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    Suppose there is a pair of newborn bunnies in the pasture in the first month, each pair of male and female bunnies grew into a large male and female rabbits after two months later. After three months from the start, each pair of male and female rabbit can give birth to a pair of small bunnies every month. If the rabbits can live forever, how many pair of rabbits in the pasture in the first N month?

(1<=N<=90)(Very IMPORTANT)

Input

3

Output

2

 

Input

5

Output

5

 

Input

88

Output

1100087778366101931

[Exercise] Coding (C) - asked in C
ID: 22018 - Available when: Unlimited - Due to: Unlimited

edited by | 6.9k views

69 Answers

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Hidden content!
****** ***** *



int * * (int month)



{

if (month == 0)

{
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}

else if (month == 1)

{
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}

else

{
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}

}





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}
answered by (-34 points)
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Hidden content!
** * ** * *



int *** (int month)



{

if (month == 0)

{
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}

else if * * == 1)

{
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}

else

{
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}
answered by (-34 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main(){
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answered by (-134 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main(){
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}
answered by (-134 points)
0 like 0 dislike
Hidden content!
* *** * * * **** *



int ** * (int month)



{

if (month == 0)

{
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}

else if == 1)

{
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}

else

{
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}

}





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}
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}
answered by (-34 points)
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Hidden content!
#include <stdio.h>

#include<stdlib.h>

int main()

{
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answered by (-249 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



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{
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}
answered by (-412 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include<stdlib.h>

int main()

{
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}
answered by (-249 points)
0 like 0 dislike
Hidden content!
** * **** * * * *



int * * (int month)



{

if (month == 0)

{
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}

else if * == 1)

{
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}

else

{
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}

}





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}
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}
answered by (-34 points)
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Hidden content!
#include <stdio.h>

int fibo(int);



int main()

{
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}



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{
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* * ** **** ** ** *** ** * * * * * * 1;
** **** ** * * **
* ** * * ****** * ** * ** * ** * * * * * - 1) + fibo(num - 2));

}
answered by (20 points)
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