2 like 0 dislike
9.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 9.6k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
* * **** * ** ** * ** *** **
for(;;)
* * * *** * *** ** * ****
for(i=1;i<(a+b);i++)
{
**** *** *** * * *** * * **** *** *
** ***** * *** * * * ** *
* * * ** * * * * **** **
* * ** * * * * * ****
* * *** * * ** *** ** ** *** *** ** * * *
* ****** ** * ** *
}

i=1;
j++;
if(j==10){break;}
**** * **** ******** *

** * ** * ** * ** * ** *** ** * * * * *
** * * ** ** * * ** * * * * ***** * * *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* * ** *** * * ** * * * * * * ** ** * *
** ** ***** *** ** ***
* *** * * * * * * ********** *** *** ** * * * * * * * * ** *
** * ** * * * ** ** *** * ** * **** **** ** ** *
    {
* * * ** * ** **** * * * * ** ** ***** *** * **** ******** * **
* *** ****** * ** * ** * ** *
* ** ** * *** * ** ** ** * * * * ***** * *** ** * **** ** * *
***** ** * ** ****** ******* * *** * ** *** ** * * ** * ** * * * * **
** **** *** ** *** ** * ****** * * ** * * ** *
    }
***** ********** *** * *** ** * * * * *
* * * ***** *** * ** * ***** **
    else
***** *** ** ** * ** ** ** ** ** **** * * *** * * **
** ** * ** ** ** * ****** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * ****** * * *** ****** nom,denom,i,a;
*** ** * *** ** * %d", &nom, &denom);
* * * *** * * ** * i<=denom; ++i)
    {
* * * * ** ******* ** * * * *** * *** ********* * *** *** *
** ** ** * * ** **** ** * ** *** *** ** * && denom%i==0)
**** * *** *** * *** ** * * ***** * ** *
***** **** ******* * * * * * * **** ** ** * * ** * **** * ** = nom/i;
****** *** *** ** *** ** * ****** **** * *** * * *** = denom/i;
*** * *** * * ** * *** * ** *** * ** ** ****** * *
**** * * ***** ** ***** * * *** ** **** * * * * ** *** * ** *** ** * ***** * *
* ** ** * ** * *** * * * ***** * * ** *** * ** * ***
* ** ****** *** * ** * ** **** * ** * ** * * * **** ** **** *** * *** **** * * ***

***** * ** * * * * * * ** ** * * ** * ***

    }
** * * * ** * * ** * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** ** ******** * * ** * ** nom,denom,i,a;
*** * * * * * *** *** ** * * * **** %d", &nom, &denom);
* * ** ** ***** ***** * *** i<=denom; ++i)
    {
**** ** * **** *** * *** *** ***** ** ******* * ** *** * ** **
* ** * * * * *** *** ***** * * ** * * * && denom%i==0)
** ** ** * * ** * ** * ***** *** ***** *
**** *** *** *** * ****** ** * ** **** ** * *** * ***** = nom/i;
* * ** ** * ** ** * * ** * ** ** ** ** * * * = denom/i;
** *** ** **** *** * ****** ** * * * ** * * ** ** ** *** * * * * ***
* * * * *** ** *** *** ** ** * ** * * * * * * * * ***** *** * * * * * * **
** ******* * ** ** ** * * * * * * * *** * * ****
** **** * ** **** *** * ** * * * * *** * * * * *** *** ** * *** * *** * * **

*** * * * **** **** ***** ** * * ***

    }
* ***** * ** * * * ** *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * * * **** * * *** * nom,denom,i,a;
*** ** ***** *** ** * ** * * * %d", &nom, &denom);
** * * ** * * *** ** * i<=denom; ++i)
    {
*** ** * * ** * *** * ** *** ** ** ****
* * * ** * *** ** * * ** ** **** * * * * ** * ** ** && denom%i==0)
**** * * ** **** ** * * * ******* * ***** * ****
** ** * **** * *** * ** **** * ** ** * * * ** ** **** * ** = nom/i;
* * * * * ** * * * ** *** * ** ** * ** *** *** ** * * * * = denom/i;
****** *** * * * * ** * ** * ** ** **** **** ** ** *** * ** * ** * *
* ** * * **** * ** * * * * * * *** *** ***** * ***** ** * ** **** * ** *** * *
* ** * ** * * * ** * **** * ** * * * ** *** * *** ***** *** * *
*** * * ** * ** ** * ** ********* * **** ******** *** * ** ******** * ** * ** * * *

** ** ** *** **** * **** * * * * ** **

    }
** *** * * * ** *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* **** * * ******* * * *** * **** * ** ***** * * **
***** * ** * ** ** **** ****
**** * ** ** ***** * **** ** * ** *** *** * * * * * * *
** * * ** * * ** ***** ******** * * * * * ****
    {
** ** *** **** * * ** ** * * * * * * * * * * ** **** **** ** **
*** * *** * * * * * *** * ** *
** *** * * * * * * ** * * *** ** *** * *** *
* ** * * *** ** * * * * * *** * ** ******* **** *** ** ***** ** ***** **
** *** * ** * ** * * *** * * ****
    }
* * * * ** * * * * *** * * * **** * * *
* ** * * * * ** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** * ** * ** * a, b, rem, n, d;

** **** * **** ** * * * **** ** * &a, &b);

* *** ** *** **** * = a;
* * *** *** * * ** * = b;

* * *** ** **** * ** * ** != 0)
* ** ******* ** * *
* * ** *** **** * **** * *** * * ** *** * = a % b;
* ***** * *** * ** ** ********* ** ** *** ** * ***** = b;
* ****** * *** *** * *** *** * * ** * * *** *** = rem;
**** * * *** * ** *

** * * ***** * % d == 0)
** ** *** * ** ***** *** ** ** **** * * ******* * *** * n/d);
* ** * * * ** *** *** *
* * *** * * * ** ** * * * * * * ** * ** *** n/a, d/a);

** * **** ** ** * ** ** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.211
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.6k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.3k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.8k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users