2 like 0 dislike
16.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 16.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
* ** * ****** * ** **** ** **
for(;;)
* ** * * ** * ** ******
for(i=1;i<(a+b);i++)
{
** * * ***** * * ** *** * * * *
* ** * * *** * *
*** * * * ** *** * *
**** *** ** * ** **
* ** ***** * ** * ***** ** *** *** ****** * ***
** * *** * **** * ** **
}

i=1;
j++;
if(j==10){break;}
* * **** **** * * **** * ***

** ** * ** * ** * ***** ** ***** * ** * **** * ** * ** ***
* * ** *** * * *** ** ** ******** * *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** *** * * ** * *** *** * *** *** **** * ** ** *
*** ** * ** ** *********
**** **** * ** * * *** * ** ****** * ** ** * *
* * * * ** * ** * ** * ** ** * * * ** **** **** *** **
    {
* *** ** ** * ****** *** * *** ** ** *** * * * * ** ** *
** * ** *** **** ** ** *** ***** ** **** **** * **
** *** ** **** * ** * ** * ****** ** ** ** *** * * *** ** ** ***
* * *** * ** ** ** ***** * ** **** *** * * * * **** **
* ** *** * ***** ****** * * *** * ** **** *
    }
**** * * * *** * **** * * * ** *** ** *
* ** * * *** * ** * * *** * ** **** ***
    else
** ***** ** *** ****** * * ** * *** ** * ** * **** *** *****
** ** ** ** ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * ** * * * * * **** nom,denom,i,a;
*** *** * **** ** ** * **** * ***** %d", &nom, &denom);
*** * * ******* * ** * * * * i<=denom; ++i)
    {
** * **** * * *** * ** * ** * * * * *** *** * * ** *
** ** * ** * * *** * * * ** ** ** ** * * * ** * && denom%i==0)
***** * *** ** * ******* * ** *** * * ****
* * * * * * ** * * * * ** ** ******** * * * * ** *** ** * ** * = nom/i;
* **** ** * * ** ** ** *** * * ** * ** * *** ** *** * * *** = denom/i;
* ** ** * *** * * * ***** * * ** * * * * **** ** *****
** *** ** ** **** ** * * * *** ** * * * ** * * * * * * * * * ***** * *
* * * * ** *** * * * ** *** * * ** ***** * * * **** * *
** * * ** * * * * ** ***** *** ** ** * * * * *** * * ** ** * * *** * ***** *****

* * * *** *** * ***** * *** * *** * ** *** ** * *

    }
***** * * * * ** ** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** * ** * ** nom,denom,i,a;
* *** * ** * * * *** *** * ** *** %d", &nom, &denom);
****** * ** * ** ** * **** i<=denom; ++i)
    {
*** **** * * * * * **** * * *** *** *** * ** * ***** **
* ** * **** ** * ***** * *** ** ** * **** ** && denom%i==0)
* *** * * ******* **** *** * *** ** *** *
*** *** * * ** * ** ***** * ** * * * * ******** ** * * ** = nom/i;
* * * * ** *** ** ****** ** *** ****** * ** * * * * * * *** = denom/i;
** *** ** * * * ** ** * * ** * ** * * ** * * **** * ** * **
* * * * ** ** *** **** ** ** * * **** * ******** * * * ** * ** * * *** ** ***** ***
* * * * * * *** *** **** ** * * * * * **** * * * ** * * * ** **
******* ***** * * ** ** ** * * * *** ** * ** * * * *** ** * * * ** * * * **** ** *

* ** ** ** * * * ** * * *** * * * ***** ***

    }
**** ** * ***** ** * *** * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * * ** * * *** * nom,denom,i,a;
**** *** * ** ** * * * **** * * %d", &nom, &denom);
* * ** * * * ** i<=denom; ++i)
    {
* * ** ** *** * **** * * *** **** ** * * *** ** * ** * *
* ** **** *** *** * * *** **** *** * **** ** && denom%i==0)
* * * * * ****** ** * ** * * ** ** * * *
** ****** ** **** **** * ** * ** ** ** * ** ** ** * * * **** * = nom/i;
* * * * ***** * * *** * **** ** * * * * * *** *** *** ** * ** = denom/i;
** ****** * ****** ********* ** * *** * * * **** * * * * *** ** ** ** ** *
*** * * *** * **** *** * * * * * * * **** * ** ** * ** ** ***** *** ** * * **
** *** * *** *** * * * **** *** *** * * * ** * ** *
* ** * * **** ** * * ** * * ** **** ** * ** * ***** *** ***** ** * * **** * ** ** ** * *** * **

* ** **** * * ** ** ** * **** **** *** **

    }
** * * * * **** ** * *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** *** * ** *** **** * ** * *** * * ** * ** *** * *
* * * **** ** * * ** **
** * *** * * **** *** * *** * ** * * *** **** ** ** **
* ** ** * **** ** * * **** ****** * * ******
    {
** * * * ** **** * ** * ** * ** * * **** ** *** * * ***
** *** * * * *** ** ** *** *** ** * *
* *** ** ****** * * **** * **** ** * ***** * ** **** **** * ** **
* ***** ** * *** ** ** *** * * * ** **** * ** ****** *** * **** * * * *** *
* * * * ** * * ** * * * *** ** * ** *
    }
*** ** * * ** *** ** ** * ** ** ** **** ***
** * * * ** **** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ****** ** * ** * *** a, b, rem, n, d;

** *** ** *** **** * * ** ***** ** * ****** &a, &b);

* ** * * * *** **** = a;
* * * ** * ** * **** = b;

* *** ** * * ** * * * **** != 0)
* *** * * * * * *** **** **
** * * * **** * * ** ** *** ********* **** = a % b;
** * * ** ** * * ********* **** * ** **** * * = b;
** * ** * * * ** ****** ** * ***** ** = rem;
* *** * * **** ** *** **

* * * * * *** ** ** **** * % d == 0)
* * *** *** * *** **** *** * * ** * * * ** ** ** ** * n/d);
** ****** ******* * **
* * * * ***** * ******** * *** * *** ** * **** * * * * * ** * ** n/a, d/a);

* *** *** * * * *** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 16.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 16.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 21.1k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16k views
12,783 questions
183,442 answers
172,219 comments
4,824 users