Final Exam 2 (20%)

1 like 0 dislike
6.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 6.7k views

37 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
* ** ** *  ** *  **  **  * *  i,flag=1;
 *** *  *  * ** *    * *** ** * * **  * *****  * *   **** ***
 **   * ** ***   ** ** **** ***    *  *   ***  * ** * * ** ** *******  *   **  
*        * *    ** *   ******  *

** * ** ***** *    ***  * ** flag;
}


char prefix[100],txt[100],i;

int main(){
 ***** *    * * *** *   **       *** ** ****  *
**  *  **  ** **   ***  * *  *  * 

** **   **  *  ***  **** * *****  ** **      **
**  *  *       *  *  **  *  *** **** **     ******** **   *****   * *  ******    ** *  ***** 
**   ***   *  *  **  ** **  ****** ** ** **  * ** ** * **  *****  ** is a prefix of ",prefix, txt);
*   * * ** * **    ****   * *  * **    ***  *  * ** * *  ** * **  **  ***   ***** * ** 
   *  * **  ****   *    * ***** 
 ****  * * **         * *  * {
 * **   *** * *** *    **  ** **** ** * ** ** *********   * *  * * ***    * ** **   *  ** ** ** ** *  **   *     
****     *  **   *  * * ***   *    *   * * ** ******   *** * * ***  is not a prefix of ",prefix, txt);
*   *  *****  * ***  ****  ****  *  *   ****  * ***  *    * * * * **     * ****  * ****  ******* *  
   *   ****    * * * ** ****   * 
 ***** ***    * *  **    ** *    0;
}
answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    ******  ********* 
**** ** ** **   ***  * 
char prefix(char string1[],char string2[] )
{
  **  * * *** *  ** *  *** i,a;
* * **  ** *   ***  **   ***  * *
*   *    ***     *    *  **** ** **  * ** * *   
* **   * ******  

*    **  *** *  *  ***  **  **** *** ** 
  {
***  ** * ** * * *  *    *** **     *    *   *  *  * ***  
     * *  *   **     *     *** * **   *** *   **** ** ***  *
 *  * *      *  
 * ***    *   * ******* ****  * 
**    **** * ***  * **  * ***     is a prefix of %s", string1,string2);}
**  * * *     ****  ***** ***** *** is not a prefix of %s", string1,string2);}
  *   ** ** ** 
* ** ** *  *  ***
* *   * * **   
 * * *   ** *****     **    * **    ***** ** **  ** *   ****   **
  *  *  **** *
  * * * * * **  ***  * *       ***  * ** **   * **** ******  
* * **  *   *     * *** * *   **  * *   
***  * *** **  ** * * *  *  ** *** ***  *      *** * **  ***      *
 * *   ******      *  *   * **      *  
 * * * ***** *
 * **  * *  **  * * *  * * *  ***  * 
**      *** *  **  *   *  *    *  * is a prefix of %s", string2,string1);}
*****  *     *  * **   * ***    is not a prefix of %s", string2,string1);}
   * * ****  

}
int main(void)
{
** * * *  *   **   chaine1[1001], chaine2[1001];
* *** *  * *      ******   *** ** *  * * 
**   *  *    *   *  ***        * *  *** **
** * * *  ** **       *****
* **  *** **   0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
**   *   *  * * 
   **** ** ***      
int main(void)
{
*        **   *  ******  * ** str1[100],str2[100],i;
   * * ***  **  *   *** ** ****  *******  ***  * * ** *  
 **    * *   * ** * *  *  ***  *  ** **   * **   
  ****   ** *  *  *** *** ****
**  **     **   * *  ** * *  *  * **   * **   ***  **  ****** **  
 *  ****    ** ** **   **  * *  ****  *** * ** * *  ** * * *** ***** *   * * **** * *  is not a prefix of %s",str1,str2);
***      * * * *      * * **  **   *    **  **  **  * * **** * *  **   *  ***  0;
 *** **  *** * * *  **    *  ****    ***  *****  * * ** *  *      *** *****  
 * ***  *     ** ** * ** ****  

 printf("%s is a prefix of %s",str1,str2);
 *   *  * ***  **** * * ** * 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
*** **    *   **   ****  ** * *  str1[100],str2[100];
* *       *  ***    * * *** i,c=0;
*  *   **        ** **  ***  *** ***** * *  * 
**    ** *** *** ***  **  *** ***   ***     * * **    
   *** ****   * *   * ***  ** ***    ** *
 * ***  * * **  * *   *
***  **  * **** **    ***  *  ****** *  * *   **   ** ******   **** 
*  *        *       *     *****  *  *   **  * ***** 
  * **  *** ****** **  *  ** *     ** *  **   *  ***  ** **    **  *     ***  * 
** ****  ***  *  *  *   *** * * *    *** **** * **** 
    }
*   *  ** **  *       * *  **   ***
 *  * *   * *** *   * * **  
***  *     ** *** * * *** * *   ** **  * *      *  *  ** * ** *  is a prefix of %s",str1,str2);
* ******* **  *******  *  * 
  ****  ***   ***  *  ****  *
**   **** ****  *  **** ** 
 *  *  ***  *  * * *   ***  **   *  * *** * * *** *  *   * *  * ** is not a prefix of %s",str1,str2);
* ** ***  * *** *     
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
***     ** **  *** *  *  *****  ** ***     pre[100],str[100];
  * ***   **   *  ***  * **   *    i;
 * *  *    ** **     * * *** * *  * ** **  ** * *** 
**   ** * *  **   *   * * ****    *  *   *   *   *     * ****    *
***   *** *  **   ***   ****** *  *  * ** ** **       *  
    {
   **   ** *  ****  **   * **   *  **  **    *  ********  **    **   * *      ***** ****
**** *  ** *******  * ** *  *   *******         **** ** ***** *    ****   * * *    * ***
**  * **    * ***  ***   ** * *  *  *  *    *  * **** **** **   *  ** ****     *  * * *   *  ***** * *** *** ** * ***  * is a prefix of %s",pre,str);
* *      ****  ** *  * ** *      *   * ** * *  ** *  * * *   ** **  *      * ***    *  * ** ****      *
*****  ** *** ***    * *   *  * * ***    ****    *  ** *** **   **  ** * * * * ** 
*** *** * **    ** * * * **   *       ** *    ******* ****  * 

***  *    **  * *    ** ****  * ** **  ***** *     * *    *   ** *  ** 
 * ** *  * ***   *  * **   *  **  *   ***   *   ** ****        * *  **  * ** ***  ***   * **** ** *** ***    * * * * is not a prefix of %s",pre,str);
  ***   *** * **  **  *  **   ***** * *    * *    ***    ** *  **  *  ** * **  * **    *   ****** ***  ******    
** ****   *    *     * *    * *  ** *     *  ****            *   ****  
    }
    return 0;
 }
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
 * *  ***    * *      **     * ** str1[100],str2[100];
 *   ****  * **   * **   **   i,c=0;
*** *  **   *  **  *   **   * * ** *** *    * * *  * * * **  ** *
*****  * **** *     **** ** ** *  * ***  ** ******
**      *******  **    **   *   ** **** **
*  *    *   ***  *  **** *
***     ***** *   * ** ***  ******  **    ** * * *** *    *  * ** 
*   **   **  * * ** * * *  *  **  *** * ** *  *    * **** *  ** *
**  *** *  * *****   * ****     ***    **  ***** *     ** **   ***  ** * * ** * *
   ***** **   ** *    * ** ** **** ** **   *   *  * ** 
    }
   *********      **** * ****   
* *     * **** ****   ** *** 
***** ** * * *  ***  *  * *  ** ***   *** * *  ** is a prefix of %s",str1,str2);
** * * **        ** ***** 
   **    *  **  * * * ** **    
*  **   *  **   *** * ****
*****  *  *  ***  *** *   * * ** * * ****     ***      **        *  ** is not a prefix of %s",str1,str2);
  ** *  *** *   **  *    ***** 
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ***  * * **
#include   ** ***  **  ***
#include     *    *   *  **

int main()
{
*** ***** *      * ***** prefix[100];
*  *  * *  ** * *    *   ** ** ** word[100];
 **** ***   **  **  ** *   * ** ** ** %s", prefix, word);
*** * *    * *        ***  *** * i;
*   **  *  *    *  ** ***  *      = 0; i< strlen(prefix); ++i)
** *  **  ****** *******   *    *  
 ****** *** *  *  *** * **   * * **   ***  *** *** * *       *** *** 
*  **  ** *     ** **    *    *** **** *** *   ***
  **      **   * * ** *  *** *   ******* * *  ****** * ** **** **    **  **   *  *  ***   **** * *  is not a prefix of %s", prefix, word);
* *  **  *  **              * *** *** ******    *** ****** *** *  *  * ** **  * *** 0;
 * ***             * * *  **   * ** **   *  *  *  **
* * *  **    *       * **** 
***** ***  * ***      ** *  *** ** *  *   is a prefix of %s", prefix, word);
** *    *    ***  *****  * ***  0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*  ****  *  ** *** ***    n,count;
**    ** **** *  *     ** *   a[100],b[100]={0},c[100]={0};
   *  * **** ** **   *** * ***  * *     %s",a,b);
  **** * **     * * *  *** * 
  *** **         **  * *** * *      ******  ***  ** * 
**** * *  **   **** * * ** ****** * *** ** ***   
 * * * ** **   *     ****
  * *** **    ***   * *   ** * ** * * **  * ** *  **  * *   
 **** * ** * *******  ** **  * 
 *      **    * **   *   **** ***  * * *  *  * 
 * * ** ** * ********* *** (strcmp(a,c)==0)
******* *  **    *  *     **
 ***   ** *   **   ** **  * *  **   * * * * * ** **   **  ****     ****    is a prefix of %s",a,b);
 *  * *   *  **   
  *  *** ***** **  * *  **  
*****  * *** *    * 
**** *   ** ** **  *    * *** ** * ****       **  *       *  is not a prefix of %s",a,b);
 *       **  **    *   * ***
    * *** **     * * ***   * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
 *  ****     * ** **  *  *** * String[50],string[50];
 * * ******** ** * * *   * ******* a,b=0;
   *  ** *  * * *** * ***    * ** ***  ***** *   ** 
 * *  ** * ** ******* *** *  **   **   * ** *  *** 

 ** *  * * ***   * * ****** *  * * *    * 
   *   * ** *     ****   **
*  *   *    ** * *   **  *  *  *  * * * * ** ** *  *  *  ** *** * ** **  
 ****      **  * **  * *  ** **  * *** ****    **   **  *
*  ** *   ***    * ***** ** *    **** ******  ** * *   * **  * * **   *     *
*    * * *   * **** **  *** ** *** * *      ** *    * *
    }
 **** ***  ****  *  **  * ** 
*****   **  * *  *  * *  *
* **  * *   ***      * *   **   ****  *  *  * *  *  *** *  **   * *** is a prefix of %s",String,string);
******  ** ** *** ***     
*   *   ******  **  * * * 
* *  * **  *  ***  *  ** *
   *  ** ** *  * **  ***    * ****  *  ***   *   **    *** *** ***  is not a prefix of %s",String,string);
 *  * ** * *** *** **  *  *** 
  return 0;
}
answered by (-107 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **  ** **    *
#include  **  *     *** *****

int main()
{
  *    *****  **** **  *  *  a[100],b[100];
 **  ***  ** *    **   **   *   ** * %s",a,b);
 *** *   **  ***   ** ****  * i,j,prefix = 1,len = strlen(a);
  *   *     *  *   ** * *** * * = 0 ; i < len ; i++)
     * **  * * *    *   *   * 
* ** *********  *** **  *  ****    ***      * * ** * **** *  * != b[i])
 *** *  **  * *** *  *   *  * ** * *  * ****      **
* **** ****  * * * * * ***** *** ** *** * ***   * ** **   ***    *  **  **  *   *  ** = 0;
       *     ***  * **  *   * * * * * * *  **  * *   *** *    *  ***  * * * *  ** ******   * is not a prefix of %s",a,b);
 *  ***      ***** **  ***  ***  *** *  ***  * * ** *  *    * ** *  * **      **
**  * *  * **  ********* **  * ***     **  *  **    * ** * *

*  ***     *** *** *   *** *** **
***    * **  **        ** *** ** == 1)
 ************ * ** * ***  * * *** **  * *          ***  **     is a prefix of %s",a,b);


  * ***** * ** ** * *  **   **    0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.21
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.1k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.9k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.2k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users