Final Exam 2 (20%)

1 like 0 dislike
4.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 4.9k views

37 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
  * **  *  * * * *   * *   ***  i,flag=1;
 ****  ** *  ****    ** *  *    * ** **  * **  *  *  * *
 *** ** ** *******  *  **  ***  *  *   *    *** *   *********   * **       *
**   ***  ** * ** *  * 

 ** ** ***      *      **  ** flag;
}


char prefix[100],txt[100],i;

int main(){
    * * **** *   *  ** * *  **  *  **** *  ******  
*** ***  ***    ** **   * *  ***  *   **

    ** ***       ** **  ******  ** *   ***   *
 ***  *      *** *   **   ***   *     *      * * **********   * *      **  *  ***** * * ** *    
  * *   *****  * ***  **       **  ***  ** * * *   **   * ***  is a prefix of ",prefix, txt);
** **** ** * ** *     ***** * ** *** *   * * ****** *   *  *  ** * * *      * ***** 
**** ** * *  ******* * * 
********  ******     * **  {
* ** ***   ********* *** ******** ***    *** *** **        * * * **   ** * **    ** **** ** * *    **  **
****  ** **  *   * **    **  * *    *    **  ** ** * ***  * *  is not a prefix of ",prefix, txt);
* ***** **** **** ***  *    ****  ****  *  *  * ** **  ** ** ***** ***   *   ** * ***  * *   *  *    *  * **
 * ***   ** **   *  *    * 
     **   *** * *    ** * * 0;
}
answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * ******    ***  
 *****  *  *    ** 
char prefix(char string1[],char string2[] )
{
   *    ** ***  *** *  **  ***     i,a;
*  * ** * ** * *****  *  *  * * *
**  ** ** *  *   * * **** **   *   ** *  *   **  ** 
*** * **  *   **  

* *    *****    *   *  *   **** *** ** **** * 
  {
**** *     *** ** **** ***  *** *   * ** *    *** * ** *  *
  **  **   **    ***** *  *  *    ***  *            ** *  ** ****
** ****  * *    
    *  ** *  ** ** * ** **   *  ***  * 
 * *   **    *           **  *  * ***** is a prefix of %s", string1,string2);}
 *****   **** **** *   * ***** * ** is not a prefix of %s", string1,string2);}
   *** **** 
**  * *  * **   *
     ** **  **
  *  *    ***** * * *** ******    *     ** **     *    * ****  ** ** ** * *
*      * *  * 
** ***   *    * **** ****         *** * *  ** *****
** *** **           **  **** * ******* **
** ****** *** ** *        *  **** * *  ** *** *    *  ****** ** **  
**  ****  **  *     **  * * ** *  ***  ** ** 
* **    ** 
  * * ** * *** *  * ****  *     * **   ***
********  *     **   **   * * * * **  * **  is a prefix of %s", string2,string1);}
 **** ** *  ****** * ***    * **** * is not a prefix of %s", string2,string1);}
**  **  ******

}
int main(void)
{
**********  * ** * chaine1[1001], chaine2[1001];
* * *  **   ** *  *  ** *  * *   ***
   ** * ***** * ** ****   *** * *** **
 **   * *   * * * * ******* * *****
**** ****** *  * 0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 * *  ** *****   ***   *
* ****   * *****  ** *    
int main(void)
{
**  ** ** **  **   *** *  **  ** *** str1[100],str2[100],i;
* *** *  ** ***     ****   * *  **  *        *
   * **** ******    *   *** *   * * * **** ***  *   
*  *  **      * *  * *** ** *  
**  * * * * ** *  *  *      **  * *  * * *    *  *   * *** * *   *** 
** *  *** * *** *  **  *  ***** *   *** *   *  ** ******************   ***  ** *  ** ****  is not a prefix of %s",str1,str2);
       * * *  *  * ***   *  *   *  *  ***  *** ****  * * ***  * *** ** **    *  * * 0;
*   * ** *** *     * **  * *** * * *  **  *   * ****  **   **** *****   *  **** 
* *   * *  * * * * *   *** * 

 printf("%s is a prefix of %s",str1,str2);
 * ***       ***  **  ****** 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
*    *  ** * *     **  **  str1[100],str2[100];
*   ** *    *   ** ** * ** ** **  i,c=0;
 *** **** ** ** * ****  * **      * * *** * *   
** ***  ** * ***  ** ***    ** ***   *** ** * 
 *   * * * * *  *****  ****  **** ***      *
  *  * ** **** * * *    ** **
 *   * ** ****  *  *  * ***  * ***  ***  *** **** *** *   ** * ** * 
 **     * **      *     *  *** ***  ** ** **    ***          
 **** **  ***   **   * ** *  *  * ** ** *   * ***  *   * *** ** ********** * **  *   * ** 
*    * ** *   * ** * **    ** * *  *   * * *  ***  * *
    }
  * *   ** ****** *** ***   *
*  ** *           *    ** *
 ****  ***** *     *    **** * ** **  ******** *   **   *  ** *** is a prefix of %s",str1,str2);
 * *  ******        * **  *  
 *  **** * **    *  *  *   
  * **    * ** *    * * * *  *** 
* ****** ** *  **** * ***  *  **      * *  *** *   * ****    ** * is not a prefix of %s",str1,str2);
   **** ******* * *** ** ** 
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
 ***   **  ***** * *  **   *  **   * * pre[100],str[100];
 ********* *    ***    ***    * i;
 ***   *    *   **  **  * ** ** *  *  * *      *  * 
** **** ***  * *   * * *  * ** * ******* * **   * *  * 
* *      * *** **  ***   ** ****  * * *  * * *  * * **   
    {
*** *   *    ** * * ** * ********  *   *  ***  ********   **  ******** **  **      *
**   * * **  *** *    ******* * *  * * * ***  *    *    * ***  *  *   *** *******
 ****** ****  **    **  **  * *     *   * ***** * * *  **  *  * ***** *   **   ** ***   *   ****** *** * *  ** *   is a prefix of %s",pre,str);
  ** * *  *  *    *  *** **    *  *  **** * *    *     ***  *   ** ****   *  **** ** *** *     ** *     *****  ** *
*        *******      *** **       *  ** *   ******* *** *  **  * * ** **  * * *  ** 
 ** * * *  *   *  **** *****  *  **  * *** **  **  *  

**   *     *   * *   *  * **** *    * **     *     *   *  **    *   * * * * 
   *  * ** *  *   * ** * **   ** ***** *   ****** ***   **  *        * *** * * **** *****  **  *    **   ** *  ****  **    is not a prefix of %s",pre,str);
 **  *** * *** *   * **    *******    ****  * * ****  **  * *  **      ** * *     **** *  *  *   ****  ** *  * *   ** **
 * *** *   ** * * * *  *  ** **     *   **  *  *********  ** * ** ** * * * **
    }
    return 0;
 }
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
* ****  ****      **  **    * * *   str1[100],str2[100];
* *     * ***   *   *  * ** i,c=0;
 *  ********** ** ***  **  *  **  ** **   * *  **** 
*  ** ****** ******     * * ** *****  **  ***   * *  *
 ****   * **     *  **  * ***    *   * ** *  
          *    ***     *****
**    * **** **    * * ** *****  * ** * **    ** * ******   * **   *    *
 *****   * * ***** ******* * *** ***  * *** *        *       
**  *   ***  ***  *  **** *** *  ** * *  * * ***   *    * *** *** ***   * *   *
  *** * **  ** *    ***  **** * ** * *  * * *** *  *  
    }
 ****   * * ****  ** ** **** * * * 
  *  **** *    ** ***  * **   **
****  * *** *  *** ****** * ***  * *   * * *   *  ***   *  **     ** ***  is a prefix of %s",str1,str2);
** * * **  ***   * *  **   ***
*******  ****   ** ***   *  ** *
 ****  * ***   **   ******  * *
***  *   *** ** *****  * **  *  **   *** * * ** **    * ***  ***** is not a prefix of %s",str1,str2);
*  *** * **  * * *   *****
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   ** *     ** **
#include  **  **  *** **** 
#include * *  **  ** * ***** 

int main()
{
 * ******* *   **  *****   prefix[100];
 *  *  *    *  ** * *****    *    word[100];
 **  *  * ***  * ***  ** * **   **  ** %s", prefix, word);
**** ***    *  **   ***   i;
* *   **** * *   *  *  = 0; i< strlen(prefix); ++i)
 **** ***** * *** *  *   
**   *  ***   ***   * * *      *    *  *  ** *** ****  ** *  *   ** ** 
**   *   ** *   **  *    * ** * *****      ****      
*** * *    * ** *   ***  ** ***  * **  ** *** *** *  **    * * *  **  ***  * ** **  *** *  **  * is not a prefix of %s", prefix, word);
* *** * **    **       *   *  * ***   **   *    * *** *  **       *    **   *****  **   0;
     **   *** **  ** ** ***  ***** *******    *** **      
  *  *    **  ****   * * **
 * *** * *   * ** *   * * ** ***  is a prefix of %s", prefix, word);
 ******   ** *    **  * * * 0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *    **  *** *     ** *** ** ** n,count;
  ******     ** *** * **   ** a[100],b[100]={0},c[100]={0};
** *   ** * ******  ** * ** *  * *    *  %s",a,b);
**  ** *  ** *  * *  ***** *  *
****   **  *****  * * *** *     *** **  *********
 * ** **  * *  ** **** **** * **       *   ** **  * *** *  
******* **     * ******  *   ****
**  * * ** ***   **  ***  *    * ** *** * ****** *   ***  ******  * 
* *    *  * ** *  * * 
**  *   *  **    *****  ***  *             * *  ****
 **     *  *  ** *    * **     **  (strcmp(a,c)==0)
*   * * * *   **     * * *****
* *     ** * ** **  *  *  * *  **   *  **** *    *  ****  *** *  * ** **** is a prefix of %s",a,b);
 ** * **  *   * ** *  ** *   
*   * **** *  * **  *     **
*** *** * ******   * *    
** * **  ** ******* * ***   ** ***** ** **   *   * *    *  * * ****** is not a prefix of %s",a,b);
 * ** *   ** ** *    ** ***
   ***   **      *   *  * * **      0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
   ***  *  *  ** ** * ** ** String[50],string[50];
* ***  ** ** **   ***** ** a,b=0;
**** *  *  **** * ****    * ** * ** **** *  **       ** * * *
*  *****  * * * * *   * * * ***  *  **    *    *

  *** *     *** * *    ** **  ** ** * * **  *  *
 * **  * **** * * ** *   *
 *** * ** **    **  *   * *   ****  ** *  *  **  *   **   *** * *   *
  * * * * *      *   *  ***** * ** **      * ** * 
***  *  * ***  ***  *  **      * ****  * ******    *   * * *   *    *   **  * 
*  ** **** **  *******  **  * **    *   *    * ** ** *  **
    }
**  *  **  **  * *  **     *   * 
   ******   * *   * *  **       
 * *  ** **** **    ** **** * ***  **** **   * *  ****    *   is a prefix of %s",String,string);
     ********   ** * ****
    **  *   ** ***  *  *   
  ** ***** ** **   ** * * *   *
  ***** *  **   * *** *** *  *** ** ** *   ****** ***** *  *** is not a prefix of %s",String,string);
*  ** *  ** *    ** *  *  * * 
  return 0;
}
answered by (-107 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ****   *  *    *
#include ****** * ***    *  

int main()
{
***  * *   **  *** *     * a[100],b[100];
 *   * ** **  ** **   * *  * **** * %s",a,b);
 *   ***  * *** *  ** **  * i,j,prefix = 1,len = strlen(a);
 * * * *    *  **  **** **    * *  = 0 ; i < len ; i++)
****   *   ****  *  *     
    * **  * ***  *  *     ** *    * *    * *   * != b[i])
******  **  *** * ****  *   *  * ***  * * **  *   * *** * 
*  *** *  *  * * ****  * * ***   * ** ***** *     *  * **  ****  **  *       * *** *** = 0;
**** **  *  ** ** * * *   *   *** ** ***   **  **** ** *  ***   ***  ** *** * *   **  *   ***  is not a prefix of %s",a,b);
* ** ***  * * *** ** *  * * *  *  * *  * *   * ** * * * **  **    **   *  *    *   ** *
* ***  ** ******  ***  *  * * **     *** * * * * *** *

*  **** * ****  ** *  *
     *  *    **   **  * *** ** * == 1)
 * * * *   * **  *  * ** *   ** *  *****  * * *   * * *** * **  **** *  ** is a prefix of %s",a,b);


* ****** * ** ***  * **  *   ** ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.179
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 4.5k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 4.8k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 3.7k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 943 views
12,783 questions
183,443 answers
172,219 comments
4,824 users