Final Exam 2 (20%)

1 like 0 dislike
16.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 16.8k views

37 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
 *  *  ****   ** **  ** * ** i,flag=1;
* ****  ** ****   *  ** **   * * *  *****  * ** * ****  
* ** *   *   *  ** *    *****   ** ***  ** **    ** **  *  *  **  * *
  ** ** ** * ** *******      *

 *** *  *  *   **    **   *   flag;
}


char prefix[100],txt[100],i;

int main(){
*   * **   * * ***      ****  * *** *  * * * 
* * * * *  *   * **  * * *  *  *  *  *

* **  **** *   *** **   * ***  * *      *  *
*   *  ** *** **  * **   ****   * * * * ** *** *  ***    ******* * **   *  ** *** **  ****       *
 ****  * *    **  *   *  **  *****  * *  *  *   ***   *   *** is a prefix of ",prefix, txt);
 ***   ****  *  **  ****     * * **  *   ** *****  *    ********  **  ** *******   *  * **  * *  *
* * *  **** * ****   **   * 
**   *  *     *   *  ***** ** *  {
 ** * ***   **     ** *******  *** **    **** **   ***  ** **** ** * * *  *   ***    *  *  * *****
*** *  ****** ** * * **  *****      * * * *    **   *  ****     * *   is not a prefix of ",prefix, txt);
*** ***    *  *  ** * ******* ******  ****  ***  *** **  ***     * *     * * ** * **   ******   * * 
**    **** *  *** *** **
** *** *  *  **        * ** ** * 0;
}
answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * **** *   * * * * *
* **** *   *  **
char prefix(char string1[],char string2[] )
{
******  *  *   **** ** i,a;
* *  * ***   **   *     ****
  *****  *** * * *  ***  ****   * * 
*  *   *    

***  ******   * * * * * ***   *  *   * *
  {
**  **** *  *** *  **   * * ***    *   ** *  **   *  *
 *    ** *   **  **    **  * **   **** *  *** *   * *
**   ** *  
 *  *    *** **  ** *** * ***
  * ****     *   ***  ****  *  is a prefix of %s", string1,string2);}
**** *  ** ********  *   *    *    * *  is not a prefix of %s", string1,string2);}
* *    *  * 
**** * *      **  * *
**  *      * 
* * *  *    ****  * *** * ****   ** *  **   **  * * *****   * *     * *  * **
 ***   **  *** * *
***  * * * * **   *    **  *  *** **     ****      **    
** **   * ** * * * * ** ******   ***   *
 ***  **** ***  *** *** * *      **   *    * *  *     ******* *  
***  *   ** **      *   ***    *  * * *  * 
*     ***** **
 ** *     * *  * * ****    *
*     * *  ** **    ***  ** **   is a prefix of %s", string2,string1);}
  ** * *   *** ** *  * *       ****     is not a prefix of %s", string2,string1);}
**** *  ***** 

}
int main(void)
{
*  *  ** *** ** * *** chaine1[1001], chaine2[1001];
*    * ***   ****** * **  *   ** * ***
* * *  ** **  *****    ** **     ** ** 
* * *  **   ****  *   * ** *
*  * **  *   ***  * 0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
* **** *** *  *    
   **** **    *  * * *
int main(void)
{
 * * *     ***  **  ** * * **   str1[100],str2[100],i;
*    * ***  *  ** * ****    ** *  *****  *****
     ***   ** ****     ******* ** ******    *  * * **
 *** **  *  * * **   *** * **
 ** ** *    *    ** *     **  * ** *  ** *******    ******* * *  * 
 ***     * ** ** *  *** *   * ******** ** * **      *   * **      *  * **  ***  * ***  ***** ***  * ** is not a prefix of %s",str1,str2);
** ******    *  ********** * *  *** ** *** ** *  **  * **   ***** **        ** *** 0;
* *** **  * ** ** * *  *** **** * *** * **  ****  **  *   ***       *    ***  *    ** * * *
* **  *  * ****  *  * *  * * 

 printf("%s is a prefix of %s",str1,str2);
 * **  *** *** * *    ** * **  0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
* ****     ***********  *   str1[100],str2[100];
   * *** ** ** * *** ** * * *  i,c=0;
    * ** *******  *** *  **    **  *** *    ** **** * 
*  *   *** **  ** ** ** ***   ** **  *    ***
** *** * **     *  * *  ***** * ** *    *****  ** 
*  ** *    * * ***  *   * 
*   *     *  **  ***  ** **   ***   ****  *  *** *        * *** * * 
*   *** **   *  * **  *  *  *    *  *** **  *   * *** * 
** ** **  * **   * **  *  *   * * *  * ** *   *  ** *********   ****   * ***** *
  ***       * *   **    **     *    *   ******  **
    }
*  *  ** * **    * *  * ***  * *** 
* **** **  ****   *  ******  
 *     ** * * * ***   **  * **  ***       *    *** * *** *** *  is a prefix of %s",str1,str2);
***** *  * *** *    **** ***    *
          **      ** ***  *** *
 * *    ** * ** * *** *   
*  ** **    ****  ****  ** ***   *****  * *   ******  *   * * *** is not a prefix of %s",str1,str2);
***  **** **    * *     * * **  *
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
 *      ** *******   ****     * *   * pre[100],str[100];
* **** *   ****    **  *  ****    ****  i;
 **   **  *  * * *  * **  ******  *  *   **** *** * * * ***
 *   *  **    * *    *   *   **** * *** ***      *****   
  *    ** ***    * *  * * ** ***  * * ** *   * **   *
    {
 *  **   * * **  ** ***  * ***        *   *  **** * ** ***  * *   **** ***** 
****  ** *  *       * ** **  * *  *   ***  ******  *** **    ***  ** * *   ** ****  **    *  
 * * *  *** *  ***  **** * *   ** ****  ***********  ** *  *     ** ****      ***   *  ** ***  ** *  **** **   ***  * * *** *****   *  is a prefix of %s",pre,str);
 *****   **** * * ** * *  *   ***  ****        *** ***   ** * *** **         ** **  *  ** **** ***** ***  *** ****
** *    *  ** **** *** *   * *  *** ******   *    ** *     * *** *   **  ** ** ** ** **  
    *    *   ** ** * *  **** ** * ** **  *    ***  * *   *   

** *  **    * ***** *** **   *      ***** * *   * *  *** **  * *    ** *
****  * ****  ***  * *  ** * * *      * ******    * *** ** *  **   ***** *   * ***  * ** **    *****  * *    **    is not a prefix of %s",pre,str);
    *  *    * * * ***** * *  *  *  ** *** **  * *****   *****     *  *  *  * *  ***   *    *** ***     
**  ***       * **  **   * ****  * *** *    *  *  *  *** *  * **   * * 
    }
    return 0;
 }
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    * ** ****** ****  * * *  str1[100],str2[100];
   **** *   * ** * **     *** i,c=0;
  *****  *    * * *** * **** * *    * ** **
 *** **** *****  *    *****   *    *     *  * * **  
   **  *****  *   * **     *  ***  ***  ** 
 ***  **  *  **  ****  ****
  * * **    ***  ***        *  * * ******  * **  ******   ****   *
   ***   *     **** **** *   ***** ***    * ***  *  * * 
** * ***  ***   * ** *** *  * **** * **   * **** ****  *  ** * *    * * *****  * *
***  * *   ***   *  **  ** * *** * * **  **    ** * **  
    }
* * *  **   **     * *** ** **  * *
* *** ** * ** * ** * ****     *
* ****  *** ***    * * ** ** *  *   * ****      ** * **   *  is a prefix of %s",str1,str2);
**     * *  ********* ** * **  
*  *    **    *    ***  *   **
  * * ** ** ***  * *** *   **  
***  * ** ** **  * *  * *   **   ** * * *    ***  *    *** **   *** is not a prefix of %s",str1,str2);
 *  * *** ***    **** *** * * 
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** * ** ** *  
#include   *** * ** **   
#include ***** * *** *

int main()
{
     ***  *** * * * ***** ***  prefix[100];
 *** *    *****  ****  * *      word[100];
***   * **            **    **  ** ** *   %s", prefix, word);
  *** *  *** **  * ** * *  ** i;
* ***  *****     *  *  * *  ** = 0; i< strlen(prefix); ++i)
* *  **    **  ** *  * *  
 * **** ***     **  *  * *  * **** *  ***  ******   *** ***   ****
* ***    **   *   *   * *   * ***** **    *  
 **  * ****  * * * *  * **   * *** * ***  * *****   *   * ***** *  **   * *   *   *  *** is not a prefix of %s", prefix, word);
*     **  * **   **  *** *  *****       * ***    ** *****   * * ****    *   ** 0;
  ***    ******   ** * ** ** * ***  ** *  **** * **  
    * *  * *   ** * * *** *
    *   *  **   **    * * *  *** *   **     is a prefix of %s", prefix, word);
  *   *** ** ****  **  ** *  ***  *  0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***   ***** * *  * *  ****  *  * n,count;
 *  *  **  **  * **   *  *** * a[100],b[100]={0},c[100]={0};
  ***  *  **  ****  ***** **  *  * **   *   * %s",a,b);
**   * * ** ** *****  ** * ****     ** *
* **   * * **  ** **  * *   *  ****   *  *  *   *   * *
*  **** ** *  ******    * *    **       ** * ***** 
** * ** * *  * **  * * * *
    * **  *** ***  ***  ***  *   *   *** ** *** ** *    **  * ** * 
* ***** ***    * **     
***  ***  *  *      ****** ****  * * **  **     *** 
  * *  ** *    ** * *****  ****  (strcmp(a,c)==0)
**     *  *     **  *****  ***
* *  *  **   * *  ***    **   * ****** * * **  * **  * **  *   is a prefix of %s",a,b);
 *** ** *    *    *  *** * 
*  * *    ****   *** *** *  ***
  ****** * *  ***  *  ***   * *
 * * *** * * *** ** *** *** **    * * **   * **  *****  * * *** ** is not a prefix of %s",a,b);
    ****   *  ** **     
   *  *   ** ** *    * ***    ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
   *** * * ** * **  *  *     String[50],string[50];
 * *   *    * * * ******** * a,b=0;
   ******** * *   *** ** *     *      *  * *  **  * 
   **    ** ****  *  * *    **** *  *  **   ***   

 *   *   * **  ******* ****  *  ** **  ***** 
**    ** *   *   **  **  * ****
     *******    ***     *   **  ***  *  **     **   * ** **        
  *  **  * ****    ** ****   ** **  ** *   **
*** **  * * *     ** ***     *    * * *  ***  ****   ** ****  *** *   * * *** * ***
  ** *  * *   **  * *     ****    *     ******  **** * * 
    }
     * ****  *  * **  **   **
  **  ******  **    * * * **    *
*  * ******    * * *  ***   *  **** * ** ****   ** *  ** **    is a prefix of %s",String,string);
 ***** * ** *   *    ** ***
 * * ** *** * * **    *            **
*      ** * *  * *** * **  *   *
    **  ** * ****   ****  **  *   **     *     ** ** * * *  is not a prefix of %s",String,string);
* * *** **    **   * * * *
  return 0;
}
answered by (-107 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include      *      *** 
#include  **  * * ***** ** *

int main()
{
*  **  **     * * ***  * ***** * * a[100],b[100];
   ********   ** ***   *****  ****  * * * %s",a,b);
  **  ** **  *** **   * ***** i,j,prefix = 1,len = strlen(a);
  * ***   * *  * * *  **     * = 0 ; i < len ; i++)
 * **  ***  *  *  * * *   
 ****   *********     ** **  ** * ********  * * ******  != b[i])
*** **   * **  * ***** * * *  * ** ***  * *** *** *** *
  * * ** * *****   * *      **   * ****   *  *   **  ***  *** *   * ****** ***   **    = 0;
***     *  **** ** ********* * * *********  **** **    * *   *   * **** ****** **   * **** **  ** ** * is not a prefix of %s",a,b);
 *    ******  *** *  ** * * **  *    **    *  **    * * *** ** *** ******   *   * 
    ** ** ****  *****   * * *  *  * **** ****  ******   

  ** ***  *    ***  *  **  
*** *     * * *   **   **   * * == 1)
 **  * *         *** * ***** **** * * **** *        * **   is a prefix of %s",a,b);


  *** ** ** *  * *    *  **   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 15.3k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 14.4k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 18.1k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.6k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 3.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users