2 like 0 dislike
7.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 7.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
***** * *** * * ***** * ** *
for(;;)
** * ** ** ** ** * *
for(i=1;i<(a+b);i++)
{
* ** *** *** * ** * ***** * * * *
******** * * ******** **
* ***** **** ****
**** * ** **** ** * **
* * **** * * ** ** * *** * ** * * ** **
*** * * **** * *****
}

i=1;
j++;
if(j==10){break;}
** ** ** **** *** *** ******

** * ** * * * ** **** ******** * ** * *** ** ****
* * ** *** * ** ** ****** *** ** * * * * ** *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* * * * * * ** ** * ** * ** *** * *** *** *** **
*** ** * *** **** * **** ** *
* ** * ***** **** ** * ***** *** *** * * *** * **** * ** *
** * ********* * ***** ** * * * ** * ** ** ** * * **
    {
* * * *** * ** * *** * ** * * ****** * * *** * ***** * *** *** * * ** *
* ** *** *** * ** * *** * ***** ***
** ** * * *** **** * * * * *** ** **** ** * ** ***** **** ** * * *
** * * * *** ** * * *** * * ** * **** ** *** * * *** ** * * * ***
* ** ** ****** ** * * ** ** * **** *** ** * ** ** *
    }
** ** * ** ** ** *** * * ** * * * * **** ***
*** * **** * * * * *** ** ** * **
    else
* * ** * ***** * *** * ** ** * * ** ** * * * **** *** * **
* *** *** * * ** *** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * * * ** ** nom,denom,i,a;
* * *** * ** ** * * ** **** * * %d", &nom, &denom);
** * * * * **** * i<=denom; ++i)
    {
* *** * *** * * ** * * * * ** * * * * * ** * * *
** * ***** *** * ** ***** * * ***** * * * ** *** && denom%i==0)
* * ** **** * ** *** ** ** * ***** *** **
** ** * ******* ** * ** *** * * * ** ** ** ***** *** * * ** = nom/i;
**** * ** * * * * ** *** ** **** * ** * *** * **** * * ****** *** * ** * = denom/i;
* ** * * ** ** * * ****** *** ** ** *** ******* * * * * **** **
* ** ** * * *** ** *** * ** ** ** ** * ** ** * * * ** * * *** ** ** **
* * * * *** ** * * * * * * * *** *** * ** * ** ** ** * * ****
* * * ** *** ** * * ** * ****** * * ** * ** * * ***** *** ** * *** * *** *

**** ** * * * ***** * ** *** ** ****

    }
* ** ** *** **************** ** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** ** * * * ** ** * * nom,denom,i,a;
* ** ** *** * * * * * %d", &nom, &denom);
**** * ** ** * ** * * ** * i<=denom; ++i)
    {
* * * * ** ** * * * * * * * * * * * * ** * *
* * * * *** ** ****** * * ***** * * ***** * * && denom%i==0)
*** * * * ** * ** ***** ** * * * ** **** **
** * * ***** ** ****** * ** * ** ** * * ** ** *** ** = nom/i;
* * * **** * ** *** * *** * * ** * * **** *** ** *** ** ** = denom/i;
*** ** *** ********* *** * *** *** * * ***** * * *** *** ** *
******* * ** *** * ** * ** * * * *** **** * * * * * * * * ** * *** *** *
* * * * * *** * * * ** * ** **** ** * ** **
** *** **** *** *** ** * * *** * ****** *** ** ** ** * * * ** ** *

* * **** ** **** *** ** ** ** * * * **

    }
***** * *** * ** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** * *** *** **** nom,denom,i,a;
** **** ** * ********* * * ** %d", &nom, &denom);
* * * * ** * * * *** * i<=denom; ++i)
    {
** ** *** ******* *** * * * ** **** * ***** **** ** ** ** * ***
* *** * * *** ** * * * * ** * ** ** **** * ** * * * * && denom%i==0)
**** ** * * ******* * ** ****** **
** * ** * ** ***** * * ** * * * ** ** ** **** * * = nom/i;
** * * ** ***** ** * * ** * * ** * * *** * **** * = denom/i;
**** ** ** *** **** ** * * * * * ** * * * * *** ***** *** * ** * *
**** ** ** * *** ** ****** *** ** * * * *** *** * ** * * ** * *** * **** ** *
* * * * * ******* * ****** * *** ** *** ** * *
* ** ** * * ** * * ** * * ** * * * ***** * * ** * ** *** ** ** * * ** **** * * *******

* **** ** * ** * ** * **** ** ******* * ****

    }
* *** ** * * ** ** * *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
*** * *** ** *** * * * * ** ****** ** * * * *** * *
* * ** ******* ***
* *** ** * ** ** ** * ** ******* *** * ** * * * *
** * ** ** **** * * * * **** ** ** ** * * * *
    {
* * ** * ** * * * * * ** *** * * *** *** * * ***** ****** **
* ** *** *** * * * * * ** *** *
* * *** * * * * *** *** * * **** *** * *** * * *** * ** *
* ** *** * * * * * * * * **** * * *** ** * *** ** ** ****
* *** **** * ** * * ** *** * ****
    }
* *** * * * * * * *** * ** *
* * **** * *** * **** * * * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * * * * a, b, rem, n, d;

** *** **** *** * * ** * ** * ** * &a, &b);

* ** *** * * * = a;
* ** * ** * * = b;

* * ** ** * **** * ******** * != 0)
*** ** * ** ** * *
** ***** * * * * * * ** * ** **** **** * ** ** = a % b;
** * ** ** ** ** * * * ***** * * = b;
**** *** ** * * *** * * * * *** **** ** = rem;
* *** * * * * *** * * ***

** ***** * * *** * * % d == 0)
*** *** ** ****** * * * ** * * * * * ******** **** * * * * n/d);
*** ***** * * ** * * * * **
* * ** ** * * * ****** ****** * ** * ** **** * ** * ** * n/a, d/a);

** * * ** *** * *** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.12
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 8.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 7.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9.8k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 7.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users