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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
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Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * * ** *
#include <ctype.h>
#include <math.h>
#include * * *** * * **
int main(){
** * * * * ** * *** *** * * * h,m;
** ** ** * ** ** * ** **** * * * * * * ** ** * * *
* * ** ** * * * * * * * ** arch,arcm,sum=0;
**** * * * * *** ** ** * *** ** *
* * * * ** * * ** ** * *** * * = m * 6;
* * * ** ** * * ** ** ** = h * 30 + m * 0.5;
* * * * * * * * * * * * * > arch){
* * * ** * * * * * * ******** * * * * * * * * * * *** = arcm - arch;
* * * * * ** *** * * * * * ** * * * ** * * * * * **
** * * * * ** * * * ** *
* * * * * ** * ** * * * < arch){
*** * * * ** **** * * * * * ** * * * * *** ** ***** = arch - arcm;
* ** * * * * ** * * * * ** ** * * * * * * * * ** * * * **** ** **** * ** *
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* *** * * * * * * * * * * ** ** * *** * * ** * * ** ** * ** * ** * ****** *
* ** * * ** * * ***
* ** * *** * * *** *** * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * * * *
#include **** * * ** *
#include <ctype.h>
#include <math.h>
int main()
{
* ** * * * ** * ** ** * ** a,b,c,d,e;
** * ** * ** * * * * * ** * * * * **
** * * * * * * ***** * * * *** * *
*** * ** * * ***** * * * * *
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* ** ***** * ** * * **** * ** ** *
* *** ** *** *** * * *** * (c>=d)
** ** * ** * * ** * ** * *
* * * * * * * ** * (c<d)
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****** * ** **** * * * * * *** * * * * * *
* *** ** * * *** ** ** * ** * 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include ** *** ** ** ** *
int main()
{
** * * * ** * *** * *** * * ** * * ** ,j ,n=0;
**** * * * * * * ** i;
* * * * * * * * * * ** * *** * * * ** * * *** *** * **
** *** ** * * * * = i % 12 ;
* * *** **** * * =( i * 30 )+( j / 2) ;
** * * * * * * ** ** ** = j * 6 ;
** ** * * * * * * * * =k-l ;
if(m < 0)
* * * * ** ** * *
** * *** * * * ** * ** *** * * ** = - m;
* ** **
* * * ** * ** ** * * if(m > 180)
** * ** ** *** * *
* ** * ** ** * * **** * *** * *** * ** * * = 360 - m ;
* * * * * * * * * **
* ** * ** * * * * * * * * *** * * **
** ** ** * * * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* *** ** * * * * * ** ** h,m;
* * * ** *** * * * * ang1,ang2;
** ** *** * **** **** ** * * *** ***** * *
** * * ** * ** ** ((30*h+0.5*m)>6*m)
* * * * * *
** * ** * * * * **** *** * ** * = (30*h+0.5*m) - 6*m;
** * * *** * * * *** * * ** *** * * * = 360 - ang1;
** * * * ** * ** ** * ** * * * * * (ang1 > ang2)
** * * * ** * * ** * * * * **** * ***** * * ** * * ** * * *
**** * * ** * * * * ** * * * **
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* * * * *
**** * * * * ** * **
* ** * * * ** * *
**** ** ***** * * * * * * ** ** *** * = 6*m - (30*h+0.5*m);
** ** * * * * ** ** * *** * * ** *** = 360 - ang1;
* * * * ** * ** ** * * * * * * (ang1 > ang2)
*** ** * * * ** *** * ** * * * * * * * ** * * * * ** **** * ** *
** * **** * ** * * ** ** ** ***** ***
** * * * * * **** *** ** * * ** * * * * ** * * ** ** *** ***** * *
}
* ** ** * * ** * * * * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * * * * **
* * ** * ** **
int ** **
* * * ** * * * ** *** a ,b ,i;
* * * * * * * * * * * c;
* * * *** * * * ** * * * ** ** *** *
* ** ** ** * ** * ** ** * * ***** * * * * **
* * * * * * * * != 12)
*** * ** * * = b*6 - b*0.5- a * 30;
** * * * * * ***** *
** * * ** * * * = b*6 - b*0.5;
* *** * *** * ** * *** c * 0 )
** * * *** * * * ** ** ** = -c;
*** ** * * * ** * ** * * * **** *** * ** * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * * * *
int main()
{
* * * * * * * * m=0,k=0,l=0 ,j ;
* * * *** * * * i;
** ** * * ** ** ** * * * * *** * * * * * * * * *
* * * * * ** ****** = i % 12 ;
* ** ** ** * * * =( i * 30 )+( j / 2) ;
** ** **** * * * * * = j * 6 ;
*** *** *** ** * =k-l ;
* * ** * ** * * * < 0)
*** * * * *** ** ** * *
* * * * * * * ** * ** ** *** = - m;
* * * * * * * * * ** *
* * *** ** ** * *** if(m > 180)
* ** * ** *** * *
* ** * * * * * * ** * * = 360 - m ;
* * *** * * * * * *
** ** * ** * * ****** * ** *** ** *
* * ** * * *** * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * ** * *** * a,b=0;
* ** ** ** *** * * * * c,d=0;
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}
* * * * * * * * *** * *** *** ** *
** * ** * * ** ** * * * * * * * ** * * * * * * * * * * * * * * * *
}
* ** * **** * * 0;
}
answered
Dec 1, 2016
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SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * ** * * hour,min;
* * * * ** * * ** * ** * d,k,a1,a2;
* * ** *** * * * *** * * * ** * ** * * ** * * ** **** *
* * * * ** * * * * (hour==12)
* ** *** * * * * ** * * * * ** * *
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* * * * * ** * * * *** 0;
* * * * ** * * * * * * * *
* * * ** * * * * *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
**** * * * * * * * * * * * a,b;
* * ** * * ** * * ** ** q,w,e;
***** **** ** **** * * * **** * *** * **** *** * * *
* * * * * * * ** * * ** ** **
{
* ** * * * * ** * ** ** ** * * * * * * * * * * *** * * * == 0)
* * * * * ** * ** *** * ** * * * * * * * ** * = 6*b - b/2;
** * **** ** ** * * ** * ** * * ** * ** * * * if(b%2 != 0)
* * * ** * *** * * * * * * *** * * * *** * * = 6*b - b/2 - 0.5;
* * * * * ** ** * * * * * * * * * * ** ***
** *** ** * * * * ** * * ** * ** * *** * = 360 - q;
** * * * * * * * * * ** ** *** ** * * * * * * if(q<0)
* * * * * ** ** * * * ** * * * * * * * *** * = 360 + q;
}
** * * * * * * * ** ** * *
{
* ** * * * * * * * *** * ** ** * * * * ** * ** *** == 0)
* * * **** ** * * ** * * * * * * ** ** * ** * * = 6*b - b/2 - 30*a;
* * * * * * * * ** * * * * * *** ** * * * * * * if(b%2 != 0)
* * * * ** *** * ** * * * * * * * * ** * * = 6*b - b/2 - 0.5 - 30*a;
* ** * * ** ** * ** * * ** ** * * * * * ** **** * * * * * *
* * * ** * * *** ** ** * * * * * ** * * * ** = 360 - q;
* ** * * * * * ** * ** * * * ** * * * *** * if(q<0)
** * * * *** ** * * * * ** * * * ***** *** ** *** * * * = 360 + q;
}
* * * ** * * **** * * * ** * ** * * *** * * ** ** ** ** * *
* * * * * * * * * * ** * *** * * * * * * * * * * * ** * ** *** * * * * ***** * ** * ** * *** * * * *
** ** * * * * ** *** * * * ** * * ** * * ** ** ** if(w>q)
* ** ** * ***** * ** * * * * * * * ** ** * * * * *** * ** *** * * * ** * * ** * * ** * **
* ** * * **** * *** * ** * * * * * * ** * ** * * * = b%2;
* ** * * * * ** * * ** ** 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * * * *** ** * * a,b=0;
* *** ** * * ** ***** ** *** * * c,d=0;
* * ** * *** *** * * * * * * * ****** * * *
** * * * * * * * ** * * ** * * * ** ** * * * * * ** * *
** * * * * * * * * ** * ** * **
* * * *** * * * *** *
* * ** * ** * * * * ****
* * ** * *** ** * **** * * * * * ** * ** * *** * * * ** *
* * * * ** * * * * ** *
******** * * * * * * *
* * * * * * * ** * ** * * * * * * * * * ** *** * * * * ****** * *
}
** * * * * * ** ** * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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