2 like 0 dislike
15.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 15.1k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
*** * ** * **** * ** ** * * ******
for(;;)
* * *** * * ** * * *
for(i=1;i<(a+b);i++)
{
* * * * ** * ** ** * * ** * * * *
** ** * *** **** * *
****** * * * * ****** **
* ** *** * ** * ****
* * * ** ** ** ** ** * * ** * * **** * **
* * *** * * * * *
}

i=1;
j++;
if(j==10){break;}
* * * * * * * ** ** * *

* * * *** * ** ** * ** ** * ** * *
********* * ** ** ** ** ** ** ** * * ** * ** ** *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* **** ***** * * * * * * ** * ** *** ** ** * ** ****
* ***** *** * ** ** *
** * * * ** * ** ** * **** * * * ** * * * * * * * *
* * * ** * * ** ** * * ***** ** ** ** ** * ** * **
    {
* * **** * ** * * * ** * * *** *** * * ****** * ***** *** ** *
* * *** **** ** ** **** * * * * * *
*** * **** ** * * * ** ** ** *** * ** *** * ** ** * * ** * *** * *
**** ** **** * * * ** * * *** ******* * * ** * *** * * **
*** ** ** ** ** * ** * * * ***** **
    }
* * ** *** * * * ** * * * * ***** * * *
* *** **** ** ***** * **** * *
    else
* * * * **** **** *** ** ** *** **** * *** *** **** * * * ****
* * ** *** * ** *** *** * * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * *** *** ** * * ** * nom,denom,i,a;
**** * * *** * * * ****** * ***** %d", &nom, &denom);
* ** * ** ** *** ** ** **** * i<=denom; ++i)
    {
* * ** *** ** *** * * **** ** ***** * ** ** ** ** *
** ******** * * **** * **** ** * ** ** * ** * && denom%i==0)
* **** ** * * * * *** * ** *** *** * **** *
* ****** ** ** * *** ****** ***** *** *** * *** ****** *** * * * = nom/i;
* * ** * ** *** ** *** ** * * * * * * * * ** ** * * *** * ** ** = denom/i;
** ** * * **** * ***** ** * * ** * * ****** ** * ** ** **
* * * * * *** * ** * * ** * * **** * * *** *** ** * * * ** * ****** ** * * ** * * *
* *** * ** * ** * * * ** *** **** ******** * * *** * * **** *
** *** ** ***** *** *** *** ****** * * *** ** * * * ** * * * *** * * * * * **

* ** * ** * * * ** **** ********** ** ** *

    }
** *** ** ** * ** * ** *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** * * **** * * *** * nom,denom,i,a;
* * *** **** ** * ** **** %d", &nom, &denom);
* * * **** * * *** * * *** ** i<=denom; ++i)
    {
* ** * * * **** **** * * * * ** *** **** * ***** *** ***
*** **** ** * ********* * ** *** * * && denom%i==0)
* * *** * * * *** ***** ** ** ** * **** *****
* *** *** ** **** * * * ** ** * *** ** **** * * * ** = nom/i;
****** ** * ** * **** * **** *** * *** * * *** ** *** ** *** = denom/i;
* * ** **** *** ** *** *** *** ** * ** * *** **** ** *** ******* ** **
**** *** * * *** ***** * ** * * * * ** *** *** ** ** ****** * ** *
* ** * ***** *** ** * ** * * ** * * ****** ** * *** ***
** * **** ****** * * **** * *** * *** * * ** * * **** * * *** * *** ** * * * ***

** * *** ******* * ** * ** * * **** * * *

    }
*** ** *** ** * * *** * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** * * ** *** ** * **** * nom,denom,i,a;
*** * *** * * * **** ** *** *** * * %d", &nom, &denom);
* * **** **** * *** i<=denom; ++i)
    {
* * * ** * * * * * *** **** **** * ****** * ** ***
*** * * *** ** * ** * **** ** * * * *** && denom%i==0)
** ** ** ** * * ** ***** * * * * ** ****
* ****** * ** * * ** * * * * * **** * **** ** * **** * * * * ** * = nom/i;
** * ** **** * *** ** * * ** ** * *** * ** * ***** = denom/i;
*** * ** * ** * ** *** ** *** * * ** ** **** * ** * ****** *
* ***** ** ** **** ** ** *** * ** *** * * * * * * *** * * ** ** ***
**** * * ***** * * ** ** * * ** * ** ** ***** * *** * * ** **
* * * * **** ** ** * *** * * * ****** * * * *** * * ** * * *** ** ** * ** * *

* ** * * * * **** ** **** * * * *

    }
* * * * ** * ** ** ** ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** * * * * ** * ****** **** * ** * ** * ** * *
* ** *** * *** ** * ****
* *** ** *** ** * * * ** ** ** * **** ** *** ** ** * * *** **
* ** **** ** ** ** * ** * ***** * ** *** * * *
    {
* ** ** * ***** * * * * ***** * ***** * ** * * ** * * ** *
*** * ***** ** ** ** * * *** ** ***** *
** * ** * *** **** ** * ** *** *** * * * ***** ** ** * ** * *
* * * *** ** ** * * * ** * * * * **** ******* * * * ** * * **
****** *** **** * *** * * * * ** * * * *
    }
* ** * * * ******* ** *** ** ** ** *
** * * ********* ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * *** ****** * ** *** a, b, rem, n, d;

* * * * *** * *** * **** * &a, &b);

** **** ** * = a;
** *** ** * *** ***** * ** * = b;

*** * ** ***** *** * *** != 0)
** ** * ** * ***
* * * ** ** * ** * * ** ** * * *** *** = a % b;
* ** * * ** ** ***** ** *** ******* ** *** ** ** = b;
* ** * ****** ** * *** ** **** * * ***** = rem;
*** *** * **** * *

* * * ** * *** * * ****** * % d == 0)
** ** *** ** ** * *** **** * ****** **** * ***** * * ** ** * n/d);
* * ** ***** * ***
** * **** * *** ****** ** * ** ** * ** ** * * ** ** n/a, d/a);

* **** ** * ** * * ** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.51
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 19.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users