Final Exam 2 (20%)

1 like 0 dislike
4.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 4.9k views

37 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
  **  * * *** ** * *   *  * ****  i,flag=1;
  ** * * ***  *       ***  ** **  * ****   *** * *   
 ** * * * * *  * ***** * **  **  * *** * ** * **** * *    * * *** **  *     *
     *  * ****  *** ** **  * *

** ** * ** * *   ** * *  **** * ***  flag;
}


char prefix[100],txt[100],i;

int main(){
**   * * ***  **  * *   ****** ****  *  ****
****** * ** * **   * * * ******** ** ****

**   * ** *       * * **  ****   *  *** * ******* 
*   **    *** ****  **** ***** *     * ****** *   **** ** *   * ***       *  * * ** ** ***   * 
 *** ** *  ***   *  ***     ** *   **  *  * ** ***   *  *   * ** * *  is a prefix of ",prefix, txt);
 **  * *** * *   *   ******** * **  ***  * *   *  **  * ***    ** * *    *   * * *   * *  **
****  *****  * ****  ** **  
********  * ***     ** *   * ** {
 ** *  * ****     * *  *       *   * ** **  * ** ******  ***** *  *    ***    ***   *  *     *   * * *   ****  *  *  * *  *  *
***  ** * *** **  *** *******    *  **  ***** * ****       *** is not a prefix of ",prefix, txt);
  ****** * *  ** **** *******   *   ** ****   *   *** * * *    *       ** ***  *    *  *******      * *
   *  ** *  ** ** *  ****  *
** *   * **** ** *  **  *  *  0;
}
answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * *** ****** ****
 ** * * ****  ******  
char prefix(char string1[],char string2[] )
{
 ****** *  *** ***  ** ** *  i,a;
 *** *   ** *  *      ****  ** *
*   * **** ***     * * * ** ** *   *   *  * *
 ** * ***  ****

*** * ****     *    ** * * *  *  ***  * *
  {
* * *  **  *    *  * *  *  * ** *   * ****    **  *   * 
*** *  * *   * * *** *   *****   * ****    ** *    **  
*** *** ***
*  ** *** *   ** ****    *** * 
 * *  ***** *  * * * * *****   *  * is a prefix of %s", string1,string2);}
*  ************   *  ** *     *      *  is not a prefix of %s", string1,string2);}
*    **  **** 
* *   **   ** *  *
* * ***  ** *
*    **  ***    ******* * *  * **   *  ** *  **** **    *    *** *   * * ** * *     
*   *  * *   *  
  ***  **  *** **   **    ** ***     ** * *    *** ** **  
*****     *** *** ***   * *  *  *** **  * ** **
   * **   * *  ** ** * ***  **   ** *  *****       *** ***** *** ***      *
  *  *** ***    * **** *   ** ***   ** * *
 * * * ***   * * 
* *  **    * ** * **** *   ** ** * 
  *  **  *** ****      **** *** ** * is a prefix of %s", string2,string1);}
** ****  * * ***  ***** *  * ***  is not a prefix of %s", string2,string1);}
********    ***

}
int main(void)
{
****  * * ******  chaine1[1001], chaine2[1001];
** ** ** * ******   *     **  ** *  
   ** *    *    * * * ** ****         ** **
  *  **   *  *  *** * ***   **  
*  ** *  * *********  * 0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
  *      **    *****
 ***   * ***  **  ** 
int main(void)
{
* * ****  *     *  * **** *   str1[100],str2[100],i;
*  **      ***     *** **  *** * * ***  ** ** *   ***  *  
**** ****   * **  * ** * ***   **  **  * * 
 * *   ******* *  *** * ***
  **** **   ** ******  *  *        *  **     **      **    ****  
**   ** **** ** **   **** *         **   ** * ** **** *  *  **   *  ****   *  *     ***   *** *  ***** is not a prefix of %s",str1,str2);
* ***  ** *   *   *   ****  *   *   ** ***** **  **   * ** **  *** *  ** ** *   ****** 0;
***** *   * **** * * * * * *** ** *  * *****  * ** ** **  *  **  *** ***    * *  **
*  *****    **  ****  ***   *

 printf("%s is a prefix of %s",str1,str2);
* * *** ******* * ** *** ** *  0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
  * **    ** ***   *  *  * *** *  **  str1[100],str2[100];
 **   ***** *     *   *  * i,c=0;
******      *   *    * *   *** *   *       * *   ** *
 * ***  * ****   **  ****   **** **      *   *  *    **
* * ***   **** **    * ***   **    *** 
        * *  * *** * *  * 
 ***   * ***   *  *** ***  ********** *            * ** *****    *   ****
* ** ****  * **  *   **  *  * ***  *    ****       *** 
*  * **** *** * ****   ***  *  *    ** ** *** * **    ** * ********     * *** *    ** *
   ***   * ****      **** ** *   *  **  **    ** *****
    }
 ** ***  * *** *    ****     **  * *** *
**** * * *     *   *     
 ** ** *  ***** *      *  * * *   *** ***   * ****** * ** ** ** * ** **  is a prefix of %s",str1,str2);
****** * **  ** *  * * ***
  * ***  * *  *** ** *    * 
 * * *  * *    **** *  * ** 
***   * * ** * *  *** ***   *   *   ** * *  ****     *     is not a prefix of %s",str1,str2);
 *  *** *    **  *  ** * 
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
* *** *  *** * **   *   **** * *  * pre[100],str[100];
   ***   * ****** * *    *** *   ***  i;
**  ** *        * * **          ****** *  **      ** 
** ***  * ** **   *   **   *  **  **** *** *     
* **   **    *  ****  *  *** * * *** ** *  * ** **  * *    
    {
   **  *   *** *** *  *** **    **   **** * ***    ** **** ******   * 
*  ** *  **  ** **  ***** **    * ****  ** **     ** **   **  ** **    **    ** * *   *
**   ** * *** *  *   *  * * ***** ** ***  * *  * *   * * ** *   *** ** * *     ***** *** *   ****  *   * ****     *  *  * * *  is a prefix of %s",pre,str);
* ** ***  *  ** *  *    *   * *   * * *****   *  ***  ** * ******* ***  *  * * **** *** **** **  * * *****  **** *****  * 
***  * ** * ** *  **  * ** ** **  **** **   * ** *  *** *********     *  *     **** 
*   ***  **  *  **   ****  * ***** *  ***** ** * 

   **  ** * ** * *** * *  ******  * ** ****  * **  ** * ****  * *   *  **   * * ***  *
**** *   * **  *** **  *     *** *  *  **   * *   ****    *    ********* ** *  ******  ** ***   * **      is not a prefix of %s",pre,str);
*    * *** ***** *  **   **  **  *** ****   * ***  ** *   * * *  *** *** * ***          *  *  ** **
 * * ** ***          * * ******* ***** *** * * ***** *  *    ** ***  * * *
    }
    return 0;
 }
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
 *** ***  **  * *   ***    * str1[100],str2[100];
 *  *  * * *  *** **  *  **    i,c=0;
  ****** ***** *     * *  ** *  **     * *     *
   *** ** **  ******* ** * **   *  *** ** *    * 
*     ****  * * * * *  * * ***  *  ** ***
  ***  **** * ****     ****
 **  **  **  *   ** *   * **     *  ** ****   *  *  *   *  ******  * *
*** *  *** **** * * ****  *  *   * **   *  *******    ***
  *  **   **     ***    **   *     ** *    *  *** ** *   * ******* **  *** ***  * *
   *** * ***  * * *  **  *  ** *** ** * * * * **  *     
    }
 ***  *  * ***** ***** *      *  *
** ***     *  *****     * *
***  * *  **    * *   *** * * ** ******   **** * **    ********   * is a prefix of %s",str1,str2);
**  *   **     *    *** **** *
 * ** **  ** *****  * ** 
**     * ** ***** * *  *  **
**** * ****  *    *  **  ****   ** *   ** *** **  *  *  **** *  * is not a prefix of %s",str1,str2);
    *  * **    ***   ** *** *
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  ** *  * * 
#include * * *** ***   *   
#include  *   *  ***   * 

int main()
{
 * * ** ******** * *   **** prefix[100];
   * * **    * *****      * *   word[100];
**  ** * *   *   *   *    ****  ***  *  * %s", prefix, word);
** **  *     **** * *     **  i;
 *  * **  ***   * *  **** **    = 0; i< strlen(prefix); ++i)
***  *     * *  * **   * **
* **  **    *** **  *    ***  **** **   **** **    *** **     **  *** *   
* ** ***  *** * *  * ******   ** ****  * * * *  *   ***
***  *   ***** *** * **    * *  ** *****  *** ** *  ** **  ** *  * *   * **   * *******  *    is not a prefix of %s", prefix, word);
 *** ***  *   *** *** * *** ***      * **   **  ** ** ** * **     * ** * *      ** *   * **  0;
* * ** *    *******    **  *    * *   *  *   *   *** **** **
  *  *** ** *  *    * ***     *
* * ** ****   **   * *     **  ***  ****  ** is a prefix of %s", prefix, word);
**** **** * *   ***  * * * *  0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  ** * **  *** *   *      *     n,count;
*  * ******* ***    ********* *** a[100],b[100]={0},c[100]={0};
*   *  * ** *** ***   *****  *  **   ***  ** %s",a,b);
** * * *       * ** **   *  **  ** *  
** * * * * * *  ***   **   *  ** ***  *   *     ** * ***
    * *  * **      *     *** * *  **** * *** **  
**** **   * * * *  * ***
 ** * **   *****  **** *  * **  ***  * **   *  * *   ** **  ** * 
*   **    **  * *  ** ** 
   **    ** ******   * **  *   *  *  *** * ****        *
   **  ** *  *  ** **  * ** * (strcmp(a,c)==0)
  * *  ** *  *  ** ******* **
    *** *    **     *   ***    * * * ** *** ***  ****** ** *    *     is a prefix of %s",a,b);
* *  * *  * *  ** *  * *** **  
 **  ** *  * *  ** * * *  **** *
     **** *    *   *****   *  *
* **  ** **   *  * *** *** *  *  * *** ***       * ******  *  **   is not a prefix of %s",a,b);
 *** * * ****  *** **   *      
 ***   ** * *****  ***   *   *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
* * ***   *   *  *  ***** ****   String[50],string[50];
*** * *  **** *****     ***     a,b=0;
*****   **     *** * **   * ** ***** **  ***** *    **
*    * *  * **  *  **** *   *** ***  *   ** *  *  ** **

** **** *  *****  *   * *** *  * * ***
 ***  * * * *  **   **  *  
*   * ** * *   *     ***  * **  *   * *** **  *  * *   * * *  * *******   ** 
**  *  * * *   ****   **   ** *  ** ** ***** **    
 ****  ** *  **   ****  ***       ***  **  ****   ***   ***  * * ****** 
*   * *    *  *** * *    ****   *  *     * ***  * *
    }
**   *  **  * ****  ** * * * ***   *    *
 *  ***   * ***      *** * 
   ***  **** * *******    ** * *****        *   **  ***  *   ***** **  *  is a prefix of %s",String,string);
 * **** **   *  *      **  ***
 * *  *  * *   *   ** *       *
 * *  **   *****   **      * 
*  *  *  *** * ** ****** ****           * ****       ***  ***   is not a prefix of %s",String,string);
*  *         *  ** *****
  return 0;
}
answered by (-107 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **    * * * ** 
#include   ** * *** * 

int main()
{
   *   *******      ***     a[100],b[100];
  * * *   ** *  *  *  * ***** ***    * **    %s",a,b);
 * ***  *   * * ** * *  i,j,prefix = 1,len = strlen(a);
  *  * ** ****** *  *  * *  ***  = 0 ; i < len ; i++)
  * ***** ** * * * ***        *
 ***      ** ** ** *    *    * **  ** ***** * * * **  ****  != b[i])
   ** *    * *   ** *  **   *** ****  ** ** * *  ** ***    * *
******  *    *** * ****** *** *** ** * * *   * *** * * *    **** *  * *    * **  *     = 0;
  **** ** ****    **        * * ****    ** ** ** * *** *  *  *  ***** *  *** * *    * * *  ** **** is not a prefix of %s",a,b);
 * **  *    *  ******* *  * ****  *******  *   ***      * ****  ******  * ** *** *** *  *
***   * *  ***  * * ******** * *** *** * *  **   * 

 *** *****  **   * ** * *
**  *** ** *** ****** *   **** * *   == 1)
**     **  **       * ** *  *  * *      *   ** **    * **  *** *     is a prefix of %s",a,b);


   * ** *  ****   *  * **   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.47
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 4.5k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 4.8k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 3.7k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 943 views
12,783 questions
183,443 answers
172,219 comments
4,824 users