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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * **** * * * ***
#include <ctype.h>
#include <math.h>
#include * * * *
int main(){
* * * ** ** ** ***** * * h,m;
** * ** * * ***** * ** * * * ** ** * **
*** * *** ** ** *** **** ** arch,arcm,sum=0;
* ** * * *** * *** ** * * * * * * **
*** ** ** * * **** * * = m * 6;
** * * * * * * * ** * * = h * 30 + m * 0.5;
** * * * * *** ** * * * * ** ** > arch){
** * * * * * * ***** *** ** * = arcm - arch;
* ** * * ** *** * ***** * ** * **** * * * * ** * * *** * * * *** * *
** * ** ** * ** * * *
* * ** * ** * * ** * * * * * < arch){
* * * *** * * * ** ** * ** * * * * *** * *** * * * ** = arch - arcm;
* ** *** * * * * * *** * * * ** * *** * * * * **** * * ** ** *** * * *
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* * * * ** *** ** * * * * * * * * * ** *** * * ** * ** * * *** * * * * *
** * * * * * ** * **
** * * * ** * * * * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * ** ** * **
#include * * * * * * *
#include <ctype.h>
#include <math.h>
int main()
{
* * * * * * * *** * a,b,c,d,e;
** * * ** ** ** * **** * * * * ** * * ** ** * *
* * * ** ** ** * ** * * ** * ** * ** * * * * * *
**** * * * * * * * *
* * * *** *** * * ** *
** * * * *** * * * * *** ****** *
*** * * * ** * * * * * * *** * * (c>=d)
* **** *** * * ** ** * * * *
* * * *** *** * * * (c<d)
* ** * ** ** * * * * * * * * **
*** ** * * ** * * * * * (e>180)
* * * ** * ** *
**** ** * * * * * * * * * * * * * * **** * *
* * * * * * * ** * * 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include ** * * ** *** *
int main()
{
*** * * ** ** ** * ** * * * ** * * **** ,j ,n=0;
*** ** ** * *** * * i;
* ** * *** * * * * * * * ** ** * * * * * ** * * * ***
** ***** * ** * *** = i % 12 ;
* * * * * ** * * =( i * 30 )+( j / 2) ;
* * * * **** * * * * * = j * 6 ;
* * * * *** * * ** * =k-l ;
if(m < 0)
** * * * ** ** * * *
* * * * * * * ** ** * ** ** * ** * = - m;
* * ***** * * * * *
* * *** * *** * if(m > 180)
* * * * ** * * * *
*** * ** * * * * * * * ** ** * * = 360 - m ;
* ***** * ** * ** * *
* * * ** * ** ** ** * * ** ** * * * ** *
** ** ** * * * * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * * * h,m;
* * *** * * * * ** *** ang1,ang2;
* * * * * * * * *** * * * * ** * ** * * * * ****
** *** * ((30*h+0.5*m)>6*m)
* * * * ** * *** * *
* **** *** * ** ** * * * * ** * *** * ** = (30*h+0.5*m) - 6*m;
* * * * ** **** ** *** * ** * ** * = 360 - ang1;
* ** **** * * ** * * * * * *** * * * (ang1 > ang2)
** ** ** * **** * * * ** * *** * * * * * * * ** * * * * ** ** * * *
* *** * * ** * * * * * *** * * * * ** *
* ** * *** ******** * * * * ** * ** ***** * * *** ** ** *** * *
* * ** ** * *
* * * * ** * * *
*** ***** ** **** *
** * * * * ** ** * * * ** * * * * * * * = 6*m - (30*h+0.5*m);
*** *** * ** ** ** * * * * ** ** * * * = 360 - ang1;
* * * * **** ** ** * * * ** * * * (ang1 > ang2)
* ** * * ** * *** * * ** *** * * *** *** ** * * * * ** * *
** ** ** * * * ** ** * * **** ** * * ** **
***** * ** *** * * ** * * * * * * *** * * ** * **
}
* * * * * ** **** 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * *** * ** * *
* * ** * ** *
int * * *
* * ** * * * * * ** a ,b ,i;
**** ** * *** ** * * ** c;
* * * * ** *** * * ** ** * * *
* * * * *** * * ** ****** * ** * * ** * ** ** *
* * * * * * ** != 12)
****** * * * ** * * = b*6 - b*0.5- a * 30;
* * ** * * **
* * * ** *** * * * = b*6 - b*0.5;
** * *** * * ** * c * ** ** 0 )
* * * * ** * = -c;
** * * * ***** ** * ** * ** * * * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include *** * * * * *
int main()
{
* * * ** * ** m=0,k=0,l=0 ,j ;
* * ** * * **** i;
* * * * * ** * * * * * ** * * *** * ** **
* ** * * * * * * = i % 12 ;
**** ** ** =( i * 30 )+( j / 2) ;
* * * ** * * ** = j * 6 ;
***** * ** * * * ** =k-l ;
* * ** * *** * * ** < 0)
* * *** * * ** *
** ** **** ** * * * * * * ***** * *** = - m;
* ** * * * * *
* ** ** * *** ** ** * if(m > 180)
* * * * **** **** * * * **
* * * * * * * * * * * ** ** ** * * = 360 - m ;
***** ** * ** ** **** *
* ** * ** * * * * * * *** * ** * *
** ** * ** * *** * ** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* *** *** * ** * * * * a,b=0;
*** * * * ** **** * ***** * * c,d=0;
** * * * * * * * * * * * * * ** ** * ** ** *** *
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}
* * ** * ** ** ** ** ***** ** * * *
** *** ** * ** * ** ** * ** ** * * * * * ** ** ** *** * * * **
}
* * * * **** * * * * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * ** * * * ** * * hour,min;
* * * * * * ** ** * * d,k,a1,a2;
* *** * * * *** ** * * ** * * *** * * * ** * * * * * * * *
* * * ** ** ** (hour==12)
* ** * *** * * * * * * * * *
** * *** * * * **
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** * * ** * * * ** * * * * * * *
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** **** * *** ** * * * * * *
** ** ** * * * * *** * * ** 0;
* ** * ** * ** * ** ** * **
** * * ** * ** * *** *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** *** * * ** ** ** * * a,b;
* * * * * ** * * * * * ** * ** * q,w,e;
* ** * * * ** *** * * * **** ** * * ** * * * *
** * ** ** * * * * **
{
* * *** * * * ** ** ** ** **** *** * * * *** * * ** * == 0)
* * * ******* * **** *** * ** * * ** * * * ** * * **** = 6*b - b/2;
* * *** * * * ** * * * ** *** * * *** * ** * if(b%2 != 0)
** * * * * ** * ** * *** ** * * * * *** ** * * * = 6*b - b/2 - 0.5;
** ** * * **** * * ** *** * * * * * *** ** * ** * ** * *
** * * * * * * * * *** ** * * * ** **** * * * * = 360 - q;
* * * * ** * * * * * ** * * * * * * * * ** * * ** if(q<0)
* * ** ** * ****** * * * * ** * * *** = 360 + q;
}
* * * * * ** * * *** *
{
* * * ** * * * * *** * ** * * * * * *** == 0)
** * ** ** * * * * * ** **** * * * * *** ** = 6*b - b/2 - 30*a;
* * ** * * * ** * * ** ** * * * ** * * * if(b%2 != 0)
* * ** * * ** * * * * * * ** * * * * * * * * = 6*b - b/2 - 0.5 - 30*a;
* * * * ** ** * ** *** * * * * *** * **** * ** *
* * ** ** * ** * ** ** * * ** * * * = 360 - q;
** * *** ** * * * * * * * * * * * * * * * if(q<0)
** * * * * ** * ** * ** ** * ** * * * * ** * * * * = 360 + q;
}
** * ** * * ** ** * *** *** ** * * *** *** * * * * * ** *** *** ** *
** * * ** * ** * * * * ** ** * * * ** * **** * * * * ** **** * * * * * * *
* ** * ** * * *** * * * ** * * * ** * *** ** if(w>q)
*** * * * ** ** ** * * * * * * ** * ** * * * * * * * * * ** * * * * * * ** * * ** *
*** ** ** * * *** *** * * * * *** * * * * * = b%2;
* ** * * * * *** * * * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** * ** * *** * * ** **** * a,b=0;
* ** * ** ** * * * * * * **** c,d=0;
* * ** * * ** * ** * * ** * ** * *** * * * *
* * * * ** ** * ** *** * * * ** * ** * * * *
* * ** * *** ** * * * *** * * ****
** * *** * **** *** ** * * *
** * **** * * * * * * ** **
** ** * *** * * ** ** * *** * * * * ** ** * *** * *** * ** * *
* ** * * * *** * * *
* * *** ** ** * * ** * * *
* * * * * * * * ***** ** ** * * * ** * * ** * * * * ** * * * *
}
* * ** * * ** *** * * ** * * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
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ID: 18085 -
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