2 like 0 dislike
12.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 12.7k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
* * * * ** ** * **** * *
for(;;)
* ** * *** * * * ****
for(i=1;i<(a+b);i++)
{
**** ****** *** *** * *** * * * ****** *
* * ** *** * *** **
** **** * * * **** * *
*** ** **** * *** * ** **
* * ** * ** **** ** * ** ** ** ********* * * * *****
** * ***** ** ** *
}

i=1;
j++;
if(j==10){break;}
** *** * * ** ***

** * ********** * * ** * *** ** * ***** **
** **** ** * * * **** * * *** ** ** *** **


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
**** ** * *** *** * * * * * * **** * *****
* * *** * ** ** ******
***** * ****** * * ***** ** * ** ** * **** ** *** * *** ***
*** * **** ** * ** * * * ** * * * ******
    {
* **** * ** *** * ** * ** * ****** * * * ***** * * ** ** * **
*** * *** * * **** ** * ** * ******** *
* * ** ** * * * ** ** ** ** * * *** ** ****** * ** * ** * ** ** **
* **** * *** * *** ** * * ** * * ** **** ** ** ** ** *** * **
** ** * ** * * * *** * **** * **** ** * *
    }
* ******* ** ** * * * * * **
* * ** * * * ***** ** ** ** * ** *
    else
*** * ** * * *** * ** ***** * *** * ***** *** *** * * ** ** * *
** ** *** * * **** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** * * * ******* *** * * nom,denom,i,a;
** ** * ** ** *** ***** %d", &nom, &denom);
* * *** ** * * ** * * ** i<=denom; ++i)
    {
* * * *** ** * * * *** * ***** * *** ** * *
** * *** * * * * * * *** ** * * **** ** ** * * && denom%i==0)
** ** * * *** ** ** * ** **** ** ** * ******
* *** *** *** * *** **** * * * ** *** *** * * **** * * * * * ** = nom/i;
****** ** *** ****** ***** * * *** ** * * *** ** *** = denom/i;
* ** * ** ** * ** ** * * * ** *** * ** **** ** ** * ** ** * ***
*** **** **** * * *** * ** ** * ******* * * * * ** * * * ** *** *** ** **** * *
** *** **** * * *********** * * ** * *** *** ** * * * ** *
***** * *** * ** * * *** *** * * ** * * ** * ** * * * **** * ** * * ** * * * * *

**** ** ** * **** ** * **** *** ** **** * *

    }
* * * ** ****** * ** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * **** *** **** * * * * nom,denom,i,a;
*** ** ** * * *** * ******* * ** * ** %d", &nom, &denom);
* * * * ******* * * **** i<=denom; ++i)
    {
** * ** ***** **** * *** ***** * ** * *** * * *** ****** * * * *
***** *** * *** * * *** * * * * ** * ** * * && denom%i==0)
**** ** * *** * * **** * ** ** * * **** *** *
*** ***** * **** **** ** *** * ** *** * * *** * * *** *** * * ****** = nom/i;
* *** * ******* *** * *** ** * * * ********* *** *** * * * ****** = denom/i;
* ** **** ***** * **** * * ** ** * * * ** *** * * * ** * *** **** ****** * **
* ** ** ** ** * ***** * * * * **** *** * ** * ** * * ** * ***
******** ******** * ** * * * *** ** *** * * **** **
* * * * * ***** * **** * *** *** **** **** ** * ** ***** **** ** * * * *** * * *******

* ** * * * * ** * ** * * ****** * *

    }
** ** * ** **** ** ** * *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** ** *** * ** * ** * ** nom,denom,i,a;
** ** ***** * ** * ******* ****** * %d", &nom, &denom);
** * ******* * *** ** * * ** * i<=denom; ++i)
    {
** * * * * ***** * * * * ****** *** * *****
* * ** ** * ** * ****** * *** * * ***** * **** * * && denom%i==0)
** * *** ** ** * *** * *** * ** ** * * * *
*********** * * *** * * *** ** * ** ** *** * * * * * * = nom/i;
* *** ** *** * *** ** ** * * *** * * * *** * **** ** * * = denom/i;
** * * ** ***** * * * ** * * * *** * * ** * * ** * * * ** **** *
* * ** * * ***** * * **** * * ** ** * * * ******* *** ******** * * ***** *
*** * ** * ** * ******** * * * * ***** ****** ** **
*** ** * * ** **** ****** ** ** ** * ****** ** * * * **** *** ****** *** * ** ****** **

* *** *** *** ** **** ** * **** *** ** *** ***

    }
* ** * ** ** ** ** *** * * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* ** *** * * * * ** *** ** * ** * * *** * ** ** *
* * ** ****** ** * *
* ** ** *** * * ** ** **** * *** ***** ** ***** *** *
* * ***** ** * * ** * ********** ** * ** * ** **
    {
* * ***** ********* *** ** *** * *** * ** **** *** ** * * ** * *
****** * ** * ** ** * * ** ** **** ******* **
** ***** * ** **** **** ***** ** ** * **** ** *** *** ***** **
** *** * * * * *** ** * ** * * * * ** ** * * * *
** ** * ******* * * * * * ** * ** **
    }
* * ** * * **** *** * ** * * * **** **
***** * * ** * ** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * * * *** **** a, b, rem, n, d;

* * *** *** ** ** *** ** *** &a, &b);

*** ********* * *** * = a;
** **** * *** * * = b;

* * ** *** *** ** != 0)
* *** * * * **
* *** * * **** * * ** * ** ***** * * ** ***** ** * = a % b;
*** ** * * **** *** * * ** * ** * * * ** = b;
* * ** * * * * ** * ** **** * *** * *** * ** * ** = rem;
* ***** ** * ***** * ****

*** *** * * * *** * % d == 0)
** * * ** * ** * * * *** **** ** * ** * * * ** ** ******* n/d);
** *** * ** ** ****
* * ** ** *** ***** ** * * * ** ** ** * *** * * * * n/a, d/a);

*** * * * * * * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.39
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 12.9k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.3k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users