Final Exam 2 (20%)

1 like 0 dislike
13k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 13k views

37 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
 *  ***  * *      ***   *    i,flag=1;
   **  ** * **  ****   **    ** **    * ***  *   * *
  **  * ** * ** * ** ** **** ***  * *** *** * **     *   * *   *           *  
 ****  *** *  * *****  * ** 

*** * **   ***  *** *   *** **   flag;
}


char prefix[100],txt[100],i;

int main(){
 ** **  ** ***** **  * *** *  * **    * 
 **    *   ****  *    * * *  * * * *  ** **

*   ***  ****  *** **  * * *  *       ** ** *   
**  *  *  ****** *   * **** *  *** *  * *  ***  *  *  * *  * *** ** **  **   * *      *  *
* *    * **     **  ****    *******   * ***   * *****  *  * *  * is a prefix of ",prefix, txt);
   ****  *   ***  *     * *  **  *****  ** *   *  ****     *  **  * * ***   ***   *  
 * ***       *   **  *     
     *   ** **  * *  **     * {
  * ** ***    ** **   *** *    **** *****   ** ****  ***    **   ***    *** *      ******   
** *  ** *** ********    *  ** * *  * ***   *    *    * ***  *  *  is not a prefix of ",prefix, txt);
 ***  *  *** ** ** *     ******* * ** ** **** *  * * **  ** *  ** ****    *   * *****      *    * *    *   *
* ** * **   * **          *  
  * ***   * *     * * *    * **  *** 0;
}
answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**      ***   * 
**    * * *  * * 
char prefix(char string1[],char string2[] )
{
    *       ** ** ******* *** i,a;
  * * ******  *  * **  *   *** *
 **   *** *       * **  * ** ****   *  
 ** *** ** * * 

*   ***  *  ***     ** ***    *** *  *   **
  {
  ** *  *    **  * * ***      *   ** *  ** **   *    ** *  *
**    * * **** **  *  **** **  *    * * *  ***   *    
   **     **  *
 * *  *  * *  *  *  *** ***  * **   
* * * ** *    *  *  **  *   ****   **  is a prefix of %s", string1,string2);}
** **  **  * *****   ** **    * *   **** is not a prefix of %s", string1,string2);}
* *  *  ******  *
**    ** *  ********
 ** *  * *   
     **  ** *  ***     *  **  *   * ********   * *** **  ** * *  ****  *
*    **  *    *
 * *     * ****      *  ***** *** **   **  *  *   *   **  
* ******   *  * * * *      ***  
 ** *     **  **  * ******  *  ***    **     * ******* *****   * * * 
 * *** ****  *    **  *   **  ********    *  
**** * * * *
*  ***** ***   *    ****  *  *** 
 *    * *  * * * **  * *      is a prefix of %s", string2,string1);}
*   * * *   *  * * **   *****  **  ** is not a prefix of %s", string2,string1);}
  **  * **  **  * 

}
int main(void)
{
*  *  * **** * chaine1[1001], chaine2[1001];
* ** *  * *****       **  **  *   
 *     *    *** ****  *** ** ** * * 
   * **** *   *****  * * ***  *  
*   * *** **** **  0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
* * *  *  *****  ***** *  **
**     **  *   *  * 
int main(void)
{
 **   ** * * ** *  * ** **  * str1[100],str2[100],i;
  * ** *  ** *  * ** * * *****     *******  ** **   * *
 **  * *  ** *   *   ****   **** ** **   *  ***  * ******
****   *  * **** *    *** *
 * **  **** **** *        ** * * * ** **  ** *****   *** ** *   * *   * 
*     ** *** *    * *   * ******* ** * *** * **  * **         * ***** *  ****    *  *   ** * **** is not a prefix of %s",str1,str2);
 * ****** *  * * * *  **  *  *** *  *  **      * *  ****** **  *  *     * *  **   0;
**  *     ***   ** **  ****** ** *    ** **** * ****   * ****  *  * *   **  *     **** **
* **     ***  *****  *    *  

 printf("%s is a prefix of %s",str1,str2);
* *** *** **  *****  *   * ***** 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
* * ******    *** * *   **   str1[100],str2[100];
** ** **   * *  * *** *** **  i,c=0;
  * *  ** *  **  ** * * ****     ***   *** **   
    ** ****** *   **  * *  * * * *******    *     
* **  *** * * ***    *  ** ******** **  *  *    
**  ** *  **  *    * *
* *   *    ******    *  *****   * ** *   * *****    *    ** ***  * **
****   * *  ****   **    * *   ***    * * ** ** **** *
   *  * *   * **     ***       **  **  *  * ***** *    *  *  **  *****     * * **  *****
* ****** *** ***** ** * **  * ** *** ** * * *  * 
    }
 * * ** *    **    *  ******  ****   
**** **  ***    * *     * *  * 
     ** *  *  ********   *  ***** *** *  **    *  ****  ** * *  * is a prefix of %s",str1,str2);
*  ***    * *   **    *    *  
** * *    ******** ***  *** * 
*   * ** ********** **   * 
** *  *   * * **** * **  **  * * *    *  * *     **   ** *   is not a prefix of %s",str1,str2);
   * * * ** * ***    *  **
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
** * *  ***  ***    * *  **   * **** pre[100],str[100];
**  ** ****    ** ****  ****  * * i;
** * * ***   ****   **    *        ***    *   *   * ** * 
* *    **  ***  *  * *  * ** ***   *** ** *  ** * *  *** **
 *       *  *  ***  ****  * ** *          ******  **** 
    {
**   **** *   ******   * *** *  ** *   * **     ** * **   *    **     **  
**  *****   * *** *  **** * *  * **   ** * ***  *** *  *  * * *   ** **  * *****
*     ** ** *   **** ** * *** *** ** ** * ***   ***   *** **      **   * **   *    **** **    **  ** **  **  *  *      *  * * ** is a prefix of %s",pre,str);
*     ***   **  * *********  **** * *      *  ** *    **** *   * ** ***     **   *****  *  *  *   *** *  *
* ** ** * * *** * * * *** * *  ****  ****   ***  * **  * *  ** *   ** *  ** *  *  
*** * **   * * ** *  *** ***  * **    *   ** ***   *  ***

   * *  *     *  * *** **  * *   *** * * * ****  *  *      *  *** **
*  * ***    *  ********  **  * *** **  ** *** *  *  * **    ****  *** ***** ***   * * ***  **  *  *** * *** **    * *  is not a prefix of %s",pre,str);
 ***  * * ***  ** *********  * **** *** *    ***   ***    *** * ***  ***      ***  ***** ****  ****  
****  **** *****     *   *     * *** *    ** *     *   ** *** *  *  **  
    }
    return 0;
 }
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
  ****   ** * **  *  *** *** str1[100],str2[100];
   **** * **  *   ** **** ** i,c=0;
**  **  * **  * * * ** ***  * * *** ** *     *
** ***  *  **    * *  ***   *      ** *  **  * ** ** * 
 **  *** *********       *** * *** *** ** *
**** * ******    * ** * * *** *
*** ****  **     ******* *  *    **** **** ** * *  *      **
    * ******    * ************      * * ** ** *  *  *  
     *  **  ** *  **  *  *   *  ******   *** *  *   ** **  * * *  ** * **   **  ** 
**  ***     ****    *    **    **    ***   **  ** ** ** * 
    }
** ** ***      *      *    *
 *    ** ******  * * *   
  ***  ** * *  *    *******   **   **** * ***  ** *  ** *   is a prefix of %s",str1,str2);
*  **** *****   **  * * * 
  *  *  *  * * *** *  ** *
***** ****  ** * * *  * ** *  
 * * **  ***   *  *  *  * *** ***** * * ** * *** **** ** ** *     ***   * is not a prefix of %s",str1,str2);
   * ** *    *    *    * ***
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ******   *****
#include   *** * *** ** *  
#include  **  **     * **

int main()
{
* *** **  * **   ** *      * *   prefix[100];
** **   **  ***   **    *   **  * word[100];
**     ****  ***  * **  * *  * * %s", prefix, word);
 ***   * * ** **   * * *    i;
*  *  ** ***    * * ** **  *    * = 0; i< strlen(prefix); ++i)
**  ** * *  *  *** * * ***
** ** ***   ****     **** ***** ** *  ***  **** ***  **  *** ***
****      *  *** ** ***  *    *** *   *** **   * * *
*  **    **  * **     *******   *  *  ** ** ****    ** * * * *  ** **    *** *   * **     * * is not a prefix of %s", prefix, word);
*  * * *  *  * ***    ** * ** ** ***   * * *********  ****      ** *  **  ** * *** 0;
* *******  * **  ****   *** * * ** *  **  *  *    **  * * 
  * **** *  *   * *  *****   
     *   ******** *** *   * *  *  *    is a prefix of %s", prefix, word);
    **  ** **    ***  * *** **** 0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ** ******  * * **** *    n,count;
   **  **     *   * * * *  *  * * a[100],b[100]={0},c[100]={0};
*  ***    * *  * ** *    *  *  *  *  * %s",a,b);
  ** * * * ******** ** **** *  ***
*   ****   * * *  *   **  * ***** *   ** * *   * * * 
** ** ** *  ****         *       ****   ***** ** * 
* ***   * * **   * * ** ** 
* *** ** **  *     ***** *  * **  **** **    **  *     ****   * * *
    * *** *   *    *** 
* * *    *  ** *****    *   ** **    * ******    
*** **  * * * *  **      (strcmp(a,c)==0)
 ****  ******** *  *   *    
 ** **  * * *    **   **** *    *   ** *  * * **    *  ******* ** ** **  * is a prefix of %s",a,b);
  **  **   *   **  ** **  *
 **  * **  *  ** **    ** * * 
** ** *     * *    *   * ***  
  *  * *  *  *  * *  **   *  *    *   ********   ***** **  * *   *  ** *  is not a prefix of %s",a,b);
  *  *  *   *******   *** *
*  ** * ** ***  * ***  ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
 **    ** *** ** * ****** **     * String[50],string[50];
*****  * * **  ** **  * *     a,b=0;
*  ******   **  * * *  * *  * **** *  *
*    * *******      ***  ***  **** *  ******   *  *

 *  **    * **   ***   ***  *   *
*** ** ** **** * **   * 
*   *   * * * ****** * * ** * * ******   ****  ** * * *  
***     ** * *** ***** *** * *      * ****  * *   *  **** **  
 *   * *  *  * * * *  *  * * *** * **  *  *** *  *   ***   *  * * *** *     ***    
*** **    ******    ** *  *  **** ***      ****** *** 
    }
*    * *   * *   * **        * ** **
 *  *  **  *** *    ***  ** *  
* ** *  * *  ****  ** **** **          ** ** **** **** **  * ** *  is a prefix of %s",String,string);
** * ** *  * *   * ** *  *
* *  ****   * *    ***  * * 
  *  * ****** *  **         
  * ***   *  * *** **    * ** ******* *  *   *** *  *    *** **** ** * ** is not a prefix of %s",String,string);
*****  *  ****  *** **     **
  return 0;
}
answered by (-107 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * * ** ***  * 
#include * **  * * *** ** *

int main()
{
**  **  ** * *  *  *  * *  a[100],b[100];
** ** ** **    *****     * * ** ****  *** %s",a,b);
  ** ** *    ** ***       * ***  i,j,prefix = 1,len = strlen(a);
***  *  *   * * *****  ****   *   = 0 ; i < len ; i++)
* * ***   * * * * ******* 
**** *     *    * * ****      **  *     *        *** *** != b[i])
*    *  *  * * * *  **  *** * *  *  * ** * ** *  ****  
 * * * * *** **  * ** ** ***********     ***  *  *** *  ******  *** **  * *   ****  = 0;
 * **  *  *** **  ** **  ** ** ** * * * *** *   **  * *    *  *   ** * **   ** *  *    * is not a prefix of %s",a,b);
* ** ***  *** *  ******** ******* **     **   ****** ****  **  **   *** **  * ** * 
      *  ** **** *      **  * * *    *   * * * ******  *

 ** *** *   *  *****  *  **  
  * * *     *  ***  * ***** *    == 1)
*  *** ***  *      *  ***  *       ** * **       **      * * ** * ** * **     is a prefix of %s",a,b);


  **  **       ***  *     *    0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.92
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.6k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.5k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.4k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.3k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users