2 like 0 dislike
14.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
*** * * * ** * ****** * * ****
for(;;)
** ** ** *** * **
for(i=1;i<(a+b);i++)
{
* * * * * *** * ** ******* *** * ** * * * * *
*** * ** **** ** ******* * **
** *** * * ***** * *
*** ** ** ** * ****** * * *
* * * ***** * ** ******* * * **** * *** ** *
* * ** **** * * * **
}

i=1;
j++;
if(j==10){break;}
** * * *** * * * * *

* * **** * *** *** **** * * * ** *** ** ** ** **** *
**** ** *** *** ** * ** * ** ** *** * * ** **** *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
*** * * ** * * *** *** ** * ***** * ***** * * * * *
*** * * * ** * ** ** * ** *
* ** ** * ** ****** *** ** **** * ******* *** * * * ** * ** * *
* * ****** **** ** * ** *** ** ** *** **
    {
* * * **** ** * ** ** * *** * ** ****** * *** ** ** **** * **
*** ** ** *** **** **** * ** * * *
* *** * * * ** ** ** *************** * ** * **** * ** ***** ***** * * * ** ****
* * ** *** ** ** ** *** ***** ***** *** ** * * * **** **** ** **
* * * ** * * * * * ** *** ** ** ** ** *** * *** *
    }
* * **** * ** *** * ** * * ** ** * *
*** ** * * * ** * * ** *** * *
    else
* * * * * * * * * * ** * ** ***** ***** * ** **** * * * ** * * **
** ** * * * *** **** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** ***** * **** nom,denom,i,a;
*** *** * * ** ** * * ******* %d", &nom, &denom);
* ** * ** **** * **** * i<=denom; ++i)
    {
* * ** *** * * * * * * * ** * *** **** * * **** * **
**** *** * * * * * ***** **** * * * ******** && denom%i==0)
** **** ** * * *** **** ** * * *** *
* * ** * * ** * *** ** ** * * ** *** * * * ****** ** * * ** * = nom/i;
** * ** ** * * *** * * ***** ** * * **** **** ** ** *** ** = denom/i;
**** * * **** ***** * * ** * * ** * * * * * ** ** * ** * * *
******** ** * * ** ** * ***** ** * * * **** ***** ** ** * *** * ***** ***** *** * * **
** * * * * * * * ** * ** **** *** ******* *** * * *** ** * * *
*** *** **** ** * **** **** * * *** *** * * ******** ** ***** ** * * **

* * ** * * ** * * ***** * * **** * * *

    }
* *** ** ***** ** ******* * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** ** ** *** nom,denom,i,a;
** * ** * ****** * * ** * ** ** %d", &nom, &denom);
* * * * * * ** * *** *** * i<=denom; ++i)
    {
***** * * * **** **** ***** * * ***** ** ******* * ***
* ** * *** * * *** ** ** * * ** * *** *** ** && denom%i==0)
** ** ***** ** * * * * ** * ** * * *
* ** * * ** ** ** * ** *** * **** * * * ** * * * * **** = nom/i;
** * ** ** * * * *** * * * * ** ** * ***** * *** *** * *** = denom/i;
* ** *** ** *** * ** ** *** * ** ***** ** * *** * * *** ** * *** *
* ** ** * *** * ***** ** * * **** *** ** **** * ** *** ***** * **** * * * * ***** * *
******* * ** * ** *** ** * *** *** *** * * * ** *** * * **** *
***** *** *** **** * * * *** * ** * * ** ** *** * * ** * * * ** * * ***** * **** * ***

*** ***** * * * * ** * * * **** * ** *** * * ** **

    }
*** ***** ** ** ** ******** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
**** ** **** *** * *** nom,denom,i,a;
*** * ** ** * * * ****** ** ** * *** %d", &nom, &denom);
*** ** ** * ******** * i<=denom; ++i)
    {
* ******* * ** * *** * * **** ** * * * ** *** * ** *
* ******* * * *** *** * * * * * **** * * ** * && denom%i==0)
*** * * ** ** ** * * ** *** * ** * **** ** **
** ** ** *** **** * *** * * * *** * ** ** * * * **** = nom/i;
* * * * **** * ** * * * ***** ** ** * *** * * * ***** * ** * = denom/i;
* * **** * ** *** **** ** ***** * * * ** ** * * **** ** * *
* * ** * ** * * ** *** * ** ****** * * *** * * * ***** * * * ** ** *** * * *
***** ** ** **** * * * *** *** **** * ** ** * ** *
** * * ****** * ** * ** * *** * ** * **** * * * ** * * ** ** ** *** * ** *** * **

* * ** *** * *** * ** * ** * * * ** **

    }
** * *** ** * ** * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** *** ***** *** ** * ****** * ** * *** ** *** **** *
* * * * ** ** * * **
* ** ** * * **** ** *** * ** * * * * ** * *** * ** ** * * *
*** *** * * * ****** * * * * *** ** * ** * * *
    {
* *** * ** * * *** * ****** * *** *** * *** *
* ** ** ** * * ** * ** **** ** ** * **
* * *** *** ** * * * * ** * **** ** *** ** * ** * *** * **
*** * * * * ** * * * ** ******* * ** ** ** * ****** * * * * ** ** ***
** * * * * * *** * ** ** * * * *
    }
*** * ** * *** * ** * *** * * ***** * * ***
* ** * * * ******* *** * ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ** * * ****** a, b, rem, n, d;

** ** *** *** ** * ** *** **** * * ** ** * &a, &b);

** * ** * **** * **** ** = a;
*** ***** * ** * ** * ** = b;

*** * ** ** ** *** ** * ** != 0)
** * * **** * * * * ****
* * * * ** * ** *** **** * * **** * * **** = a % b;
* * ** ** ** * * ** * * **** * * ****** ** * = b;
** ***** * *** * ** * * ** * ** * *** = rem;
** * **** *

* ** * ** **** * * ** * * % d == 0)
* *** ****** * **** ** *** ** * * * * * * * * *** ***** * n/d);
* **** * * ** ** * ***
* *** * ** ** * * * * * * * * * ** * ***** ** * * n/a, d/a);

** ***** * *** * * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.78
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.7k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.5k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.6k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users