** ** ***   **** 
    }
   * * ****  **  *    **** *   * 
 * ** *      * **  *  **** *
  ****     ** * * ***  *** *******      * **** * *     *   ** is a prefix of %s",String,string);
*  *********  ***    ***  *
  *** *  **  ****  ***  * **  
*** **  *  *     *  *  *      *
*    ** ****** * *  * ** * ***  * ** * * *   * *      *  **   ******* is not a prefix of %s",String,string);
* ** * **** *  *   **  *****
  return 0;
}
answered by (-107 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   * *    **  * 
#include *** * * ** * * 

int main()
{
* ** *    *     * *  **** * ****  *  a[100],b[100];
* * *****  * * ***   **   *  *   %s",a,b);
  *  * **  *  *** *   ***  *   i,j,prefix = 1,len = strlen(a);
* ***  ** * * *  * *****    * ** = 0 ; i < len ; i++)
   * *  ****  ***  * * * ** 
**  ****  *** ****     *** ***     *      **     **** ***  * *  != b[i])
*  * *   **  **   * *  **** **** *   *     ***   
  ******** **** *** ***   *   *  * ** ** *   * **  *****    **** ** ***  *   ***   *** * ** = 0;
 *   **    * * **  *** ** * * ***** ******     * ***   * *    **  ** ***  *   *  ***  *   **  * is not a prefix of %s",a,b);
    * * **   **    **  **  *  * ** **  * ** *******     **  ** ** ** * *****  *** **  *  *
 *  *  **** ** *** *  ** **** * ** *  **     

 * * ** * ***        * **  *   
* * * ** **  **  * ** **  ****   == 1)
*   *    * *     *    ***** *  ** *    ** *  *  ***   *  * * ****  ****** is a prefix of %s",a,b);


*** **  * ****  *   * *  * * * ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.104
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.1k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.5k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 453 views
12,783 questions
183,443 answers
172,219 comments
4,824 users