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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
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#include <ctype.h>
#include <math.h>
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answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * * * ** **
#include ** * * * ** * *
#include <ctype.h>
#include <math.h>
int main()
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answered
Dec 1, 2016
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410523016
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Hidden content!#include * * *** ***** *
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}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
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}
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}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include ** * *** ** * * ***
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return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include ** * * *
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{
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* * * * * * * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
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* * * * **** * * ** * * * ** ** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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*** * * ** * * * *** * * ** * * **** * * * * if(q<0)
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*** * ** * * **** * *** * * * * *** ***** = b%2;
** * * * * ** *** * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* ** * * * ** * * * * * a,b=0;
* * * * * * * * *** * ** * c,d=0;
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* * ** * ** *** * ** * ** ** * * * ** * ** * * ** ** * ****
}
* * ** * * * * * ** * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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